DU A Unit Admission Question Solution 2012-2013
āĻ¨āĻŋāĻā§āĻ° āĻāĻŋāĻĄāĻŋāĻāĻ¤ā§ āĻĻā§āĻā§ āĻ¨āĻžāĻ āĻŦāĻŋāĻ¸ā§āĻ¤āĻžāĻ°āĻŋāĻ¤:
āĻā§āĻ°ā§āĻ¸āĻāĻŋ āĻāĻŋāĻ¨āĻ¤ā§ āĻĒāĻžāĻļā§āĻ° āĻŦāĻžāĻāĻ¨āĻāĻŋ āĻā§āĻ˛āĻŋāĻ āĻāĻ°:Â Â
āĻā§āĻ°ā§āĻ¸ā§āĻ° āĻĄā§āĻŽā§ āĻāĻŋāĻĄāĻŋāĻ(āĻāĻāĻžāĻŦā§ āĻĒāĻĻāĻžāĻ°ā§āĻĨāĻŦāĻŋāĻā§āĻāĻžāĻ¨+āĻ°āĻ¸āĻžā§āĻ¨+āĻāĻā§āĻāĻ¤āĻ°āĻāĻŖāĻŋāĻ¤ āĻāĻ° āĻŦāĻŋāĻāĻ¤ āĻŦāĻŋāĻļ āĻŦāĻāĻ°ā§āĻ° āĻ¸āĻāĻ˛ āĻĒā§āĻ°āĻļā§āĻ¨ā§āĻ° āĻ¸āĻŽāĻžāĻ§āĻžāĻ¨ āĻĨāĻžāĻāĻŦā§ āĻāĻŋāĻĄāĻŋāĻāĻ¤ā§)
āĻĒāĻĻāĻžāĻ°ā§āĻĨāĻŦāĻŋāĻā§āĻāĻžāĻ¨
- āĻāĻāĻāĻŋ āĻāĻĻāĻ°ā§āĻļ āĻā§āĻ°āĻžāĻ¨ā§āĻ¸āĻĢāĻ°āĻŽāĻžāĻ°ā§āĻ° āĻā§āĻŖ āĻ āĻŽā§āĻā§āĻ¯ āĻā§āĻŖā§āĻĄāĻ˛ā§āĻ° āĻĒāĻžāĻ āĻ¸āĻāĻā§āĻ¯āĻžāĻ° āĻ
āĻ¨ā§āĻĒāĻžāĻ¤ 6:1āĨ¤ āĻ¯āĻĻāĻŋ āĻŽā§āĻā§āĻ¯ āĻā§āĻŖā§āĻĄāĻ˛ā§āĻ¤ā§ āĻĒā§āĻ°āĻ¤āĻŋ āĻ¸ā§āĻā§āĻ¨ā§āĻĄā§ āĻŦā§āĻ¯āĻ¯āĻŧāĻŋāĻ¤ āĻļāĻā§āĻ¤āĻŋ 6J āĻšāĻ¯āĻŧ, āĻ¤āĻŦā§ āĻā§āĻŖ āĻā§āĻŖā§āĻĄāĻ˛ā§āĻ¤ā§ āĻŦā§āĻĻā§āĻ¯ā§āĻ¤āĻŋāĻ āĻā§āĻˇāĻŽāĻ¤āĻž āĻāĻ¤?
- 6 J
- \(3.6 \mathrm{Js}^{-1}\)
- 6 W
- 36 W
Ans. 6 W
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨ āĻā§āĻ¤ āĻĒā§āĻ°āĻā§āĻ°āĻŋāĻ¯āĻŧāĻž āĻļāĻŦā§āĻĻ āĻ¤āĻ°āĻā§āĻ āĻĻā§āĻŦāĻžāĻ°āĻž āĻĒā§āĻ°āĻĻāĻ°ā§āĻļāĻŋāĻ¤ āĻšāĻ¯āĻŧ āĻ¨āĻž?
- āĻĒā§āĻ°āĻ¤āĻŋāĻ¸āĻ°āĻŖ
- āĻŦā§āĻ¯āĻ¤āĻŋāĻāĻžāĻ°
- āĻ¸āĻŽāĻŦāĻ°ā§āĻ¤āĻ¨
- āĻ āĻĒāĻŦāĻ°ā§āĻ¤āĻ¨
Ans. āĻ¸āĻŽāĻŦāĻ°ā§āĻ¤āĻ¨
- āĻāĻŋāĻ¤ā§āĻ°ā§ āĻāĻāĻāĻŋ āĻŦāĻ°ā§āĻ¤āĻ¨ā§āĻ¤ā§ āĻ¸āĻŽāĻžāĻ¨ā§āĻ¤āĻ°āĻžāĻ˛ āĻ¸āĻ¨ā§āĻ¨āĻŋāĻŦā§āĻļā§ āĻ¸āĻāĻ¯ā§āĻā§āĻ¤ āĻ¤āĻŋāĻ¨āĻāĻŋ āĻ°ā§āĻ§ āĻĻā§āĻāĻžāĻ¨ā§ āĻšāĻ¯āĻŧā§āĻā§āĨ¤ āĻŦā§āĻ¯āĻžāĻāĻžāĻ°āĻŋāĻ° āĻ¤āĻĄāĻŧāĻŋā§-āĻāĻžāĻ˛āĻ āĻļāĻā§āĻ¤āĻŋ 12v āĻāĻŦāĻ āĻ
āĻā§āĻ¯āĻ¨ā§āĻ¤āĻ°ā§āĻŖ āĻ°ā§āĻ§ āĻ¨āĻāĻ¨ā§āĻ¯āĨ¤ āĻ
ā§āĻ¯āĻžāĻŽāĻŋāĻāĻžāĻ°ā§āĻ° āĻĒāĻžāĻ 3.2A āĻšāĻ˛ā§ X-āĻāĻ° āĻ°ā§āĻ§ āĻāĻ¤?
- \(2.1 \Omega\)
- \(4.6 \Omega\)
- \(6.0 \Omega\)
- \(15 \Omega\)
Ans. \(15 \Omega\)
- āĻāĻāĻāĻŋ āĻ§āĻžāĻ°āĻā§āĻ° āĻĻā§āĻ āĻĒāĻžāĻ¤ā§āĻ° āĻŽāĻ§ā§āĻ¯ā§ āĻŦāĻŋāĻāĻŦ āĻĒāĻžāĻ°ā§āĻĨāĻā§āĻ¯ V āĻāĻŦāĻ āĻ§āĻžāĻ°āĻā§āĻ° āĻ¸āĻā§āĻāĻŋāĻ¤ āĻļāĻā§āĻ¤āĻŋ X. āĻ§āĻžāĻ°āĻā§āĻ° āĻŦāĻŋāĻāĻŦ āĻĒāĻžāĻ°ā§āĻĨāĻā§āĻ¯ āĻŦā§āĻĻā§āĻ§āĻŋ āĻāĻ°ā§ 3V āĻāĻ°āĻž āĻšāĻ˛ā§,āĻ¸āĻā§āĻāĻŋāĻ¤ āĻļāĻā§āĻ¤āĻŋ āĻŦā§āĻĻā§āĻ§āĻŋ āĻĒā§āĻ¯āĻŧā§ āĻāĻ¤ āĻšāĻŦā§?
- 3X
- 6X
- 9X
- 27X
Ans. 9X
- 100W āĻā§āĻˇāĻŽāĻ¤āĻž āĻ¸āĻŽā§āĻĒāĻ¨ā§āĻ¨ āĻāĻāĻāĻŋ āĻšāĻŋāĻāĻžāĻ°ā§ 2kg āĻāĻ°ā§āĻ° āĻāĻāĻāĻŋ āĻāĻĒāĻžāĻ°ā§āĻ° āĻāĻ¨ā§āĻĄāĻā§ 40s āĻ¯āĻžāĻŦā§ āĻ¤āĻžāĻĒ āĻĻā§āĻāĻ¯āĻŧāĻž āĻšāĻ˛ā§ āĻāĻŖā§āĻĄāĻāĻŋāĻ° āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻž āĻāĻ¤ āĻŦā§āĻĻā§āĻ§āĻŋ āĻšāĻŦā§?
- 5K
- 10K
- 20K
- 50K
Ans. 5K
- āĻĒāĻžāĻ¨āĻŋ āĻ¸āĻžāĻĒā§āĻā§āĻˇā§ āĻāĻžāĻā§āĻ° āĻĒā§āĻ°āĻ¤āĻŋāĻ¸āĻ°āĻžāĻā§āĻ 9/8. āĻŦāĻžāĻ¯āĻŧā§ āĻ¸āĻžāĻĒā§āĻā§āĻˇā§ āĻāĻžāĻā§āĻ° āĻĒā§āĻ°āĻ¤āĻŋāĻ¸āĻ°āĻžāĻā§āĻ 3/2 āĻšāĻ˛ā§ āĻŦāĻžāĻ¯āĻŧā§āĻ° āĻ¸āĻžāĻĒā§āĻā§āĻˇā§ āĻĒāĻžāĻ¨āĻŋāĻ° āĻĒā§āĻ°āĻ¤āĻŋāĻ¸āĻ°āĻžāĻā§āĻ āĻāĻ¤?
- 2/3
- 4/4
- 4/3
- 3/4
Ans. 4/3
- āĻāĻāĻāĻŋ āĻāĻŽāĻ¨ āĻāĻŽāĻŋāĻāĻžāĻ° āĻā§āĻ°āĻžāĻ¨āĻāĻŋāĻ¸ā§āĻāĻžāĻ°ā§āĻ° \(\beta=100\) āĻāĻŦāĻ \(\mathbf{I}_{\mathrm{B}}=50 \mu \mathrm{A}\) āĻšāĻ˛ā§, \(\alpha\) āĻāĻ¤?
- 1.01
- 0.99
- 1.00
- 1.10
Ans. 0.99
- āĻāĻāĻāĻŋ āĻā§āĻļāĻŋāĻ āĻ¨āĻ˛ā§āĻ° āĻŦā§āĻ¯āĻžāĻ¸ \(0.04 \times 10^{-4} \mathrm{~m}\) āĻāĻ° āĻāĻ āĻĒā§āĻ°āĻžāĻ¨ā§āĻ¤ āĻĒāĻžāĻ¨āĻŋāĻ¤ā§ āĻĄā§āĻŦāĻžāĻ˛ā§ āĻĒāĻžāĻ¨āĻŋ āĻ¨āĻ˛ā§āĻ° āĻāĻŋāĻ¤āĻ° 0.082 m āĻāĻĒāĻ°ā§ āĻāĻ ā§āĨ¤ āĻĒāĻžāĻ¨āĻŋāĻ° āĻ¤āĻ˛āĻāĻžāĻ¨ āĻāĻ¤? [āĻĻā§āĻāĻ¯āĻŧāĻž āĻāĻā§, āĻ¸ā§āĻĒāĻ°ā§āĻļāĻā§āĻŖ = 0° āĻāĻŦāĻ āĻĒāĻžāĻ¨āĻŋāĻ° āĻāĻ¨āĻ¤ā§āĻŦ \(=1.0 \times 10^{3} \mathrm{~kg} / \mathrm{m}^{3}\)]
- \(8.5 \times 10^{-4} \mathrm{~N} / \mathrm{m}\)
- \(7.5 \times 10^{-4} \mathrm{~N} / \mathrm{m}\)
- \(9.0 \times 10^{-4} \mathrm{~N} / \mathrm{m}\)
- \(8.0 \times 10^{-4} \mathrm{~N} / \mathrm{m}\)
Ans. \(8.0 \times 10^{-4} \mathrm{~N} / \mathrm{m}\)
- āĻāĻāĻāĻŋ āĻ¤āĻžāĻ°ā§āĻ° āĻāĻĒāĻ° āĻāĻžāĻ¨ F āĻšāĻ˛ā§ āĻĻā§āĻ°ā§āĻā§āĻ¯ āĻŦā§āĻĻā§āĻ§āĻŋ āĻšāĻ¯āĻŧ x, āĻ¤āĻžāĻ°āĻāĻŋ āĻ¯āĻĻāĻŋ āĻšā§āĻā§āĻ° āĻ¸ā§āĻ¤ā§āĻ° āĻŽā§āĻ¨ā§ āĻāĻ˛ā§ āĻāĻŦāĻ āĻ¤āĻžāĻ°ā§āĻ° āĻāĻĒāĻžāĻĻāĻžāĻ¨ā§āĻ° āĻāĻ¯āĻŧāĻ āĻāĻ° āĻā§āĻŖāĻžāĻā§āĻ Y āĻšāĻ¯āĻŧāĨ¤ āĻ¤āĻŦā§ āĻ¤āĻžāĻ°ā§ āĻ¸āĻā§āĻāĻŋāĻ¤ āĻŦāĻŋāĻāĻŦāĻļāĻā§āĻ¤āĻŋ āĻāĻ¤?
- \(\frac{1}{2} \mathrm{Yx}\)
- \( \mathrm{Yx}\)
- \(\frac{1}{2} \mathrm{Fx}\)
- \(\mathrm{Fx}\)
Ans. \(\frac{1}{2} \mathrm{Fx}\)
- āĻ¤ā§āĻŽāĻžāĻ° āĻāĻāĻāĻŋ \(15 \Omega\) āĻ°ā§āĻ§ āĻĒā§āĻ°ā§ā§āĻāĻ¨ āĻāĻŋāĻ¨ā§āĻ¤ā§ āĻ¤ā§āĻŽāĻžāĻ° āĻāĻžāĻā§ āĻāĻ¯āĻŧā§āĻāĻāĻž \(10 \Omega\) āĻ°ā§āĻ§ āĻāĻā§āĨ¤ āĻā§āĻāĻžāĻŦā§ āĻ¤ā§āĻŽāĻŋ \(10 \Omega\) āĻ°ā§āĻ§ āĻŦā§āĻ¯āĻŦāĻšāĻžāĻ° āĻāĻ°ā§ \(15 \Omega\) āĻ°ā§āĻ§āĻāĻŋ āĻ¤ā§āĻ°āĻŋ āĻāĻ°āĻŦā§?
- āĻ¤āĻŋāĻ¨āĻāĻŋ āĻ¸āĻŽāĻžāĻ¨ā§āĻ¤āĻ°āĻžāĻ˛ āĻ¸āĻāĻ¯ā§āĻā§āĻ°
- āĻ¤āĻŋāĻ¨āĻāĻŋ āĻļā§āĻ°ā§āĻŖāĻŋāĻŦāĻĻā§āĻ§ āĻ¸āĻāĻ¯ā§āĻā§
- āĻĻā§āĻāĻŋ āĻļā§āĻ°ā§āĻŖāĻŋāĻŦāĻĻā§āĻ§ āĻ¸āĻāĻ¯ā§āĻā§
- āĻĻā§āĻāĻŋ āĻ¸āĻŽāĻžāĻ¨ā§āĻ¤āĻ°āĻžāĻ˛ āĻ¸āĻāĻ¯ā§āĻā§ āĻ āĻāĻāĻāĻŋ āĻļā§āĻ°ā§āĻŖāĻŋāĻŦāĻĻā§āĻ§ āĻ¸āĻāĻ¯ā§āĻā§
Ans. āĻĻā§āĻāĻŋ āĻ¸āĻŽāĻžāĻ¨ā§āĻ¤āĻ°āĻžāĻ˛ āĻ¸āĻāĻ¯ā§āĻā§ āĻ āĻāĻāĻāĻŋ āĻļā§āĻ°ā§āĻŖāĻŋāĻŦāĻĻā§āĻ§ āĻ¸āĻāĻ¯ā§āĻā§
- 300 Hz āĻāĻŽā§āĻĒāĻžāĻā§āĻā§āĻ° āĻāĻŦāĻ āĻŦāĻŋāĻĒāĻ°ā§āĻ¤ āĻĻāĻŋāĻā§ āĻ
āĻā§āĻ°āĻāĻžāĻŽā§ āĻĻā§āĻāĻŋ āĻ
āĻāĻŋāĻ¨ā§āĻ¨āĨ¤ āĻ¤āĻ°āĻā§āĻā§āĻ° āĻāĻĒāĻ°āĻŋāĻĒāĻžāĻ¤āĻ¨ā§āĻ° āĻĢāĻ˛ā§ āĻāĻāĻāĻŋ āĻ¸ā§āĻĨāĻŋāĻ° āĻ¤āĻ°āĻā§āĻā§āĻ° āĻ¸ā§āĻˇā§āĻāĻŋ āĻšāĻ¯āĻŧā§āĻā§āĨ¤ āĻ¸ā§āĻĨāĻŋāĻ° āĻ¤āĻ°āĻā§āĻā§āĻ° āĻĒāĻ° āĻĒāĻ° āĻĻā§āĻāĻŋ āĻ¨āĻŋāĻ¸ā§āĻĒāĻ¨ā§āĻĻ āĻŦāĻŋāĻ¨ā§āĻĻā§āĻ° āĻĻā§āĻ°āĻ¤ā§āĻŦ 1.5 m. āĻ
āĻā§āĻ°āĻāĻžāĻŽā§ āĻ¤āĻ°āĻā§āĻ āĻĻā§āĻāĻŋāĻ° āĻŦā§āĻ āĻāĻ¤?
- \(100 \mathrm{~m} / \mathrm{s}\)
- \(200 \mathrm{~m} / \mathrm{s}\)
- \(450 \mathrm{~m} / \mathrm{s}\)
- \(900 \mathrm{~m} / \mathrm{s}\)
Ans. \(900 \mathrm{~m} / \mathrm{s}\)
- āĻāĻāĻāĻŋ āĻāĻžāĻĄāĻŧāĻŋ āĻ¸ā§āĻāĻž āĻāĻ¤ā§āĻ¤āĻ°āĻĻāĻŋāĻā§ 90m āĻĒāĻĨ 15s āĻ¸āĻŽāĻ¯āĻŧā§ āĻ
āĻ¤āĻŋāĻā§āĻ°āĻŽ āĻāĻ°ā§āĨ¤ āĻĒāĻ°āĻŦāĻ°ā§āĻ¤ā§āĻ¤ā§ āĻāĻžāĻĄāĻŧāĻŋāĻāĻŋ āĻĻā§āĻ°ā§āĻ¤ āĻā§āĻ°ā§ āĻĻāĻā§āĻˇāĻŋāĻŖ āĻĻāĻŋāĻā§ 40m āĻĻā§āĻ°āĻ¤ā§āĻŦ 5s āĻ¸āĻŽāĻ¯āĻŧā§ āĻ
āĻ¤āĻŋāĻā§āĻ°āĻŽ āĻāĻ°ā§āĨ¤ āĻāĻ 20 s āĻ¸āĻŽāĻ¯āĻŧāĻāĻžāĻ˛ āĻāĻžāĻĄāĻŧāĻŋāĻāĻŋāĻ° āĻāĻĄāĻŧ āĻŦā§āĻā§āĻ° āĻŽāĻžāĻ¨ āĻāĻ¤?
- 2.5 m/s
- 5.0 m/s
- 6.5 m/s
- 7.0 m/s
Ans. 2.5 m/s
- āĻāĻāĻāĻŋ āĻāĻ°ā§āĻ° āĻŦāĻŋāĻĒāĻ°ā§āĻ¤ āĻĻā§āĻāĻŋ āĻĻā§āĻ¯āĻŧāĻžāĻ˛ā§āĻ° āĻŽāĻ§ā§āĻ¯āĻŦāĻ°ā§āĻ¤ā§ āĻĻā§āĻ°āĻ¤ā§āĻŦ 4 m. āĻāĻāĻāĻŋ āĻĻā§āĻ¯āĻŧāĻžāĻ˛ā§ āĻāĻāĻāĻŋ āĻ
āĻŦāĻ¤āĻ˛ āĻĻāĻ°ā§āĻĒāĻŖ āĻ˛āĻžāĻāĻžāĻ¨ā§ āĻāĻā§āĨ¤ āĻĻāĻ°ā§āĻĒāĻŖ āĻšāĻ¤ā§ 2.5 m āĻĻā§āĻ°ā§ āĻāĻāĻāĻŋ āĻŦāĻ¸ā§āĻ¤ā§ āĻ°āĻžāĻāĻ˛ā§ āĻ¤āĻžāĻ° āĻĒā§āĻ°āĻ¤āĻŋāĻŦāĻŋāĻŽā§āĻŦ āĻŦāĻŋāĻĒāĻ°ā§āĻ¤ āĻĻā§āĻ¯āĻŧāĻžāĻ˛ā§ āĻāĻ āĻŋāĻ¤ āĻšāĻ¯āĻŧāĨ¤ āĻĻāĻ°ā§āĻĒāĻŖā§āĻ° āĻĢā§āĻāĻžāĻ¸ āĻĻā§āĻ°āĻ¤ā§āĻŦ āĻāĻ¤?
- 2.5 m
- 1.54 m
- 1.44 m
- 2.25 m
Ans. 1.54 m
- āĻŦāĻ˛āĻŦāĻŋāĻĻā§āĻ¯āĻžāĻ° āĻŦāĻŋāĻāĻŋāĻ¨ā§āĻ¨ āĻŽā§āĻ˛āĻŋāĻ āĻā§āĻ¤ āĻ°āĻžāĻļāĻŋ āĻ¸āĻŽā§āĻš āĻšāĻ˛ā§-
- āĻāĻ°, āĻŦāĻ˛ āĻāĻŦāĻ āĻ¸āĻŽāĻ¯āĻŧ
- āĻāĻ°, āĻĻā§āĻā§āĻ°ā§āĻ¯ āĻāĻŦāĻ āĻ¸āĻŽāĻ¯āĻŧ
- āĻŦāĻ˛, āĻļāĻā§āĻ¤āĻŋ āĻāĻŦāĻ āĻ¸āĻŽāĻ¯āĻŧ
- āĻŦāĻ˛, āĻāĻ° āĻāĻŦāĻ āĻ¸āĻŽāĻ¯āĻŧ
Ans. āĻāĻ°, āĻĻā§āĻā§āĻ°ā§āĻ¯ āĻāĻŦāĻ āĻ¸āĻŽāĻ¯āĻŧ
- 0°C āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻžāĻ° 2.1 kg āĻŦāĻ°āĻĢ 40° C āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻžāĻ° 5.9 kg āĻĒāĻžāĻ¨āĻŋāĻ° āĻ¸āĻžāĻĨā§ āĻŽāĻŋāĻļā§āĻ°āĻŋāĻ¤ āĻāĻ°āĻž āĻšāĻ˛ā§āĨ¤ āĻŽāĻŋāĻļā§āĻ°āĻŖā§āĻ° āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻž āĻāĻ¤ āĻšāĻŦā§? āĻĒāĻžāĻ¨āĻŋāĻ° āĻāĻĒā§āĻā§āĻˇāĻŋāĻ āĻ¤āĻžāĻĒ \(=4.2 \times 10^{3} \mathrm{~J} \mathrm{~kg}^{-1} \mathbf{K}^{-1}\), āĻŦāĻ°āĻĢ āĻāĻ˛āĻ¨ā§āĻ° āĻāĻĒā§āĻā§āĻˇāĻŋāĻ āĻ¸ā§āĻĒā§āĻ¤āĻ¤āĻžāĻĒ \(=3.36 \times 10^{5} \mathrm{~J} \mathrm{~kg}^{-1}\)
- 7.5°C
- 9.5°C
- 10.5°C
- 8.5°C
Ans. 8.5°C
- āĻĒā§āĻĨāĻŋāĻŦā§āĻĒā§āĻˇā§āĻ ā§ āĻŽāĻšāĻžāĻāĻ°ā§āĻˇā§āĻ¯āĻŧ āĻā§āĻˇā§āĻ¤ā§āĻ° āĻĒā§āĻ°āĻžāĻŦāĻ˛ā§āĻ¯ g. āĻāĻžāĻ˛ā§āĻĒāĻ¨āĻŋāĻ āĻāĻāĻāĻŋ āĻā§āĻ°āĻšā§āĻ° āĻāĻ¨āĻ¤ā§āĻŦ āĻ¯āĻĻāĻŋ āĻĒā§āĻĨāĻŋāĻŦā§āĻ° āĻāĻ¨āĻ¤ā§āĻŦā§āĻ° āĻ¸āĻŽāĻžāĻ¨ āĻšāĻ¯āĻŧ āĻāĻŦāĻ āĻŦā§āĻ¯āĻžāĻ¸āĻžāĻ°ā§āĻ§ āĻ¯āĻĻāĻŋ āĻĻā§āĻŦāĻŋāĻā§āĻŖ āĻšāĻ¯āĻŧ āĻ¤āĻŦā§ āĻāĻ āĻā§āĻ°āĻšā§āĻ° āĻĒā§āĻˇā§āĻ ā§ āĻŽāĻšāĻžāĻāĻ°ā§āĻˇā§āĻ¯āĻŧ āĻā§āĻˇā§āĻ¤ā§āĻ° āĻĒā§āĻ°āĻžāĻŦāĻ˛ā§āĻ¯ āĻāĻ¤?
- g
- 2g
- 4g
- 8g
Ans. 2g
- āĻāĻāĻāĻŋ āĻĒāĻžāĻĨāĻ°āĻā§ āĻ¸ā§āĻĨāĻŋāĻ° āĻ
āĻŦāĻ¸ā§āĻĨāĻžāĻ¯āĻŧ āĻāĻāĻāĻŋ āĻāĻāĻā§ āĻĻāĻžāĻ˛āĻžāĻ¨ āĻĨā§āĻā§ āĻā§āĻĄāĻŧā§ āĻĻā§āĻāĻ¯āĻŧāĻž āĻšāĻ˛ā§āĨ¤ āĻā§āĻŽāĻŋāĻ¤ā§ āĻĒā§āĻāĻžāĻ¤ā§ āĻĒāĻžāĻĨāĻ°āĻāĻŋāĻ° 4 s āĻāĻ° āĻŦā§āĻļāĻŋ āĻ¸āĻŽāĻ¯āĻŧ āĻ˛āĻžāĻā§āĨ¤ āĻŦāĻžāĻ¤āĻžāĻ¸ā§āĻ° āĻāĻ°ā§āĻˇāĻŖ āĻā§āĻˇā§āĻĻā§āĻ° āĻšāĻ˛ā§ āĻĒāĻžāĻĨāĻ°āĻāĻŋāĻ° āĻĒā§āĻ°āĻĨāĻŽ 4 s āĻ¸āĻŽāĻ¯āĻŧā§ āĻĒāĻ¤āĻ¨ā§āĻ° āĻĻā§āĻ°āĻ¤ā§āĻŦ āĻāĻŦāĻ āĻĒā§āĻ°āĻĨāĻŽ 2s āĻ¸āĻŽāĻ¯āĻŧā§ āĻĒāĻ¤āĻ¨ā§āĻ° āĻĻā§āĻ°āĻ¤ā§āĻŦā§āĻ° āĻ
āĻ¨ā§āĻĒāĻžāĻ¤ āĻāĻ¤?
- 1/4
- 4/1
- 1/2
- 2/1
Ans. 4/1
- āĻāĻāĻāĻŋ āĻ¤ā§āĻāĻ¸ā§āĻā§āĻ°āĻŋāĻ¯āĻŧ āĻĒāĻĻāĻžāĻ°ā§āĻĨā§āĻ° āĻ
āĻ°ā§āĻ§āĻžāĻ¯āĻŧā§ 1600 āĻŦāĻāĻ°āĨ¤ āĻāĻ¤ āĻ¸āĻŽāĻ¯āĻŧ āĻĒāĻ°ā§ āĻ¤ā§āĻāĻ¸ā§āĻā§āĻ°āĻŋāĻ¯āĻŧ āĻĒāĻĻāĻžāĻ°ā§āĻĨā§āĻ° 15/16 āĻ
āĻāĻļ āĻā§āĻˇāĻ¯āĻŧāĻĒā§āĻ°āĻžāĻĒā§āĻ¤ āĻšāĻŦā§?
- 1500 years
- 4800 years
- 6400 years
- 9600 years
Ans. 6400 years
- āĻāĻāĻāĻŋ āĻŦā§āĻĻā§āĻ¯ā§āĻ¤āĻŋāĻ āĻāĻ¸ā§āĻ¤ā§āĻ°āĻŋāĻ¤ā§ 220 V āĻāĻŦāĻ 1200 w āĻ˛ā§āĻāĻž āĻāĻā§āĨ¤ āĻ¯āĻĻāĻŋ āĻĒā§āĻ°āĻ¤āĻŋ āĻāĻāĻ¨āĻŋāĻ āĻŦāĻŋāĻĻā§āĻ¯ā§ā§ āĻļāĻā§āĻ¤āĻŋāĻ° āĻŽā§āĻ˛ā§āĻ¯ 1.00 āĻāĻžāĻāĻž āĻšāĻ¯āĻŧ, āĻ¤āĻžāĻšāĻ˛ā§ āĻāĻ¸ā§āĻ¤ā§āĻ°āĻŋāĻāĻŋ 2 āĻāĻ¨ā§āĻāĻž āĻāĻžāĻ˛āĻžāĻ˛ā§ āĻāĻ¤ āĻāĻ°āĻ āĻĒāĻĄāĻŧāĻŦā§?
- 3 Tk
- 2.6 Tk
- 2.3 Tk
- 2.4 Tk
Ans. 2.4 Tk
- āĻāĻāĻāĻŋ āĻŦāĻ¸ā§āĻ¤ā§āĻā§ āĻāĻ¨ā§āĻā§āĻŽāĻŋāĻā§āĻ° āĻ¸āĻžāĻĨā§ 30° āĻā§āĻŖā§ āĻ¨āĻŋāĻā§āĻˇā§āĻĒ āĻāĻ°āĻž āĻšāĻ˛ā§āĨ¤ āĻĒāĻ°āĻŦāĻ°ā§āĻ¤ā§āĻ¤ā§ āĻāĻāĻ āĻŦāĻ¸ā§āĻ¤ā§āĻā§ āĻāĻāĻ āĻāĻĻāĻŋ āĻĻā§āĻ°ā§āĻ¤āĻŋāĻ¤ā§ āĻāĻ¨ā§āĻā§āĻŽāĻŋāĻā§āĻ° āĻ¸āĻžāĻĨā§ 40° āĻā§āĻŖā§ āĻ¨āĻŋāĻā§āĻˇā§āĻĒ āĻāĻ°āĻž āĻšāĻ˛ā§āĨ¤ āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨āĻāĻŋ āĻ¸āĻ¤ā§āĻ¯ āĻ¨āĻ¯āĻŧ?
- āĻāĻ¨ā§āĻā§āĻŽāĻŋāĻ āĻĒāĻžāĻ˛ā§āĻ˛āĻž āĻŦā§āĻĻā§āĻ§āĻŋ āĻĒā§āĻ˛
- āĻŦā§āĻā§āĻ° āĻāĻ¨ā§āĻā§āĻŽāĻŋāĻ āĻāĻĒāĻžāĻāĻļ āĻŦā§āĻĻā§āĻ§āĻŋ āĻĒā§āĻ˛ā§
- āĻ¸āĻ°ā§āĻŦā§āĻā§āĻ āĻāĻā§āĻāĻ¤āĻž āĻŦā§āĻĻā§āĻ§āĻŋ āĻĒā§āĻ˛
- āĻŦāĻ¸ā§āĻ¤ā§āĻāĻŋāĻ° āĻāĻĄā§āĻĄāĻ¯āĻŧāĻ¨āĻāĻžāĻ˛ āĻŦā§āĻĻā§āĻ§āĻŋ āĻĒā§āĻ˛
Ans. āĻŦā§āĻā§āĻ° āĻāĻ¨ā§āĻā§āĻŽāĻŋāĻ āĻāĻĒāĻžāĻāĻļ āĻŦā§āĻĻā§āĻ§āĻŋ āĻĒā§āĻ˛ā§
- m āĻāĻ°ā§āĻ° āĻāĻāĻāĻŋ āĻŦāĻ¸ā§āĻ¤ā§ r āĻŦā§āĻ¯āĻžāĻ¸āĻžāĻ°ā§āĻ§ā§āĻ° āĻŦā§āĻ¤ā§āĻ¤āĻžāĻāĻžāĻ° āĻĒāĻĨā§ āĻ¸āĻŽāĻĻā§āĻ°ā§āĻ¤āĻŋāĻ¤ā§ āĻāĻ˛āĻā§āĨ¤ āĻŦā§āĻ¤ā§āĻ¤āĻžāĻāĻžāĻ° āĻāĻ¤āĻŋāĻ° āĻĒāĻ°ā§āĻ¯āĻžāĻ¯āĻŧāĻāĻžāĻ˛ T. āĻŦāĻ¸ā§āĻ¤ā§āĻāĻŋāĻ° āĻāĻĒāĻ° āĻā§āĻ¨ā§āĻĻā§āĻ°āĻŽā§āĻā§ āĻŦāĻ˛ā§āĻ° āĻŽāĻžāĻ¨ āĻāĻ¤?
- \(\frac{4 \pi^{2} \mathrm{mr}}{\mathrm{T}^{2}}\)
- \(\frac{4 \pi^{2} \mathrm{mr}^{2}}{\mathrm{~T}}\)
- \(\frac{4 \pi \mathrm{mr}^{2}}{\mathrm{~T}^{2}}\)
- \(\pi \mathrm{mr}^{2}\)
Ans. \(\frac{4 \pi^{2} \mathrm{mr}}{\mathrm{T}^{2}}\)
- āĻāĻāĻāĻŋ \({ }_{92}^{238} \mathrm{U}\) āĻ¨āĻŋāĻāĻā§āĻ˛āĻŋāĻ¯āĻŧāĻžāĻ¸ āĻĻā§āĻ āĻ§āĻžāĻĒā§ āĻā§āĻˇāĻ¯āĻŧ āĻšāĻ¯āĻŧā§ \({ }_{91}^{234} \mathrm{~Pa}\) āĻ¨āĻŋāĻāĻā§āĻ˛āĻŋāĻ¯āĻŧāĻžāĻ¸ āĻ¸ā§āĻˇā§āĻāĻŋ āĻāĻ°ā§āĨ¤ āĻāĻ āĻĻā§āĻ āĻ§āĻžāĻĒā§ āĻā§ āĻā§ āĻ§āĻ°āĻ¨ā§āĻ° āĻ°āĻļā§āĻŽāĻŋ āĻ¨āĻŋāĻ°ā§āĻāĻ¤ āĻšāĻ¯āĻŧ?
- \(\alpha\) and \(\beta\)
- \(\alpha\) and \(\gamma\)
- \(\beta^{-}\) and \(\beta^{-}\)
- \(\beta\) and \(\gamma\)
Ans. \(\alpha\) and \(\beta\)
- āĻ¸āĻ°āĻ˛ āĻāĻ¨ā§āĻĻāĻŋāĻ¤ āĻāĻ¤āĻŋāĻ¤ā§ āĻāĻ˛āĻŽāĻžāĻ¨ āĻāĻāĻāĻŋ āĻŦāĻ¸ā§āĻ¤ā§āĻ° āĻŽā§āĻ āĻļāĻā§āĻ¤āĻŋ E. āĻāĻŽā§āĻĒāĻžāĻā§āĻ āĻ
āĻĒāĻ°āĻŋāĻŦāĻ°ā§āĻ¤āĻŋāĻ¤ āĻ°ā§āĻā§ āĻŦāĻŋāĻ¸ā§āĻ¤āĻžāĻ° āĻĻā§āĻŦāĻŋāĻā§āĻŖ āĻāĻ°āĻ˛ā§ āĻ¸āĻ°āĻ˛ āĻāĻ¨ā§āĻĻāĻŋāĻ¤ āĻāĻ¤āĻŋāĻ¤ā§ āĻāĻ˛āĻŽāĻžāĻ¨ āĻŦāĻ¸ā§āĻ¤ā§āĻāĻŋāĻ° āĻŽā§āĻ āĻļāĻā§āĻ¤āĻŋ āĻāĻ¤ āĻšāĻŦā§?
- E
- 2E
- E/2
- 4E
Ans. 4E
- āĻāĻāĻāĻŋ āĻāĻŖāĻžāĻ° āĻāĻ°āĻŦā§āĻ P. āĻāĻŖāĻžāĻāĻŋāĻ° āĻāĻ¤āĻŋāĻļāĻā§āĻ¤āĻŋ āĻĻā§āĻŦāĻŋāĻā§āĻŖ āĻāĻ°āĻž āĻšāĻ˛ā§ āĻāĻ° āĻ¨āĻ¤ā§āĻ¨ āĻāĻ°āĻŦā§āĻ āĻāĻ¤ āĻšāĻŦā§?
- \(\sqrt{2} \mathrm{P}\)
- 2P
- 4P
- 8P
Ans. \(\sqrt{2} \mathrm{P}\)
- āĻ¸ā§āĻĨāĻŋāĻ° āĻ
āĻŦāĻ¸ā§āĻĨāĻžāĻ¯āĻŧ āĻĨāĻžāĻāĻž āĻāĻāĻāĻŋ āĻŦāĻ¸ā§āĻ¤ā§ āĻŦāĻŋāĻ¸ā§āĻĢā§āĻ°āĻŖā§āĻ° āĻĢāĻ˛ā§ \(\mathbf{M}_{\mathbf{1}}\) āĻāĻŦāĻ \(\mathbf{M}_{\mathbf{2}}\) āĻāĻ°ā§āĻ° āĻĻā§āĻāĻŋ āĻāĻ¨ā§āĻĄā§ āĻŦāĻŋāĻāĻā§āĻ¤ āĻšāĻ¯āĻŧ āĻāĻŦāĻ āĻāĻ¨ā§āĻĄ āĻĻā§āĻāĻŋ āĻŦāĻŋāĻĒāĻ°ā§āĻ¤ āĻĻāĻŋāĻā§ āĻ¯āĻĨāĻžāĻā§āĻ°āĻŽā§ \(\mathbf{V}_{\mathbf{1}}\) āĻāĻŦāĻ \(\mathbf{V}_{\mathbf{2}}\) āĻŦā§āĻ āĻĒā§āĻ°āĻžāĻĒā§āĻ¤ āĻšāĻ¯āĻŧāĨ¤ \(\mathbf{V}_{\mathbf{1}}\) āĻāĻŦāĻ \(\mathbf{V}_{\mathbf{2}}\) āĻāĻ° āĻ
āĻ¨ā§āĻĒāĻžāĻ¤ āĻāĻ¤ āĻšāĻŦā§?
- \(\frac{\mathrm{M}_{1}}{\mathrm{M}_{2}}\)
- \(\frac{\mathrm{M}_{2}}{\mathrm{M}_{1}}\)
- \(\left(\frac{\mathrm{M}_{1}}{\mathrm{M}_{2}}\right)^{1 / 2}\)
- \(\left(\frac{\mathrm{M}_{2}}{\mathrm{M}_{1}}\right)^{1 / 2}\)
Ans. \(\frac{\mathrm{M}_{2}}{\mathrm{M}_{1}}\)
- āĻšāĻžāĻāĻĄā§āĻ°ā§āĻā§āĻ¨ āĻĒāĻ°āĻŽāĻžāĻŖā§āĻ° āĻļāĻā§āĻ¤āĻŋ āĻ¸ā§āĻ¤āĻ°ā§āĻ° āĻĒā§āĻ°āĻāĻžāĻļ \(\mathbf{E}=-\frac{\mathbf{1 3 . 6}}{\mathbf{n}^{2}} \mathrm{eV}\) [n =
1, 2, …] āĻā§āĻŽāĻŋ āĻ āĻŦāĻ¸ā§āĻĨāĻž āĻĨā§āĻā§ āĻĒāĻ°āĻŦāĻ°ā§āĻ¤ā§ āĻāĻā§āĻāĻ¤āĻ° āĻļāĻā§āĻ¤āĻŋāĻ¸ā§āĻ¤āĻ°ā§ āĻ¯ā§āĻ¤ā§ āĻāĻāĻāĻŋ āĻšāĻžāĻāĻĄā§āĻ°ā§āĻā§āĻ¨ āĻĒāĻ°āĻŽāĻžāĻŖā§ āĻā§ āĻĒāĻ°āĻŋāĻŽāĻžāĻŖ āĻļāĻā§āĻ¤āĻŋ āĻļāĻļāĻžāĻˇāĻŖ āĻāĻ°ā§?- 3.4 eV
- 4.5 eV
- 10.2 eV
- 13.6 eV
Ans. 10.2 eV
- Higgs āĻĒā§āĻ°āĻā§āĻ°āĻŋāĻ¯āĻŧāĻž āĻāĻ āĻ§āĻ°āĻ¨ā§āĻ°-
- āĻāĻ° āĻ¤ā§āĻ°āĻŋāĻ° āĻĒā§āĻ°āĻā§āĻ°āĻŋāĻ¯āĻŧāĻž
- āĻļāĻā§āĻ¤āĻŋ āĻ¤ā§āĻ°āĻŋāĻ° āĻĒā§āĻ°āĻā§āĻ°āĻŋāĻ¯āĻŧāĻž
- āĻāĻ˛ā§āĻāĻā§āĻ°āĻ¨ āĻ¤ā§āĻ°āĻŋāĻ° āĻĒā§āĻ°āĻā§āĻ°āĻŋāĻ¯āĻŧāĻž
- āĻŦāĻ˛ āĻ¤ā§āĻ°āĻŋāĻ° āĻĒā§āĻ°āĻā§āĻ°āĻŋāĻ¯āĻŧāĻž
Ans. āĻāĻ° āĻ¤ā§āĻ°āĻŋāĻ° āĻĒā§āĻ°āĻā§āĻ°āĻŋāĻ¯āĻŧāĻž
- āĻāĻāĻ āĻĻā§āĻ°ā§āĻā§āĻ¯ āĻāĻŦāĻ āĻāĻāĻ āĻĒāĻĻāĻžāĻ°ā§āĻĨ āĻĻāĻŋā§ā§ āĻ¤ā§āĻ°āĻŋ āĻĻā§āĻāĻŋ āĻ¤āĻžāĻ° P āĻāĻŦāĻ Q āĻā§ āĻāĻāĻāĻŋ āĻŦā§āĻ¯āĻžāĻāĻžāĻ°āĻŋāĻ° āĻ¸āĻžāĻĨā§ āĻ¸āĻŽāĻžāĻ¨ā§āĻ¤āĻ°āĻžāĻ˛ā§ āĻ¸āĻāĻ¯ā§āĻā§āĻ¤ āĻāĻ°āĻž āĻšā§ā§āĻā§āĨ¤ P āĻ¤āĻžāĻ°ā§āĻ° āĻŦā§āĻ¯āĻžāĻ¸ 2 mm āĻāĻŦāĻ Q āĻ¤āĻžāĻ°ā§āĻ° āĻŦā§āĻ¯āĻžāĻ¸ 1 mm. P āĻāĻŦāĻ Q āĻāĻ° āĻ¤ā§āĻŋā§ āĻĒā§āĻ°āĻŦāĻžāĻšā§āĻ° āĻ
āĻ¨ā§āĻĒāĻžāĻ¤ āĻāĻ¤?
- \(\frac{1}{4}\)
- \(\frac{1}{2}\)
- \(\frac{2}{1}\)
- \(\frac{4}{1}\)
Ans. \(\frac{4}{1}\)
- 5 kg āĻāĻ°ā§āĻ° āĻāĻāĻāĻŋ āĻ°āĻžāĻāĻĢā§āĻ˛ āĻĨā§āĻā§ 20 g āĻāĻ°ā§āĻ° āĻāĻāĻāĻŋ āĻŦā§āĻ˛ā§āĻ 1000 m/s āĻāĻ¤āĻŋāĻ¤ā§ āĻā§āĻā§ āĻ¯āĻžāĻ¯āĻŧāĨ¤ āĻĒāĻŋāĻāĻ¨ āĻĻāĻŋāĻā§ āĻ°āĻžāĻāĻĢā§āĻ˛ā§āĻ° āĻ§āĻžāĻā§āĻāĻžāĻ° āĻŦā§āĻ āĻāĻ¤?
- 4 m/s
- 400 m/s
- 4000 m/s
- 40 m/s
Ans. 4 m/s
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻ˛ā§āĻāĻāĻŋāĻ¤ā§āĻ°ā§ 50 s āĻ¸āĻŽāĻ¯āĻŧāĻāĻžāĻ˛ā§ āĻāĻāĻāĻŋ āĻāĻžāĻĄāĻŧāĻŋāĻ° āĻŦā§āĻā§āĻ° āĻĒāĻ°āĻŋāĻŦāĻ°ā§āĻ¤āĻ¨ āĻĻā§āĻāĻžāĻ¨ā§ āĻšāĻ¯āĻŧā§āĻā§āĨ¤ āĻāĻ āĻ¸āĻŽāĻ¯āĻŧāĻāĻžāĻ˛ā§ āĻāĻžāĻĄāĻŧāĻŋāĻāĻŋ āĻāĻ¤ āĻĻā§āĻ°āĻ¤ā§āĻŦ āĻ
āĻ¤āĻŋāĻā§āĻ°āĻŽ āĻāĻ°ā§āĻā§?
- 500 m
- 400 m
- 350 m
- 300 m
Ans. 350 m
āĻ°āĻ¸āĻžā§āĻ¨
- Sr, Tc, Zr āĻāĻŦāĻ Rb āĻĒāĻ°āĻŽāĻžāĻŖā§āĻ° āĻŦā§āĻ¯āĻžāĻ¸āĻžāĻ°ā§āĻ§ā§āĻ° āĻā§āĻ°āĻŽ āĻšāĻ˛ā§-
- Rb > Sr > Zr > Tc
- Tc > Sr > Rb > Zr
- Sr > Tc > Zr > Rb
- Zr > Tc > Rb > Sr
Ans. Rb > Sr > Zr > Tc
- āĻāĻāĻāĻŋ \(CH_3CN\) āĻ
āĻŖā§āĻ¤ā§ \(\sigma \) āĻāĻŦāĻ \(\pi \) āĻŦāĻ¨ā§āĻ§āĻ¨ā§āĻ° āĻ¸āĻāĻā§āĻ¯āĻž āĻ¯āĻĨāĻžāĻā§āĻ°āĻŽā§-
- 5 and 2
- 4 and 3
- 5 and 3
- 4 and 2
Ans. 5 and 2
- āĻ¸ā§āĻĄāĻž āĻ
ā§āĻ¯āĻžāĻļ āĻļāĻŋāĻ˛ā§āĻĒāĻā§āĻˇā§āĻ¤ā§āĻ°ā§ āĻā§āĻ¨ āĻĒāĻĻā§āĻ§āĻ¤āĻŋāĻ¤ā§ āĻ¤ā§āĻ°āĻŋ āĻāĻ°āĻž āĻšāĻ¯āĻŧ?
- Bessemer process
- Chamber process
- Solvay process
- Haber process
Ans. Solvay process
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨ āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻžāĻāĻŋ āĻĄāĻŋāĻ¸āĻĒā§āĻĒāĻ°āĻļāĻ¨ā§āĻļāĻ¨ āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻž?
- \(\mathrm{H}_{2} \mathrm{~S}+\mathrm{Cl}_{2} \rightarrow 2 \mathrm{HCl}+\mathrm{S}\)
- \(\mathrm{CuSO}_{4}+\mathrm{NH}_{4} \mathrm{OH} \rightarrow \mathrm{Cu}(\mathrm{OH})_{2}+\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}\)
- \(\mathrm{Fe}+\) dil. \(\mathrm{H}_{2} \mathrm{SO}_{4} \rightarrow \mathrm{FeSO}_{4}+\mathrm{H}_{2}\)
- \(\mathrm{Cl}_{2}+\mathrm{NaOH} \rightarrow \mathrm{NaOCl}+\mathrm{NaCl}+\mathrm{H}_{2} \mathrm{O}\)
Ans. \(\mathrm{Cl}_{2}+\mathrm{NaOH} \rightarrow \mathrm{NaOCl}+\mathrm{NaCl}+\mathrm{H}_{2} \mathrm{O}\)
- 10.0 āĻŽāĻŋ.āĻ˛āĻŋ. NaOH āĻĻā§āĻ°āĻŦāĻŖāĻā§ 0.12 M āĻāĻ¨āĻŽāĻžāĻ¤ā§āĻ°āĻžāĻ° 15.0 āĻŽāĻŋ.āĻ˛āĻŋ. āĻ
āĻā§āĻ¸āĻžāĻ˛āĻŋāĻ āĻāĻ¸āĻŋāĻĄ āĻĻā§āĻŦāĻžāĻ°āĻž āĻāĻžāĻāĻā§āĻ°ā§āĻļāĻ¨ āĻāĻ°āĻ˛ā§ āĻĒā§āĻ°āĻļāĻŽāĻ¨ āĻŦāĻŋāĻ¨ā§āĻĻā§ āĻĒāĻžāĻāĻ¯āĻŧāĻž āĻ¯āĻžāĻ¯āĻŧāĨ¤ NaOH āĻāĻ° āĻāĻ¨āĻŽāĻžāĻ¤ā§āĻ°āĻž āĻāĻ¤?
- 0.25 M
- 0.36 M
- 0.32 M
- 0.40 M
Ans. 0.36 M
- āĻŦā§āĻ˛ā§āĻāĻāĻŽā§āĻ¯āĻžāĻ¨ āĻ§ā§āĻ°ā§āĻŦāĻā§āĻ° āĻāĻāĻ āĻšāĻ˛ā§-
- J/molecule
- J.s
- J/K
- g/cc
Ans. J/K
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨āĻāĻŋāĻ° āĻŦā§āĻ¯āĻžāĻ¸āĻžāĻ°ā§āĻ§ āĻ¸āĻŦāĻā§āĻ¯āĻŧā§ āĻāĻŽ?
- \({ }_{9} \mathrm{~F}^{-}\)
- \({ }_{10} \mathrm{Ne}\)
- \({ }_{11} \mathrm{Na}^{+}\)
- \({ }_{12} \mathrm{Mg}^{2+}\)
Ans. \({ }_{12} \mathrm{Mg}^{2+}\)
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨ āĻ¯ā§āĻāĻāĻŋ āĻāĻ˛ā§āĻ¯āĻŧ āĻĻā§āĻ°āĻŦāĻŖā§ āĻ¸āĻŦāĻā§āĻ¯āĻŧā§ āĻ¸āĻšāĻā§ āĻāĻ°ā§āĻĻā§āĻ° āĻŦāĻŋāĻļā§āĻ˛ā§āĻˇāĻŋāĻ¤ āĻšāĻ¯āĻŧ?
- \(\mathrm{CCl}_{4}\)
- \(\mathrm{SnCl}_{2}\)
- \(\mathrm{SiCl}_{4}\)
- \(\mathrm{PbCl}_{4}\)
Ans. \(\mathrm{SiCl}_{4}\)
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻŽāĻŋāĻļā§āĻ°āĻŖāĻ¸āĻŽā§āĻš āĻĨā§āĻā§ āĻŦāĻžāĻĢāĻžāĻ° āĻĻā§āĻ°āĻŦāĻŖāĻāĻŋ āĻļāĻ¨āĻžāĻā§āĻ¤ āĻāĻ°-
- \(0.2 \mathrm{M} 10 \mathrm{~mL} \mathrm{CH}_{3} \mathrm{COOH}+0.2 \mathrm{M} 10 \mathrm{~mL} \mathrm{NaOH}\)
- \(0.2 \mathrm{M} 10 \mathrm{~mL} \mathrm{CH}_{3} \mathrm{COOH}+0.1 \mathrm{M} 10 \mathrm{~mL} \mathrm{NaOH}\)
- \(0.1 \mathrm{M} 10 \mathrm{~mL} \mathrm{CH}_{3} \mathrm{COOH}+0.2 \mathrm{M} 10 \mathrm{~mL} \mathrm{NaOH}\)
- \(0.2 \mathrm{M} 10 \mathrm{~mL} \mathrm{HCl}+0.1 \mathrm{M} 10 \mathrm{~mL} \mathrm{NaOH}\)
Ans. \(0.2 \mathrm{M} 10 \mathrm{~mL} \mathrm{CH}_{3} \mathrm{COOH}+0.1 \mathrm{M} 10 \mathrm{~mL} \mathrm{NaOH}\)
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨ āĻ¯ā§āĻāĻāĻŋ āĻ¸āĻŦāĻā§āĻ¯āĻŧā§ āĻāĻŽ āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻžāĻ¯āĻŧ āĻŦāĻŋā§ā§āĻāĻŋāĻ¤ āĻšāĻŦā§?
- \(\mathrm{Na}_{2} \mathrm{CO}_{3}\)
- \(\mathrm{K}_{2} \mathrm{CO}_{3}\)
- \(\mathrm{MgCO}_{3}\)
- \(\mathrm{BaCO}_{3}\)
Ans. \(\mathrm{MgCO}_{3}\)
- āĻĒāĻāĻžāĻ¸āĻŋāĻ¯āĻŧāĻžāĻŽ āĻ¸āĻžāĻ¯āĻŧāĻžāĻ¨āĻžāĻāĻĄā§āĻ° āĻāĻĒāĻ¸ā§āĻĨāĻŋāĻ¤āĻŋāĻ¤ā§ āĻšāĻžāĻāĻĄā§āĻ°ā§āĻā§āĻ¨ āĻ¸āĻžāĻ¯āĻŧāĻžāĻ¨āĻžāĻāĻĄ āĻĒā§āĻ°āĻĒāĻžāĻ¨āĻ˛ā§āĻ° āĻ¸āĻžāĻĨā§ āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻž āĻāĻ°ā§āĨ¤ āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻžāĻ° āĻā§āĻļāĻ˛āĻāĻŋ āĻšāĻ˛ā§-
- nucleophilic addition
- electrophilic substitution
- nucleophilic substitution
- electrophilic addition
Ans. nucleophilic substitution
- āĻā§āĻ°āĻŋāĻāĻ¨āĻžāĻ°ā§āĻĄ āĻŦāĻŋāĻāĻžāĻ°āĻ āĻšāĻ˛ā§-
- \(\mathrm{CH}_{3} \mathrm{ONa}\)
- \(\mathrm{R}^{\prime} \mathrm{BaCl}\)
- \(\mathrm{RMgX}\)
- \(\mathrm{R}^{\prime} \mathrm{CaX}\)
Ans. \(\mathrm{RMgX}\)
- \(\mathrm{Zn}^{2+} \mid \mathrm{Zn}\) āĻāĻŦāĻ \(\mathbf{A g}^{+} \mid \mathbf{A g}\) āĻ¤āĻĄāĻŧāĻŋāĻĻā§āĻŦāĻžāĻ° āĻĻā§āĻāĻŋāĻ° āĻŦāĻŋāĻāĻžāĻ°āĻŖ āĻŦāĻŋāĻāĻŦ āĻ¯āĻĨāĻžāĻā§āĻ°āĻŽā§ -0.76 V āĻāĻŦāĻ +0.80 V. āĻāĻ āĻ¤āĻĄāĻŧāĻŋāĻĻā§āĻŦāĻžāĻ° āĻĻā§āĻāĻŋ āĻĻā§āĻŦāĻžāĻ°āĻž āĻ¤ā§āĻ°āĻŋ āĻā§āĻˇā§āĻ° āĻŽā§āĻ āĻŦāĻŋāĻāĻŦ āĻāĻ¤ āĻšāĻŦā§?
- -0.04 V
- +1.56 V
- +0.04 V
- -1.56 V
Ans. +1.56 V
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨ āĻā§āĻ¯āĻŧāĻžāĻ¨ā§āĻāĻžāĻŽ āĻ¸ā§āĻāĻāĻŋ āĻĒāĻ°āĻŽāĻžāĻŖā§āĻ° āĻāĻāĻāĻŋ āĻāĻ˛ā§āĻā§āĻā§āĻ°āĻ¨ā§āĻ° āĻāĻ¨ā§āĻ¯ āĻ¸āĻŽā§āĻāĻŦ āĻ¨āĻ¯āĻŧ?
- n = 2, 1 = 1, m = 0, s = + 1/2
- n = 3, 1 = 1, m = 2, s =-1/2
- n = 1, 1 = 0, m = 0, s = -1/2
- n = 2, 1 = 0, m = 0, s = +1/2
Ans. n = 3, 1 = 1, m = 2, s =-1/2
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨ āĻ¯ā§āĻāĻāĻŋāĻ¤ā§ āĻ¸āĻā§āĻāĻžāĻ˛āĻ¨ āĻ
āĻā§āĻˇāĻŽ \(\pi \) āĻāĻ˛ā§āĻā§āĻā§āĻ°āĻ¨ āĻāĻā§?
- \(\mathrm{C}_{2} \mathrm{H}_{2}\)
- \(\mathrm{C}_{6} \mathrm{H}_{6}\)
- \(\mathrm{C}_{3} \mathrm{H}_{8}\)
- \(\mathrm{C}_{2} \mathrm{H}_{4}\)
Ans. \(\mathrm{C}_{2} \mathrm{H}_{4}\)
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨āĻāĻŋ āĻ
āĻ¸āĻ¤ā§āĻ¯?
- \(\mathrm{NH}_{4}^{+}\) is the conjugate acid of base \(\mathrm{NH}_{3}\)
- \(\mathrm{NH}_{3}\) and \(\mathrm{H}_{2} \mathrm{O}\) are conjugate pair
- \(\mathrm{OH}^{-}\) is the conjugate base of acid \(\mathrm{H}_{2} \mathrm{O}\)
- \(\mathrm{OH}^{-}\) and \(\mathrm{H}_{2} \mathrm{O}\) are conjugate pair
Ans. \(\mathrm{NH}_{3}\) and \(\mathrm{H}_{2} \mathrm{O}\) are conjugate pair
- āĻāĻĨāĻžāĻ¨āĻ˛āĻā§ 170° C āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻžāĻ¯āĻŧ āĻ
āĻ¤āĻŋāĻ°āĻŋāĻā§āĻ¤ āĻāĻžāĻĸāĻŧ āĻ¸āĻžāĻ˛āĻĢāĻŋāĻāĻ°āĻŋāĻ āĻāĻ¸āĻŋāĻĄ āĻĻā§āĻŦāĻžāĻ°āĻž āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻž āĻāĻ°āĻ˛ā§ āĻā§ āĻā§āĻĒāĻ¨ā§āĻ¨ āĻšāĻ¯āĻŧ?
- \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{HSO}_{4}\)
- \(\mathrm{C}_{2} \mathrm{H}_{4} \mathrm{SO}_{4}\)
- \(\mathrm{CH}_{2}=\mathrm{CH}_{2}\)
- \(\mathrm{CH}_{3} \mathrm{CHO}\)
Ans. \(\mathrm{CH}_{2}=\mathrm{CH}_{2}\)
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨ āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻžāĻāĻŋ āĻĒā§āĻ°āĻļāĻŽāĻ¨ āĻāĻ¨āĻĨāĻžāĻ˛āĻĒāĻŋ, \(\Delta \mathbf{H}\) neutral āĻĒā§āĻ°āĻāĻžāĻļ āĻāĻ°ā§?
- \(\mathrm{H}_{2} \mathrm{SO}_{4}(\mathrm{aq})+\mathrm{Ca}(\mathrm{OH})_{2}(\mathrm{aq}) \rightarrow \mathrm{CaSO}_{4}(\mathrm{aq})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})\)
- \(\mathrm{H}_{2} \mathrm{SO}_{4}(\mathrm{aq})+2 \mathrm{NH}_{3}(\mathrm{aq}) \rightarrow\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}(\mathrm{aq})\)
- \(\mathrm{HCl}(\mathrm{aq})+1 / 2 \mathrm{Ca}(\mathrm{OH})_{2}(\mathrm{aq}) \rightarrow 1 / 2 \mathrm{CaCl}_{2}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(1)\)
- \(2 \mathrm{HCl}(\mathrm{aq})+\mathrm{Ca}(\mathrm{OH})_{2}(\mathrm{aq}) \rightarrow \mathrm{CaCl}_{2}(\mathrm{aq})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})\)
Ans. \(\mathrm{HCl}(\mathrm{aq})+1 / 2 \mathrm{Ca}(\mathrm{OH})_{2}(\mathrm{aq}) \rightarrow 1 / 2 \mathrm{CaCl}_{2}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(1)\)
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨ āĻ¯ā§āĻāĻāĻŋāĻ° āĻāĻā§āĻ¤āĻŋ āĻ¤ā§āĻ°āĻŋāĻā§āĻŖāĻžāĻāĻžāĻ° āĻ¸āĻŽāĻ¤āĻ˛ā§āĻ¯āĻŧ?
- \(\mathrm{BCl}_{3}\)
- \(\mathrm{H}_{3} \mathrm{O}^{+}\)
- BrFs
- \(\mathrm{PH}_{3}\)
Ans. \(\mathrm{BCl}_{3}\)
- āĻšāĻžāĻāĻĄā§āĻ°ā§āĻā§āĻ¨ā§āĻ° āĻĒāĻžāĻ°āĻŽāĻžāĻŖāĻŦāĻŋāĻ āĻŦāĻ°ā§āĻŖāĻžāĻ˛ā§āĻ° āĻā§āĻ¨ āĻ¸āĻŋāĻ°āĻŋāĻāĻāĻŋāĻ¤ā§ āĻĻā§āĻļā§āĻ¯āĻŽāĻžāĻ¨ āĻ
āĻā§āĻāĻ˛ā§āĻ° āĻ°āĻļā§āĻŽāĻŋ āĻĻā§āĻāĻž āĻ¯āĻžāĻ¯āĻŧ?
- Paschen
- Lyman
- Balmer
- Brackett
Ans. Balmer
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨āĻāĻŋ āĻ¸āĻŦāĻā§āĻ¯āĻŧā§ āĻ¸ā§āĻĨāĻŋāĻ¤āĻŋāĻļā§āĻ˛ āĻāĻžāĻ°ā§āĻŦā§-āĻā§āĻ¯āĻžāĻāĻžāĻ¯āĻŧāĻ¨?
- \(\mathrm{CH}_{3}^{+}\)
- \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}^{+} \mathrm{H}\)
- \(\mathrm{H}_{2} \mathrm{C}^{+}-\mathrm{CH}_{3}\)
- \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{C}^{+}\)
Ans. \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{C}^{+}\)
- 18.5% \(\mathrm{N}_{2} \mathrm{O}_{4}\), 25°C āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻžāĻ¯āĻŧ āĻāĻŦāĻ 1 atm āĻāĻžāĻĒā§āĨ¤ āĻŦāĻŋā§ā§āĻāĻŋāĻ¤ āĻšāĻ˛ā§ K āĻāĻ° āĻŽāĻžāĻ¨ āĻāĻ¤?
- 0.142 atm
- 0.185 atm
- 0.220 atm
- 0.125 atm
Ans. 0.142 atm
- āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¨ āĻ¯ā§āĻāĻāĻŋ Fehling āĻĻā§āĻ°āĻŦāĻŖā§āĻ° āĻ¸āĻžāĻĨā§ āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻž āĻāĻ°ā§āĨ¤ āĻ˛āĻžāĻ˛ āĻ
āĻ§āĻāĻā§āĻˇā§āĻĒ āĻĻā§āĻ¯āĻŧ?
- \(\mathrm{RCH}_{2} \mathrm{X}\)
- \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CO}\)
- \(\mathrm{RCH}_{2} \mathrm{OH}\)
- \(\mathrm{RCH}_{2} \mathrm{CHO}\)
Ans. \(\mathrm{RCH}_{2} \mathrm{CHO}\)
- IUPAC āĻ¨āĻžāĻŽāĻāĻ°āĻŖ āĻ
āĻ¨ā§āĻ¸āĻžāĻ°ā§ \(\mathrm{CH}_{3}-\mathrm{CH}\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)-\mathrm{CH}_{2}-\mathrm{CHBr}-\mathrm{CHCl}-\mathrm{CH}_{3}\) āĻāĻ° āĻ¨āĻžāĻŽ āĻšāĻ˛ā§-
- 2-chloro-3-bromo-5-ethyl hexane
- 2-chloro-3-bromo-5-methyl heptane
- 3-bromo-2-chloro-5-ethyl hexane
- 3-bromo-2-chloro-5-methyl heptane
Ans. 3-bromo-2-chloro-5-methyl heptane
- āĻ
ā§āĻ¯āĻžāĻ°ā§āĻŽā§āĻāĻŋāĻ āĻĒā§āĻ°āĻ¤āĻŋāĻ¸ā§āĻĨāĻžāĻĒāĻ¨ āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻžāĻ¯āĻŧ āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨ āĻā§āĻ°ā§āĻĒāĻāĻŋ āĻŽā§āĻāĻž āĻ¨āĻŋāĻ°ā§āĻĻā§āĻļāĻ?
- \(-\mathrm{NO}_{2}\)
- \(-\mathrm{OH}\)
- \(-\mathrm{Cl}\)
- \(-\mathrm{CH}_{3}\)
Ans. \(-\mathrm{NO}_{2}\)
- \(\mathrm{Fe}(\mathrm{OH})_{3}, \mathrm{Cu}(\mathrm{OH})_{2}, \mathrm{Zn}(\mathrm{OH})_{2}\) āĻāĻŦāĻ \(\mathrm{Co}(\mathrm{OH})_{2}\)
- brown, pink, white and blue
- brown, blue, white and pink
- pink, white, brown and blue
- brown, white, blue and pink
Ans. brown, blue, white and pink
- \(\operatorname{Sn}(\mathrm{s})+2 \mathrm{Ag}^{+}(\mathrm{aq}) \rightarrow \mathrm{Sn}^{2+}(\mathrm{aq})+2 \mathrm{Ag}(\mathrm{s})\) āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻžāĻāĻŋāĻ°
āĻā§āĻˇā§āĻ¤ā§āĻ°ā§ āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨āĻāĻŋ āĻā§āĻˇā§āĻ° voltage āĻŦā§āĻĻā§āĻ§āĻŋ āĻāĻ°āĻŦā§?- increase in the size of silver rod
- increase in the concentration of \(\mathrm{Sn}^{2+}\) ions
- increase in the concentration of \(\mathrm{Ag}^{+}\) ions
- increase in the size of tin rod
Ans. increase in the concentration of \(\mathrm{Ag}^{+}\) ions
- āĻŽā§āĻ¯āĻžāĻāĻ¨ā§āĻ¸āĻŋāĻ¯āĻŧāĻžāĻŽ āĻĢāĻ¸āĻĢā§āĻā§āĻ° āĻ¸āĻāĻā§āĻ¤ āĻšāĻ˛ā§-
- \(\mathrm{Mg}_{2}\left(\mathrm{PO}_{4}\right)_{3}\)
- \(\mathrm{MgPO}_{4}\)
- \(\mathrm{Mg}_{2}\left(\mathrm{PO}_{4}\right)_{2}\)
- \(\mathrm{Mg}_{3}\left(\mathrm{PO}_{4}\right)_{2}\)
Ans. \(\mathrm{Mg}_{3}\left(\mathrm{PO}_{4}\right)_{2}\)
- 10.0g āĻ
āĻā§āĻ¸āĻŋāĻā§āĻ¨ā§ āĻ
āĻŖā§āĻ° āĻ¸āĻāĻā§āĻ¯āĻž āĻāĻ¤?
- \(3.76 \times 10^{23}\)
- \(6.02 \times 10^{22}\)
- \(9.63 \times 10^{23}\)
- \(1.88 \times 10^{23}\)
Ans. \(1.88 \times 10^{23}\)
- 300 K āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻžāĻ¯āĻŧ āĻŦāĻžāĻ¤āĻžāĻ¸ā§āĻ° \(\mathrm{N}_{2}\) āĻ
āĻŖā§āĻ° āĻāĻ¤āĻŋ āĻāĻ¤?
- 450 m/s
- 516 m/s
- 400 m/s
- 600 m/s
Ans. 516 m/s
āĻāĻŖāĻŋāĻ¤
- \(f(x)=4-(x-3)^{2}\) āĻĢāĻžāĻāĻļāĻ¨ā§āĻ° āĻĄā§āĻŽā§āĻ¨ āĻāĻŦāĻ āĻ°ā§āĻā§āĻ āĻ¯āĻĨāĻžāĻā§āĻ°āĻŽā§-
- \(\mathbb{R}, \mathbb{R}\)
- \(\mathbb{R}, \mathrm{f}(\mathrm{x}) \leq 4\)
- \(\mathrm{x} \geq 4, \mathbb{R}\)
- \(\mathbb{R}, x \geq 3\)
Ans. \(\mathbb{R}, \mathrm{f}(\mathrm{x}) \leq 4\)
-
\(f(x)=\frac{x-3}{2 x+1}\) āĻāĻŦāĻ \(x \neq-\frac{1}{2}\) āĻšāĻ˛ā§, \(f^{-1}(-2)\) āĻāĻ° āĻŽāĻžāĻ¨ āĻšāĻŦā§-
- \(\frac {1}{2}\)
- \(\frac {1}{5}\)
- 2
- 5
Ans. \(\frac {1}{5}\)
- āĻāĻāĻāĻŋ āĻāĻ˛ā§āĻā§āĻā§āĻ°āĻŋāĻ āĻĢāĻŋāĻ˛ā§āĻĄā§ āĻāĻ˛ā§āĻā§āĻā§āĻ°āĻ¨ā§āĻ° āĻ¤ā§āĻŦāĻ°āĻŖ āĻāĻŦāĻ āĻļāĻā§āĻ¤āĻŋ āĻ¸āĻŽāĻžāĻ¨ā§āĻĒāĻžāĻ¤āĻŋāĻāĨ¤ \(10^{-20} \mathrm{~N}\) āĻļāĻā§āĻ¤āĻŋāĻ° āĻāĻ¨ā§āĻ¯ āĻ¤ā§āĻŦāĻ°āĻŖ \(10^{10} \mathrm{~m} / \mathrm{s}^{2}\) āĻšāĻ˛ā§, \(10^{-25} \mathrm{~N}\) āĻļāĻā§āĻ¤āĻŋāĻ° āĻāĻ¨ā§āĻ¯ āĻ¤ā§āĻŦāĻ°āĻŖ āĻšāĻŦā§-
- \(10^{5} \mathrm{~m} / \mathrm{s}^{2}\)
- \(10^{15} \mathrm{~m} / \mathrm{s}^{2}\)
- \(10^{-5} \mathrm{~m} / \mathrm{s}^{2}\)
- \(10^{-15} \mathrm{~m} / \mathrm{s}^{2}\)
Ans. \(10^{5} \mathrm{~m} / \mathrm{s}^{2}\)
- āĻŦāĻžāĻ¸ā§āĻ¤āĻŦ āĻ¸āĻāĻā§āĻ¯āĻžāĻ¯āĻŧ \(\frac{1}{|2 x-3|}>5\) āĻ
āĻ¸āĻŽāĻ¤āĻžāĻāĻŋāĻ° āĻ¸āĻŽāĻžāĻ§āĻžāĻ¨ āĻšāĻ˛ā§-
- \(\left(\frac{7}{5}, \frac{8}{5}\right)\)
- \(\left[\frac{7}{5}, \frac{8}{5}\right]\)
- \(\left(\frac{7}{5}, \frac{3}{2}\right) \cup\left(\frac{3}{2}, \frac{8}{5}\right)\)
- \(\left[\frac{7}{5}, \frac{3}{2}\right] \cup\left[\frac{3}{2}, \frac{8}{5}\right]\)
Ans. \(\left(\frac{7}{5}, \frac{3}{2}\right) \cup\left(\frac{3}{2}, \frac{8}{5}\right)\)
- \(x^{2}+4 x+2 y=0\) āĻĒāĻ°āĻžāĻŦā§āĻ¤ā§āĻ¤ā§āĻ° āĻļā§āĻ°ā§āĻˇāĻŦāĻŋāĻ¨ā§āĻĻā§ āĻšāĻŦā§-
- (2, -2)
- (-2, -2)
- (-2, 2)
- (2, 2)
Ans. (-2, 2)
- \(\left(2 x^{2}-\frac{1}{2 x^{3}}\right)^{10}\) āĻāĻ° āĻŦāĻŋāĻ¸ā§āĻ¤ā§āĻ¤āĻŋāĻ¤ā§ x āĻŦāĻ°ā§āĻāĻŋāĻ¤ āĻĒāĻĻāĻāĻŋ āĻāĻ¤āĻ¤āĻŽ āĻāĻŦāĻ āĻāĻ° āĻŽāĻžāĻ¨ āĻāĻ¤?
- āĻĒāĻā§āĻāĻŽ āĻāĻŦāĻ ā§Ē40
- āĻāĻ¤ā§āĻ°ā§āĻĨ āĻāĻŦāĻ 1920
- āĻˇāĻˇā§āĻ āĻāĻŦāĻ 252
- āĻ¸āĻĒā§āĻ¤āĻŽ āĻāĻŦāĻ 30
Ans. āĻĒāĻā§āĻāĻŽ āĻāĻŦāĻ ā§Ē40
- \(\mathbf{A}=\left[\begin{array}{rr}1 & \mathbf{i} \\ -\mathbf{i} & 1\end{array}\right], \mathbf{B}=\left[\begin{array}{rr}\mathbf{i} & -1 \\ -1 & -\mathbf{i}\end{array}\right]\) āĻāĻŦāĻ \(\mathbf{i}=\sqrt{-\mathbf{1}}\) āĻšāĻ˛ā§, AB āĻāĻ° āĻŽāĻžāĻ¨ āĻšāĻŦā§-
- \(\left[\begin{array}{ll}1 & 0 \\ 0 & 1\end{array}\right]\)
- \(\left[\begin{array}{ll}0 & 0 \\ 0 & 0\end{array}\right]\)
- \(\left[\begin{array}{cc}\mathrm{i} & 0 \\ 0 & \mathrm{i}\end{array}\right]\)
- \(\left[\begin{array}{ll}i & 1 \\ 1 & i\end{array}\right]\)
Ans. \(\left[\begin{array}{ll}0 & 0 \\ 0 & 0\end{array}\right]\)
- āĻŽāĻžāĻ¨ āĻ¨āĻŋāĻ°ā§āĻŖāĻ¯āĻŧ āĻāĻ°: \( \underset {h \rightarrow 0} {\overset { } {\mathrm lim} } \frac{e^x-1}{x}\)
- 1
- -1
- 2
- 3
Ans. 1
- āĻ¸ā§āĻŦāĻ°āĻŦāĻ°ā§āĻŖāĻā§āĻ˛ā§āĻā§ āĻ¸āĻŦ āĻ¸āĻŽāĻ¯āĻŧ āĻāĻāĻ¤ā§āĻ°ā§ āĻ°ā§āĻā§ KACHUA āĻļāĻŦā§āĻĻāĻāĻŋāĻ° āĻŦāĻ°ā§āĻŖāĻā§āĻ˛ā§āĻā§ āĻ¸āĻžāĻāĻžāĻ¨ā§āĻ° āĻ¸āĻāĻā§āĻ¯āĻž āĻšāĻŦā§-
- 24
- 72
- 144
- 8
Ans. 72
- âaâ āĻāĻ° āĻā§āĻ¨ āĻŽāĻžāĻ¨ā§āĻ° āĻāĻ¨ā§āĻ¯ \(2 \hat{\mathbf{i}}+\hat{\mathbf{j}}-\hat{\mathbf{k}}, \hat{\mathbf{i}}-2 \hat{\mathbf{j}}+4 \hat{\mathbf{k}}\) āĻāĻŦāĻ
\(\hat{\mathbf{i}}-\mathbf{3} \hat{\mathbf{j}}+\mathbf{a} \hat{\mathbf{k}}\) āĻā§āĻā§āĻāĻ°āĻ¤ā§āĻ°āĻ¯āĻŧ āĻ¸āĻŽāĻ¤āĻ˛ā§āĻ¯āĻŧ?- 5
- 4
- 3
- 2
Ans. 5
- x āĻ
āĻā§āĻˇāĻā§ (4, 0) āĻŦāĻŋāĻ¨ā§āĻĻā§āĻ¤ā§ āĻ¸ā§āĻĒāĻ°ā§āĻļ āĻāĻ°ā§ āĻāĻŦāĻ āĻā§āĻ¨ā§āĻĻā§āĻ° 5x – 7y +1 = 0 āĻ¸āĻ°āĻ˛āĻ°ā§āĻāĻžāĻ° āĻāĻĒāĻ° āĻ
āĻŦāĻ¸ā§āĻĨāĻŋāĻ¤ āĻāĻŽāĻ¨ āĻŦā§āĻ¤ā§āĻ¤ā§āĻ° āĻ¸āĻŽā§āĻāĻ°āĻŖ āĻšāĻŦā§-
- \(x^{2}+y^{2}-8 x-6 y+9=0\)
- \(x^{2}+y^{2}-8 x+6 y+16=0\)
- \(x^{2}+y^{2}-8 x+6 y+9=0\)
- \(x^{2}+y^{2}-8 x-6 y+16=0\)
Ans. \(x^{2}+y^{2}-8 x-6 y+16=0\)
- āĻāĻāĻāĻ¨ āĻ˛ā§āĻā§āĻ° 3 āĻā§āĻĄāĻŧāĻž āĻāĻžāĻ˛ā§ āĻŽā§āĻāĻž āĻāĻŦāĻ 2 āĻā§āĻĄāĻŧāĻž āĻŦāĻžāĻĻāĻžāĻŽā§ āĻŽā§āĻāĻž āĻāĻā§āĨ¤ āĻāĻāĻĻāĻŋāĻ¨ āĻ
āĻ¨ā§āĻ§āĻāĻžāĻ°ā§ āĻ¤āĻžāĻĄāĻŧāĻžāĻšā§āĻĄāĻŧāĻž āĻāĻ°ā§ āĻ˛ā§āĻāĻāĻŋ āĻāĻžāĻĒāĻĄāĻŧ āĻĒāĻ°āĻ˛āĨ¤ āĻ¸ā§ āĻĒā§āĻ°āĻĨāĻŽā§ āĻāĻāĻāĻŋ āĻŦāĻžāĻĻāĻžāĻŽā§ āĻŽā§āĻāĻž āĻĒāĻ°āĻžāĻ° āĻĒāĻ° āĻĒāĻ°āĻŦāĻ°ā§āĻ¤ā§ āĻŽā§āĻāĻžāĻ āĻŦāĻžāĻĻāĻžāĻŽā§ āĻšāĻāĻ¯āĻŧāĻžāĻ° āĻ¸āĻŽā§āĻāĻžāĻŦāĻ¨āĻž-
- 1/3
- 2/15
- 1/10
- 3/10
Ans. 1/3
- \(3 x^{2}-5 x+1=0\) āĻ¸āĻŽā§āĻāĻ°āĻŖā§āĻ° āĻŽā§āĻ˛āĻĻā§āĻŦāĻ¯āĻŧ \(\alpha, \beta\) āĻšāĻ˛ā§, \(\frac{1}{\alpha}, \frac{1}{\beta}\) āĻŽā§āĻ˛āĻŦāĻŋāĻļāĻŋāĻˇā§āĻ āĻ¸āĻŽā§āĻāĻ°āĻŖāĻāĻŋ āĻšāĻŦā§-
- \(3 x^{2}-5 x+1=0\)
- \(x^{2}-5 x+3=0\)
- \(5 x^{2}-3 x-1=0\)
- \(3 x^{2}+5 x-1=0\)
Ans. \(x^{2}-5 x+3=0\)
- \(\int \sqrt{\frac{1+x}{1-x}} d x=f(x)+c\) āĻšāĻ˛ā§, f(x) āĻāĻ° āĻŽāĻžāĻ¨-
- \(\sin ^{-1} x+\sqrt{1-x^{2}}\)
- \(\sin ^{-1} x-\sqrt{1-x^{2}}\)
- \(\cos ^{-1} x-\sqrt{1-x^{2}}\)
- \(\sin ^{-1} x-\sqrt{1+x^{2}}\)
Ans. \(\sin ^{-1} x-\sqrt{1-x^{2}}\)
- āĻ¯āĻĻāĻŋ \(y=\sqrt{\cos 2 x}\) āĻšāĻ¯āĻŧ, āĻ¤āĻŦā§ āĻ \(\frac{d y}{d x}=?\)
- \(-\frac{\sin 2 x}{\sqrt{\cos 2 x}}\)
- \(-\frac{\cos 2 x}{\sqrt{\sin 2 x}}\)
- \(-\frac{2 \sin x}{\sqrt{\tan x}}\)
- \(\frac{\tan 2 x}{\sqrt{\sin 2 x}}\)
Ans. \(-\frac{\sin 2 x}{\sqrt{\cos 2 x}}\)
- \(\tan \left(\tan ^{-1}\left(\frac{1}{3}\right)+\tan ^{-1}\left(\frac{1}{2}\right)\right)\) āĻāĻ° āĻŽāĻžāĻ¨ āĻšāĻŦā§-
- 5/6
- 1
- \(\frac {\pi}{4} \)
- \(-\frac{5}{6} \)
Ans. 1
- \(\frac{(i+1)^{2}}{(i-1)^{4}}\) āĻāĻāĻŋāĻ˛ āĻ¸āĻāĻā§āĻ¯āĻžāĻāĻŋāĻ° āĻāĻ°ā§āĻā§āĻŽā§āĻ¨ā§āĻ āĻšāĻŦā§-
- \(\pi \)
- \(-\pi \)
- \(\frac {\pi}{2} \)
- \(-\frac {\pi}{2} \)
Ans. \(-\frac {\pi}{2} \)
- sin(ax + b) āĻāĻ° n āĻ¤āĻŽ āĻ
āĻ¨ā§āĻ¤āĻ°āĻ āĻšāĻŦā§-
- \(a^{n} \sin \left(\frac{\pi}{2} n+a x+b\right)\)
- \(a^{n} \cos \left(\frac{\pi}{2} n+a x+b\right)\)
- \((-1)^{\mathrm{n}} a^{\mathrm{n}} \sin (\mathrm{ax}+\mathrm{b})\)
- \((-1)^{n} a^{n} \cos (a x+b)\)
Ans. \(a^{n} \sin \left(\frac{\pi}{2} n+a x+b\right)\)
- \(8+4 \sqrt{5} \mathbf{i}\) āĻāĻ° āĻŦāĻ°ā§āĻāĻŽā§āĻ˛ āĻšāĻŦā§-
- \(\pm(3-2 i)\)
- \(\pm(\sqrt{10}+\sqrt{2} \mathrm{i})\)
- \(\pm(\sqrt{10}-\sqrt{2} \mathrm{i})\)
- \(\pm(3+2 i)\)
Ans. \(\pm(\sqrt{10}+\sqrt{2} \mathrm{i})\)
- y = mx, \(\mathbf{y}=\mathbf{m}_{1} \mathbf{x}\) āĻāĻŦāĻ y = b āĻ¸āĻ°āĻ˛āĻ°ā§āĻāĻžāĻ¯āĻŧā§āĻ° āĻĻā§āĻŦāĻžāĻ°āĻž āĻāĻ āĻŋāĻ¤ āĻ¤ā§āĻ°āĻŋāĻā§āĻā§āĻ° āĻŦāĻ°ā§āĻāĻāĻāĻā§ āĻā§āĻˇā§āĻ¤ā§āĻ°āĻĢāĻ˛ āĻšāĻŦā§-
- \(\frac{\mathrm{b}^{2}\left(\mathrm{~m}_{1}-\mathrm{m}\right)}{2 \mathrm{~mm}_{1}}\)
- \(\frac{b^{2}\left(m-m_{1}\right)}{2 m m_{1}}\)
- \(\frac{\mathrm{b}^{2}\left|\mathrm{~m}-\mathrm{m}_{1}\right|}{\mathrm{mm}_{1}}\)
- \(\frac{\mathrm{b}^{2}\left|\mathrm{~m}-\mathrm{m}_{1}\right|}{2 \mathrm{~mm}_{1}}\)
Ans. \(\frac{\mathrm{b}^{2}\left|\mathrm{~m}-\mathrm{m}_{1}\right|}{2 \mathrm{~mm}_{1}}\)
- \(\frac{1}{2}+\frac{1}{3^{2}}+\frac{1}{2^{3}}+\frac{1}{3^{4}}+\frac{1}{2^{5}}+\frac{1}{3^{6}}+\ldots \ldots \ldots\) āĻ§āĻžāĻ°āĻžāĻ° āĻ¸āĻŽāĻˇā§āĻāĻŋ āĻšāĻŦā§-
- \(\frac {24}{19} \)
- \(\frac {19}{24} \)
- \(\frac {5}{24} \)
- \(\frac {5}{19} \)
Ans. \(\frac {19}{24} \)
- āĻāĻāĻāĻ¨ āĻā§āĻˇāĻ āĻāĻāĻāĻŋ āĻāĻ¯āĻŧāĻ¤āĻžāĻāĻžāĻ° āĻŦāĻžāĻāĻžāĻ¨ā§āĻ° āĻ¤āĻŋāĻ¨ āĻĻāĻŋāĻ āĻŦā§āĻĄāĻŧāĻž āĻĻāĻŋāĻ¯āĻŧā§ āĻāĻŦāĻ āĻāĻ¤ā§āĻ°ā§āĻĨāĻĻāĻŋāĻā§ āĻāĻāĻāĻŋ āĻĻā§āĻāĻ¯āĻŧāĻžāĻ˛ āĻĻāĻŋāĻ¯āĻŧā§ āĻā§āĻ°āĻžāĻ āĻĻāĻŋāĻ˛āĨ¤ āĻ¯āĻĻāĻŋ āĻ¤āĻžāĻ° āĻāĻžāĻā§ 100m āĻŦā§āĻĄāĻŧāĻž āĻĨāĻžāĻā§ āĻ¤āĻŦā§ āĻā§āĻ°āĻžāĻ āĻĻā§āĻāĻ¯āĻŧāĻž āĻ¸ā§āĻĨāĻžāĻ¨ā§āĻ° āĻ¸āĻ°ā§āĻŦā§āĻā§āĻ āĻāĻ¯āĻŧāĻ¤āĻ¨ āĻšāĻŦā§-
- \(2500 \mathrm{~m}^{2}\)
- \(1250 \mathrm{~m}^{2}\)
- \(750 \mathrm{~m}^{2}\)
- \(2000 \mathrm{~m}^{2}\)
Ans. \(1250 \mathrm{~m}^{2}\)
- \(\left|\begin{array}{lll}\mathbf{a} & \mathbf{1} & \mathbf{b}+\mathbf{c} \\ \mathbf{b} & \mathbf{1} & \mathbf{c}+\mathbf{a} \\ \mathbf{c} & \mathbf{1} & \mathbf{a}+\mathbf{b}\end{array}\right|\) āĻāĻ° āĻŽāĻžāĻ¨ āĻšāĻŦā§-
- 0
- \(a b c(a+b)(b+c)(c+a)\)
- abc
- \((a+b)(b+c)(c+a)\)
Ans. 0
- āĻ¯āĻĻāĻŋ \(x^{2}+3 x y+5 y^{2}=1\) āĻšāĻ¯āĻŧ, āĻ¤āĻžāĻšāĻ˛ā§ \(\frac{\mathrm{d} \mathbf{y}}{\mathrm{d} \mathrm{x}}\) āĻ¸āĻŽāĻžāĻ¨ āĻšāĻŦā§-
- \(-\frac{2 x+3 y}{3 x+10 y}\)
- \(\frac{2 x+3 y}{3 x+10 y}\)
- \(\frac{2 x-3 y}{3 x+10 y}\)
- \(\frac{2 x+3 y}{3 x-10 y}\)
Ans. \(-\frac{2 x+3 y}{3 x+10 y}\)
- āĻĻāĻļāĻŽāĻŋāĻ āĻ¸āĻāĻā§āĻ¯āĻž 2013 āĻāĻ° āĻĻā§āĻŦāĻŋāĻŽāĻŋāĻ āĻĒā§āĻ°āĻāĻžāĻļ āĻšāĻŦā§-
- 11111011101
- 10111011111
- 10101110111
- 10101110101
Ans. 11111011101
- u āĻŦā§āĻā§ āĻ
āĻ¨ā§āĻā§āĻŽāĻŋāĻā§āĻ° āĻ¸āĻžāĻĨā§ \(\alpha \) āĻā§āĻŖā§ āĻĒā§āĻ°āĻā§āĻˇāĻŋāĻĒā§āĻ¤ āĻŦāĻ¸ā§āĻ¤ā§āĻ° āĻ¸āĻ°ā§āĻŦā§āĻā§āĻ āĻāĻā§āĻāĻ¤āĻž āĻšāĻŦā§-
- \(\frac{u^{2} \sin 2 \alpha}{2 g}\)
- \(\frac{\mathrm{u}^{2} \sin ^{2} \alpha}{2 \mathrm{~g}}\)
- \(\frac{u^{2} \sin 2 \alpha}{g}\)
- \(\frac{u^{2} \sin ^{2} \alpha}{g}\)
Ans. \(\frac{\mathrm{u}^{2} \sin ^{2} \alpha}{2 \mathrm{~g}}\)
- 3P āĻāĻŦāĻ 2P āĻŦāĻ˛āĻĻā§āĻŦāĻ¯āĻŧā§āĻ° āĻ˛āĻŦā§āĻ§āĻŋ R. āĻĒā§āĻ°āĻĨāĻŽ āĻŦāĻ˛ āĻĻā§āĻŦāĻŋāĻā§āĻŖ āĻāĻ°āĻ˛ā§ āĻ˛āĻŦā§āĻ§āĻŋāĻ° āĻĒāĻ°āĻŋāĻŽāĻžāĻŖāĻ āĻĻā§āĻŦāĻŋāĻā§āĻŖ āĻšāĻ¯āĻŧāĨ¤ āĻŦāĻ˛āĻĻā§āĻŦāĻ¯āĻŧā§āĻ° āĻ
āĻ¨ā§āĻ¤āĻ°ā§āĻāĻ¤ āĻā§āĻŖ āĻšāĻŦā§-
- 110°
- 120°
- 150°
- 135°
Ans. 120°
- \(3 x^{2}+5 y^{2}=15\) āĻāĻĒāĻŦā§āĻ¤ā§āĻ¤ā§āĻ° āĻā§āĻā§āĻ¨ā§āĻĻā§āĻ°āĻŋāĻāĻ¤āĻž āĻšāĻŦā§-
- \(\sqrt{3 / 5}\)
- \(\sqrt{5 / 3}\)
- \(\sqrt{2 / 5}\)
- \(\sqrt{5 / 2}\)
Ans. \(\sqrt{2 / 5}\)
- \(\mathbf{x}=\mathbf{y}^{2}\) āĻāĻŦāĻ \(\mathbf{y}=\mathbf{x}-\mathbf{2}\) āĻĻā§āĻŦāĻžāĻ°āĻž āĻāĻŦāĻĻā§āĻ§ āĻā§āĻˇā§āĻ¤ā§āĻ°ā§āĻ° āĻā§āĻˇā§āĻ¤ā§āĻ°āĻĢāĻ˛ āĻšāĻŦā§-
- \(1 \frac{1}{3}\)
- \(3 \frac{1}{6}\)
- \(4 \frac{1}{2}\)
- \(4 \frac{3}{4}\)
Ans. \(4 \frac{1}{2}\)
- āĻāĻāĻāĻŋ āĻŦāĻ¸ā§āĻ¤ā§āĻāĻŖāĻž āĻāĻžāĻĄāĻŧāĻž āĻāĻĒāĻ°ā§āĻ° āĻĻāĻŋāĻā§ āĻĒā§āĻ°āĻā§āĻˇā§āĻĒ āĻāĻ°āĻ˛ā§ āĻ¨āĻŋāĻ°ā§āĻĻāĻŋāĻˇā§āĻ āĻŦāĻŋāĻ¨ā§āĻĻā§ P āĻ¤ā§ āĻĒā§āĻāĻžāĻ¤ā§ \(\mathbf{t}_{\mathbf{1}}\) āĻ¸āĻŽāĻ¯āĻŧ āĻ˛āĻžāĻā§āĨ¤ āĻ¯āĻĻāĻŋ āĻāĻ°āĻ \(\mathbf{t}_{\mathbf{2}}\) āĻ¸āĻŽāĻ¯āĻŧ āĻĒāĻ° āĻŦāĻ¸ā§āĻ¤ā§āĻāĻŋ āĻā§āĻŽāĻŋāĻ¤ā§ āĻĒāĻ¤āĻŋāĻ¤ āĻšāĻ¯āĻŧ āĻ¤āĻŦā§ āĻāĻŖāĻžāĻāĻŋāĻ° āĻ¸āĻ°ā§āĻŦā§āĻā§āĻ āĻāĻā§āĻāĻ¤āĻž āĻšāĻŦā§-
- \(\frac{1}{2} \mathrm{~g}\left(\mathrm{t}_{1}+\mathrm{t}_{2}\right)^{2}\)
- \(\frac{1}{8} g\left(t_{1}+t_{2}\right)^{2}\)
- \(\frac{1}{2} g\left(t_{1}^{2}+t_{2}^{2}\right)\)
- \(\frac{1}{8} \mathrm{~g}\left(\mathrm{t}_{1}^{2}+\mathrm{t}_{2}^{2}\right)\)
Ans. \(\frac{1}{8} g\left(t_{1}+t_{2}\right)^{2}\)
āĻā§āĻŦāĻŦāĻŋāĻā§āĻāĻžāĻ¨
- āĻāĻ¯āĻŧāĻžāĻ˛ā§āĻ¸ā§āĻ° āĻ˛āĻžāĻāĻ¨ āĻšāĻ˛ā§ āĻāĻāĻāĻŋ āĻāĻžāĻ˛ā§āĻĒāĻ¨āĻŋāĻ āĻ¸ā§āĻŽāĻžāĻ°ā§āĻāĻž āĻ¯āĻž —– āĻāĻŦāĻ —- āĻ
āĻā§āĻāĻ˛ā§āĻ° āĻŽāĻ§ā§āĻ¯ā§ āĻ
āĻŦāĻ¸ā§āĻĨāĻŋāĻ¤?
- āĻāĻ°āĻŋāĻ¯āĻŧā§āĻ¨ā§āĻāĻžāĻ˛ āĻ āĻ āĻ¸ā§āĻā§āĻ°ā§āĻ˛āĻŋāĻ¯āĻŧāĻž
- āĻāĻāĻ°ā§āĻĒ āĻ āĻāĻļāĻŋāĻ¯āĻŧāĻž
- āĻŦāĻžāĻāĻ˛āĻžāĻĻā§āĻļ āĻ āĻāĻžāĻ°āĻ¤
- āĻā§āĻ°āĻŋāĻ¯āĻŧāĻž āĻ āĻāĻžāĻĒāĻžāĻ¨
Ans. āĻāĻ°āĻŋāĻ¯āĻŧā§āĻ¨ā§āĻāĻžāĻ˛ āĻ āĻ āĻ¸ā§āĻā§āĻ°ā§āĻ˛āĻŋāĻ¯āĻŧāĻž
- Liliopsida āĻŦāĻ˛āĻ¤ā§ āĻāĻŋ āĻŦā§āĻāĻžāĻ¯āĻŧ?
- āĻāĻāĻŦā§āĻāĻĒāĻ¤ā§āĻ°ā§ āĻāĻĻā§āĻāĻŋāĻĻ
- āĻĻā§āĻŦāĻŋāĻŦā§āĻāĻĒāĻ¤ā§āĻ°ā§ āĻāĻĻā§āĻāĻŋāĻĻ
- āĻ˛āĻŋāĻ˛āĻŋāĻ¯āĻŧā§āĻ¸ā§ āĻā§āĻ¤ā§āĻ°
- āĻ˛āĻŋāĻ˛āĻŋāĻ¯āĻŧā§āĻ˛āĻŋāĻ¸ āĻŦāĻ°ā§āĻ
Ans. āĻāĻāĻŦā§āĻāĻĒāĻ¤ā§āĻ°ā§ āĻāĻĻā§āĻāĻŋāĻĻ
- āĻāĻāĻ˛āĻŋāĻ¯āĻŧāĻž āĻšāĻ˛ā§-
- āĻĻā§āĻˇā§āĻāĻŋāĻ° āĻ¸āĻžāĻĨā§ āĻ¸āĻāĻļā§āĻ˛āĻŋāĻˇā§āĻ āĻ āĻā§āĻ
- āĻļā§āĻ°āĻŦāĻŖā§āĻ° āĻ¸āĻžāĻĨā§ āĻ¸āĻāĻļā§āĻ˛āĻŋāĻˇā§āĻ āĻ āĻā§āĻ
- āĻā§āĻ°āĻžāĻŖā§āĻ° āĻ¸āĻžāĻĨā§ āĻ¸āĻāĻļā§āĻ˛āĻŋāĻˇā§āĻ āĻ āĻā§āĻ
- āĻāĻžāĻĻā§āĻ¯ āĻāĻ°ā§āĻŦāĻŖā§āĻ° āĻ¸āĻžāĻĨā§ āĻ¸āĻāĻļā§āĻ˛āĻŋāĻˇā§āĻ āĻ āĻā§āĻ
Ans. āĻļā§āĻ°āĻŦāĻŖā§āĻ° āĻ¸āĻžāĻĨā§ āĻ¸āĻāĻļā§āĻ˛āĻŋāĻˇā§āĻ āĻ āĻā§āĻ
- āĻŽā§āĻ¸ā§āĻā§āĻ˛āĻŋāĻ¯āĻŧāĻž āĻĒāĻžāĻāĻ¯āĻŧāĻž āĻ¯āĻžāĻ¯āĻŧ āĻā§āĻ¨ āĻĒā§āĻ°āĻžāĻŖā§āĻ¤ā§?
- āĻŽāĻžāĻ¨ā§āĻˇ
- āĻāĻ°āĻļā§āĻ˛āĻž
- āĻšāĻžāĻāĻĄā§āĻ°āĻž
- āĻŽāĻžāĻ
Ans. āĻšāĻžāĻāĻĄā§āĻ°āĻž
- āĻā§āĻ°āĻžāĻ˛āĻ¯āĻŧā§āĻĄ āĻŽā§āĻ˛ āĻā§āĻĨāĻžāĻ¯āĻŧ āĻĒāĻžāĻāĻ¯āĻŧāĻž āĻ¯āĻžāĻ¯āĻŧ?
- Cycas
- Fucus
- Hibiscus
- Daucus
Ans. Cycas
- āĻĢā§āĻ¸āĻĢā§āĻ¸ā§āĻ¯āĻŧ āĻ§āĻŽāĻ¨āĻŋ āĻŦāĻšāĻ¨ āĻāĻ°ā§-
- oxygenated blood
- deoxygenated blood
- pure blood
- venous blood
Ans. deoxygenated blood
- āĻŽāĻžāĻ¨ā§āĻˇā§āĻ° RBC āĻāĻ° āĻāĻĄāĻŧ āĻāĻ¯āĻŧā§āĻˇā§āĻāĻžāĻ˛ āĻšāĻā§āĻā§-
- 96 days
- 120 days
- 28 days
- 62 days
Ans. 120 days
- āĻ¨āĻŋāĻāĻā§āĻ˛āĻŋāĻ¯āĻŧāĻžāĻ¸ā§āĻ° āĻĒā§āĻ°āĻĨāĻŽ āĻŦāĻ°ā§āĻŖāĻ¨āĻž āĻāĻ°ā§āĻ¨-
- āĻ°āĻŦāĻžāĻ°ā§āĻ āĻŦā§āĻ°āĻžāĻāĻ¨
- āĻ ā§āĻ¯āĻžāĻ°āĻŋāĻ¸ā§āĻāĻāĻ˛
- āĻ˛ā§āĻ āĻĒāĻžāĻ¸ā§āĻ¤ā§āĻ°
- āĻāĻ˛ā§āĻāĻāĻžāĻ¨ā§āĻĄāĻžāĻ° āĻĢā§āĻ˛ā§āĻŽāĻŋāĻ
Ans. āĻ°āĻŦāĻžāĻ°ā§āĻ āĻŦā§āĻ°āĻžāĻāĻ¨
- āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¨āĻāĻŋāĻ¤ā§ āĻĒā§āĻ˛āĻžāĻ¸āĻŽāĻŋāĻĄ āĻ¨ā§āĻ?
- E. coli
- A. tumefaciens
- Yeast
- Chlorella
Ans. Chlorella
- āĻŽāĻžāĻ¨ā§āĻˇā§āĻ° āĻŦāĻā§āĻˇāĻĻā§āĻļā§āĻ¯āĻŧ āĻāĻļā§āĻ°ā§āĻāĻž āĻāĻ¯āĻŧāĻāĻŋ?
- 7
- 12
- 10
- 15
Ans. 12
- āĻ¸āĻĒā§āĻ¤āĻŽ āĻāĻ°ā§āĻāĻŋāĻ āĻ¸ā§āĻ¨āĻžāĻ¯āĻŧā§āĻā§ āĻŦāĻ˛āĻž āĻšāĻ¯āĻŧ-
- āĻā§āĻāĻžāĻ¸
- āĻā§ā§°āĻā§āĻ˛āĻŋāĻ¯āĻŧāĻžāĻ°
- āĻĢā§āĻ¯āĻžāĻ¸āĻŋāĻ¯āĻŧāĻžāĻ˛
- āĻ āĻĒāĻāĻŋāĻ
Ans. āĻĢā§āĻ¯āĻžāĻ¸āĻŋāĻ¯āĻŧāĻžāĻ˛
- āĻā§āĻ°ā§āĻŦāĻ¸ āĻāĻā§āĻ°ā§ āĻāĻ¤āĻāĻŋ NADH \(_{2}\) āĻ¤ā§āĻ°āĻŋ āĻšāĻ¯āĻŧ?
- 1
- 2
- 3
- 4
Ans. 3
- āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¨āĻāĻŋ āĻĢāĻžāĻ°ā§āĻ¨ āĻĒāĻžāĻ¤āĻžāĻ° āĻ¨āĻžāĻŽ?
- Stomium
- Fronds
- Prothallus
- Scale leave
Ans. Fronds
- F1-āĻāĻ¨ā§āĻ° āĻāĻĻā§āĻāĻŋāĻĻāĻā§ āĻĒā§āĻ°āĻā§āĻāĻ¨ā§āĻ¨ āĻĒā§āĻ¯āĻžāĻ°ā§āĻ¨ā§āĻā§āĻ° āĻ¸āĻžāĻĨā§ āĻā§āĻ°āĻ¸ āĻāĻ°āĻžāĻā§ āĻŦāĻ˛āĻž āĻšāĻ¯āĻŧ-
- āĻŦā§āĻ¯āĻžāĻ āĻā§āĻ°āĻ¸
- āĻā§āĻ¸ā§āĻ āĻā§āĻ°āĻ¸
- āĻŽāĻ¨ā§āĻšāĻžāĻāĻŦā§āĻ°āĻŋāĻĄ āĻā§āĻ°āĻ¸
- āĻĄāĻžāĻāĻšāĻžāĻāĻŦā§āĻ°āĻŋāĻĄ āĻā§āĻ°āĻ¸
Ans. āĻā§āĻ¸ā§āĻ āĻā§āĻ°āĻ¸
- āĻā§āĻ¨āĻāĻŋ Ommatidium āĻāĻ° āĻ
āĻāĻļ āĻ¨āĻ¯āĻŧ?
- rhabdosome
- retinai sheath
- retinal cell
- ocellus
Ans. ocellus
- T2 āĻŦā§āĻ¯āĻžāĻāĻā§āĻ°āĻŋāĻāĻĢāĻžāĻ¯ā§ āĻāĻ¯āĻŧāĻāĻŋ āĻāĻŋāĻ¨ āĻĨāĻžāĻā§?
- 150
- 145
- 155
- 160
Ans. 150
- āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¨āĻāĻŋ āĻā§āĻŦāĻ˛ āĻŦāĻžāĻāĻ˛āĻžāĻĻā§āĻļā§ āĻĒāĻžāĻāĻ¯āĻŧāĻž āĻ¯āĻžāĻ¯āĻŧ?
- Knema bengalensis
- Tactaria chattagramica
- Artocarpus heterophyllus
- Ficus benghalensis
Ans. Knema bengalensis
- āĻā§āĻ¨āĻāĻŋ āĻāĻžāĻāĻ˛ā§āĻŽ āĻāĻŋāĻ¸ā§āĻ¯ā§āĻ° āĻ
āĻāĻļ āĻ¨āĻ¯āĻŧ?
- āĻ¸āĻŋāĻāĻ¨āĻ˛
- āĻā§āĻ°āĻžāĻāĻŋāĻĄ
- āĻā§āĻ°āĻžāĻāĻŋāĻ¯āĻŧāĻž
- āĻāĻĄ āĻĢāĻžāĻāĻŦāĻžāĻ°
Ans. āĻ¸āĻŋāĻāĻ¨āĻ˛
- āĻāĻ¨āĻ¸ā§āĻ˛āĻŋāĻ¨ āĻ¨āĻŋāĻāĻ¸āĻ°āĻŖāĻāĻžāĻ°ā§ āĻā§āĻ°āĻ¨ā§āĻĨāĻŋāĻ° āĻ¨āĻžāĻŽ āĻšāĻ˛ā§-
- āĻ¯āĻā§ā§
- āĻ āĻā§āĻ¨ā§āĻ¯āĻžāĻļāĻ¯āĻŧ
- āĻĒā§āĻ˛ā§āĻšāĻž
- āĻāĻāĻ˛ā§āĻāĻ¸ āĻ āĻŦ āĻ˛ā§āĻ¯āĻžāĻā§āĻāĻžāĻ°āĻšā§āĻ¯āĻžāĻ¨ā§āĻ¸
Ans. āĻāĻāĻ˛ā§āĻāĻ¸ āĻ āĻŦ āĻ˛ā§āĻ¯āĻžāĻā§āĻāĻžāĻ°āĻšā§āĻ¯āĻžāĻ¨ā§āĻ¸
- āĻ
āĻ¸ā§āĻĨāĻŋ āĻ¯ā§ āĻāĻŦāĻ°āĻŖ āĻĻā§āĻŦāĻžāĻ°āĻž āĻāĻŦā§āĻ¤ āĻĨāĻžāĻā§ āĻ¤āĻžāĻā§ āĻŦāĻ˛ā§-
- āĻĒā§āĻ°āĻŋāĻā§āĻ¨āĻŋāĻ¯āĻŧāĻžāĻŽ
- āĻĒā§āĻ°āĻŋāĻ āĻ¸ā§āĻāĻŋāĻ¯āĻŧāĻžāĻŽ
- āĻĒā§āĻ°āĻŋāĻāĻžāĻ°ā§āĻĄāĻŋāĻ¯āĻŧāĻžāĻŽ
- āĻĒā§āĻ°āĻŋāĻāĻ¨ā§āĻĄā§āĻ°āĻŋāĻ¯āĻŧāĻžāĻŽ
Ans. āĻĒā§āĻ°āĻŋāĻ āĻ¸ā§āĻāĻŋāĻ¯āĻŧāĻžāĻŽ
- āĻŦāĻžāĻ¸ā§āĻ āĻ¤āĻ¨ā§āĻ¤ā§ āĻā§āĻ¨āĻāĻŋ?
- āĻĒāĻžāĻ āĻ¤āĻ¨ā§āĻ¤ā§
- āĻāĻžāĻ°ā§āĻĒāĻžāĻ¸ āĻ¤ā§āĻ˛āĻž
- āĻļāĻŋāĻŽā§āĻ˛ āĻ¤ā§āĻ˛āĻž
- āĻāĻ¯āĻŧā§āĻ°
Ans. āĻĒāĻžāĻ āĻ¤āĻ¨ā§āĻ¤ā§
- āĻā§āĻ¨āĻāĻŋ âāĻŦā§ āĻŽā§āĻ˛ā§āĻĄâ?
- Penicillium
- Saprolegnia
- Agaricus
- Helminthosporium
Ans. Penicillium
- āĻā§āĻĻāĻ°ā§āĻ āĻ¸ā§āĻˇā§āĻāĻŋāĻāĻžāĻ°ā§ āĻĒāĻ°āĻā§āĻŦā§āĻ° āĻ¨āĻžāĻŽ-
- Entamoeba histolytica
- Wuchereria bancrofti
- Ades fatigans
- Culex quinquefasciatus
Ans. Wuchereria bancrofti
- āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¨āĻāĻŋāĻā§ āĻšāĻŋāĻ˛ āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻž āĻŦāĻ˛āĻž āĻšāĻ¯āĻŧ?
- \(CO_2\) āĻĨā§āĻā§ \(O_2\) āĻ¨āĻŋāĻ°ā§āĻāĻŽāĻ¨
- \(H_2O\) āĻĨā§āĻā§ \(O_2\) āĻ¨āĻŋāĻ°ā§āĻāĻŽāĻ¨
- \(S_2O\) āĻĨā§āĻā§ \(O_2\) āĻ¨āĻŋāĻ°ā§āĻāĻŽāĻ¨
- \(NO_2\) āĻĨā§āĻā§ \(O_2\) āĻ¨āĻŋāĻ°ā§āĻāĻŽāĻ¨
Ans. \(H_2O\) āĻĨā§āĻā§ \(O_2\) āĻ¨āĻŋāĻ°ā§āĻāĻŽāĻ¨
- āĻŽāĻžāĻ¨ā§āĻˇā§āĻ° āĻĻā§āĻšā§ āĻā§āĻ¨āĻāĻŋ āĻā§āĻ¸ā§āĻā§āĻ¸ā§āĻā§āĻ°āĻ¨ āĻ¤ā§āĻ°āĻŋ āĻāĻ°ā§?
- āĻ¸ā§āĻā§āĻ°ā§āĻāĻžāĻŽ
- āĻāĻ¨ā§āĻāĻžāĻ°āĻ¸ā§āĻāĻŋāĻļāĻŋāĻ¯āĻŧāĻžāĻ˛ āĻā§āĻˇ
- āĻāĻĒāĻŋāĻĄāĻŋāĻĄāĻžāĻāĻŽāĻŋāĻ¸
- āĻ¸ā§āĻĒāĻžāĻ°ā§āĻŽāĻžāĻā§āĻā§āĻ¨āĻŋāĻ¯āĻŧāĻž
Ans. āĻāĻ¨ā§āĻāĻžāĻ°āĻ¸ā§āĻāĻŋāĻļāĻŋāĻ¯āĻŧāĻžāĻ˛ āĻā§āĻˇ
- āĻāĻŋāĻ¨ā§āĻā§āĻ° āĻā§āĻ˛āĻ¸ā§āĻ° āĻ¸āĻŦāĻā§āĻ¯āĻŧā§ āĻāĻŋāĻ¤āĻ°ā§āĻ° āĻ¸ā§āĻ¤āĻ°ā§āĻ° āĻ¨āĻžāĻŽ āĻšāĻ˛ā§-(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻ¨ā§āĻ¯āĻžāĻāĻāĻžāĻ° āĻ¸ā§āĻ¤āĻ°
- āĻ°āĻŋāĻāĻŽā§āĻ¯āĻžāĻāĻŋāĻāĻ¸ā§āĻ¤āĻ°
- āĻĒā§āĻ°āĻŋāĻāĻ¸ā§āĻā§āĻ°āĻžāĻāĻžāĻŽāĻāĻŋ
- āĻŽā§āĻ¯āĻžāĻ¨ā§āĻāĻ˛
Ans. āĻ¨ā§āĻ¯āĻžāĻāĻāĻžāĻ° āĻ¸ā§āĻ¤āĻ°
-
“Diversity and classification of flowering plants” āĻŦāĻāĻāĻŋāĻ° āĻ˛ā§āĻāĻ āĻā§?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- Carolus Linnaeus
- George Bentham
- Theophrastus
- Armen Takhtajan
Ans. Armen Takhtajan
- āĻā§āĻ¨āĻāĻŋ āĻ¸āĻžāĻ¯āĻŧāĻžāĻ¨ā§āĻŦā§āĻ¯āĻžāĻāĻā§āĻ°āĻŋāĻ¯āĻŧāĻž āĻ¨āĻ¯āĻŧ?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- Nostoc
- Anabaena
- Aulosira
- Clostridium
Ans. Clostridium
- āĻāĻ°āĻļā§āĻ˛āĻžāĻ° āĻĒā§āĻ°āĻŋāĻā§āĻ°āĻĢāĻŋāĻ āĻĒāĻ°ā§āĻĻāĻž āĻĨāĻžāĻā§ āĻā§āĻ¨ āĻ¸ā§āĻĨāĻžāĻ¨ā§?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻā§āĻ°āĻĒ
- āĻāĻŋāĻāĻžāĻ°ā§āĻĄ
- āĻšā§āĻĒāĻžāĻāĻŋāĻ āĻ¸āĻŋāĻāĻžāĻŽ
- āĻŽā§āĻ¸ā§āĻ¨ā§āĻā§āĻ°āĻ¨
Ans. āĻŽā§āĻ¸ā§āĻ¨ā§āĻā§āĻ°āĻ¨
- āĻāĻ˛ā§āĻāĻžāĻ°ā§āĻ° āĻāĻžāĻ āĻā§?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻāĻžāĻĻā§āĻ¯ āĻ¤ā§āĻ°āĻŋ āĻāĻ°āĻž
- āĻāĻžāĻĻā§āĻ¯ āĻ¸āĻā§āĻāĻ¯āĻŧ āĻāĻ°āĻž
- āĻ¸ā§āĻĒā§āĻ° āĻ¨āĻŋāĻ°ā§āĻāĻŽāĻ¨ā§ āĻ¸āĻžāĻšāĻžāĻ¯ā§āĻ¯ āĻāĻ°āĻž
- āĻŦāĻāĻļ āĻŦāĻŋāĻ¸ā§āĻ¤āĻžāĻ°ā§ āĻ āĻāĻļ āĻā§āĻ°āĻšāĻŖ āĻāĻ°āĻž
Ans. āĻ¸ā§āĻĒā§āĻ° āĻ¨āĻŋāĻ°ā§āĻāĻŽāĻ¨ā§ āĻ¸āĻžāĻšāĻžāĻ¯ā§āĻ¯ āĻāĻ°āĻž
āĻŦāĻžāĻāĻ˛āĻž
- ‘āĻ¸āĻŽāĻāĻŋāĻŦā§āĻ¯āĻžāĻšāĻžāĻ°’ āĻļāĻŦā§āĻĻāĻāĻŋāĻ¤ā§ āĻŽā§āĻ āĻāĻ¯āĻŧāĻāĻŋ āĻāĻĒāĻ¸āĻ°ā§āĻ āĻāĻā§?
- ā§¨
- ā§Š
- ā§§
- ā§Ē
Ans. ā§Ē
- āĻĒāĻžāĻ ā§āĻ¯ āĻā§āĻ¨ āĻāĻŦāĻŋāĻ¤āĻžāĻ¯āĻŧ āĻŦāĻžāĻ¤āĻžāĻŦāĻŋ āĻ¨ā§āĻŦā§âāĻ° āĻāĻ˛ā§āĻ˛ā§āĻ āĻāĻā§?
- āĻ¤āĻžāĻšāĻžāĻ°ā§āĻ āĻĒāĻĄāĻŧā§ āĻŽāĻ¨ā§
- āĻŦāĻžāĻāĻ˛āĻžāĻĻā§āĻļ
- āĻāĻāĻāĻŋ āĻĢāĻā§āĻā§āĻ°āĻžāĻĢ
- āĻāĻŦāĻ°
Ans. āĻ¤āĻžāĻšāĻžāĻ°ā§āĻ āĻĒāĻĄāĻŧā§ āĻŽāĻ¨ā§
- āĻā§āĻ¨ āĻļāĻŦā§āĻĻāĻāĻŋ āĻāĻĒāĻ¸āĻ°ā§āĻāĻ¯ā§āĻā§ āĻāĻ āĻŋāĻ¤?
- āĻ āĻŦāĻ°ā§āĻŖā§āĻ¯
- āĻ¤āĻ°ā§āĻŖ
- āĻĒāĻ°ā§āĻā§āĻˇāĻž
- āĻāĻ˛ā§āĻˇ
Ans. āĻ āĻŦāĻ°ā§āĻŖā§āĻ¯
- āĻĻā§āĻšā§āĻ° āĻŦāĻ¯āĻŧāĻ¸ āĻ
āĻ¨ā§āĻ¯āĻžāĻ¯āĻŧā§ āĻŽāĻ¨ā§āĻ° āĻŦāĻ¯āĻŧāĻ¸ āĻ¨āĻž āĻŦāĻžāĻĄāĻŧāĻ˛ā§ āĻ¤āĻžāĻā§ āĻŦāĻ˛ā§-
- āĻļāĻžāĻ°ā§āĻ°āĻŋāĻ āĻĒā§āĻ°āĻ¤āĻŋāĻŦāĻ¨ā§āĻ§ā§
- āĻŽāĻ¨ā§āĻŦāĻŋāĻāĻžāĻ°āĻā§āĻ°āĻ¸ā§āĻ¤
- āĻŽāĻžāĻ¨āĻ¸āĻŋāĻ āĻ°ā§āĻā§
- āĻŦā§āĻĻā§āĻ§āĻŋāĻĒā§āĻ°āĻ¤āĻŋāĻŦāĻ¨ā§āĻ§ā§
Ans. āĻŦā§āĻĻā§āĻ§āĻŋāĻĒā§āĻ°āĻ¤āĻŋāĻŦāĻ¨ā§āĻ§ā§
- āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¨āĻāĻŋ āĻļā§āĻĻā§āĻ§ āĻŦāĻžāĻ¨āĻžāĻ¨?
- āĻ¸ā§āĻŦāĻžāĻ¯āĻŧāĻ¤ā§āĻ¤ā§āĻŦāĻļāĻžāĻ¸āĻ¨
- āĻ¸āĻžāĻ¯āĻŧāĻ¤ā§āĻ¤ā§āĻŦāĻļāĻžāĻ¸āĻ¨
- āĻ¸ā§āĻŦāĻžāĻ¯āĻŧāĻ¤ā§āĻ¤āĻļāĻžāĻ¸āĻ¨
- āĻ¸ā§āĻŦāĻžāĻ¯āĻŧāĻ¤ā§āĻ¤ā§āĻŦāĻļāĻžāĻˇāĻŖ
Ans. āĻ¸ā§āĻŦāĻžāĻ¯āĻŧāĻ¤ā§āĻ¤āĻļāĻžāĻ¸āĻ¨
- âThe situation has come to a headâ āĻāĻ° āĻ
āĻ°ā§āĻĨ-
- āĻĒāĻ°āĻŋāĻ¸ā§āĻĨāĻŋāĻ¤āĻŋāĻ° āĻāĻ¨ā§āĻ¨āĻ¤āĻŋ āĻāĻā§āĻā§
- āĻĒāĻ°āĻŋāĻ¸ā§āĻĨāĻŋāĻ¤āĻŋ āĻ¸āĻŦāĻā§āĻ¯āĻŧā§ āĻāĻžāĻ˛ā§ āĻ āĻŦāĻ¸ā§āĻĨāĻžāĻ¯āĻŧ āĻāĻ¸ā§ āĻĻāĻžāĻāĻĄāĻŧāĻŋāĻ¯āĻŧā§āĻā§
- āĻĒāĻ°āĻŋāĻ¸ā§āĻĨāĻŋāĻ¤āĻŋāĻ° āĻ āĻŦāĻ¨āĻ¤āĻŋ āĻāĻā§āĻā§
- āĻĒāĻ°āĻŋāĻ¸ā§āĻĨāĻŋāĻ¤āĻŋ āĻāĻ°āĻŽ āĻ āĻŦāĻ¸ā§āĻĨāĻžāĻ¯āĻŧ āĻĒā§āĻāĻā§āĻā§
Ans. āĻĒāĻ°āĻŋāĻ¸ā§āĻĨāĻŋāĻ¤āĻŋ āĻāĻ°āĻŽ āĻ āĻŦāĻ¸ā§āĻĨāĻžāĻ¯āĻŧ āĻĒā§āĻāĻā§āĻā§
- āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¨āĻāĻŋ āĻļāĻžāĻŽāĻ¸ā§āĻ° āĻ°āĻžāĻšāĻŽāĻžāĻ¨ā§āĻ° āĻāĻžāĻŦā§āĻ¯āĻā§āĻ°āĻ¨ā§āĻĨ āĻ¨āĻ¯āĻŧ?
- āĻĻā§āĻāĻ¸āĻŽāĻ¯āĻŧā§āĻ° āĻŽā§āĻā§āĻŽā§āĻāĻŋ
- āĻāĻĻā§āĻāĻ āĻāĻā§āĻ° āĻĒāĻŋāĻ ā§ āĻāĻ˛ā§āĻā§ āĻ¸ā§āĻŦāĻĻā§āĻļ
- āĻ¨āĻŋāĻ āĻŦāĻžāĻ¸āĻā§āĻŽā§
- āĻāĻāĻ āĻ¸āĻ¨ā§āĻ§ā§āĻ¯āĻžāĻ¯āĻŧ āĻŦāĻ¸āĻ¨ā§āĻ¤
Ans. āĻāĻāĻ āĻ¸āĻ¨ā§āĻ§ā§āĻ¯āĻžāĻ¯āĻŧ āĻŦāĻ¸āĻ¨ā§āĻ¤
- ‘āĻ¤ā§āĻˇāĻžāĻ°āĻ§āĻŦāĻ˛’ āĻā§āĻ¨ āĻ¸āĻŽāĻžāĻ¸ā§āĻ° āĻāĻĻāĻžāĻšāĻ°āĻŖ?
- āĻ¸āĻžāĻ§āĻžāĻ°āĻŖ āĻāĻ°ā§āĻŽāĻ§āĻžāĻ°āĻ¯āĻŧ
- āĻāĻĒāĻŽāĻžāĻ¨ āĻāĻ°ā§āĻŽāĻ§āĻžāĻ°āĻ¯āĻŧ
- āĻāĻĒāĻŽāĻŋāĻ¤ āĻāĻ°ā§āĻŽāĻ§āĻžāĻ°āĻ¯āĻŧ
- āĻŽāĻ§ā§āĻ¯āĻĒāĻĻāĻ˛ā§āĻĒā§ āĻāĻ°ā§āĻŽāĻ§āĻžāĻ°āĻ¯āĻŧ
Ans. āĻāĻĒāĻŽāĻžāĻ¨ āĻāĻ°ā§āĻŽāĻ§āĻžāĻ°āĻ¯āĻŧ
- āĻŖ-āĻ¤ā§āĻŦ āĻŦāĻŋāĻ§āĻŋ āĻ
āĻ¨ā§āĻ¸āĻžāĻ°ā§ āĻā§āĻ¨ āĻā§āĻā§āĻ āĻ
āĻļā§āĻĻā§āĻ§ āĻŦāĻžāĻ¨āĻžāĻ¨ā§āĻ° āĻĻā§āĻˇā§āĻāĻžāĻ¨ā§āĻ¤?
- āĻ§āĻ°āĻ¨, āĻŦāĻ°āĻŖ
- āĻŦāĻ°ā§āĻŖāĻ¨āĻž, āĻĒā§āĻ°ā§āĻ¨ā§
- āĻ¨ā§āĻ¤ā§āĻ°āĻā§āĻ¨āĻž, āĻĒāĻ°āĻāĻ¨āĻž
- āĻ°ā§āĻĒāĻžāĻ¯āĻŧāĻŖ, āĻĒā§āĻ°āĻŖāĻ¯āĻŧāĻ¨
Ans. āĻ¸āĻŦāĻā§āĻ˛ā§āĻ āĻ¸āĻ āĻŋāĻāĨ¤
- āĻ¸āĻ¨ā§āĻ§āĻŋāĻāĻāĻŋāĻ¤ āĻā§āĻ¨ āĻļāĻŦā§āĻĻāĻāĻŋ āĻļā§āĻĻā§āĻ§?
- āĻŦā§āĻšāĻĻāĻāĻļ
- āĻāĻžāĻ¤ā§āĻ¯āĻžāĻāĻŋāĻŽāĻžāĻ¨
- āĻāĻĻā§āĻ¯āĻžāĻ¨ā§āĻ¤
- āĻļāĻŋāĻ°ā§āĻā§āĻā§āĻĻ
Ans. āĻŦā§āĻšāĻĻāĻāĻļ
- āĻĒā§āĻ°āĻŽāĻĨ āĻā§āĻ§ā§āĻ°ā§ āĻ¸āĻŽā§āĻĒāĻžāĻĻāĻŋāĻ¤ ‘āĻ¸āĻŦā§āĻāĻĒāĻ¤ā§āĻ°’ āĻĒāĻ¤ā§āĻ°āĻŋāĻāĻž āĻāĻ¤ āĻ¸āĻžāĻ˛ā§ āĻĒā§āĻ°āĻĨāĻŽ āĻĒā§āĻ°āĻāĻžāĻļāĻŋāĻ¤ āĻšāĻ¯āĻŧ?
- ā§§ā§¯ā§§ā§Š
- ā§§ā§¯ā§§ā§Ē
- ā§§ā§¯ā§§ā§Ģ
- ā§§ā§¯ā§§ā§
Ans. ā§§ā§¯ā§§ā§Ē
- ‘āĻāĻ°ā§āĻŦāĻ°â āĻļāĻŦā§āĻĻā§āĻ° āĻ
āĻ°ā§āĻĨ-
- āĻ°āĻžāĻā§āĻˇāĻ¸
- āĻāĻ¨ā§āĻ§āĻĻā§āĻ°āĻŦā§āĻ¯ āĻŦāĻŋāĻļā§āĻˇ
- āĻ°āĻžāĻ¸āĻžāĻ¯āĻŧāĻ¨āĻŋāĻ āĻĒāĻĻāĻžāĻ°ā§āĻĨ
- āĻāĻ°āĻŖā§āĻ¯āĻŧ
Ans. āĻ°āĻžāĻā§āĻˇāĻ¸
- ‘Lyric’ āĻļāĻŦā§āĻĻā§āĻ° āĻŦāĻžāĻāĻ˛āĻž āĻĒāĻ°āĻŋāĻāĻžāĻˇāĻž-
- āĻāĻžāĻ¨
- āĻ¸ā§āĻ°
- āĻāĻĨāĻž
- āĻā§āĻ¤āĻŋāĻāĻŦāĻŋāĻ¤āĻž
Ans. āĻā§āĻ¤āĻŋāĻāĻŦāĻŋāĻ¤āĻž
- ‘āĻāĻ°ā§āĻŖāĻžāĻāĻžāĻ˛â āĻļāĻŦā§āĻĻā§āĻ° āĻ
āĻ°ā§āĻĨ-
- āĻĻā§āĻĒāĻžāĻā§āĻāĻž
- āĻā§āĻā§āĻā§āĻāĻŋāĻāĻž
- āĻŽāĻžāĻāĻĄāĻŧāĻ¸āĻžāĻ° āĻ¤ā§āĻ°āĻŋ āĻāĻžāĻ˛
- āĻŽāĻžāĻāĻ§āĻ°āĻžāĻ° āĻ¨āĻŋāĻā§āĻˇā§āĻĒāĻ¯ā§āĻā§āĻ¯ āĻāĻžāĻ˛
Ans. āĻŽāĻžāĻāĻĄāĻŧāĻ¸āĻžāĻ° āĻ¤ā§āĻ°āĻŋ āĻāĻžāĻ˛
- āĻŦāĻžāĻāĻ˛āĻž āĻŦā§āĻ¯āĻā§āĻāĻ¨āĻŦāĻ°ā§āĻŖā§āĻ° āĻĒā§āĻ°āĻ¤āĻŋāĻŦāĻ°ā§āĻā§āĻ° āĻĒāĻā§āĻāĻŽ āĻŦāĻ°ā§āĻŖā§āĻ° āĻ§ā§āĻŦāĻ¨āĻŋāĻāĻŋ-
- āĻā§āĻˇāĻ§ā§āĻŦāĻ¨āĻŋ
- āĻ āĻā§āĻˇāĻ§ā§āĻŦāĻ¨āĻŋ
- āĻŽāĻšāĻžāĻĒā§āĻ°āĻžāĻŖāĻ§ā§āĻŦāĻ¨āĻŋ
- āĻ¨āĻžāĻ¸āĻŋāĻā§āĻ¯āĻ§ā§āĻŦāĻ¨āĻŋ
Ans. āĻ¨āĻžāĻ¸āĻŋāĻā§āĻ¯āĻ§ā§āĻŦāĻ¨āĻŋ
- ‘āĻ¯ā§āĻŽāĻ¨ āĻāĻ°ā§āĻŽ āĻ¤ā§āĻŽāĻ¨ āĻĢāĻ˛’ āĻ āĻŦāĻžāĻā§āĻ¯ā§ āĻŦā§āĻ¯āĻŦāĻšā§āĻ¤ āĻšāĻ¯āĻŧā§āĻā§-
- āĻ¨āĻŋāĻ°ā§āĻ§āĻžāĻ°āĻ āĻŦāĻŋāĻļā§āĻˇāĻŖ
- āĻā§āĻ°āĻŋāĻ¯āĻŧāĻž āĻŦāĻŋāĻļā§āĻˇāĻŖ
- āĻ¸āĻžāĻĒā§āĻā§āĻˇ āĻ¸āĻ°ā§āĻŦāĻ¨āĻžāĻŽ
- āĻŦāĻŋāĻļā§āĻˇāĻŖā§āĻ° āĻŦāĻŋāĻļā§āĻˇāĻŖ
Ans. āĻ¸āĻžāĻĒā§āĻā§āĻˇ āĻ¸āĻ°ā§āĻŦāĻ¨āĻžāĻŽ
- āĻāĻāĻžāĻ§āĻŋāĻ āĻ¸ā§āĻŦāĻžāĻ§ā§āĻ¨ āĻŦāĻžāĻā§āĻ¯āĻā§ āĻāĻāĻāĻŋ āĻŦāĻžāĻā§āĻ¯ā§ āĻ˛āĻŋāĻāĻ˛ā§ āĻ¸ā§āĻā§āĻ˛ā§āĻ° āĻŽāĻžāĻāĻāĻžāĻ¨ā§ āĻā§ āĻāĻŋāĻšā§āĻ¨ āĻŦā§āĻ¯āĻŦāĻšā§āĻ¤ āĻšāĻ¯āĻŧ?
- āĻā§āĻ˛āĻ¨
- āĻĄā§āĻ¯āĻžāĻļ
- āĻ¸ā§āĻŽāĻŋāĻā§āĻ˛āĻ¨
- āĻāĻŽāĻž
Ans. āĻ¸ā§āĻŽāĻŋāĻā§āĻ˛āĻ¨
- āĻā§āĻ¨ āĻļāĻŦā§āĻĻāĻāĻŋ āĻļā§āĻĻā§āĻ§?
- āĻ¸āĻŽā§āĻā§āĻˇāĻ¨
- āĻ¸āĻŽā§āĻā§āĻ¨
- āĻļāĻŋāĻ°āĻā§āĻā§āĻĻ
- āĻļāĻŋāĻ°āĻā§āĻā§āĻĻ
Ans. āĻ¸āĻŽā§āĻā§āĻ¨
- ‘āĻŽāĻ’ āĻļāĻŦā§āĻĻā§āĻ° āĻ
āĻ°ā§āĻĨ-
- āĻŽā§āĻŖā§āĻĄāĻ§āĻžāĻ°ā§
- āĻā§āĻ
- āĻā§ā§ā§
- āĻŽāĻŋāĻˇā§āĻāĻŋāĻāĻžāĻ¤ā§āĻ¯āĻŧ āĻĻā§āĻ°āĻŦā§āĻ¯
Ans. āĻā§āĻ
- ‘āĻĒāĻŋāĻĒāĻžāĻ¸āĻŋāĻ¤â āĻļāĻŦā§āĻĻā§āĻ° āĻŦāĻŋāĻļā§āĻˇā§āĻ¯āĻ°ā§āĻĒ
- āĻĒāĻŋāĻĒāĻžāĻ¸ā§
- āĻĒāĻŋāĻĒāĻžāĻ¸ā§
- āĻĒāĻŋāĻĒāĻžāĻ¸āĻž
- āĻĒāĻŋāĻ¯āĻŧāĻžāĻ¸ā§
Ans. āĻĒāĻŋāĻĒāĻžāĻ¸āĻž
- ‘Vertical’ āĻļāĻŦā§āĻĻā§āĻ° āĻĒāĻ°āĻŋāĻāĻžāĻˇāĻž-
- āĻ āĻ¨ā§āĻā§āĻŽāĻŋāĻ
- āĻāĻā§āĻāĻ¤āĻž
- āĻāĻ˛ā§āĻ˛āĻŽā§āĻŦ
- āĻĻā§āĻ¯āĻŧāĻžāĻ˛
Ans. āĻāĻ˛ā§āĻ˛āĻŽā§āĻŦ
- ‘āĻ¸āĻžāĻšāĻāĻ°ā§āĻ¯’ āĻļāĻŦā§āĻĻāĻāĻŋ āĻāĻ āĻŋāĻ¤ āĻšāĻ¯āĻŧā§āĻā§-
- āĻĒā§āĻ°āĻ¤ā§āĻ¯āĻ¯āĻŧāĻ¯ā§āĻā§
- āĻ§āĻžāĻ¤ā§āĻ¯ā§āĻā§
- āĻ¸āĻ¨ā§āĻ§āĻŋāĻ¯ā§āĻā§
- āĻ¸āĻŽāĻžāĻ¸āĻ¯ā§āĻā§
Ans. āĻĒā§āĻ°āĻ¤ā§āĻ¯āĻ¯āĻŧāĻ¯ā§āĻā§
- ‘āĻ¨āĻŋāĻ°āĻžāĻāĻžāĻ°’ āĻļāĻŦā§āĻĻā§āĻ° āĻļā§āĻĻā§āĻ§ āĻ¸āĻ¨ā§āĻ§āĻŋāĻŦāĻŋāĻā§āĻā§āĻĻ āĻā§āĻ¨āĻāĻŋ?
- āĻ¨āĻŋ + āĻāĻāĻžāĻ°
- āĻ¨āĻŋāĻ + āĻāĻāĻžāĻ°
- āĻ¨āĻŋāĻ° + āĻāĻāĻžāĻ°
- āĻ¨āĻŋāĻ°āĻ + āĻāĻžāĻ°
Ans. āĻ¨āĻŋāĻ + āĻāĻāĻžāĻ°
- āĻāĻžāĻ° āĻŽā§āĻā§āĻ¯āĻŧāĻžāĻ āĻāĻ°āĻž āĻĻāĻžāĻāĻ¤ āĻŦāĻžāĻ˛āĻŦ-āĻāĻ° āĻāĻ˛ā§āĻ¯āĻŧ āĻāĻāĻāĻ āĻāĻ°ā§?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻŽā§āĻĻāĻžāĻŦā§āĻŦā§āĻ°ā§āĻ°
- āĻŽāĻāĻ¸ā§āĻĻā§āĻ°
- āĻāĻāĻ¨ā§āĻ¸ā§āĻ°
- āĻ°āĻžāĻšāĻžāĻ¤ā§āĻ°
Ans. āĻŽā§āĻĻāĻžāĻŦā§āĻŦā§āĻ°ā§āĻ°
- ‘āĻāĻžāĻŦā§āĻ¯ āĻāĻāĻ¤ā§ āĻ¯āĻžāĻ° āĻ¨āĻžāĻŽ āĻāĻ¨āĻ¨ā§āĻĻ āĻ¤āĻžāĻ°āĻ āĻ¨āĻžāĻŽ āĻŦā§āĻĻāĻ¨āĻž’- āĻŦāĻžāĻā§āĻ¯āĻāĻŋ āĻāĻā§ āĻ¯ā§ āĻ°āĻāĻ¨āĻžāĻ¯āĻŧ-(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻŦāĻŋāĻ˛āĻžāĻ¸ā§
- āĻšā§āĻŽāĻ¨ā§āĻ¤ā§
- āĻ¸āĻžāĻšāĻŋāĻ¤ā§āĻ¯ā§ āĻā§āĻ˛āĻž
- āĻ¯ā§āĻŦāĻ¨ā§āĻ° āĻāĻžāĻ¨
Ans. āĻ¸āĻžāĻšāĻŋāĻ¤ā§āĻ¯ā§ āĻā§āĻ˛āĻž
- ‘āĻŽāĻžāĻ¤ā§āĻšā§āĻĻāĻ¯āĻŧā§ āĻĒāĻā§āĻˇāĻĒāĻžāĻ¤āĻŋāĻ¤āĻž āĻ¨āĻžāĻāĨ¤’ āĻŦāĻžāĻā§āĻ¯āĻāĻŋ āĻā§āĻ¨ āĻ°āĻāĻ¨āĻžāĻ° āĻ
āĻ¨ā§āĻ¤āĻ°ā§āĻāĻ¤?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻ āĻ°ā§āĻ§āĻžāĻā§āĻā§
- āĻ¯ā§āĻŦāĻ¨ā§āĻ° āĻāĻžāĻ¨
- āĻŦāĻŋāĻ˛āĻžāĻ¸ā§
- āĻāĻŽāĻ˛āĻžāĻāĻžāĻ¨ā§āĻ¤ā§āĻ° āĻĻāĻĒā§āĻ¤āĻ°
Ans. āĻ āĻ°ā§āĻ§āĻžāĻā§āĻā§
- ‘āĻŦāĻŋāĻ˛āĻžāĻ¸ā§’ āĻāĻ˛ā§āĻĒā§ āĻāĻ¨āĻŋāĻļ āĻļāĻ¤āĻā§āĻ° āĻ¯ā§ āĻ¸āĻŽāĻžāĻ-āĻ¸āĻāĻ¸ā§āĻāĻžāĻ°āĻā§āĻ° āĻāĻĨāĻž āĻāĻā§ āĻ¤āĻžāĻ° āĻ¨āĻžāĻŽ-(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻāĻļā§āĻŦāĻ°āĻāĻ¨ā§āĻĻā§āĻ° āĻŦāĻŋāĻĻā§āĻ¯āĻžāĻ¸āĻžāĻāĻ°
- āĻ°āĻžāĻŽāĻŽā§āĻšāĻ¨ āĻ°āĻžāĻ¯āĻŧ
- āĻ āĻā§āĻˇāĻ¯āĻŧāĻā§āĻŽāĻžāĻ° āĻĻāĻ¤ā§āĻ¤
- āĻā§āĻĻā§āĻŦ āĻŽā§āĻā§āĻĒāĻžāĻ§ā§āĻ¯āĻžāĻ¯āĻŧ
Ans. āĻā§āĻĻā§āĻŦ āĻŽā§āĻā§āĻĒāĻžāĻ§ā§āĻ¯āĻžāĻ¯āĻŧ
- ‘āĻĒāĻžāĻā§āĻā§āĻ°āĻŋ’ āĻāĻŦāĻŋāĻ¤āĻžāĻ¯āĻŧ āĻ¯āĻžāĻ¤ā§āĻ°ā§āĻ°āĻž āĻā§āĻĨāĻžāĻ¯āĻŧ āĻŦāĻ¸ā§ āĻ
āĻĒā§āĻā§āĻˇāĻž āĻāĻ°ā§?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻ¤ā§āĻ°ā§
- āĻŽāĻžāĻ¸ā§āĻ¤ā§āĻ˛ā§
- āĻŦāĻ¨ā§āĻĻāĻ°ā§
- āĻĻāĻžāĻĄāĻŧā§
Ans. āĻŦāĻ¨ā§āĻĻāĻ°ā§
- ‘āĻ¤āĻžāĻŽā§āĻ°āĻļāĻžāĻ¸āĻ¨’ āĻŽāĻžāĻ¨ā§-(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻ¸ā§āĻŦā§āĻ°āĻļāĻžāĻ¸āĻ¨
- āĻāĻžāĻ˛ā§ āĻāĻāĻ¨
- āĻ¤āĻžāĻŽāĻžāĻ° āĻĒāĻžāĻ¤ā§ āĻā§āĻĻāĻžāĻ āĻāĻ°āĻž āĻāĻĻā§āĻļ
- āĻāĻāĻāĻ¨ āĻ°āĻžāĻāĻžāĻ° āĻ¨āĻžāĻŽ
Ans. āĻ¤āĻžāĻŽāĻžāĻ° āĻĒāĻžāĻ¤ā§ āĻā§āĻĻāĻžāĻ āĻāĻ°āĻž āĻāĻĻā§āĻļ
- āĻāĻŽāĻžāĻĻā§āĻ° āĻĻāĻ˛ā§ āĻā§āĻš āĻĻāĻ˛āĻĒāĻ¤āĻŋ āĻ¨āĻžāĻāĨ¤ āĻāĻžāĻšāĻžāĻĻā§āĻ° āĻĻāĻ˛ā§?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻāĻŦāĻŋāĻĻā§āĻ°
- āĻ¤āĻ°ā§āĻŖāĻĻā§āĻ°
- āĻ¸āĻžāĻ§āĻāĻĻā§āĻ°
- āĻŦāĻā§āĻ¤āĻžāĻĻā§āĻ°
Ans. āĻ¤āĻ°ā§āĻŖāĻĻā§āĻ°
āĻāĻāĻ°ā§āĻāĻŋ
- He hates _____ kept _____.
- to be, waiting
- being kept, wait
- to be, to wait
- to, waiting
Ans. to be, waiting
- The groom arrived at the community center exactly _____ time.
- in
- for
- by
- on
Ans. on
- I have _____ him to give _____ smoking.
- said, up
- talked, for
- told, up
- told, in
Ans. told, up
- Misuse of _____ energy has _____ destruction.
- solar, shown
- renewable, increase
- nuclear, cause
- atomic, wreaked
Ans. atomic, wreaked
- A man _____ by a speeding bus while he was crossing the road.
- was run over
- was run down
- had been run
- has been run over
Ans. was run over
- There is _____ milk in the bottle.
- very few
- any
- very little
- many
Ans. very little
- I’d like _____ information, please.
- an
- some
- few
- piece
Ans. some
- Yoga is _____ a good exercise for _____ breathing.
- taken, controlling
- treated, considerable
- not, slowly
- considered, controlling
Ans. considered, controlling
- He _____ prefers _____ speak very little.
- doesn’t, to
- himself, to
- himself, for
- does, for
Ans. himself, to
- It _____ heavily when he _____ up.
- had snowed, woke
- snows, wake
- was snowing, woke
- is snowing, wakes
Ans. was snowing, woke
- A group of lions is called ‘pride of lions’, what is a
group of dogs called?- a pack of dogs
- a colony of dogs
- a flock of dogs
- a cluster of dogs
Ans. a pack of dogs
- The synonym of ‘prowl’ is –
- dive
- chase
- prance
- stalk
Ans. stalk
- Cats are carnivorous, but human beings are _____
- herbivorous
- omnivorous
- farinaceous
- cadaverous
Ans. omnivorous
- ‘Cats are nocturnal animals’ means –
- cats have predatory eyesight
- cats are sensitive to smell
- cats hunt during daytime
- cats are active at night
Ans. cats are active at night
- ‘retractile claws’ in the passage means _____
- claws that are extra sharp
- cats that can change shape
- claws that can move inwards
- claws that are sensitive to feelings
Ans. claws that can move inwards
- What is the meaning of the expression âbottom of my heartâ?
- close to my heart
- core of my heart
- lower part of my heart
- close to my liver
Ans. core of my heart
- The word ‘desperation’ is a/an _____.
- adjective
- verb
- adverb
- noun
Ans. noun
- The synonym of ’embellish’is _____
- adorn
- shock
- impoverish
- destroy
Ans. adorn
- The correct translation of ‘āĻ°āĻŦāĻŋāĻŦāĻžāĻ° āĻšāĻāĻ¤ā§ āĻŦā§āĻˇā§āĻāĻŋ āĻšāĻāĻ¤ā§āĻāĻŋāĻ˛’
- It was raining from Sunday
- It has been raining from Sunday
- It had been raining since Sunday
- It rained since Sunday
Ans. It had been raining since Sunday
- The verb of ‘beauty’is _____
- beautician
- beautify
- beautiful
- beautification
Ans. beautify
- The antonym of ‘stubborn’ is _____
- agreeable
- obstinate
- difficult
- irritable
Ans. agreeable
-
Choose the correct spelling.
- indegenus
- indigionus
- indigenous
- indigeneous
Ans. indigenous
-
The word ‘constraint’ means-
- freedom
- limitation
- plentiful
- endless
Ans. limitation
- The idiom ‘let things slide’ means
- ignore
- lose gradually
- reveal a secret
- set free
Ans. ignore
- The expression ‘to look after’ means
- to take care
- to follow
- to imitate
- to gaze
Ans. to take care
-
Choose the correct sentence:
- The jury are arguing among themselves
- The jury is arguing among themselves
- The jury has argued among themselves
- The jury has been arguing among themselves
Ans. The jury are arguing among themselves
-
Choose the correct sentence:
- It is you who is to pay
- It is you who are to leave
- It is you who is late
- It is you who has won the prize
Ans. It is you who are to leave
-
Choose the correct sentence:
- He suspicioned that something was wrong
- He suspicious that something is wrong
- He suspected that something was wrong
- He suspect that something is wrong
Ans. He suspected that something was wrong
- Why were the daffodils in Wordsworthâs âI Wandered Lonely as a Cloud’ dancing?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- The poet was day dreaming
- The flowers had cheerful company
- The sea waves beside them had gone wild
- There was a strong wind
Ans. There was a strong wind
- Why is the poet so sad to see the daffodils in “The Daffodils”?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- The poet is sad because the flowers have not bloomed fully
- The poet is sad because winter will soon arrive
- The poet is sad because the flowers remind him of his own death
- The poet is sad because flowers bring very hot weather
Ans. The poet is sad because the flowers remind him of his own death
Read the passage and answer questions 11-15:
Cats are carnivorous mammals of the family Felidae. They cannot chew their food, and their teeth are adapted to stab, anchor, and cut flesh. All cats except the cheetah have strong, sharp retractile claws, They are not adapted for long chases but prowl their prey on padded feet and try to overwhelm it in short dash or pounce. Big cats roam over a large area, usually alone but sometimes in family groups, for example, a pride of lions can contain as many as 37 individuals. Cats generally are nocturnal animals, the retina of their eyes made extra sensitive to light by a layer of guanine, which causes the eyes to shine in the dark. Tigers are largest of the cats. They are identified by their characteristic striped coat. They inhabit forests and grasslands in Asia where populations have suffered from hunting, deforestation, and demand for tiger parts in traditional medicine.