DU A Unit Admission Question Solution 2006-2007
āĻ¨āĻŋāĻā§āĻ° āĻāĻŋāĻĄāĻŋāĻāĻ¤ā§ āĻĻā§āĻā§ āĻ¨āĻžāĻ āĻŦāĻŋāĻ¸ā§āĻ¤āĻžāĻ°āĻŋāĻ¤:
āĻā§āĻ°ā§āĻ¸āĻāĻŋ āĻāĻŋāĻ¨āĻ¤ā§ āĻĒāĻžāĻļā§āĻ° āĻŦāĻžāĻāĻ¨āĻāĻŋ āĻā§āĻ˛āĻŋāĻ āĻāĻ°:Â Â
āĻā§āĻ°ā§āĻ¸ā§āĻ° āĻĄā§āĻŽā§ āĻāĻŋāĻĄāĻŋāĻ(āĻāĻāĻžāĻŦā§ āĻĒāĻĻāĻžāĻ°ā§āĻĨāĻŦāĻŋāĻā§āĻāĻžāĻ¨+āĻ°āĻ¸āĻžā§āĻ¨+āĻāĻā§āĻāĻ¤āĻ°āĻāĻŖāĻŋāĻ¤ āĻāĻ° āĻŦāĻŋāĻāĻ¤ āĻŦāĻŋāĻļ āĻŦāĻāĻ°ā§āĻ° āĻ¸āĻāĻ˛ āĻĒā§āĻ°āĻļā§āĻ¨ā§āĻ° āĻ¸āĻŽāĻžāĻ§āĻžāĻ¨ āĻĨāĻžāĻāĻŦā§ āĻāĻŋāĻĄāĻŋāĻāĻ¤ā§)
Physics
-
1.0m āĻĻā§āĻ°ā§āĻ āĻ 1.0mm āĻŦā§āĻ¯āĻžāĻ¸āĻžāĻ°ā§āĻ§ā§āĻ° āĻŦā§āĻ˛āĻ¨āĻžāĻāĻžāĻ° āĻ¤āĻžāĻ°ā§āĻ° āĻāĻĒāĻ° 100N āĻŦāĻ˛ āĻĒā§āĻ°āĻ¯āĻŧāĻžā§āĻ āĻāĻ°āĻ˛ā§ āĻĻā§āĻ°ā§āĻā§āĻ¯ āĻŦā§āĻĻā§āĻ§āĻŋ āĻĒā§āĻ¯āĻŧā§ 1.001m āĻšāĻ¯āĻŧāĨ¤ āĻ¤āĻžāĻ°ā§āĻ° āĻāĻ¯āĻŧāĻ āĻāĻ° āĻā§āĻŖāĻžāĻā§āĻ āĻāĻ¤?
- \(\frac{1}{\pi} \times 10^{11} \mathrm{Nm}^{-2}\)
- \(10^{\mathrm{11}} \mathrm{Nm}^{-2}\)
- \(\pi \times 10^{11} \mathrm{Nm}^{-2}\)
- \(\pi^{2} \times 10^{11} \mathrm{Nm}^{-2}\)
Ans. \(\frac{1}{\pi} \times 10^{11} \mathrm{Nm}^{-2}\)
- āĻāĻāĻāĻŋ āĻ¸āĻŽāĻžāĻ¨ā§āĻ¤āĻ°āĻžāĻ˛ āĻĒāĻžāĻ¤ āĻ§āĻžāĻ°āĻāĻā§ āĻāĻžāĻ°ā§āĻāĻŋāĻ¤ āĻāĻ°āĻžāĻ° āĻĢāĻ˛ā§ āĻĒāĻžāĻ¤āĻĻā§āĻŦāĻ¯āĻŧā§āĻ° āĻŽāĻ§ā§āĻ¯ā§ āĻŦāĻŋāĻāĻŦ āĻĒāĻžāĻ°ā§āĻĨāĻā§āĻ¯ āĻšāĻ˛ VāĨ¤ āĻŦāĻŋāĻāĻŦ āĻĒāĻžāĻ°ā§āĻĨāĻā§āĻ¯ āĻāĻ¤ āĻšāĻ˛ā§ āĻ§āĻžāĻ°āĻā§āĻ° āĻ¸āĻā§āĻāĻŋāĻ¤ āĻļāĻā§āĻ¤āĻŋ āĻĻā§āĻŦāĻŋāĻā§āĻŖ āĻšāĻŦā§?
- \(\frac{1}{4} \mathrm{~V}\)
- \(\frac{1}{2} \mathrm{~V}\)
- \(\sqrt{2} \mathrm{~V}\)
- 2V
Ans. \(\sqrt{2} \mathrm{~V}\)
- āĻŦāĻžāĻ¯āĻŧā§ āĻĨā§āĻā§ āĻ
āĻ¨ā§āĻ¯ āĻā§āĻ¨ āĻŽāĻžāĻ§ā§āĻ¯āĻŽā§āĻ° āĻāĻŋāĻ¤āĻ° āĻāĻāĻāĻŋ āĻāĻ˛āĻžā§āĻ āĻ°āĻļā§āĻŽāĻŋ āĻĒā§āĻ°āĻŦā§āĻļ āĻāĻ°āĻžāĻ° āĻĒāĻ° āĻ¤āĻžāĻ° āĻāĻ¤āĻŋ 15% āĻšā§āĻ°āĻžāĻ¸ āĻĒāĻžāĻ¯āĻŧāĨ¤ āĻ āĻŽāĻžāĻ§ā§āĻ¯āĻŽā§āĻ° āĻĒā§āĻ°āĻ¤āĻŋāĻ¸āĻ°āĻžāĻā§āĻ āĻšāĻ˛āĻžā§
- 1.5
- 1.33
- 1.61
- 1.18
Ans. 1.18
- āĻā§āĻ¨āĻžā§ āĻ§āĻžāĻ¤ā§āĻ° āĻāĻžāĻ°ā§āĻ¯ āĻ
āĻĒā§āĻā§āĻˇāĻ \(3.2 \times 10^{-19} \mathrm{~J}\)āĨ¤ āĻ āĻ§āĻžāĻ¤ā§āĻ¤ā§ \(4500\) Å āĻ¤āĻ°āĻā§āĻāĻĻā§āĻ°ā§āĻā§āĻ¯ā§āĻ° āĻāĻ˛ā§āĻ āĻ°āĻļā§āĻŽāĻŋ āĻāĻĒāĻ¤āĻŋāĻ¤ āĻšāĻ˛ā§ āĻ¨āĻŋāĻāĻ¸ā§āĻ¤ āĻāĻ˛ā§āĻā§āĻā§āĻ°āĻ¨ā§āĻ° āĻ¸āĻ°ā§āĻŦā§āĻā§āĻ āĻāĻ¤āĻŋāĻļāĻā§āĻ¤āĻŋ āĻ¨āĻŋāĻ°ā§āĻŖāĻ¯āĻŧ āĻāĻ°āĨ¤ [āĻ¯āĻāĻ¨ āĻĒā§āĻ˛āĻžāĻā§āĻā§āĻ° āĻ§ā§āĻ°ā§āĻŦāĻā§āĻ° āĻŽāĻžāĻ¨ \(=6.63 \times 10^{-34} \mathrm{~J}-\mathrm{s} \) ]
- \(0.8 \times 10^{-19} \mathrm{~J}\)
- \(2.4 \times 10^{-19} \mathrm{~J}\)
- \(1.0 \times 10^{-19} \mathrm{~J}\)
- \(1.2 \times 10^{-19} \mathrm{~J}\)
Ans. \(1.2 \times 10^{-19} \mathrm{~J}\)
- \(300 \mathrm{Nm}^{-1}\) āĻŦāĻ˛ āĻ§ā§āĻ°ā§āĻŦāĻ āĻ¸āĻŽā§āĻĒāĻ¨ā§āĻ¨ āĻāĻāĻāĻŋ āĻĒā§āĻ°āĻŋāĻāĻā§ āĻāĻ¤āĻā§āĻā§ āĻ¸āĻāĻā§āĻāĻŋāĻ¤ āĻāĻ°āĻ˛ā§ 1.5J āĻāĻžāĻ āĻāĻ°āĻž āĻšāĻŦā§?
- 0.1m
- 1.5m
- 3.01
- 1.0m
Ans. 0.1m
- āĻĻā§āĻ°ā§āĻā§āĻ¯ āĻ¸āĻāĻā§āĻāĻ¨ā§āĻ° āĻ¸āĻŽā§āĻāĻ°āĻŖ āĻšāĻ˛āĻžā§-
- \(L=\frac{L}{\sqrt{1-\frac{v^{2}}{c^{2}}}}\)
- \(\mathrm{L}=\mathrm{L}_{0} \sqrt{1-\frac{\mathrm{v}^{2}}{\mathrm{c}^{2}}}\)
- \(\mathrm{L}=\frac{\mathrm{L}}{\sqrt{1+\frac{\mathrm{v}^{2}}{\mathrm{c}^{2}}}}\)
- \(\mathrm{L}=\mathrm{L}_{0} \sqrt{1+\frac{\mathrm{v}^{2}}{\mathrm{c}^{2}}}\)
Ans.\(\mathrm{L}=\mathrm{L}_{0} \sqrt{1-\frac{\mathrm{v}^{2}}{\mathrm{c}^{2}}}\)
- āĻā§āĻ¯āĻžāĻĨāĻžā§āĻĄ āĻ°āĻļā§āĻŽāĻŋāĻ° āĻā§āĻˇā§āĻ¤ā§āĻ°ā§ āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¨ āĻ§āĻ°ā§āĻŽāĻāĻŋ āĻ¸āĻ¤ā§āĻ¯ āĻ¨āĻ¯āĻŧ?
- āĻā§āĻ¯āĻžāĻĨāĻžā§āĻĄ āĻ°āĻļā§āĻŽāĻŋāĻ° āĻ¸āĻ°āĻ˛āĻ°ā§āĻāĻžāĻ¯āĻŧ āĻāĻŽāĻ¨ āĻāĻ°ā§
- āĻā§āĻ¯āĻžāĻĨāĻžā§āĻĄ āĻ°āĻļā§āĻŽāĻŋ āĻĒāĻ°āĻ¸ā§āĻĒāĻ°āĻā§ āĻāĻāĻ°ā§āĻˇāĻŖ āĻāĻ°ā§
- āĻā§āĻ¯āĻžāĻĨāĻžā§āĻĄ āĻ°āĻļā§āĻŽāĻŋ āĻ¤āĻžāĻĒ āĻā§āĻĒāĻžāĻĻāĻ¨ āĻāĻ°ā§
- āĻā§āĻ¯āĻžāĻĨāĻžā§āĻĄ āĻ°āĻļā§āĻŽāĻŋ āĻĢāĻā§āĻā§āĻ°āĻžāĻĢāĻŋāĻ āĻĒā§āĻ˛ā§āĻā§āĻ° āĻāĻĒāĻ° āĻā§āĻ°āĻŋāĻ¯āĻŧāĻž āĻāĻ°ā§
Ans. āĻā§āĻ¯āĻžāĻĨāĻžā§āĻĄ āĻ°āĻļā§āĻŽāĻŋ āĻĒāĻ°āĻ¸ā§āĻĒāĻ°āĻā§ āĻāĻāĻ°ā§āĻˇāĻŖ āĻāĻ°ā§
- āĻāĻāĻāĻŋ āĻāĻžāĻ°ā§āĻ¨ā§ āĻāĻā§āĻāĻŋāĻ¨ āĻĒāĻžāĻ¨āĻŋāĻ° āĻšāĻŋāĻŽāĻžāĻā§āĻ āĻ āĻ¸ā§āĻĢā§āĻāĻ¨āĻžāĻā§āĻā§āĻ° āĻŽāĻ§ā§āĻ¯ā§ āĻāĻžāĻ°ā§āĻ¯āĻ°āĻ¤ āĻāĻā§āĨ¤ āĻāĻā§āĻāĻŋāĻ¨āĻāĻŋāĻ° āĻĻāĻā§āĻˇāĻ¤āĻž āĻāĻ¤?
- 100%
- 0%
- 26.8%
- 28.6%
Ans. 26.8%
- āĻāĻāĻāĻŋ āĻĻāĻŋāĻ āĻĒāĻ°āĻŋāĻŦāĻ°ā§āĻ¤ā§ āĻĒā§āĻ°āĻŦāĻžāĻšāĻā§ \(I=100 \sin 500 \pi t\) āĻ¸āĻŽā§āĻāĻ°āĻŖ āĻĻā§āĻŦāĻžāĻ°āĻž āĻĒā§āĻ°āĻāĻžāĻļ āĻāĻ°āĻž āĻ¯āĻžāĻ¯āĻŧāĨ¤ āĻ āĻĒā§āĻ°āĻŦāĻžāĻšā§āĻ° āĻāĻŽā§āĻĒāĻžāĻā§āĻ āĻāĻ¤?
- 200 Hz
- 250 Hz
- 300 Hz
- 500 Hz
Ans. 250 Hz
- āĻāĻāĻāĻŋ āĻ
āĻŦāĻ¤āĻ˛ āĻĻāĻ°ā§āĻĒāĻŖā§āĻ° āĻŦāĻā§āĻ°āĻ¤āĻžāĻ° āĻŦā§āĻ¯āĻžāĻ¸āĻžāĻ°ā§āĻ§ 30 cmāĨ¤ āĻāĻāĻāĻŋ āĻŦāĻ¸ā§āĻ¤ā§āĻā§ āĻŦāĻā§āĻ°āĻ¤āĻžāĻ° āĻā§āĻ¨ā§āĻĻā§āĻ°ā§ āĻ°āĻžāĻāĻ˛ā§ āĻāĻ° āĻĒā§āĻ°āĻ¤āĻŋāĻŦāĻŋāĻŽā§āĻŦā§āĻ° āĻĻā§āĻ°āĻ¤ā§āĻŦ āĻāĻ¤?
- 15 cm
- 45 cm
- 30 cm
- 60 cm
Ans. 30 cm
- āĻāĻāĻāĻŋ āĻāĻžāĻ°ā§ āĻ¤ā§āĻāĻ¸ā§āĻ¤ā§āĻ°āĻŋāĻ¤ā§ āĻĒāĻĻāĻžāĻ°ā§āĻĨ āĻāĻ˛āĻĢāĻž āĻāĻŖāĻž āĻŦāĻŋāĻāĻŋāĻ°āĻŖ āĻāĻ°ā§ āĻ¯āĻž āĻāĻ° 10g āĨ¤ āĻāĻ āĻ
āĻ°ā§āĻ§āĻžā§ā§ āĻĒāĻ°ā§ āĻāĻ° āĻāĻ° āĻšāĻŦā§-
- 5g
- āĻĒā§āĻ°āĻžā§ 10g
- 10g
- āĻā§āĻ¨ā§āĻžāĻāĻŋāĻ āĻ¨ā§
Ans. 5g
- āĻāĻāĻāĻŋ āĻ¤āĻžāĻ°āĻāĻžāĻ° āĻāĻ° āĻĒāĻžāĻāĻ āĻ¸ā§ā§āĻ° āĻāĻ°ā§āĻ° āĻ¸āĻŽāĻžāĻ¨āĨ¤ āĻ¤āĻžāĻ°āĻāĻžāĻāĻŋ āĻā§āĻˇā§āĻ āĻŦāĻŋāĻŦāĻ°ā§ āĻĒāĻ°āĻŋāĻŖāĻ¤ āĻšāĻ˛ā§ āĻāĻ° āĻļā§ā§āĻžāĻ°ā§āĻāĻļāĻŋāĻ˛ā§āĻĄ āĻŦā§āĻ¯āĻ¸āĻžāĻ°ā§āĻ§ āĻāĻ¤ āĻšāĻŦā§? [āĻ¸ā§āĻ°ā§āĻ¯ā§āĻ° āĻāĻ°= \(\left.2 \times 10^{30} \mathrm{~kg} . \mathrm{G}=6.67 \times 10^{-11} \mathrm{Nm}^{2} \mathrm{~kg}^{-2}\right]\)]
- 14.8 km
- 7.2 km
- 14.2 km
- 15.8 km
Ans. 14.8 km
- 5N āĻāĻŦāĻ 10N āĻŽāĻžāĻ¨ā§āĻ° āĻĻā§āĻāĻŋ āĻŦāĻ˛ āĻāĻāĻāĻŋ āĻāĻŖāĻžāĻ° āĻāĻĒāĻ° āĻāĻ°ā§āĻĒāĻŋāĻ¤ āĻšāĻ˛ā§, āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨ āĻŦāĻ˛āĻāĻŋ āĻāĻŖāĻžāĻāĻŋāĻ° āĻāĻĒāĻ° āĻ˛āĻŦā§āĻĻāĻŋ āĻŦāĻ˛ āĻšāĻ¤ā§ āĻĒāĻžāĻ°ā§ āĻ¨āĻž?
- 5 N
- 10 N
- 15 N
- 20 N
Ans. 20 N
- āĻā§āĻ¨ā§ āĻ¸āĻŋāĻ¸ā§āĻā§āĻŽ 1500J āĻ¤āĻžāĻĒ āĻļā§āĻˇāĻŖ āĻāĻ°ā§ āĻāĻŦāĻ 82J āĻāĻžāĻ āĻ¸āĻŽā§āĻĒāĻžāĻĻāĻ¨ āĻāĻ°ā§āĨ¤ āĻ¸āĻŋāĻ¸ā§āĻā§āĻŽā§āĻ° āĻ
āĻ¨ā§āĻ¤:āĻ¸ā§āĻš āĻļāĻā§āĻ¤āĻŋāĻ° āĻĒāĻ°āĻŋāĻŦāĻ°ā§āĻ¤āĻ¨ āĻšāĻŦā§-
- 1418 J
- 1232 J
- 1582 J
- 1237 J
Ans. 1418 J
- āĻāĻāĻāĻŋ 60W āĻŦā§āĻĻā§āĻ¯ā§āĻ¤āĻŋāĻ āĻŦāĻžāĻ¤āĻŋāĻā§ 220V āĻ¤ā§āĻŋā§ āĻ¸āĻ°āĻŦāĻ°āĻžāĻš āĻā§āĻ¸ā§āĻ° āĻ¸āĻāĻā§ āĻ¸āĻāĻ¯ā§āĻā§āĻ¤ āĻāĻ°āĻž āĻšāĻ˛ā§āĨ¤ āĻ āĻŦāĻžāĻ¤āĻŋāĻ¤ā§ āĻāĻŋ āĻĒāĻ°āĻŋāĻŽāĻžāĻŖ āĻ¤ā§āĻŋā§ āĻĒā§āĻ°āĻŦāĻžāĻšāĻŋāĻ¤ āĻšāĻŦā§?
- 0.2727A
- 2.727A
- 0.2727mA
- 2.727mA
Ans. 0.2727A
- āĻĢā§āĻ°ā§āĻā§ā§āĻŽā§āĻŦāĻ āĻ¯ā§ āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻžā§ āĻĒā§āĻ¯āĻžāĻ°āĻžāĻā§ā§āĻŽā§āĻŦāĻā§ āĻĒāĻ°āĻŋāĻŖāĻ¤ āĻšā§ āĻ¤āĻžāĻā§ āĻŦāĻ˛āĻž āĻšā§-
- Debye temperature
- Neel temperature
- Curie temperature
- None of these
Ans. Curie temperature
- āĻāĻāĻāĻŋ āĻā§āĻ°ā§āĻ¨ āĻšā§āĻāĻ¸ā§āĻ˛ āĻŦāĻžāĻāĻŋā§ā§ \(90 \mathrm{kmh}^{-1}\) āĻŦā§āĻā§ āĻĒā§āĻ˛āĻžāĻāĻĢāĻ°āĻŽā§āĻ° āĻĻāĻŋāĻā§ āĻ
āĻā§āĻ°āĻ¸āĻ° āĻšāĻā§āĻā§āĨ¤ āĻĒā§āĻ˛āĻžāĻāĻĢāĻ°āĻŽā§ āĻ
āĻŦāĻ¸ā§āĻšāĻŋāĻ¤ āĻ¯āĻžāĻ¤ā§āĻ°ā§ \(\mathbf{6 5 0} \mathbf{H z}\) āĻāĻŽā§āĻĒāĻžāĻā§āĻā§ āĻļāĻŦā§āĻĻ āĻļā§āĻ¨āĻ¤ā§ āĻĒāĻžā§āĨ¤ āĻšā§āĻāĻ¸ā§āĻ˛ā§āĻ° āĻĒā§āĻ°āĻā§āĻ¤ āĻāĻŽā§āĻĒāĻžāĻā§āĻ āĻāĻ¤? [āĻŦāĻžā§ā§āĻ¤ā§ āĻļāĻŦā§āĻĻā§āĻ° āĻĻā§āĻ°ā§āĻ¤āĻŋ = \(\left.325 \mathrm{~ms}^{-1}\right]\)
- 600Hz
- 90Hz
- 550Hz
- 320Hz
Ans. 600Hz
- āĻāĻāĻāĻŋ āĻāĻŽāĻ¨-āĻŦā§āĻ¸ āĻā§āĻ°āĻžāĻ¨āĻāĻŋāĻ¸ā§āĻāĻ° āĻŦāĻŋāĻ¨ā§āĻ¯āĻžāĻ¸ā§ āĻāĻŽāĻŋāĻāĻ° āĻāĻžāĻ°ā§āĻ¨ā§āĻ 1.2 mA āĻāĻŦāĻ āĻāĻžāĻ˛ā§āĻā§āĻāĻ° āĻāĻžāĻ°ā§āĻ¨ā§āĻ \(9 \times 10^{-4} \mathrm{~A}\) āĻšāĻ˛ā§ āĻŦā§āĻ¸ āĻāĻžāĻ°ā§āĻ¨ā§āĻā§āĻ° āĻŽāĻžāĻ¨ āĻšāĻŦā§
- \(0.3 \times 10^{-3} \mathrm{~A}\)
- \(0.3 \times 10^{3} \mathrm{~A}\)
- \(3 \times 10^{-3} \mathrm{~A}\)
- \(3 \times 10^{3} \mathrm{~A}\)
Ans. \(0.3 \times 10^{-3} \mathrm{~A}\)
- āĻ¸ā§āĻĨāĻŋāĻ° āĻ
āĻŦāĻ¸ā§āĻĨāĻžāĻ¨ āĻĨā§āĻā§ āĻāĻāĻāĻŋ āĻā§āĻ°ā§āĻ¨ \(10 \mathrm{~ms}^{-2}\) āĻ¸āĻŽāĻ¤ā§āĻŦāĻ°āĻŖā§ āĻāĻ˛āĻžāĻ° āĻ¸āĻŽāĻ¯āĻŧ 125m āĻĻā§āĻ°āĻ¤ā§āĻŦā§ āĻ
āĻŦāĻ¸ā§āĻĨāĻŋāĻ¤ āĻāĻāĻāĻŋ āĻĒāĻžā§āĻˇā§āĻāĻā§ āĻāĻ¤ āĻŦā§āĻā§ āĻ
āĻ¤āĻŋāĻā§āĻ°āĻŽ āĻāĻ°āĻŦā§?
- \(50 \mathrm{~ms}^{-1}\)
- \(10 \mathrm{~ms}^{-1}\)
- \(10 \mathrm{~ms}^{-1}\)
- \(2500 \mathrm{~ms}^{-1}\)
Ans. \(50 \mathrm{~ms}^{-1}\)
- āĻāĻāĻāĻŋ āĻŦāĻ¸ā§āĻ¤ā§āĻ° āĻāĻ° āĻŦāĻžāĻ¤āĻžāĻ¸ā§ 100g āĻ āĻ
ā§āĻ¯āĻžāĻ˛āĻā§āĻšāĻ˛ā§ 84gāĨ¤ āĻ
ā§āĻ¯āĻžāĻ˛āĻā§āĻšāĻ˛ā§āĻ° āĻāĻ¨āĻ¤ā§āĻŦ 0.8g/cc āĻšāĻ˛ā§ āĻŦāĻ¸ā§āĻ¤ā§āĻ° āĻāĻ¯āĻŧāĻ¤āĻ¨ āĻāĻ¤?
- 10.5 cc
- 16 cc
- 12.5 cc
- 20 cc
Ans. 20 cc
-
āĻāĻŋāĻ¤ā§āĻ°ā§ āĻĻā§āĻāĻžāĻ¨āĻžā§ āĻŦāĻ°ā§āĻ¤āĻ¨ā§ āĻĻāĻŋāĻ¯āĻŧā§ āĻĒā§āĻ°āĻŦāĻžāĻšāĻŋāĻ¤ āĻāĻžāĻ°ā§āĻ¨ā§āĻā§āĻ° āĻŽāĻžāĻ¨ āĻāĻ¤?- 3.0 A
- 2.25 A
- 2.0 A
- 1.5 A
Ans. 2.0 A
- āĻāĻāĻāĻŋ āĻ¸āĻ°āĻ˛ āĻĻā§āĻ˛āĻā§āĻ° āĻĻā§āĻ˛āĻ¨āĻāĻžāĻ˛ T āĻĻā§āĻ˛āĻāĻāĻŋāĻ° āĻĻā§āĻ°ā§āĻā§āĻ¯ āĻĻā§āĻŦāĻŋāĻā§āĻŖ āĻāĻ°āĻž āĻšāĻ˛ā§ āĻĒāĻ°āĻŋāĻŦāĻ°ā§āĻ¤āĻŋāĻ¤ āĻĻā§āĻ˛āĻ¨āĻāĻžāĻ˛ āĻšāĻŦā§?
- \(\sqrt{2} \mathrm{~T}\)
- \(2 \mathrm{~T}\)
- \(\frac{1}{2} \mathrm{~T}\)
- \(\frac{1}{\sqrt{2}} \mathrm{~T}\)
Ans. \(\sqrt{2} \mathrm{~T}\)
- āĻāĻāĻāĻŋ āĻ¸āĻŽāĻ¤āĻ˛ āĻ¨āĻŋāĻāĻ¸āĻ°āĻŖ āĻā§āĻ°ā§āĻāĻŋāĻ āĻ \(600 \times 10^{-9} \mathrm{~m}\) āĻ¤āĻ°āĻā§āĻāĻĻā§āĻ°ā§āĻā§āĻ¯ā§āĻ° āĻāĻ˛āĻžā§āĻ āĻ°āĻļā§āĻŽāĻŋ āĻĒā§āĻ°āĻĨāĻŽ āĻā§āĻ°āĻŽā§ 30° āĻā§āĻŖā§ āĻ
āĻĒāĻŦāĻ°ā§āĻ¤āĻŋāĻ¤ āĻšāĻ˛ā§ āĻā§āĻ°ā§āĻāĻŋāĻ āĻāĻ° āĻĒā§āĻ°āĻ¤āĻŋ āĻŽāĻŋāĻāĻžāĻ°ā§ āĻ°ā§āĻāĻžāĻ° āĻ¸āĻāĻā§āĻ¯āĻž āĻāĻ¤?
- \(6.25 \times 10^{5} \mathrm{~m}^{-1}\)
- \(8.0 \times 10^{5} \mathrm{~m}^{-1}\)
- \(7.85 \times 10^{5} \mathrm{~m}^{-1}\)
- \(8.33 \times 10^{5} \mathrm{~m}^{-1}\)
Ans. \(8.33 \times 10^{5} \mathrm{~m}^{-1}\)
- 5g āĻāĻ°ā§āĻ° āĻ¸āĻŽāĻ¤ā§āĻ˛ā§āĻ¯ āĻļāĻā§āĻ¤āĻŋ āĻāĻ¤?
- \(15 \times 10^{8} \mathrm{~J}\)
- \(4.5 \times 10^{14} \mathrm{~J}\)
- \(3 \times 10^{14} \mathrm{~J}\)
- \(45 \times 10^{14} \mathrm{~J}\)
Ans. \(4.5 \times 10^{14} \mathrm{~J}\)
- āĻā§āĻā§āĻāĻ° \(\overrightarrow{\mathbf{A}}=\hat{\mathbf{i}}-3 \hat{\mathbf{j}}+5 \hat{\mathbf{k}}\) āĻāĻŦāĻ \(\overrightarrow{\mathbf{B}}=\mathbf{a} \hat{\mathbf{i}}+\mathbf{6} \hat{\mathbf{j}}-\mathbf{1 0 \hat { k }}\) a-āĻāĻ° āĻŽāĻžāĻ¨ āĻāĻ¤ āĻšāĻ˛ā§ āĻā§āĻā§āĻāĻ° āĻĻā§āĻāĻŋ āĻ¸āĻŽāĻžāĻ¨ā§āĻ¤āĻ°āĻžāĻ˛ āĻšāĻŦā§?
- 0
- -2
- -1
- 1
Ans. -2
- 24400J āĻāĻ¤āĻŋāĻļāĻā§āĻ¤āĻŋ āĻŦāĻŋāĻļāĻŋāĻˇā§āĻ āĻāĻāĻāĻŋ āĻāĻžāĻāĻž āĻĒā§āĻ°āĻ¤āĻŋ āĻŽāĻŋāĻ¨āĻŋāĻā§ 602 āĻŦāĻžāĻ° āĻāĻžā§āĻ°ā§āĨ¤ āĻāĻžāĻāĻžāĻāĻŋāĻ° āĻā§āĻ°ā§āĻŖāĻ¨ āĻāĻĄāĻŧāĻ¤āĻž āĻšāĻŦā§-
- \(40.5 \mathrm{kgm}^{2}\)
- \(12.3 \mathrm{kgm}^{2}\)
- \(10 \mathrm{kgm}^{2}\)
- \(406.7 \mathrm{kgm}^{2}\)
Ans. \(12.3 \mathrm{kgm}^{2}\)
- āĻāĻāĻāĻŋ āĻšā§āĻāĻāĻ¸ā§āĻā§āĻ¨ āĻŦā§āĻ°ā§āĻā§āĻ° āĻāĻžāĻ°āĻāĻŋ āĻŦāĻžāĻšā§āĻ¤ā§ āĻ¯āĻĨāĻžāĻā§āĻ°āĻŽā§ 6, 18, 10 āĻāĻŦāĻ 20 āĻāĻšāĻŽā§āĻ° āĻ°āĻžā§āĻ§ āĻ¯ā§āĻā§āĻ¤ āĻāĻā§āĨ¤ āĻāĻ¤ā§āĻ°ā§āĻĨ āĻŦāĻžāĻšā§āĻ¤ā§ āĻāĻ¤ āĻŽāĻžāĻ¨ā§āĻ° āĻ°āĻžā§āĻ§ āĻļā§āĻ°ā§āĻŖāĻŋ āĻ¸āĻŽāĻŦāĻžāĻ¯āĻŧā§ āĻ¯ā§āĻā§āĻ¤ āĻāĻ°āĻ˛ā§ āĻŦā§āĻ°ā§āĻāĻāĻŋ āĻ¸āĻžāĻŽā§āĻ¯āĻžāĻŦāĻ¸ā§āĻĨāĻž āĻĒā§āĻ°āĻžāĻĒā§āĻ¤ āĻšāĻŦā§?
- \(20 \Omega\)
- \(30 \Omega\)
- \(10 \Omega\)
- \(40 \Omega\)
Ans. \(10 \Omega\)
- āĻā§-āĻĒā§āĻˇā§āĻ āĻšāĻ¤ā§ āĻ
āĻ˛ā§āĻĒ āĻāĻā§āĻāĻ¤āĻžāĻ¯āĻŧ āĻāĻŦāĻ āĻā§-āĻĒā§āĻˇā§āĻ ā§āĻ° āĻ¸āĻŽāĻžāĻ¨ā§āĻ¤āĻ°āĻžāĻ˛ā§ āĻāĻāĻāĻŋ āĻ¨āĻāĻžā§āĻ¯āĻžāĻ¨ āĻāĻ¤ āĻĻā§āĻ°ā§āĻ¤āĻŋāĻ¤ā§ āĻāĻ˛āĻ˛ā§ āĻ¯āĻžāĻ¤ā§āĻ°ā§āĻ°āĻž āĻāĻāĻ¨āĻšā§āĻ¨āĻ¤āĻž āĻ
āĻ¨ā§āĻāĻŦ āĻāĻ°āĻŦā§? āĻĒā§āĻĨāĻŋāĻŦā§āĻ° āĻŦā§āĻ¯āĻžāĻ¸āĻžāĻ°ā§āĻ§ = 6400 km āĻāĻŦāĻ \(\left.g=9.8 \mathrm{~ms}^{-2}\right]\)
- \(7.9 \mathrm{kms}^{-1}\)
- \(7.1 \mathrm{kms}^{-1}\)
- \(3.5 \mathrm{kms}^{-1}\)
- \(3.1 \mathrm{kms}^{-1}\)
Ans. \(7.9 \mathrm{kms}^{-1}\)
- āĻāĻ¯āĻŧāĻ āĻāĻ° āĻĻā§āĻŦāĻŋ-āĻāĻŋāĻĄāĻŧ āĻĒāĻ°ā§āĻā§āĻˇāĻžāĻ¯āĻŧ āĻāĻŋāĻĄāĻŧ āĻĨā§āĻā§ 1m āĻĻā§āĻ°ā§ āĻāĻāĻāĻŋ āĻāĻā§āĻāĻ˛ āĻĄāĻžā§āĻ°āĻžāĻ° āĻĒā§āĻ°āĻ¸ā§āĻĨ 0.5 mmāĨ¤ āĻāĻŋāĻĄāĻŧ āĻĻā§āĻāĻŋāĻ° āĻŽāĻ§ā§āĻ¯ā§ āĻĻā§āĻ°āĻ¤ā§āĻŦ 0.2 mm āĻšāĻ˛ā§ āĻāĻ˛āĻžā§āĻ° āĻ¤āĻ°āĻā§āĻāĻĻā§āĻ°ā§āĻā§āĻ¯ āĻāĻ¤?
- 0.5 mm
- 0.2 mm
- \(10^{-7} \mathrm{~m}\)
- \(10^{-7} \mathrm{~nm}\)
Ans. \(10^{-7} \mathrm{~m}\)
- āĻšāĻžāĻāĻĄā§āĻ°ā§āĻā§āĻ¨ āĻĒāĻ°āĻŽāĻžāĻŖā§āĻ° āĻĒā§āĻ°āĻĨāĻŽ āĻŦāĻžā§āĻ° āĻāĻā§āĻˇā§ āĻāĻ¨ā§āĻ¤ā§āĻ°ā§āĻ¨ā§āĻ° āĻŽāĻžā§āĻāĻļāĻā§āĻ¤āĻŋ -13.6 eV āĻšāĻ˛ā§, āĻ¤ā§āĻ¤ā§āĻ¯āĻŧ āĻŦāĻžā§āĻ° āĻāĻā§āĻˇā§ āĻŽāĻžā§āĻāĻļāĻā§āĻ¤āĻŋ āĻšāĻŦā§-
- -40.8 eV
- – 4.5 eV
- â 3.4 eV
- – 1.5 eV
Ans. – 1.5 eV
Chemistry
-
āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨āĻāĻŋ āĻŦāĻžāĻĢāĻžāĻ° āĻĻā§āĻ°āĻŦāĻŖ?
- \(\mathrm{CH}_{3} \mathrm{COOH} \& \mathrm{NaOH}\)
- \(\mathrm{CH}_{3} \mathrm{COOH} \& \mathrm{CH}_{3} \mathrm{COONa}\)
- \(\mathrm{NaOH} \& \mathrm{Na}_{2} \mathrm{CO}_{2}\)
- HCI & NaCl
Ans. \(\mathrm{CH}_{3} \mathrm{COOH} \& \mathrm{CH}_{3} \mathrm{COONa}\)
- āĻāĻˇā§āĻāĻŋāĻ āĻ¸āĻžā§āĻĄāĻž āĻĻā§āĻ°āĻŦāĻŖā§āĻ° āĻĒā§āĻ°āĻ¤āĻŋ āĻ˛āĻŋāĻāĻžāĻ°ā§ 5 āĻā§āĻ°āĻžāĻŽ NaOH āĻĨāĻžāĻāĻ˛ā§ āĻĻā§āĻ°āĻŦāĻŖāĻāĻŋāĻ° āĻŽāĻžā§āĻ˛āĻžāĻ°āĻŋāĻāĻŋ āĻāĻ¤?
- 1.25 M
- 12.5 M
- 0.125 M
- 1.52 M
Ans. 0.125 M
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨ āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻžāĻ¯āĻŧ āĻāĻžāĻĒ āĻŦā§āĻĻā§āĻ§āĻŋāĻ° āĻĢāĻ˛ā§ āĻ¸āĻžāĻŽā§āĻ¯āĻžāĻŦāĻ¸ā§āĻĨāĻžāĻ¯āĻŧ āĻā§āĻĒāĻžāĻĻāĻ¨ā§āĻ° āĻĒāĻ°āĻŋāĻŽāĻžāĻŖ āĻŦā§āĻĻā§āĻ§āĻŋ āĻĒāĻžāĻ¯āĻŧ?
- \(\mathrm{H}_{2}(\mathrm{~g})+\mathrm{Br}_{2}(\mathrm{~g})=2 \mathrm{HBr}(\mathrm{g})\)
- \(2 \mathrm{NO}_{2}(\mathrm{~g})+7 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g})+4 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\)
- \(\mathrm{C} \mathrm{O}_{2}(\mathrm{~g})+\mathrm{C}(\mathrm{s}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g})\)
- \(\mathrm{CaCO}_{3}(\mathrm{~s}) \rightleftharpoons \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g})\)
Ans. \(2 \mathrm{NO}_{2}(\mathrm{~g})+7 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g})+4 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})\)
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨ āĻāĻ˛ā§āĻāĻā§āĻ°ā§āĻĄāĻāĻŋāĻ° āĻĒā§āĻ°āĻŽāĻžāĻŖ āĻŦāĻŋāĻāĻžāĻ°āĻŖ āĻĒāĻā§āĻ¨āĻļāĻŋāĻ¯āĻŧāĻžāĻ˛ āĻ¸āĻ°ā§āĻŦā§āĻā§āĻ?
- \(\mathrm{H}^{+}(\mathrm{aq}) / \mathrm{H}_{2}(\mathrm{~g}), \mathrm{Pt}\)
- \(\mathrm{Cu}^{2+}(\mathrm{aq}) / \mathrm{Cu}(\mathrm{s})\)
- \(\mathrm{Na}^{+}(\mathrm{aq}) / \mathrm{Na}(\mathrm{s})\)
- \(\mathrm{Pt} / \mathrm{F}_{2}(\mathrm{~g}) / \mathrm{F}^{-}(\mathrm{aq})\)
Ans.\(\mathrm{Pt} / \mathrm{F}_{2}(\mathrm{~g}) / \mathrm{F}^{-}(\mathrm{aq})\)
- āĻāĻžāĻĒ āĻ¸ā§āĻĨāĻŋāĻ° āĻ°ā§āĻā§ āĻāĻāĻāĻŋ āĻā§āĻ¯āĻžāĻ¸ā§āĻ° (āĻāĻ¯āĻŧāĻ¤āĻ¨ \(\left.1000 \mathrm{~cm}^{3}\right)\) āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻž āĻ
āĻ°ā§āĻ§ā§āĻ āĻāĻ°āĻž āĻšāĻ˛āĨ¤ āĻĒāĻ°āĻŋāĻŦāĻ°ā§āĻ¤āĻŋāĻ¤ āĻ
āĻŦāĻ¸ā§āĻĨāĻžāĻ¯āĻŧ āĻāĻšāĻžāĻ° āĻāĻ¯āĻŧāĻ¤āĻ¨ āĻāĻ¤ āĻšāĻŦā§?
- \(2000 \mathrm{~cm}^{3}\)
- \(500 \mathrm{~cm}^{3}\)
- \(1000 \mathrm{~cm}^{3}\)
- \(1500 \mathrm{~cm}^{3}\)
Ans. \(500 \mathrm{~cm}^{3}\)
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨ āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻžāĻāĻŋāĻ° \(\mathbf{K}_{\mathbf{p}}=\mathbf{K}_{\mathbf{c}} ?\)
- \(\mathrm{PCl}_{5}(\mathrm{~g}) \rightleftharpoons \mathrm{PCl}_{3}(\mathrm{~g})+\mathrm{Cl}_{2}(\mathrm{~g})\)
- \(\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g})\)
- \(2 \mathrm{HI}(\mathrm{g}) \rightleftharpoons \mathrm{H}_{2}(\mathrm{~g})+\mathrm{I}_{2}(\mathrm{~g})\)
- \(\mathrm{CO}(\mathrm{g})+2 \mathrm{H}_{2}(\mathrm{~g})=\mathrm{CH}_{3} \mathrm{OH}(\mathrm{g})\)
Ans. \(2 \mathrm{HI}(\mathrm{g}) \rightleftharpoons \mathrm{H}_{2}(\mathrm{~g})+\mathrm{I}_{2}(\mathrm{~g})\)
- āĻāĻāĻāĻŋ āĻĢāĻ˛ā§āĻ° āĻ°āĻ¸ā§ āĻšāĻžāĻāĻĄā§āĻ°ā§āĻā§āĻ¨ āĻāĻ¯āĻŧāĻ¨ā§āĻ° āĻāĻ¨āĻ¤ā§āĻŦ \(3.3 \times 10^{-2} \mathrm{M}\) āĻ āĻ°āĻ¸ā§āĻ° pH āĻāĻ¤?
- 2.00
- 1.48
- 4.48
- 2.18
Ans. 1.48
- āĻāĻĒāĻžāĻ° āĻ¸āĻžāĻ˛āĻĢā§āĻā§āĻ° āĻāĻ˛ā§āĻ¯āĻŧ āĻĻā§āĻ°āĻŦāĻŖā§ 10 ampere āĻŦāĻŋāĻĻā§āĻ¯ā§ā§ 30 āĻŽāĻŋāĻ¨āĻŋāĻ āĻ§āĻ°ā§ āĻāĻžāĻ˛āĻ¨āĻž āĻāĻ°āĻ˛ā§ āĻā§āĻ¯āĻžāĻĨāĻžā§āĻĄā§ āĻāĻŋ āĻĒāĻ°āĻŋāĻŽāĻžāĻŖ āĻāĻĒāĻžāĻ° āĻāĻŽāĻž āĻšāĻŦā§?
- 12.0 g
- 6.0 g
- 3.0 g
- 9.0 g
Ans. 6.0 g
- \(\mathrm{N}_{2}(\mathrm{~g})+3 \mathrm{H}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{NH}_{3}(\mathrm{~g})\) āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻžāĻāĻŋāĻ° \(\mathbf{K}_{\mathbf{p}}\) āĻāĻŦāĻ \(\mathbf{K}_{\mathbf{c}}\) āĻāĻ° āĻŽāĻ§ā§āĻ¯ā§ āĻ¸āĻŽā§āĻĒāĻ°ā§āĻāĻāĻŋ āĻšāĻ˛-
- \(\mathrm{K}_{\mathrm{p}}=\mathrm{K}_{\mathrm{c}}(\mathrm{RT})^{2}\)
- \(K_{p}=K_{c}(R T)^{-2}\)
- \(\mathrm{K}_{\mathrm{p}}=\mathrm{K}_{\mathrm{c}}(\mathrm{RT})^{-1}\)
- \(\mathrm{K}_{\mathrm{p}}=\mathrm{K}_{\mathrm{c}}(\mathrm{RT})\)
Ans. \(K_{p}=K_{c}(R T)^{-2}\)
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨ āĻŦāĻ¸ā§āĻ¤ā§āĻ° āĻāĻŖāĻžāĻā§āĻ˛āĻžā§āĻ° āĻļā§āĻ§ā§āĻŽāĻžāĻ¤ā§āĻ° āĻāĻŽā§āĻĒāĻ¨-āĻāĻ¤āĻŋ āĻ°āĻ¯āĻŧā§āĻā§?
- \(\mathrm{NaCl}(\mathrm{s})\)
- \(\mathrm{H}_{2} \mathrm{O}(\mathrm{l})\)
- \(\mathrm{H}_{2} \mathrm{O}(\mathrm{g})\)
- \(\mathrm{H}_{2}(\mathrm{~g})\)
Ans. \(\mathrm{NaCl}(\mathrm{s})\)
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻ¯ā§āĻāĻā§āĻ˛āĻŋāĻ° āĻŽāĻ§ā§āĻ¯ā§ āĻā§āĻ¨āĻāĻŋ āĻāĻ¯āĻŧāĻ¨āĻŋāĻ āĻŦā§āĻļāĻŋāĻˇā§āĻā§āĻ¯ āĻ¸āĻŦāĻā§āĻ¯āĻŧā§ āĻŦā§āĻļā§?
- \(\mathrm{SiF}_{4}\)
- \(\mathrm{AlCl}_{3}\)
- Nal
- \(\mathrm{CsF}\)
Ans. \(\mathrm{CsF}\)
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻā§āĻ¤ d-āĻŦā§āĻ˛āĻ āĻŽā§āĻ˛āĻ¸āĻŽā§āĻšā§āĻ° āĻā§āĻ¨āĻāĻŋāĻ¤ā§ 4s āĻ
āĻ°āĻŦāĻŋāĻāĻžāĻ˛ā§ 1āĻāĻŋāĨ¤ āĻāĻ˛ā§āĻāĻā§āĻ°āĻ¨ āĻ°āĻ¯āĻŧā§āĻā§?
- Mn(25)
- Fe(26)
- Ni(28)
- Cu(29)
Ans. Cu(29)
- 2p āĻ
āĻ°āĻŦāĻŋāĻāĻžāĻ˛ā§āĻ° n, \(l\) āĻāĻŦāĻ m āĻāĻ° āĻŽāĻžāĻ¨ āĻšāĻā§āĻā§ āĻ¯āĻĨāĻžāĻā§āĻ°āĻŽā§-
- 2,1,2
- 2,1,(-1,0,1)
- 2,2,(-2)
- 1,1,0
Ans. 2,1,(-1,0,1)
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻ¯ā§āĻāĻā§āĻ˛āĻžā§āĻ° āĻā§āĻ¨āĻāĻŋāĻ° āĻā§āĻ¨ā§āĻĻā§āĻ°ā§āĻ¯āĻŧ āĻĒāĻ°āĻŽāĻžāĻŖā§ āĻ
āĻāĻā§āĻā§ āĻ¨āĻŋāĻ¯āĻŧāĻŽ āĻ
āĻ¨ā§āĻ¸āĻ°āĻŖ āĻāĻ°ā§ āĻ¨āĻž?
- \(\mathrm{CCl}_{4}\)
- \(\mathrm{XeF}_{2}\)
- \(\mathrm{H}_{2} \mathrm{O}\)
- \(\mathrm{NF}_{3}\)
Ans. \(\mathrm{XeF}_{2}\)
- āĻā§āĻ¨ āĻāĻ˛ā§āĻāĻā§āĻ°āĻ¨āĻŋāĻ āĻ¸ā§āĻĨāĻžāĻ¨āĻžāĻ¨ā§āĻ¤āĻ°ā§āĻ° āĻĢāĻ˛ā§ āĻšāĻžāĻāĻĄā§āĻ°ā§āĻā§āĻ¨ āĻŦāĻ°ā§āĻŖāĻžāĻ˛ā§āĻ°āĨ¤ âāĻŦāĻžāĻŽāĻžāĻ°â āĻ¸āĻŋāĻ°āĻŋāĻā§āĻ° \(4^{\text {th }}\) āĻ˛āĻžāĻāĻ¨ā§āĻ° āĻ¸ā§āĻˇā§āĻāĻŋ āĻšāĻ¯āĻŧ?
- n = 6 to n = 2
- n = 5 to n = 2
- n = 4 to n = 1
- n = 4 to n =0
Ans. n = 6 to n = 2
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨āĻāĻŋ āĻāĻžāĻ°āĻŖ-āĻŦāĻŋāĻāĻžāĻ°āĻŖ āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻž āĻ¨āĻ¯āĻŧ?
- \(\mathrm{H}_{2} \mathrm{~S}+\mathrm{Cl}_{2} \rightarrow 2 \mathrm{HCl}+\mathrm{S}\)
- \(\mathrm{CuSO}_{4}+2 \mathrm{NH}_{4} \mathrm{OH} \rightarrow \mathrm{Cu}(\mathrm{OH})_{2}+\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}\)
- \(4 \mathrm{HCl}+\mathrm{MnO}_{2} \rightarrow \mathrm{Cl}_{2}+\mathrm{MnCl}_{2}+2 \mathrm{H}_{2} \mathrm{O}\)
- \(2 \mathrm{H}_{2} \mathrm{O}+2 \mathrm{Cl}_{2} \rightarrow 4 \mathrm{HCl}+\mathrm{O}_{2}\)
Ans. \(\mathrm{CuSO}_{4}+2 \mathrm{NH}_{4} \mathrm{OH} \rightarrow \mathrm{Cu}(\mathrm{OH})_{2}+\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}\)
- \(8.0 \mathrm{~cm}^{3} \mathrm{Na}_{2} \mathrm{CO}_{3}\) āĻāĻ° āĻĻā§āĻ°āĻŦāĻŖāĻā§ āĻ¸āĻŽā§āĻĒā§āĻ°ā§āĻŖāĻ°ā§āĻĒā§ āĻĒā§āĻ°āĻļāĻŽāĻ¨ āĻāĻ°āĻ¤ā§ 10.0 cm 1.0 M HCl āĻĻā§āĻ°āĻŦāĻŖā§āĻ° āĻĒā§āĻ°āĻ¯āĻŧāĻžā§āĻāĻ¨ āĻšāĻ¯āĻŧāĨ¤ \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) āĻĻā§āĻ°āĻŦāĻŖāĻāĻŋāĻ° āĻāĻ¨āĻŽāĻžāĻ¤ā§āĻ°āĻž āĻšāĻā§āĻā§-
- 0.625 M
- 1.0 M
- 0.025 M
- 0.6 M
Ans. 0.625 M
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨ āĻ¸ā§āĻā§āĻ° āĻ§āĻžāĻ¤ā§āĻā§āĻ˛āĻŋ āĻ¸ā§āĻā§āĻāĻ¨āĻ˛ā§āĻ¸ āĻ¸ā§āĻā§āĻ˛ā§ āĻŦāĻŋāĻĻā§āĻ¯āĻŽāĻžāĻ¨?
- Fe, Cr & Ni
- Fe, Cr & Cu
- Cu, Zn & Ni
- Cu, Sn & Pb
Ans. Fe, Cr & Ni
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨ āĻ
āĻŖā§āĻāĻŋāĻ° āĻ¸āĻŦāĻā§āĻ˛āĻžā§ āĻĒāĻ°āĻŽāĻžāĻŖā§ āĻāĻāĻ āĻ¸āĻŽāĻ¤āĻ˛ā§ āĻ¨āĻ¯āĻŧ?
- \(\mathrm{BCl}_{3}\)
- \(\mathrm{PF}_{3}\)
- \(\mathrm{AlCl}_{3}\)
- \(\mathrm{C}_{6} \mathrm{H}_{6}\)
Ans. \(\mathrm{PF}_{3}\)
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨āĻāĻŋ āĻĨā§āĻā§ āĻāĻāĻāĻŋ āĻāĻ˛ā§āĻāĻā§āĻ°āĻ¨ āĻ
āĻĒāĻ¸āĻžāĻ°āĻŖā§āĻ° āĻāĻ¨ā§āĻ¯ā§ āĻ¸āĻŦāĻā§āĻ¯āĻŧā§ āĻŦā§āĻļāĻŋ āĻļāĻā§āĻ¤āĻŋ āĻĒā§āĻ°āĻ¯āĻŧāĻžā§āĻāĻ¨?
- Ar
- \(\mathrm{Al}^{3+}\)
- \(\mathrm{Na}^{+}\)
- \(\mathrm{Cl}^{-}\)
Ans. \(\mathrm{Al}^{3+}\)
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻžāĻ¯āĻŧ āĻāĻĒāĻžāĻĻāĻžāĻ¨ P āĻāĻŦāĻ Q āĻā§āĻ¨ āĻ¸ā§āĻā§ āĻŦāĻŋāĻĻā§āĻ¯āĻŽāĻžāĻ¨? \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}(\mathrm{OH}) \mathrm{CH}_{3} \stackrel{\mathrm{I}_{2} / \mathrm{OH}^{-}}{\rightarrow} \mathrm{P}_{(\mathrm{aq})}+\mathrm{Q}_{(\mathrm{s})}\)
- \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{3} ; \mathrm{CH}_{4}\) respectively
- \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COO} ; \mathrm{CHI}_{3}\) respectively
- \(\mathrm{CH}_{3} \mathrm{CH}_{3} ; \mathrm{CH}_{3} \mathrm{CH}_{3}\) respectively
- \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3} ; \mathrm{I}_{2}\) respectively
Ans. \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COO} ; \mathrm{CHI}_{3}\) respectively
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻžāĻ° āĻŽā§āĻ˛ āĻā§āĻĒāĻžāĻĻ āĻāĻŋ?
Ans.
-
- \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) āĻāĻžāĻ°āĻŋāĻ¤ āĻšāĻ¯āĻŧā§ âZâ āĻā§āĻĒāĻ¨ā§āĻ¨ āĻāĻ°ā§ āĻ¯āĻž \(\mathbf{C}_{2} \mathbf{H}_{5} \mathbf{O H}\) āĻāĻ°
āĻ¸āĻžāĻĨā§ āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻž āĻāĻ°ā§ āĻāĻˇā§āĻāĻžāĻ° āĻ¤ā§āĻ°ā§ āĻāĻ°ā§āĨ¤ Z āĻāĻŋ?- HCOOH
- \(\mathrm{CH}_{3} \mathrm{COOH}\)
- \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH}\)
- \(\mathrm{CH}_{3} \mathrm{COOC}_{2} \mathrm{H}_{5}\)
Ans. \(\mathrm{CH}_{3} \mathrm{COOH}\)
- āĻā§āĻ°āĻŋāĻāĻ¨āĻžāĻ°ā§āĻĄ āĻŦāĻŋāĻāĻžāĻ°āĻā§āĻ° āĻ¸āĻžāĻĨā§ \(\mathrm{CH}_{3} \mathrm{OH}\) āĻāĻ° āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻžāĻ¯āĻŧ āĻāĻŋ āĻšāĻ¯āĻŧ?
- Alkane
- Ether
- Esters
- Aldehyde
Ans. Alkane
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻŽā§āĻā§āĻ¤ āĻļāĻŋāĻāĻ˛ āĻ¯ā§āĻāĻā§āĻ˛āĻŋāĻ° āĻā§āĻ¨āĻāĻŋāĻ¤ā§ āĻ¸āĻŦāĻā§āĻ˛āĻžā§ āĻŦāĻ¨ā§āĻ§āĻ¨āĻ \(\sigma\)(āĻ¸āĻŋāĻāĻŽāĻž)?
- \(\mathrm{C}_{10} \mathrm{H}_{20}\)
- \(\mathrm{C}_{10} \mathrm{H}_{22}\)
- \(\mathrm{C}_{10} \mathrm{H}_{18}\)
- \(\mathrm{C}_{10} \mathrm{H}_{20} \mathrm{O}\)
Ans. \(\mathrm{C}_{10} \mathrm{H}_{22}\)
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨ āĻ¯ā§āĻāĻāĻŋāĻ° āĻāĻāĻāĻŋ āĻŦāĻ¨ā§āĻ§āĻ¨ \(\mathrm{sp}^{3}-\mathrm{sp}\) āĻšāĻžāĻāĻŦā§āĻ°āĻŋāĻĄ āĻ
āĻ°āĻŦāĻŋāĻāĻžāĻ˛ā§āĻ° āĻ
āĻ§āĻŋāĻā§āĻ°āĻŽāĻ¨ā§āĻ° āĻĢāĻ˛ā§ āĻ¸ā§āĻˇā§āĻāĻŋ āĻšāĻ¯āĻŧā§āĻā§?
- \(\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{C}-\mathrm{H}\)
- \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CHCH}_{3}\)
- \(\mathrm{H}-\mathrm{C} \equiv \mathrm{C}-\mathrm{H}\)
- \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\)
Ans. \(\mathrm{CH}_{3}-\mathrm{C} \equiv \mathrm{C}-\mathrm{H}\)
- \(\mathrm{RCOR} \rightarrow \mathrm{RCH}_{2} \mathrm{R}\) āĻ°āĻžāĻ¸āĻžāĻ¯āĻŧāĻ¨āĻŋāĻ āĻĒāĻ°āĻŋāĻŦāĻ°ā§āĻ¤āĻ¨ā§āĻ° āĻāĻ¨ā§āĻ¯ āĻā§āĻ¨ āĻŦāĻŋāĻāĻžāĻ°āĻāĻāĻŋ āĻĒā§āĻ°āĻ¯āĻŧāĻžā§āĻāĻ¨?
- \(\mathrm{H}_{2} \mathrm{SO}_{4}\)
- \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\)
- \(\mathrm{NaBH}_{4}\)
- \(\mathrm{Zn} / \mathrm{Hg}\). conc \(\mathrm{HCl}\)
Ans. \(\mathrm{Zn} / \mathrm{Hg}\). conc \(\mathrm{HCl}\)
- \(\mathrm{R}-\mathrm{CO}-\mathrm{R} \stackrel{\mathrm{Zn} / \mathrm{Hg}, \text { conc } \mathrm{HCl}}{\longrightarrow} \mathrm{R}-\mathrm{CH}_{2}-\mathrm{R}\) āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻ¯ā§āĻāĻā§āĻ˛āĻžā§āĻ° āĻŽāĻ§ā§āĻ¯ā§ āĻ¸āĻŦāĻā§āĻ¯āĻŧā§ āĻŦā§āĻļā§ āĻ
āĻŽā§āĻ˛ā§ā§ āĻšāĻ˛-
- \(\mathrm{Cl}_{3} \mathrm{CCOOH}\)
- \(\mathrm{Cl}_{2} \mathrm{CHCOOH}\)
- \(\mathrm{ClCH}_{2} \mathrm{COOH}\)
- \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}-\mathrm{COOH}\)
Ans. \(\mathrm{Cl}_{3} \mathrm{CCOOH}\)
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨āĻāĻŋ āĻā§āĻ¯āĻžāĻŽāĻŋāĻ¤āĻŋāĻ āĻ¸āĻŽāĻžāĻŖā§āĻ¤āĻž āĻĒā§āĻ°āĻĻāĻ°ā§āĻļāĻ¨ āĻāĻ°ā§?
- \(\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{CH}_{3}\)
- \(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{COOH}\)
- \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3}\)
- \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}=\mathrm{CH}_{2}\)
Ans. \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{3}\)
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻ° āĻā§āĻ¨āĻāĻŋ āĻāĻāĻ¨ā§āĻāĻ°āĻŖ āĻ āĻāĻ°ā§āĻĻā§āĻ° āĻŦāĻŋāĻļā§āĻ˛ā§āĻˇāĻŖā§āĻ° āĻĢāĻ˛ā§ āĻļā§āĻ§ā§āĻŽāĻžāĻ¤ā§āĻ° āĻāĻāĻāĻŋ āĻā§āĻĒāĻžāĻĻ āĻĻā§āĻŦā§?
- \(\mathrm{CH}_{3} \mathrm{C}\left(\mathrm{CH}_{3}\right)=\mathrm{C}\left(\mathrm{CH}_{3}\right)-\mathrm{CH}_{3}\)
- \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}-\mathrm{CH}\left(\mathrm{CH}_{3}\right)-\mathrm{CH}_{3}\)
- \(\mathrm{CH}_{3} \mathrm{C}\left(\mathrm{CH}_{3}\right)=\mathrm{CH}-\mathrm{CH}_{2}-\mathrm{CH}_{3}\)
- \(\mathrm{CH}_{2}=\mathrm{CH}\left(\mathrm{CH}_{3}\right)-\mathrm{CH}\left(\mathrm{CH}_{3}\right)-\mathrm{CH}_{3}\)
Ans. \(\mathrm{CH}_{3} \mathrm{C}\left(\mathrm{CH}_{3}\right)=\mathrm{C}\left(\mathrm{CH}_{3}\right)-\mathrm{CH}_{3}\)
Mathematics
-
\(|7-3 x| \leq 5\) āĻ āĻ¸āĻŽāĻ¤āĻžāĻāĻŋāĻ° āĻ¸āĻŽāĻžāĻ§āĻžāĻ¨-
- \(\frac{-5}{3} \leq x \leq \frac{7}{3}\)
- \(\frac{2}{3} \leq x \leq 4\)
- \(x \leq \frac{-5}{3}\)
- \(x \geq \frac{-7}{3}\) or \(x \leq \frac{-5}{3}\)
Ans. \(\frac{2}{3} \leq x \leq 4\)
- \(f(x)=\frac{3+x}{1-2 x}\) āĻšāĻ˛ā§, \(\mathbf{f}^{-1}(\mathbf{x})=?\)
- \(\frac{x-3}{2 x+1}\)
- \(\frac{3-x}{1+2 x}\)
- \(\frac{x+3}{2+x}\)
- \(\frac{x+3}{2 x+1}\)
Ans. \(\frac{x-3}{2 x+1}\)
- (1, 4) āĻāĻŦāĻ (9, -12) āĻŦāĻŋāĻ¨ā§āĻĻā§āĻĻā§āĻŦāĻ¯āĻŧā§āĻ° āĻ¸āĻāĻ¯āĻžā§āĻāĻāĻžāĻ°ā§ āĻ°ā§āĻāĻžāĻāĻļ āĻ
āĻ¨ā§āĻ¤āĻāĻ¸ā§āĻĨāĻāĻžāĻŦā§ āĻ¯ā§ āĻŦāĻŋāĻ¨ā§āĻĻā§āĻ¤ā§ 5:3 āĻ
āĻ¨ā§āĻĒāĻžāĻ¤ā§ āĻŦāĻŋāĻāĻā§āĻ¤ āĻšāĻ¯āĻŧ āĻ¤āĻžāĻ° āĻ¸ā§āĻĨāĻžāĻ¨āĻžāĻā§āĻ-
- (6, – 6)
- (3, 5)
- (2, 1)
- (- 6, 5)
Ans. (6, – 6)
- \(x^{2}-3 x+5\) āĻāĻ° āĻ¨ā§āĻ¯ā§āĻ¨āĻ¤āĻŽ āĻŽāĻžāĻ¨-
- 3
- 5
- \(\frac{15}{4}\)
- \(\frac{11}{4}\)
Ans. \(\frac{11}{4}\)
- \(\cos ^{2} 30^{\circ}+\cos ^{2} 60^{\circ}+\ldots \ldots+\cos ^{2} 180^{\circ}\) āĻāĻ° āĻŽāĻžāĻ¨-
- 0
- 2
- 3
- 4
Ans. 3
- \(\alpha\) āĻ¸ā§āĻā§āĻˇā§āĻŽāĻā§āĻŖ āĻšāĻ˛ā§, \(x \cos \alpha+\operatorname{ysin} \alpha=4\) āĻāĻŦāĻ 4x + 3y = 5 āĻ¸āĻŽāĻžāĻ¨ā§āĻ¤āĻ°āĻžāĻ˛ āĻ°ā§āĻāĻžāĻĻā§āĻŦāĻ¯āĻŧā§āĻ° āĻĻā§āĻ°āĻ¤ā§āĻŦ-
- -1 unit
- 3 units
- 1 unit
- 9 units
Ans. 3 units
- \(\overrightarrow{\mathbf{F}}_{1}\) āĻāĻŦāĻ \(\overrightarrow{\mathbf{F}}_{2}\) āĻŦāĻ˛ āĻĻā§āĻāĻāĻŋāĻ° āĻ˛āĻŦā§āĻ§āĻŋ \(\overrightarrow{\mathbf{F}}_{3}\); āĻ¯ā§āĻāĻžāĻ¨ā§ \(\overrightarrow{\mathbf{F}}_{1}=2 \hat{\mathbf{i}}-3 \hat{\mathbf{j}}\), \(\overrightarrow{\mathbf{F}}_{3}=\mathbf{5} \hat{\mathbf{i}}+4 \hat{\mathbf{j}}\) āĻšāĻ˛ā§ \(\overrightarrow{\mathbf{F}}_{2}=?\)
- \(-3 \hat{\mathrm{i}}-7 \hat{\mathrm{j}}\)
- \(7 \hat{\mathrm{i}}+\hat{\mathrm{j}}\)
- \(7 \hat{\mathrm{i}}+7 \hat{\mathrm{j}}\)
- \(3 \hat{\mathrm{i}}+7 \hat{\mathrm{j}}\)
Ans. \(3 \hat{\mathrm{i}}+7 \hat{\mathrm{j}}\)
- \(\underset {x \rightarrow 0} {\overset { } {\mathrm lim} } \frac{\left(e^{x}-e^{-x}\right)}{2 x}\)āĻāĻ° āĻŽāĻžāĻ¨-
- 0
- 1
- \(\frac{1}{2}\)
- Does not exist
Ans. 1
- āĻ¯āĻĻāĻŋ \(\cos A=\frac{4}{5}\) āĻšā§, āĻ¤āĻŦā§ \(\frac{1+\tan ^{2} A}{1-\tan ^{2} A}\) āĻāĻ° āĻŽāĻžāĻ¨-
- \(\frac{-25}{7}\)
- \(\frac{7}{5}\)
- \(\frac{25}{7}\)
- \(\frac{-7}{5}\)
Ans. \(\frac{25}{7}\)
- āĻ¯āĻĻāĻŋ \(f(x)=x^{2}-2|x|\) āĻāĻŦāĻ \(\mathbf{g}(\mathbf{x})=\mathbf{x}^{2}+1\) āĻšāĻ¯āĻŧ, āĻ¤āĻŦā§ g(f(2)) āĻāĻ° āĻŽāĻžāĻ¨-
- 0
- 65
- 5
- 1
Ans. 1
- (2,2-2x), (1,2) āĻāĻŦāĻ (2, b – 2x) āĻŦāĻŋāĻ¨ā§āĻĻā§āĻā§āĻ˛āĻžā§ āĻ¸āĻŽāĻ°ā§āĻ āĻšāĻ˛ā§, b āĻāĻ° āĻŽāĻžāĻ¨-
- -1
- 1
- 2
- -2
Ans. 2
- āĻ¯āĻĻāĻŋ \(A=\left(\begin{array}{ll}1 & 2 \\ 3 & 4\end{array}\right)\) āĻšāĻ¯āĻŧ āĻ¤āĻŦā§ \(\mathbf{A}^{-1}=?\)
- \(\frac{1}{2}\left(\begin{array}{cc}4 & -3 \\ -2 & 1\end{array}\right)\)
- \(\frac{1}{2}\left(\begin{array}{cc}4 & -2 \\ -3 & 1\end{array}\right)\)
- \(-\frac{1}{2}\left(\begin{array}{cc}4 & -3 \\ -2 & 1\end{array}\right)\)
- \(-\frac{1}{2}\left(\begin{array}{cc}4 & -2 \\ -3 & 1\end{array}\right)\)
Ans. \(-\frac{1}{2}\left(\begin{array}{cc}4 & -2 \\ -3 & 1\end{array}\right)\)
- 2(cosx + secx) = 5 āĻ¸āĻŽā§āĻāĻ°āĻŖā§āĻ° āĻ¸āĻžāĻ§āĻžāĻ°āĻŖ āĻ¸āĻŽāĻžāĻ§āĻžāĻ¨-
- \(\mathrm{n} \pi \pm \frac{\pi}{3}\)
- \(2 n \pi \pm \frac{\pi}{3}\)
- \(2 n \pi \pm \frac{\pi}{6}\)
- \(\mathrm{n} \pi \pm \frac{\pi}{6}\)
Ans. \(2 n \pi \pm \frac{\pi}{3}\)
- (4,2) āĻŦāĻŋāĻ¨ā§āĻĻā§ āĻĨā§āĻā§ 5x+12y=3 āĻ°ā§āĻāĻžāĻ° āĻāĻĒāĻ° āĻ
āĻā§āĻāĻŋāĻ¤ āĻ˛āĻŽā§āĻŦā§āĻ° āĻĻā§āĻ°ā§āĻā§āĻ¯-
- \(-\frac{7}{13}\)
- \(\frac{8}{9}\)
- \(-\frac{8}{9}\)
- \(\frac{7}{13}\)
Ans. \(\frac{7}{13}\)
- \(\int_{0}^{\frac{\pi}{2}} \sqrt{1+\sin \theta} d \theta\) āĻāĻ° āĻŽāĻžāĻ¨-
- \(\sqrt{2}\)
- 2
- \(\pi\)
- \(\frac{\pi}{2}\)
Ans. 2
- 1 āĻĨā§āĻā§ 520 āĻĒāĻ°ā§āĻ¯āĻ¨ā§āĻ¤ āĻ¸āĻāĻā§āĻ¯āĻžāĻā§āĻ˛āĻžā§ āĻĨā§āĻā§ āĻĻā§āĻŦāĻāĻ¯āĻŧāĻ¨ āĻĒāĻĻā§āĻ§āĻ¤āĻŋāĻ¤ā§ āĻāĻāĻāĻŋ āĻ¸āĻāĻā§āĻ¯āĻž āĻāĻ¯āĻŧāĻ¨ āĻāĻ°āĻž āĻšāĻ˛ā§ āĻ¸āĻāĻā§āĻ¯āĻžāĻāĻŋ āĻāĻ¨āĻ¸āĻāĻā§āĻ¯āĻž āĻšāĻāĻ¯āĻŧāĻžāĻ° āĻ¸āĻŽā§āĻāĻžāĻŦāĻ¨āĻž-
- \(\frac{1}{64}\)
- \(\frac{1}{60}\)
- \(\frac{1}{65}\)
- \(\frac{2}{65}\)
Ans. \(\frac{1}{65}\)
- āĻā§āĻ¨ āĻŦāĻŋāĻ¨ā§āĻĻā§āĻ¤ā§ āĻĻā§āĻāĻāĻŋ āĻŦāĻ˛ 120° āĻā§āĻŖā§ āĻā§āĻ°āĻŋāĻ¯āĻŧāĻžāĻļā§āĻ˛āĨ¤ āĻŦā§āĻšāĻ¤ā§āĻ¤āĻ° āĻŦāĻ˛āĻāĻŋāĻ° āĻŽāĻžāĻ¨ 10N āĻāĻŦāĻ āĻ¤āĻžāĻĻā§āĻ° āĻ˛āĻŦā§āĻ§āĻŋ āĻā§āĻˇā§āĻĻā§āĻ°āĻ¤āĻ° āĻŦāĻ˛ā§āĻ° āĻ¸āĻžāĻĨā§ āĻ¸āĻŽāĻā§āĻŖ āĻā§āĻĒāĻ¨ā§āĻ¨ āĻāĻ°āĻ˛ā§ āĻā§āĻˇā§āĻĻā§āĻ°āĻ¤āĻ° āĻŦāĻ˛ā§āĻ° āĻŽāĻžāĻ¨-
- 4N
- 5N
- 6N
- 8N
Ans. 5N
- \(\left(x^{2}+\frac{2}{x}\right)^{6}\) āĻāĻ° āĻ¸āĻŽā§āĻĒā§āĻ°āĻ¸āĻžāĻ°āĻŖā§ x āĻŽā§āĻā§āĻ¤ āĻĒāĻĻāĻāĻŋ-
- 448
- 120
- 240
- 3000
Ans. 240
- \(\tan ^{-1} 1+\tan ^{-1} 2+\tan ^{-1} 3\) āĻāĻ° āĻŽāĻžāĻ¨-
- 0
- \(\frac{\pi}{2}\)
- \(\pi\)
- \(2 \pi\)
Ans.\(\pi\)
- \(\mathbf{x y}+\mathbf{x}^{2} \mathbf{y}^{2}-\mathbf{c}=\mathbf{0}\) āĻšāĻ˛ā§, \(\frac{\mathrm{dx}}{\mathrm{dy}}=?\)
- \(-\frac{x}{y}\)
- \(\frac{\mathrm{x}}{\mathrm{y}}\)
- \(\frac{y}{x}\)
- \(-\frac{y}{x}\)
Ans. \(-\frac{x}{y}\)
- \(\int_{0}^{1} \frac{d x}{\sqrt{2 x-x^{2}}}\) āĻāĻ° āĻŽāĻžāĻ¨-
- \(\frac{\pi}{2}\)
- 1
- 0
- \(\frac{\pi}{4}\)
Ans. \(\frac{\pi}{2}\)
- 3x + 2y + k = 0 āĻ°ā§āĻāĻžāĻāĻŋ \(x^{2}+y^{2}-8 x-2 y-4=0\) āĻŦā§āĻ¤ā§āĻ¤āĻā§ āĻ¸ā§āĻĒāĻ°ā§āĻļ āĻāĻ°āĻ˛ā§ k āĻāĻ° āĻāĻāĻāĻŋ āĻŽāĻžāĻ¨-
- 1
- 27
- 5
- -1
Ans. -1
- \(\mathbf{y}=\mathbf{x}^{2}\) āĻāĻŦāĻ \(y=2 x\) āĻĻā§āĻŦāĻžāĻ°āĻž āĻāĻŦāĻĻā§āĻŦāĻž āĻāĻ˛āĻžāĻāĻžāĻ° āĻā§āĻˇā§āĻ¤ā§āĻĢāĻ˛-
- \(\frac{4}{3}\) unit \(^{2}\)
- \(\frac{3}{4}\) unit \(^{2}\)
- 4 unit \(^{2}\)
- 3 unit \(^{2}\)
Ans. \(\frac{4}{3}\) unit \(^{2}\)
- āĻāĻāĻāĻŋ āĻāĻžāĻĄāĻŧā§ āĻ¸ā§āĻĨāĻŋāĻ°āĻžāĻŦāĻ¸ā§āĻĨāĻž āĻšāĻ¤ā§ āĻ¸āĻŽāĻ¤ā§āĻŦāĻ°āĻŖā§ āĻāĻ˛āĻž āĻļā§āĻ°ā§ āĻāĻ°ā§ 5 āĻ¸ā§āĻā§āĻ¨ā§āĻĄā§ 180āĻŽāĻŋ./āĻ¸ā§. āĻāĻ¤āĻŋāĻŦā§āĻ āĻĒā§āĻ°āĻžāĻĒā§āĻ¤ āĻšāĻ˛āĨ¤ āĻāĻžāĻĄāĻŧāĻŋāĻāĻŋāĻ° āĻ¤ā§āĻŦāĻ°āĻŖ-
- \(36 \mathrm{~m} / \mathrm{sec}^{2}\)
- \(32 \mathrm{~m} / \mathrm{sec}^{2}\)
- \(30 \mathrm{~m} / \mathrm{sec}^{2}\)
- \(40 \mathrm{~m} / \mathrm{sec}^{2}\)
Ans. \(36 \mathrm{~m} / \mathrm{sec}^{2}\)
- \(4 \hat{\mathrm{i}}+2 \hat{\mathrm{j}}-3 \hat{\mathrm{k}}\) āĻāĻŦāĻ \(\lambda \hat{\mathrm{i}}-3 \hat{\mathrm{j}}+2 \hat{\mathrm{k}}\) āĻā§āĻā§āĻāĻ°āĻĻā§āĻŦāĻ¯āĻŧ āĻĒāĻ°āĻ¸ā§āĻĒāĻ° āĻ˛āĻŽā§āĻŦ āĻšāĻ˛ā§,\(\lambda\) āĻāĻ° āĻŽāĻžāĻ¨-
- 3
- -1
- 5
- 2
Ans. 3
-
\(x>0, y>0, x+y<6,2 x+y<8\) āĻļāĻ°ā§āĻ¤āĻ¸āĻŽā§āĻš āĻ¸āĻžāĻĒā§āĻā§āĻˇā§ \(z=2 x+y\) āĻ°āĻžāĻļāĻŋāĻāĻŋāĻ° āĻ¸āĻ°ā§āĻŦāĻ¨āĻŋāĻŽā§āĻ¨ āĻŽāĻžāĻ¨-
- 6
- 10
- 12
- 14
Ans. 6
- \(\frac{\mathbf{i}}{1-\frac{1}{1-\frac{1}{i}}}\) āĻāĻ° āĻŽāĻžāĻ¨-
- 1-i
- 1+i
- 2i
- -1+i
Ans.1+i
- āĻĻā§āĻŦāĻŋ-āĻŽāĻŋāĻ āĻ¸āĻāĻā§āĻ¯āĻž 10011010101 āĻāĻ° āĻĻāĻļāĻŽāĻŋāĻā§ āĻĒā§āĻ°āĻāĻžāĻļ-
- 1235
- 1237
- 1241
- 1247
Ans. 1237
- 0.3+ 0.003 + 0.00003 + … āĻ§āĻžāĻ°āĻžāĻāĻŋāĻ° āĻ
āĻ¸ā§āĻŽ āĻĒāĻ°ā§āĻ¯āĻ¨ā§āĻ¤ āĻ¯āĻžā§āĻāĻĢāĻ˛-
- \(\frac{10}{33}\)
- \(\frac{1}{3}\)
- \(\frac{1}{33}\)
- \(\frac{33}{100}\)
Ans.\(\frac{10}{33}\)
- f āĻ¸āĻŽāĻ¤ā§āĻŦāĻ°āĻŖā§ āĻāĻāĻāĻŋ āĻŦā§āĻ˛ā§āĻ¨ āĻāĻ°ā§āĻ§ā§āĻŦā§ āĻāĻ āĻā§āĨ¤ āĻŦā§āĻ˛ā§āĻ¨ā§āĻ° āĻāĻāĻ¨ā§āĻ° āĻāĻ¤ āĻ
āĻāĻļ āĻāĻŽāĻžāĻ¨āĻžā§ āĻšāĻ˛ā§ āĻŦā§āĻ˛ā§āĻ¨āĻāĻŋāĻ° āĻ¤ā§āĻŦāĻ°āĻŖ 2f āĻšāĻŦā§?
- \(\frac{\mathrm{f}}{2 \mathrm{~g}+\mathrm{f}}\)
- \(\frac{\mathrm{f}}{2 \mathrm{~g}-\mathrm{f}}\)
- \(\frac{\mathrm{f}}{\mathrm{g}+2 \mathrm{f}}\)
- \(\frac{\mathrm{f}}{\mathrm{g}-2 \mathrm{f}}\)
Ans. \(\frac{\mathrm{f}}{\mathrm{g}+2 \mathrm{f}}\)
Biology
-
āĻā§āĻ¨āĻāĻŋ āĻŽāĻŋāĻĨāĻžā§āĻā§āĻŦā§ āĻ¨āĻžāĻāĻā§āĻ°ā§āĻā§āĻ¨ āĻāĻŦāĻĻā§āĻ§āĻāĻ°āĻŖā§ āĻ
āĻāĻļ āĻā§āĻ°āĻšāĻŖ āĻāĻ°ā§?
- Xanthomonas
- Rhizobium
- Azotobacter
- Agrobacterium
Ans. Rhizobium
- āĻāĻ¸ā§āĻ āĻ°ā§āĻāĻŋ āĻ¤ā§āĻ°āĻŋāĻ¤ā§ āĻā§āĻ¨ āĻŦā§āĻ¯āĻŦāĻšā§āĻ¤ āĻšāĻ¯āĻŧ?
- āĻ ā§āĻ¯āĻžāĻ˛āĻā§āĻšāĻ˛ āĻ¤ā§āĻ°āĻŋāĻ° āĻāĻ¨ā§āĻ¯
- \(\mathrm{CO}_{2}\) āĻ¤ā§āĻ°āĻŋāĻ° āĻāĻ¨ā§āĻ¯
- \(\mathrm{O}_{2}\) āĻŦā§āĻ¯āĻŦāĻšāĻžāĻ° āĻāĻ°āĻžāĻ° āĻāĻ¨ā§āĻ¯
- āĻāĻŋāĻ¨āĻŋ āĻŦā§āĻ¯āĻŦāĻšāĻžāĻ° āĻāĻ°āĻžāĻ° āĻāĻ¨ā§āĻ¯
Ans. \(\mathrm{CO}_{2}\) āĻ¤ā§āĻ°āĻŋāĻ° āĻāĻ¨ā§āĻ¯
- ‘āĻ°âā§āĻ¯āĻžāĻŽā§āĻ¨ā§āĻāĻž’ āĻā§āĻĨāĻžāĻ¯āĻŧ āĻāĻĒāĻ¸ā§āĻĨāĻŋāĻ¤?
- Marchantia
- Pteris
- Semibarbula
- Selaginella
Ans. Pteris
- āĻŦā§āĻ¯āĻā§āĻ¤āĻŦā§āĻā§ āĻāĻĻā§āĻāĻŋāĻĻā§āĻ° āĻļāĻ¸ā§āĻ¯ āĻāĻŋāĻ°ā§āĻĒ?
- āĻšā§āĻ¯āĻžāĻĒā§āĻ˛āĻ¯āĻŧā§āĻĄ
- āĻĄāĻŋāĻĒā§āĻ˛āĻ¯āĻŧā§āĻĄ
- āĻ ā§āĻ¯āĻžāĻŽāĻĢāĻŋāĻĄāĻŋāĻĒā§āĻ˛āĻ¯āĻŧā§āĻĄ
- āĻā§āĻ°āĻŋāĻĒā§āĻ˛āĻ¯āĻŧā§āĻĄ
Ans. āĻšā§āĻ¯āĻžāĻĒā§āĻ˛āĻ¯āĻŧā§āĻĄ
- āĻā§āĻ˛āĻŋāĻ¸āĻžāĻ°āĻžāĻ¨ā§āĻĄāĻŋāĻšāĻžāĻāĻĄ āĻšāĻā§āĻā§ āĻāĻāĻāĻŋ-
- Tetrose
- Triose
- Ribose
- Pentose
Ans. Triose
- āĻā§āĻ¨āĻāĻŋ āĻāĻāĻāĻŋ āĻāĻžāĻĻā§āĻ¯āĻļā§āĻā§āĻāĻ˛ āĻāĻ° āĻāĻĻāĻžāĻšāĻ°āĻŖ?
- Grass â Nematode â Tiger
- Egg â Larva â Adult
- Flower â Fruit â Seed
- Grass â Antelope â Lion
Ans. Grass â Antelope â Lion
- āĻšā§āĻ¯āĻžāĻ āĻ āĻ¸ā§āĻ˛āĻžāĻ āĻāĻā§āĻ°ā§ C4 āĻāĻĻā§āĻāĻŋāĻĻā§ āĻĒā§āĻ°āĻĨāĻŽ āĻ¸ā§āĻĨāĻžāĻ¯āĻŧā§ āĻĒāĻĻāĻžāĻ°ā§āĻĨ āĻā§āĻ¨āĻāĻŋ?
- āĻŽā§āĻ¯āĻžāĻ˛āĻŋāĻ āĻāĻ¸āĻŋāĻĄ
- āĻ āĻā§āĻ¸āĻžāĻ˛āĻžā§ āĻāĻ¸āĻŋāĻāĻŋāĻ āĻāĻ¸āĻŋāĻĄ
- āĻĒāĻžāĻāĻāĻŋāĻ āĻāĻ¸āĻŋāĻĄ
- āĻĢāĻ¸āĻĢā§āĻā§āĻ˛āĻŋāĻ¸āĻžāĻ°āĻŋāĻ āĻāĻ¸āĻŋāĻĄ
Ans. āĻ āĻā§āĻ¸āĻžāĻ˛āĻžā§ āĻāĻ¸āĻŋāĻāĻŋāĻ āĻāĻ¸āĻŋāĻĄ
- āĻā§āĻ¨ āĻāĻĻā§āĻāĻŋāĻĻ āĻ¸ā§āĻ¨ā§āĻĻāĻ°āĻŦāĻ¨ā§āĻ° āĻŽā§āĻ¯āĻžāĻ¨āĻā§āĻ°ā§āĻ āĻŦāĻ¨ā§ āĻāĻ¨ā§āĻŽā§?
- Nymphaea nouchali
- Aegiceras corniculatum
- Erythrina indica
- Acacia nilotica
Ans. Aegiceras corniculatum
- āĻā§āĻ¨āĻāĻŋāĻ¤ā§ āĻŽā§āĻā§āĻ¤ āĻ¸āĻŽāĻĒāĻžāĻ°ā§āĻļā§āĻŦā§āĻ¯āĻŧ āĻāĻžāĻ¸ā§āĻā§āĻ˛āĻžāĻ° āĻŦāĻžāĻ¨ā§āĻĄāĻ˛ āĻĒāĻžāĻāĻ¯āĻŧāĻž āĻ¯āĻžāĻ¯āĻŧ?
- āĻāĻāĻŦā§āĻāĻĒāĻ¤ā§āĻ°ā§ āĻāĻžāĻŖā§āĻĄā§
- āĻāĻāĻŦā§āĻāĻĒāĻ¤ā§āĻ°ā§ āĻŽā§āĻ˛ā§
- āĻĻā§āĻŦāĻŋāĻŦā§āĻāĻĒāĻ¤ā§āĻ°ā§ āĻāĻžāĻŖā§āĻĄā§
- āĻĻā§āĻŦāĻŋāĻŦā§āĻāĻĒāĻ¤ā§āĻ°ā§ āĻŽā§āĻ˛ā§
Ans. āĻĻā§āĻŦāĻŋāĻŦā§āĻāĻĒāĻ¤ā§āĻ°ā§ āĻāĻžāĻŖā§āĻĄā§
- āĻŽā§āĻ¨ā§āĻĄā§āĻ˛ā§āĻ° ā§§āĻŽ āĻ¸ā§āĻ¤ā§āĻ°ā§āĻ° āĻāĻŋāĻ¨āĻžā§āĻāĻžāĻāĻĒā§āĻ° āĻ
āĻ¨ā§āĻĒāĻžāĻ¤ āĻšāĻā§āĻā§-
- 3:1
- 2:2
- 2:1:1
- 1:2:1
Ans. 1:2:1
- āĻā§āĻ¨ āĻĒāĻ°ā§āĻŦā§āĻ° āĻĒā§āĻ°āĻžāĻŖā§āĻ¤ā§ āĻā§āĻ¯āĻŧāĻžāĻ¨āĻ¨āĻžāĻ¸āĻžāĻāĻāĻ¸ āĻĨāĻžāĻā§-
- Protozoa
- Cnidaria
- Porifera
- Crustacea
Ans. Porifera
- Restriction āĻāĻ¨āĻāĻžāĻāĻŽ āĻāĻ° āĻāĻžāĻ āĻšāĻ˛āĻžā§-
- DNA-āĻā§ āĻā§āĻĻāĻ¨ āĻāĻ°āĻž
- DNA-āĻā§āĻĄāĻŧāĻž āĻ˛āĻžāĻāĻžāĻ¨āĻžā§
- DNA-āĻāĻ° āĻ¸āĻāĻā§āĻ¯āĻž āĻŦā§āĻĻā§āĻ§āĻŋ
- DNA-āĻ āĻāĻžāĻ°ā§āĻ¯āĻāĻ° āĻāĻ°āĻž
Ans. DNA-āĻā§ āĻā§āĻĻāĻ¨ āĻāĻ°āĻž
- āĻā§āĻ¨āĻāĻŋ āĻāĻŋāĻ˛ā§āĻ˛āĻŋ āĻāĻā§āĻāĻžāĻĻāĻŋāĻ¤ āĻā§āĻˇāĻžāĻā§āĻāĻžāĻŖā§ āĻ¨āĻ¯āĻŧ?
- Microtubule
- Lysosome
- Golgi apparatus
- Ribosome
Ans. Microtubule
- āĻ¤āĻŋāĻ¨āĻāĻŋ āĻāĻŋāĻ¨ āĻāĻāĻ āĻšāĻžā§āĻŽāĻžā§āĻ˛āĻžā§āĻāĻžāĻ¸ āĻā§āĻ°ā§āĻŽāĻžā§āĻ¸āĻžā§āĻŽā§ āĻ
āĻŦāĻ¸ā§āĻĨāĻžāĻ¨ āĻāĻ°āĻ˛ā§ āĻāĻŋāĻ¨āĻ¤ā§āĻ°āĻ¯āĻŧāĻā§ āĻŦāĻ˛ā§-
- Epistatic genes
- Alleles
- Linked genes
- Multiple alleles
Ans. Multiple alleles
- āĻā§āĻˇā§āĻĻā§āĻ°āĻžāĻ¨ā§āĻ¤ā§āĻ°ā§āĻ° āĻ¸āĻ°ā§āĻŦāĻŦāĻšāĻŋāĻāĻ¸ā§āĻĨ āĻāĻ˛āĻžāĻ¸ā§āĻ¤āĻ°āĻā§ āĻŦāĻ˛ā§-
- Mucosa
- Muscularis mucosa
- Submucosa
- Serosa
Ans. Serosa
- āĻā§āĻ˛āĻŋāĻĢāĻŋāĻļā§āĻ° āĻ˛āĻžāĻ°ā§āĻāĻžāĻ° āĻ¨āĻžāĻŽ-
- Tornaria
- Ephyra
- Trochophore
- Ammocoete
Ans. Ephyra
- āĻā§āĻ¯āĻžāĻ˛āĻ¸āĻŋāĻ¯āĻŧāĻžāĻŽ āĻŦāĻŋāĻĒāĻžāĻā§ āĻ¸āĻšāĻžāĻ¯āĻŧāĻ¤āĻžāĻāĻžāĻ°ā§ āĻā§āĻ°āĻ¨ā§āĻĨāĻŋ āĻšāĻ˛āĻžā§-
- Parathyroid
- Adrenal
- Pancreas
- Pituitary
Ans. Parathyroid
- āĻā§āĻ¨ āĻ
āĻ¸ā§āĻĨāĻŋāĻ¤ā§ āĻāĻ˛ā§āĻā§āĻ°ā§āĻ¨āĻ¨ āĻĒā§āĻ°āĻ¸ā§āĻ¸ āĻĨāĻžāĻā§?
- Scapula
- Ischium
- Humerus
- Ulna
Ans. Ulna
- āĻŦā§āĻā§āĻā§āĻ° āĻāĻ¨ā§āĻĻā§āĻ°āĻžāĻĢāĻŋāĻ˛āĻā§āĻ°ā§āĻļāĻ¨ āĻĒāĻ°āĻŋāĻāĻžāĻ˛āĻ¨āĻžāĻāĻžāĻ°ā§ āĻ
āĻā§āĻ āĻšāĻ˛āĻžā§-
- LH
- Bowmans’ capsule
- Medulla
- Glomerulus
Ans. Glomerulus
- āĻ
āĻˇā§āĻāĻŽ āĻāĻ°āĻžā§āĻāĻŋāĻ āĻ¸ā§āĻ¨āĻžāĻ¯āĻŧā§āĻā§ āĻŦāĻ˛ā§-
- Vagus
- Auditory
- Facial
- Olfactor
Ans. Auditory
- āĻāĻ āĻāĻžāĻĻā§āĻ¯āĻ¸ā§āĻ¤āĻ° āĻĨā§āĻā§ āĻ
āĻ¨ā§āĻ¯ āĻāĻžāĻĻā§āĻ¯āĻ¸ā§āĻ¤āĻ°ā§ āĻļāĻā§āĻ¤āĻŋ āĻĒā§āĻ°āĻŦāĻžāĻšā§āĻ° āĻ¸āĻ āĻŋāĻ āĻ§āĻžāĻ°āĻŖāĻž āĻĻā§āĻ¯āĻŧ āĻ¯ā§ āĻĒāĻŋāĻ°āĻžāĻŽāĻŋāĻĄ āĻ¤āĻž āĻšāĻ˛ā§-
- Pyramid of biomass
- Pyramid of number
- Pyramid of dry biomass
- Pyramid of energy
Ans. Pyramid of energy
- āĻā§āĻ¯āĻžāĻā§āĻāĻžāĻ°ā§ āĻā§āĻ¨ āĻā§āĻāĻžā§āĻ˛āĻŋāĻ āĻ
āĻā§āĻāĻ˛ā§āĻ° āĻĒā§āĻ°āĻžāĻŖā§?
- Oriental
- Australian
- Ethiopean
- Palaearctic
Ans. Australian
- āĻā§āĻ¨ āĻ°āĻā§āĻ¤āĻā§āĻ°ā§āĻĒ āĻŦāĻšāĻ¨āĻāĻžāĻ°ā§ āĻŦā§āĻ¯āĻā§āĻ¤āĻŋāĻā§ āĻ¸āĻžāĻ°ā§āĻŦāĻāĻ¨ā§āĻ¨ āĻĻāĻžāĻ¤āĻž’ āĻŦāĻ˛āĻž āĻšāĻ¯āĻŧ?
- B
- O
- A
- AB
Ans. O
- āĻ¸āĻā§āĻāĻžāĻā§āĻ°āĻŽāĻžāĻ¨ā§āĻ¯āĻžāĻ¯āĻŧā§ āĻŽāĻ§ā§āĻ¯āĻāĻ°ā§āĻŖā§āĻ° āĻšāĻžāĻĄāĻŧāĻā§āĻ˛āĻžā§ āĻ¯āĻĨāĻžāĻā§āĻ°āĻŽā§-
- Incus, Stapes, Maleus
- Stapes, Incus, Maleus
- Incus, Maleus, Stapes
- Maleus, Incus, Stapes
Ans. Maleus, Incus, Stapes
- āĻāĻāĻā§āĻ¨ā§āĻ¸āĻŋāĻ¸ā§ āĻŽāĻžā§āĻ āĻĒāĻžā§āĻ˛āĻžāĻ° āĻŦāĻĄāĻŋ āĻ¤ā§āĻ°āĻŋ āĻšāĻ¯āĻŧ-
- 1
- 2
- 3
- 4
Ans. 3
- āĻā§āĻˇāĻĒā§āĻ°āĻžāĻā§āĻ° āĻ¸āĻŋāĻ˛āĻŋāĻāĻžāĻ¯ā§āĻā§āĻ¤ āĻāĻŦāĻ āĻāĻĒāĻžāĻāĻŋāĻāĻž āĻāĻĒāĻ¸ā§āĻĨāĻŋāĻ¤ āĻ¯ā§ āĻļā§āĻŦāĻžāĻ˛ā§ āĻ¤āĻžāĻ° āĻ¨āĻžāĻŽ āĻšāĻā§āĻā§-(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- Navicula
- Spirogyra
- Sargassum
- Polysiphonia
Ans. Navicula
- āĻ¤āĻŋāĻ˛ āĻ¤ā§āĻ˛ā§āĻ° āĻā§āĻ¸ āĻšāĻ˛āĻžā§-(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- Glycine max
- Sesamum indicum
- Arachis hypogaea
- Helianthus annuus
Ans. Sesamum indicum
- āĻā§āĻ°ā§āĻ¸āĻŋāĻĢā§āĻ°āĻŋ āĻĒāĻ°āĻŋāĻŦāĻžāĻ°āĻā§āĻā§āĻ¤ āĻāĻĻā§āĻāĻŋāĻĻā§āĻ° āĻ
āĻŽāĻ°āĻžāĻŦāĻŋāĻ¨ā§āĻ¯āĻžāĻ¸ āĻšāĻā§āĻā§(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻĒā§āĻ°āĻžāĻ¨ā§āĻ¤ā§āĻ¯āĻŧ
- āĻŦāĻšā§āĻĒā§āĻ°āĻžāĻ¨ā§āĻ¤ā§āĻ¯āĻŧ
- āĻ āĻā§āĻˇā§āĻ¯āĻŧ
- āĻŽā§āĻ˛ā§āĻ¯āĻŧ
Ans. āĻŦāĻšā§āĻĒā§āĻ°āĻžāĻ¨ā§āĻ¤ā§āĻ¯āĻŧ
- āĻĢā§āĻ˛ āĻšāĻāĻ¯āĻŧāĻž āĻ¸āĻ¤ā§āĻ¤ā§āĻŦā§āĻ āĻā§āĻ¨āĻāĻŋāĻā§ āĻĢāĻ˛ āĻŦāĻ˛ā§ āĻŽāĻ¨ā§ āĻšāĻ¯āĻŧ?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻĄāĻžāĻ˛āĻŋāĻŽ
- āĻāĻ¤āĻž
- āĻĄā§āĻŽā§āĻ°
- āĻāĻžāĻāĻ āĻžāĻ˛
Ans. āĻĄā§āĻŽā§āĻ°
- āĻŽā§āĻŽāĻžāĻāĻŋāĻ° āĻĒāĻžāĻ˛āĻ¨āĻā§ āĻŦāĻ˛āĻž āĻšāĻ¯āĻŧ-(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- Sericulture
- Lac culture
- Apiculture
- Pisciculture
Ans. Apiculture
āĻŦāĻžāĻāĻ˛āĻž
-
āĻāĻāĻžāĻ§āĻŋāĻ āĻāĻĒāĻ¸āĻ°ā§āĻāĻ¯āĻžā§āĻā§ āĻāĻ āĻŋāĻ¤ āĻļāĻŦā§āĻĻ āĻā§āĻ¨āĻāĻŋ?
- āĻ āĻ¨āĻ¤āĻŋāĻŦā§āĻšā§
- āĻĒā§āĻ°āĻŦāĻŋāĻˇā§āĻ
- āĻ āĻŦāĻ˛āĻžā§āĻāĻ¨
- āĻ āĻāĻŖāĻ¤āĻžāĻ¨ā§āĻ¤ā§āĻ°āĻŋāĻ
Ans. āĻ āĻ¨āĻ¤āĻŋāĻŦā§āĻšā§
- âāĻāĻŋāĻŖāĻžāĻā§āĻâ āĻļāĻŦā§āĻĻā§āĻ° āĻ
āĻ°ā§āĻĨ āĻā§?
- āĻāĻāĻāĻŋāĻ˛
- āĻ¤āĻŋāĻ˛
- āĻā§āĻˇāĻ¤
- āĻāĻĄāĻŧāĻž
Ans. āĻāĻĄāĻŧāĻž
- āĻ¸āĻžāĻ§ā§ āĻ āĻāĻ˛āĻŋāĻ¤ āĻ°ā§āĻ¤āĻŋāĻ¤ā§ āĻ
āĻāĻŋāĻ¨ā§āĻ¨āĻ°ā§āĻĒā§ āĻŦā§āĻ¯āĻŦāĻšā§āĻ¤ āĻšāĻ¯āĻŧ-
- āĻ āĻŦā§āĻ¯āĻ¯āĻŧ
- āĻ¸āĻŽā§āĻŦāĻžā§āĻ§āĻ¨ āĻĒāĻĻ
- āĻ¸āĻ°ā§āĻŦāĻ¨āĻžāĻŽ
- āĻā§āĻ°āĻŋāĻ¯āĻŧāĻž
Ans. āĻ¸āĻŽā§āĻŦāĻžā§āĻ§āĻ¨ āĻĒāĻĻ
- âāĻā§āĻ°āĻŋāĻā§āĻ āĻā§āĻ˛ā§â āĻŦāĻžāĻā§āĻ¯ā§āĻ° āĻ¨āĻŋāĻŽā§āĻ¨āĻ°ā§āĻ āĻļāĻŦā§āĻĻā§āĻ° āĻāĻžāĻ°āĻ āĻ āĻŦāĻŋāĻāĻā§āĻ¤āĻŋ-
- āĻāĻ°ā§āĻ¤āĻžāĻ¯āĻŧ āĻļā§āĻ¨ā§āĻ¯
- āĻāĻ°ā§āĻŽā§ āĻļā§āĻ¨ā§āĻ¯
- āĻāĻ°āĻŖā§ āĻļā§āĻ¨ā§āĻ¯
- āĻ āĻ§āĻŋāĻāĻ°āĻŖā§ āĻļā§āĻ¨ā§āĻ¯
Ans. āĻāĻ°ā§āĻŽā§ āĻļā§āĻ¨ā§āĻ¯
- āĻ¸āĻžāĻ§ā§ āĻāĻžāĻˇāĻžāĻ¯āĻŧ āĻ˛āĻŋāĻāĻŋāĻ¤ āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻā§āĻ¤ āĻŦāĻžāĻā§āĻ¯āĻāĻŋāĻ¤ā§ āĻā§āĻ˛ā§āĻ° āĻ¸āĻāĻā§āĻ¯āĻž āĻ¨āĻŋāĻ°ā§āĻŖāĻ¯āĻŧ āĻāĻ° : ‘āĻ
āĻ¨āĻžāĻāĻ¤ āĻāĻŦāĻŋāĻˇā§āĻ¯āĻ¤ā§āĻ° āĻŦāĻŋāĻˇāĻ¯āĻŧ āĻŦāĻŋāĻŦā§āĻāĻ¨āĻž āĻāĻ°ā§ āĻā§āĻŖā§āĻ°āĻž āĻ¯āĻž āĻŦāĻ˛āĻŋāĻ˛ā§āĻ¨, āĻāĻĒāĻ¸ā§āĻĨāĻŋāĻ¤ āĻāĻ¨āĻāĻŖāĻ°āĻž āĻ¤ā§āĻā§āĻˇāĻŖāĻžāĻ¤ āĻ¤āĻžāĻšāĻž āĻ¸āĻŽāĻ°ā§āĻĨāĻ¨ āĻāĻ°āĻŋāĻ˛ā§āĨ¤’
- āĻ¤āĻŋāĻ¨
- āĻāĻžāĻ°
- āĻĒāĻžāĻāĻ
- āĻāĻ¯āĻŧ
Ans. āĻāĻ¯āĻŧ
- âāĻ¤āĻšāĻŦāĻŋāĻ˛â āĻā§āĻ¨ āĻāĻžāĻˇāĻžāĻ° āĻļāĻŦā§āĻĻ?
- āĻāĻ°āĻŦāĻŋ
- āĻ¤ā§āĻ°ā§āĻāĻŋ
- āĻāĻ°ā§āĻĻā§
- āĻĢāĻžāĻ°āĻ¸āĻŋ
Ans.āĻāĻ°āĻŦāĻŋ
- āĻļā§āĻĻā§āĻ§ āĻŦāĻžāĻ¨āĻžāĻ¨ āĻā§āĻ¨āĻāĻŋ?
- āĻĒāĻŋāĻĒāĻŋāĻ˛ā§āĻāĻž
- āĻĒā§āĻĒāĻŋāĻ˛āĻŋāĻāĻž
- āĻĒāĻŋāĻĒāĻŋāĻ˛āĻŋāĻāĻž
- āĻĒāĻŋāĻĒā§āĻ˛āĻŋāĻāĻž
Ans. āĻĒāĻŋāĻĒā§āĻ˛āĻŋāĻāĻž
- āĻļā§āĻĻā§āĻ§ āĻļāĻŦā§āĻĻāĻā§āĻā§āĻ āĻšāĻ˛āĻžā§-
- āĻāĻāĻŋāĻ¤, āĻāĻšā§āĻ¤, āĻāĻ˛, āĻŽāĻšāĻžāĻ°āĻĨ
- āĻāĻāĻŋā§, āĻāĻšāĻ°āĻŋāĻ¤, āĻ¸āĻāĻ˛, āĻ¸āĻšāĻžāĻ°āĻĨā§
- āĻāĻāĻŋā§, āĻāĻšā§āĻ¤, āĻ¸āĻāĻ˛, āĻŽāĻšāĻžāĻ°āĻĨā§
- āĻāĻāĻŋāĻ¤, āĻāĻšāĻ°āĻŋāĻ¤, āĻāĻ˛, āĻŽāĻšāĻžāĻ°āĻĨ
Ans. āĻāĻāĻŋāĻ¤, āĻāĻšā§āĻ¤, āĻāĻ˛, āĻŽāĻšāĻžāĻ°āĻĨ/āĻāĻāĻŋāĻ¤, āĻāĻšāĻ°āĻŋāĻ¤, āĻāĻ˛, āĻŽāĻšāĻžāĻ°āĻĨ
- āĻāĻĒāĻ¸āĻ°ā§āĻāĻāĻžāĻ¤ āĻļāĻŦā§āĻĻ-
- āĻ āĻā§āĻāĻ˛āĻŋ
- āĻ āĻā§āĻā§āĻ°
- āĻ āĻ¨āĻļāĻ¨
- āĻ āĻ¨āĻžāĻāĻžāĻ°
Ans. āĻ āĻ¨āĻžāĻāĻžāĻ°
- āĻ¸āĻĻā§āĻ¯ā§āĻāĻžāĻ¤ āĻļāĻŦā§āĻĻā§āĻ° āĻ¸āĻ¨ā§āĻ§āĻŋāĻŦāĻŋāĻā§āĻā§āĻĻ-
- āĻ¸āĻĻā§āĻ¯ + āĻāĻžāĻ¤
- āĻ¸āĻĻā§āĻ¯āĻ + āĻāĻžāĻ¤
- āĻ¸āĻĻā§āĻ¯āĻž + āĻāĻžāĻ¤
- āĻ¸āĻĻāĻž + āĻāĻžāĻ¤
Ans. āĻ¸āĻĻā§āĻ¯āĻ + āĻāĻžāĻ¤
- ‘Scanner’ āĻŦāĻžā§āĻāĻžāĻ¯āĻŧ-
- āĻ¸ā§āĻā§āĻˇā§āĻŽ āĻĒāĻ°ā§āĻā§āĻˇāĻž āĻ¯āĻ¨ā§āĻ¤ā§āĻ°
- āĻ§āĻžāĻ¨āĻŽāĻžāĻĄāĻŧāĻžāĻ āĻ¯āĻ¨ā§āĻ¤ā§āĻ°
- āĻŽā§āĻĻā§āĻ°āĻŖ āĻ¯āĻ¨ā§āĻ¤ā§āĻ°
- āĻāĻŽā§āĻĒāĻŋāĻāĻāĻžāĻ°
Ans. āĻ¸ā§āĻā§āĻˇā§āĻŽ āĻĒāĻ°ā§āĻā§āĻˇāĻž āĻ¯āĻ¨ā§āĻ¤ā§āĻ°
- ‘āĻ¸āĻā§āĻˇā§āĻ’ āĻāĻ° āĻŦāĻŋāĻĒāĻ°ā§āĻ¤ āĻļāĻŦā§āĻĻ āĻā§?
- āĻĒā§āĻ°āĻā§āĻˇā§āĻ
- āĻ¸ā§āĻŦāĻ¨āĻŋāĻˇā§āĻ
- āĻ¨āĻŋāĻļā§āĻā§āĻˇā§āĻ
- āĻ āĻāĻ°ā§āĻŽāĻŖā§āĻ¯
Ans. āĻ¨āĻŋāĻļā§āĻā§āĻˇā§āĻ
- āĻā§āĻ¨āĻāĻŋ āĻļā§āĻĻā§āĻ§ āĻļāĻŦā§āĻĻ?
- āĻļāĻļā§āĻ°
- āĻļā§āĻŦāĻļā§āĻ°
- āĻļā§āĻŦāĻ¸ā§āĻ°
- āĻļāĻļā§āĻĄāĻŧ
Ans. āĻļā§āĻŦāĻļā§āĻ°
- ‘āĻ˛āĻžā§āĻāĻāĻž āĻĒā§āĻ°āĻžā§ āĻāĻāĻ āĻžāĻ˛āĻāĻžāĻ āĻā§āĻ¯āĻŧā§ āĻĢā§āĻ˛āĻ˛āĨ¤’ āĻ āĻŦāĻžāĻā§āĻ¯ā§ ‘āĻā§āĻ¯āĻŧā§ āĻĢā§āĻ˛āĻ˛’ āĻā§āĻ¨ āĻ§āĻ°āĻ¨ā§āĻ° āĻā§āĻ°āĻŋāĻ¯āĻŧāĻžāĻĒāĻĻ?
- āĻ āĻ¸āĻŽāĻžāĻĒāĻŋāĻāĻž āĻā§āĻ°āĻŋāĻ¯āĻŧāĻž
- āĻ āĻāĻ°ā§āĻ¤ā§āĻ āĻā§āĻ°āĻŋāĻ¯āĻŧāĻž
- āĻ āĻāĻ°ā§āĻŽāĻ āĻā§āĻ°āĻŋāĻ¯āĻŧāĻž
- āĻ¯ā§āĻāĻŋāĻ āĻā§āĻ°āĻŋāĻ¯āĻŧāĻž
Ans. āĻ¯ā§āĻāĻŋāĻ āĻā§āĻ°āĻŋāĻ¯āĻŧāĻž
- āĻĒāĻžāĻ°ā§āĻļā§āĻŦāĻŋāĻ āĻŦā§āĻ¯āĻā§āĻāĻ¨ā§āĻ° āĻāĻĻāĻžāĻšāĻ°āĻŖ āĻā§āĻ¨āĻāĻŋ?
- āĻš
- āĻļ
- āĻ°
- āĻ˛
Ans. āĻ˛
- āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¨āĻāĻŋ ‘āĻā§āĻ’ āĻāĻ° āĻ¸āĻŽāĻžāĻ°ā§āĻĨāĻ āĻļāĻŦā§āĻĻ?
- āĻĒā§āĻ°āĻ¸ā§āĻ¨
- āĻāĻ¯āĻŧāĻžāĻ¸āĻŽāĻŋāĻ¨
- āĻāĻžāĻĢāĻ°āĻžāĻ¨
- āĻŦā§āĻ˛āĻŋ
Ans. āĻŦā§āĻ˛āĻŋ
- ‘āĻ¤ā§āĻŽāĻŋ āĻ¯ā§āĻ¤ā§ āĻĒāĻžāĻ°āĻŦā§ āĻ¨āĻžāĨ¤’ āĻ āĻŦāĻžāĻā§āĻ¯ā§āĻ° āĻ
āĻ¸ā§āĻ¤āĻŋāĻŦāĻžāĻāĻ āĻ°ā§āĻĒ āĻā§āĻ¨āĻāĻŋ?
- āĻ¤ā§āĻŽāĻŋ āĻ¯ā§āĻ¤ā§ āĻĒāĻžāĻ°āĻŦā§
- āĻ¤āĻžā§āĻŽāĻžāĻā§ āĻĨāĻžāĻāĻ¤ā§ āĻšāĻŦā§
- āĻ¤āĻžā§āĻŽāĻžāĻā§ āĻ¯ā§āĻ¤ā§ āĻšāĻŦā§
- āĻ¤ā§āĻŽāĻŋ āĻ¨āĻž āĻāĻŋāĻ¯āĻŧā§ āĻĒāĻžāĻ°āĻŦā§ āĻ¨āĻž
Ans. āĻ¤āĻžā§āĻŽāĻžāĻā§ āĻĨāĻžāĻāĻ¤ā§ āĻšāĻŦā§
- ‘The medicine will pull you roundâ āĻŦāĻžāĻā§āĻ¯āĻāĻŋāĻ° āĻŦāĻā§āĻāĻžāĻ¨ā§āĻŦāĻžāĻĻ-
- āĻāĻˇā§āĻ§āĻāĻŋ āĻ¤āĻžā§āĻŽāĻžāĻ° āĻāĻžāĻā§ āĻāĻ¸āĻŦā§ āĻ¨āĻž
- āĻāĻˇā§āĻ§āĻāĻŋ āĻ¤āĻžā§āĻŽāĻžāĻ° āĻā§āĻˇāĻ¤āĻŋ āĻāĻ°āĻŦā§
- āĻāĻˇā§āĻ§āĻāĻŋāĻ° āĻĒā§āĻ°āĻ¤āĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻž āĻšāĻŦā§ āĻ¤āĻžā§āĻŽāĻžāĻ° āĻāĻĒāĻ°
- āĻāĻˇā§āĻ§āĻāĻŋ āĻ¤āĻžā§āĻŽāĻžāĻā§ āĻāĻžāĻ˛āĻžā§ āĻāĻ°ā§ āĻĻā§āĻŦā§
Ans. āĻāĻˇā§āĻ§āĻāĻŋ āĻ¤āĻžā§āĻŽāĻžāĻā§ āĻāĻžāĻ˛āĻžā§ āĻāĻ°ā§ āĻĻā§āĻŦā§
- ‘āĻŦāĻžāĻāĻžāĻ°ā§ āĻāĻžāĻāĻž’ āĻŦāĻžāĻāĻ§āĻžāĻ°āĻžāĻ° āĻ
āĻ°ā§āĻĨ-
- āĻā§āĻ¯āĻžāĻ¤āĻŋ āĻ āĻ°ā§āĻāĻ¨ āĻāĻ°āĻž
- āĻ¨āĻžāĻŽāĻ¯āĻļ āĻšāĻāĻ¯āĻŧāĻž
- āĻŦāĻŋāĻā§āĻ°āĻŋ āĻšāĻāĻ¯āĻŧāĻž
- āĻāĻŽ āĻŽā§āĻ˛ā§āĻ¯ā§ āĻŦāĻŋāĻā§āĻ°āĻŋ āĻāĻ°āĻž
Ans. āĻŦāĻŋāĻā§āĻ°āĻŋ āĻšāĻāĻ¯āĻŧāĻž
- āĻ°āĻŦā§āĻ¨ā§āĻĻā§āĻ°āĻ¨āĻžāĻĨā§āĻ° āĻ˛ā§āĻāĻž āĻā§āĻ°āĻ¨ā§āĻĨ āĻā§āĻ¨āĻāĻŋ?
- āĻĒāĻ˛ā§āĻ˛ā§āĻ¸āĻŽāĻžāĻ
- āĻ¸āĻ¨ā§āĻ āĻĒāĻā§āĻāĻžāĻļā§
- āĻāĻžāĻ˛āĻžāĻ¨ā§āĻ¤āĻ°
- āĻāĻžāĻ¯āĻŧāĻžāĻ¨āĻ
Ans. āĻāĻžāĻ˛āĻžāĻ¨ā§āĻ¤āĻ°
- āĻāĻžāĻŽāĻžāĻ˛, āĻ¸āĻžāĻ¨āĻāĻ¯āĻŧāĻžāĻ¤, āĻ˛ā§āĻ¨āĻŋāĻ¨ āĻ āĻŽā§āĻ¸āĻžā§āĻ˛āĻŋāĻ¨āĻŋāĻ° āĻ¨āĻžāĻŽ āĻāĻā§ āĻā§āĻ¨ āĻ˛ā§āĻāĻžāĻ¯āĻŧ?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻ¸āĻžāĻšāĻŋāĻ¤ā§āĻ¯ā§ āĻā§āĻ˛āĻž
- āĻāĻžāĻˇāĻžāĻ° āĻāĻĨāĻž
- āĻāĻā§āĻļā§āĻ° āĻāĻ˛ā§āĻĒ
- āĻ¯ā§āĻŦāĻ¨ā§āĻ° āĻāĻžāĻ¨
Ans. āĻ¯ā§āĻŦāĻ¨ā§āĻ° āĻāĻžāĻ¨
- āĻ°āĻžā§āĻĻāĻž āĻā§ āĻāĻŋāĻ˛ā§āĻ¨?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻĢāĻ°āĻžāĻ¸āĻŋ āĻāĻŋāĻ¤ā§āĻ°āĻļāĻŋāĻ˛ā§āĻĒā§
- āĻĢāĻ°āĻžāĻ¸āĻŋ āĻ¨āĻžāĻā§āĻ¯āĻāĻžāĻ°
- āĻĢāĻ°āĻžāĻ¸āĻŋ āĻāĻŦāĻŋ
- āĻĢāĻ°āĻžāĻ¸āĻŋ āĻāĻžāĻ¸ā§āĻāĻ°
Ans. āĻĢāĻ°āĻžāĻ¸āĻŋ āĻāĻžāĻ¸ā§āĻāĻ°
- ‘āĻ¸āĻžā§āĻ¨āĻžāĻ° āĻ¤āĻ°ā§’ āĻāĻŦāĻŋāĻ¤āĻžāĻāĻŋ āĻā§āĻ¨ āĻāĻ¨ā§āĻĻā§ āĻ°āĻāĻŋāĻ¤?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻ¸ā§āĻŦāĻ°āĻŦā§āĻ¤ā§āĻ¤
- āĻŽāĻžāĻ¤ā§āĻ°āĻžāĻŦā§āĻ¤ā§āĻ¤
- āĻ āĻā§āĻˇāĻ°āĻŦā§āĻ¤ā§āĻ¤
- āĻ¸ā§āĻŦāĻ°āĻŽāĻžāĻ¤ā§āĻ°āĻŋāĻ
Ans. āĻŽāĻžāĻ¤ā§āĻ°āĻžāĻŦā§āĻ¤ā§āĻ¤
- āĻŽāĻžāĻ¨ā§āĻˇ āĻŽāĻ°ā§ āĻā§āĻ˛ā§ āĻĒāĻā§ āĻ¯āĻžāĻ¯āĻŧāĨ¤ āĻŦā§āĻāĻā§ āĻĨāĻžāĻāĻ˛ā§ āĻŦāĻĻāĻ˛āĻžāĻ¯āĻŧāĨ¤ āĻāĻžāĻ°āĻŖā§ āĻ
āĻāĻžāĻ°āĻŖā§ āĻŦāĻĻāĻ˛āĻžāĻ¯āĻŧāĨ¤ āĻ¸āĻāĻžāĻ˛ā§ āĻŦāĻŋāĻāĻžāĻ˛ā§ āĻŦāĻĻāĻ˛āĻžāĻ¯āĻŧāĨ¤ āĻ āĻ¸āĻāĻ˛āĻžāĻĒ āĻāĻžāĻ°?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻ¨āĻŦāĻžāĻŦ āĻ¸ā§āĻāĻžāĻāĻĻā§āĻĻā§āĻ˛āĻžāĻ°
- āĻ¨āĻŦāĻžāĻŦ āĻ¨āĻā§āĻŦāĻāĻĻā§āĻĻā§āĻ˛āĻžāĻ°
- āĻāĻŦā§āĻ°āĻžāĻšāĻŋāĻŽ āĻāĻžāĻ°ā§āĻĻāĻŋāĻ°
- āĻāĻšāĻŽāĻĻ āĻļāĻžāĻš āĻāĻŦāĻĻāĻžāĻ˛ā§āĻ°
Ans. āĻ¨āĻŦāĻžāĻŦ āĻ¸ā§āĻāĻžāĻāĻĻā§āĻĻā§āĻ˛āĻžāĻ°
- âāĻāĻāĻžāĻ¨ āĻā§āĻĄāĻŧāĻžâ āĻŦāĻ˛ā§ āĻāĻžāĻā§ āĻ¸āĻŽā§āĻŦāĻžā§āĻ§āĻ¨ āĻāĻ°āĻž āĻšāĻ¯āĻŧā§āĻā§?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻāĻŽāĻŋāĻ¨ā§āĻĻā§āĻĻāĻŋ
- āĻšāĻžāĻ°āĻžāĻ§āĻ¨
- āĻšāĻžā§āĻ¸ā§āĻ¨ āĻŽāĻŋāĻ¯āĻŧāĻž
- āĻ§āĻ¨āĻā§āĻāĻ¯āĻŧ
Ans. āĻ§āĻ¨āĻā§āĻāĻ¯āĻŧ
- āĻĒāĻ°āĻŋāĻ¤ā§āĻ¯āĻā§āĻ¤ āĻŦāĻžāĻĄāĻŧāĻŋ āĻāĻŋāĻ¨āĻ¤ā§ āĻĻā§āĻ°āĻŋ āĻšāĻ¯āĻŧ āĻ¨āĻžāĨ¤ āĻāĻŋāĻ¨ā§āĻ¤ā§ āĻāĻŽāĻ¨ āĻŦāĻžāĻĄāĻŧāĻŋ āĻĒāĻžāĻāĻ¯āĻŧāĻž āĻ¨āĻŋāĻ¤āĻžāĻ¨ā§āĻ¤ āĻ¸ā§āĻāĻžāĻā§āĻ¯ā§āĻ° āĻāĻĨāĻžāĨ¤ ‘āĻāĻāĻāĻŋ āĻ¤ā§āĻ˛āĻ¸ā§ āĻāĻžāĻā§āĻ° āĻāĻžāĻšāĻŋāĻ¨ā§’ āĻāĻ˛ā§āĻĒā§ āĻāĻā§āĻ¤āĻŋāĻāĻŋ āĻāĻžāĻ°?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻāĻžāĻĻā§āĻ°ā§āĻ°
- āĻŦāĻĻāĻ°ā§āĻĻā§āĻĻāĻŋāĻ¨ā§āĻ°
- āĻ˛ā§āĻāĻā§āĻ°
- āĻŽāĻžā§āĻĻāĻžāĻŦā§āĻŦā§āĻ°ā§āĻ°
Ans. āĻ˛ā§āĻāĻā§āĻ°
- ‘āĻĢāĻŋāĻ°ā§ āĻāĻ¸ā§ āĻĻā§āĻāĻŋ āĻ¸āĻžā§āĻ¨āĻžāĻ° āĻĒā§āĻ°āĻ¤āĻŋāĻŽāĻž āĻ˛ā§āĻāĻžāĻ¯āĻŧ āĻĒāĻĨā§āĻ° āĻĒāĻ°ā§āĨ¤’ âāĻāĻŦāĻ°â āĻāĻŦāĻŋāĻ¤āĻžāĻ° āĻ āĻ¸āĻžā§āĻ¨āĻžāĻ° āĻĒā§āĻ°āĻ¤āĻŋāĻŽāĻž āĻšāĻ˛āĻžā§-(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻŦā§āĻĻā§āĻ§ā§āĻ° āĻ¸ā§āĻ¤ā§āĻ°ā§
- āĻŦā§āĻĻā§āĻ§ā§āĻ° āĻĒā§āĻ¤ā§āĻ°āĻŦāĻ§ā§
- āĻŦā§āĻĻā§āĻ§ā§āĻ° āĻ¨āĻžāĻ¤āĻ¨āĻŋ
- āĻŦā§āĻĻā§āĻ§ā§āĻ° āĻŽā§āĻ¯āĻŧā§
Ans. āĻŦā§āĻĻā§āĻ§ā§āĻ° āĻŽā§āĻ¯āĻŧā§
- ‘āĻā§āĻ˛āĻŋāĻ¨ā§ āĻļā§āĻŦāĻžāĻ˛ā§, āĻā§āĻ˛āĻŋ āĻāĻŽāĻ˛-āĻāĻžāĻ¨āĻ¨āĨ¤’ āĻāĻāĻžāĻ¨ā§ ‘āĻāĻŽāĻ˛-āĻāĻžāĻ¨āĻ¨’ āĻļāĻŦā§āĻĻā§āĻ° āĻŦā§āĻ¯āĻā§āĻāĻ¨āĻžāĻ°ā§āĻĨ-(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻŦāĻžāĻāĻ˛āĻž āĻāĻžāĻˇāĻž
- āĻāĻāĻ°ā§āĻāĻŋ āĻāĻžāĻˇāĻž
- āĻĢāĻ°āĻžāĻ¸āĻŋ āĻāĻžāĻˇāĻž
- āĻĒāĻĻā§āĻŽāĻŦāĻ¨
Ans. āĻŦāĻžāĻāĻ˛āĻž āĻāĻžāĻˇāĻž
- ‘āĻ¨āĻŋāĻā§āĻ āĻāĻŽāĻā§ āĻāĻ āĻŋ, āĻā§ āĻ¨āĻŋāĻ¸ā§āĻĒā§āĻš, āĻā§āĻŽāĻ¨ āĻļā§āĻ¤āĻ˛āĨ¤’ āĻ āĻĒāĻāĻā§āĻ¤āĻŋāĻ° āĻ°āĻāĻ¯āĻŧāĻŋāĻ¤āĻž āĻšāĻ˛ā§āĻ¨-(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻāĻšāĻ¸āĻžāĻ¨ āĻšāĻžāĻŦā§āĻŦ
- āĻ¸ā§āĻĢāĻŋāĻ¯āĻŧāĻž āĻāĻžāĻŽāĻžāĻ˛
- āĻļāĻžāĻŽāĻ¸ā§āĻ° āĻ°āĻžāĻšāĻŽāĻžāĻ¨
- āĻ āĻŽāĻŋāĻ¯āĻŧ āĻāĻā§āĻ°āĻŦāĻ°ā§āĻ¤ā§
Ans. āĻļāĻžāĻŽāĻ¸ā§āĻ° āĻ°āĻžāĻšāĻŽāĻžāĻ¨
- āĻŦāĻŋā§ā§āĻ° āĻ¸āĻŽā§ āĻšā§āĻŽāĻ¨ā§āĻ¤ā§ āĻ āĻ¤āĻžāĻ° āĻ¸ā§āĻŦāĻžāĻŽā§āĻ° āĻŦā§āĻ¸ āĻāĻŋāĻ˛ āĻ¯āĻĨāĻžāĻā§āĻ°āĻŽā§-(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- ā§§ā§§ āĻ ā§§ā§Ŧ
- ā§§ā§Š āĻ ā§§ā§
- ā§§ā§Ģ āĻ ā§§ā§Ž
- ā§§ā§ āĻ ā§§ā§¯
Ans.ā§§ā§ āĻ ā§§ā§¯
English
Read the passage and answer (Ques.1-5)
Advertising has become a very specialized activity in modern times. In the business world of today, supply is usually greater than demand. There is great competition between different manufacturers of the same kind of product to persuade customers to buy their own particular brand. They always have to remind the consumer of the name and qualities of their product. They do this by advertising. They manufacture advertises in the newspapers and on posters. He sometimes pays for songs about his product in commercial radio programmes. He employs attractive sales-girls to distribute samples of it. He organizes competitions, with prize for the winners. He often advertises on the screens of local cinemas. Most important of all, in countries that have * television he has advertisements put into programmes that will accept them.
-
There are _____ kinds of advertisments mentioned in the passage.
- five
- six
- seven
- eight
Ans. seven
- What do sales girls do?
- sell goods
- put goods on sale
- distribute goods around
- distribute samples
Ans. distribute samples
- ‘specialized’ here stands for
- specially planned
- crafty
- unique
- specially selected
Ans. specially selected
- ‘consumer’ means
- one who eats
- one who gathers
- one who demands
- one who buys
Ans. one who buys
- ‘commercial radio programmes’ are
- radio programmes that buy advertisements
- radio programmes that deal with commerce
- radio programmes that take money from advertisers
- radio programmes that sell advertisements
Ans. radio programmes that take money from advertisers
- I ___ finished my letter yet.
- am not
- had not
- have not
- did not
Ans. have not
- He often _____ me, but has never _____ to me.
- sees, speaks
- looks, talks
- looked, spoke
- sees, spoken
Ans. sees, spoken
- Have you _____ that clock?
- wind
- wound
- winded
- wouded
Ans. wound
- The Manager of the company is somewhat susceptible _____ flattery.
- to
- of
- with
- for
Ans. to
- The old road goes _____ the village.
- aginst
- under
- over
- through
Ans. through
- He goes to school _____ foot.
- on
- by
- in
- with
Ans. on
- He made _____ few mistakes.
- an
- the
- a
- no article
Ans. a, no article
- This book is _____ one I was looking for.
- a
- an
- the
- no article
Ans. the
- Choose the correct interrogative:
- When did you have you last class?
- When have your last class?
- When did you have your last class?
- When did your last class have?
Ans. When did you have your last class?
- Choose the correct interrogative
- When is you going to arrive?
- When you going to arrive?
- When are you going to arrive?
- When you are going to arrive?
Ans. When are you going to arrive?
- I was annoyed; _____ I kept quiet
- then
- when
- still
- and
Ans. still
- He is going berserk
- He is becoming very senses
- He is becoming mad
- He is losing his senses
- He is falling ill
Ans. He is becoming mad
- Drum something in
- teach something to someone forcefully
- beat a drum
- teach something to someone intensely
- beat something like a drum
Ans. teach something to someone forcefully
-
He is trying to give up smoking, _____ ?
- isn’t he
- is he
- won’t he
- will he
Ans. isn’t he
- The girl broke the cup, _____ ?
- did she
- didn’t she
- hadn’t she
- hasn’t she
Ans. didn’t she
- Choose the correct sentence
- Neither Bob nor John are responsible for it
- Neither Bob nor John is responsible for it
- Neither Bob nor John were responsible for it
- Neither Bob nor John help responsible for it
Ans. Neither Bob nor John is responsible for it
- Choose the correct sentence
- They hardly speaking English
- They hardly talk English
- They cannot hardly speak English
- They can hardly speak English
Ans. They can hardly speak English
- Choose the correct sentence
- He told me what to do with a smile
- He told me what to do for a smile
- He told me what to do in a smile
- He told me with a smile what to do
Ans. He told me with a smile what to do
- Choose the correct affirmative sentence of, ‘He did not apply for the job through proper channel.’
- He applied through proper channle
- He applied for a different job
- He should have applied through proper channel
- He applied through a different channel
Ans. He applied through a different channel
- The correct spelling is-
- Protrector
- Protactor
- Protector
- Potactor
Ans. Protector
- The train arrives exactly at midday. It’s always___
- in time
- before time
- late
- on time
Ans. on time
- ‘Patricide’ is
- The crime of denying one’s own land
- The crime of killing one’s own father
- the crime of loving one’s own country too much
- an insect killer
Ans. The crime of killing one’s own father
-
The antonym for ‘cacophony’ is ____
- irony
- euphony
- telephony
- symphony
Ans. euphony
- Choose the correct pair of words. A good book _____ with a hard cover to _____ its contents.
- covered, wear
- hidden, reveal
- written, hide
- designed, protect
Ans. covered, wear
- Choose an acceptable English translation for the Bengali sentence- āĻ¤ā§āĻŽāĻŋ āĻāĻŋ āĻāĻāĻ°ā§āĻāĻŋāĻ¤ā§ āĻā§āĻ¨ āĻā§āĻ˛ā§ āĻā§āĻ˛āĻžāĻ¨ā§ āĻā§āĻž āĻāĻžāĻ¨ā§?
- You do know any nursery rhyme in English
- Do you know any nursery rhyme in English
- You know any English verse to forget boys, do you?
- Do you know any English forgetfulnes verse for boys?
Ans. Do you know any nursery rhyme in English
Choose the correct tag (question 19-20)