DU A Unit Admission Question Solution 2002-2003
āĻ¨āĻŋāĻā§āĻ° āĻāĻŋāĻĄāĻŋāĻāĻ¤ā§ āĻĻā§āĻā§ āĻ¨āĻžāĻ āĻŦāĻŋāĻ¸ā§āĻ¤āĻžāĻ°āĻŋāĻ¤:
āĻā§āĻ°ā§āĻ¸āĻāĻŋ āĻāĻŋāĻ¨āĻ¤ā§ āĻĒāĻžāĻļā§āĻ° āĻŦāĻžāĻāĻ¨āĻāĻŋ āĻā§āĻ˛āĻŋāĻ āĻāĻ°:Â Â
āĻā§āĻ°ā§āĻ¸ā§āĻ° āĻĄā§āĻŽā§ āĻāĻŋāĻĄāĻŋāĻ(āĻāĻāĻžāĻŦā§ āĻĒāĻĻāĻžāĻ°ā§āĻĨāĻŦāĻŋāĻā§āĻāĻžāĻ¨+āĻ°āĻ¸āĻžā§āĻ¨+āĻāĻā§āĻāĻ¤āĻ°āĻāĻŖāĻŋāĻ¤ āĻāĻ° āĻŦāĻŋāĻāĻ¤ āĻŦāĻŋāĻļ āĻŦāĻāĻ°ā§āĻ° āĻ¸āĻāĻ˛ āĻĒā§āĻ°āĻļā§āĻ¨ā§āĻ° āĻ¸āĻŽāĻžāĻ§āĻžāĻ¨ āĻĨāĻžāĻāĻŦā§ āĻāĻŋāĻĄāĻŋāĻāĻ¤ā§)
Physics
-
āĻ
āĻ¸ā§āĻ¤āĻāĻžāĻŽā§āĻ¸ā§āĻ°ā§āĻ¯ āĻĻā§āĻāĻžāĻ° āĻāĻ¨ā§āĻ¯ āĻĒāĻžāĻ¨āĻŋāĻ° āĻāĻŋāĻ¤āĻ° āĻĨā§āĻā§ āĻāĻāĻāĻŋ āĻŽāĻžāĻāĻā§ āĻ
āĻāĻŋāĻ˛āĻŽā§āĻŦā§āĻ° āĻ¸āĻžāĻĒā§āĻā§āĻˇā§ āĻ¯ā§ āĻā§āĻŖā§ āĻĻā§āĻˇā§āĻāĻŋāĻĒāĻžāĻ¤ āĻāĻ°āĻ¤ā§ āĻšāĻŦā§ āĻ¤āĻž āĻšāĻ˛ā§-
- 57.55°
- 48.75°
- 34.75°
- 44.75°
Ans. 48.75°
- āĻĢāĻžāĻ°ā§āĻ¨āĻšāĻžāĻāĻ āĻ¸ā§āĻā§āĻ˛ā§ āĻā§āĻ¨ā§ āĻŦāĻ¸ā§āĻ¤ā§āĻ° āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻž 50° F āĻšāĻ˛ā§ āĻā§āĻ˛āĻāĻŋāĻ¨ āĻ¸ā§āĻā§āĻ˛ā§ āĻ āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻž āĻšāĻŦā§-
- 273 K
- 283 K
- 290 K
- 300 K
Ans. 283 K
- āĻāĻ¯āĻŧāĻ-āĻāĻ° āĻĄāĻžāĻŦāĻ˛-āĻ¸ā§āĻ˛āĻŋāĻ āĻĒāĻ°ā§āĻā§āĻˇāĻž āĻĒā§āĻ°āĻĻāĻ°ā§āĻļāĻ¨ āĻāĻ°ā§-
- āĻāĻ˛ā§āĻā§āĻ° āĻ¸āĻŽāĻŦāĻ°ā§āĻ¤āĻ¨
- āĻāĻ˛ā§āĻā§āĻ° āĻŦāĻŋāĻā§āĻā§āĻ°āĻŖ
- āĻāĻ˛ā§āĻā§āĻ° āĻĒā§āĻ°āĻ¤āĻŋāĻĢāĻ˛āĻ¨
- āĻāĻ˛ā§āĻā§āĻ° āĻŦā§āĻ¯āĻ¤āĻŋāĻāĻžāĻ°
Ans. āĻāĻ˛ā§āĻā§āĻ° āĻŦā§āĻ¯āĻ¤āĻŋāĻāĻžāĻ°
- āĻ¸ā§āĻĨāĻŋāĻ° āĻāĻžāĻĒā§ 27°C āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻžāĻ° 2 Litre āĻŦāĻžāĻ¤āĻžāĻ¸ā§āĻ° āĻāĻ¯āĻŧāĻ¤āĻ¨ 4 L āĻāĻ°āĻ¤ā§ āĻšāĻ˛ā§ āĻāĻ¤ā§āĻ¤āĻĒā§āĻ¤ āĻāĻ°ā§ āĻ¯ā§ āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻžāĻ¯āĻŧ āĻ¨āĻŋāĻ¤ā§ āĻšāĻŦā§-
- 54°C
- 237°C
- 300°C
- 327°C
Ans. 327°C
- āĻ¯āĻāĻ¨ āĻ¸āĻžāĻĻāĻž āĻāĻ˛ā§ āĻĒā§āĻ°āĻŋāĻāĻŽā§āĻ° āĻŽāĻ§ā§āĻ¯ āĻĻāĻŋāĻ¯āĻŧā§ āĻĒā§āĻ°āĻ¤āĻŋāĻ¸āĻ°āĻŋāĻ¤ āĻšāĻ¯āĻŧ, āĻāĻ˛ā§āĻ° āĻŦāĻŋāĻā§āĻ¯ā§āĻ¤āĻŋ-
- āĻ¨ā§āĻ˛ āĻ āĻĒā§āĻā§āĻˇāĻž āĻ˛āĻžāĻ˛ā§āĻ° āĻāĻ¨ā§āĻ¯ āĻŦā§āĻļāĻŋ
- āĻšāĻ˛ā§āĻĻ āĻ āĻĒā§āĻā§āĻˇāĻž āĻŦā§āĻā§āĻ¨āĻŋāĻ° āĻāĻ¨ā§āĻ¯ āĻŦā§āĻļāĻŋ
- āĻ˛āĻžāĻ˛ā§āĻ° āĻā§āĻ¯āĻŧā§ āĻ¸āĻŦā§āĻā§āĻ° āĻāĻ¨ā§āĻ¯ āĻāĻŽ
- āĻāĻŽāĻ˛āĻžāĻ° āĻā§āĻ¯āĻŧā§ āĻŦā§āĻā§āĻ¨āĻŋāĻ° āĻāĻ¨ā§āĻ¯ āĻāĻŽ
Ans. āĻšāĻ˛ā§āĻĻ āĻ āĻĒā§āĻā§āĻˇāĻž āĻŦā§āĻā§āĻ¨āĻŋāĻ° āĻāĻ¨ā§āĻ¯ āĻŦā§āĻļāĻŋ
- āĻāĻāĻāĻŋ P-āĻāĻžāĻāĻĒ āĻ
āĻ°ā§āĻ§-āĻĒāĻ°āĻŋāĻŦāĻžāĻšā§ āĻ¤ā§āĻ°ā§ āĻāĻ°āĻ¤ā§ āĻ¸āĻŋāĻ˛āĻŋāĻāĻ¨ āĻāĻ° āĻ¸āĻžāĻĨā§ āĻ¯ā§āĻāĻŋ āĻ¯ā§āĻ (āĻĄā§āĻĒāĻŋāĻ) āĻāĻ°āĻ¤ā§ āĻšāĻŦā§āĨ¤
- Phosphorus
- Antimony
- Arsenic
- Indium
Ans. Indium
- āĻāĻāĻāĻŋ āĻŦā§āĻĻā§āĻ¯ā§āĻ¤āĻŋāĻ āĻŦāĻžāĻ¤āĻŋāĻ° āĻŽāĻžāĻ§ā§āĻ¯āĻŽā§ āĻŦāĻŋāĻĻā§āĻ¯ā§ā§ āĻļāĻā§āĻ¤āĻŋāĻā§ āĻ°ā§āĻĒāĻžāĻ¨ā§āĻ¤āĻ°āĻŋāĻ¤ āĻāĻ°ā§ āĻĒāĻžāĻāĻ¯āĻŧāĻž āĻ¯āĻžāĻ¯āĻŧ-
- āĻļā§āĻ§ā§ āĻ¤āĻžāĻĒāĻļāĻā§āĻ¤āĻŋ
- āĻļā§āĻ§ā§ āĻāĻ˛ā§āĻāĻļāĻā§āĻ¤āĻŋ
- āĻ¤āĻžāĻĒāĻļāĻā§āĻ¤āĻŋ āĻāĻŦāĻ āĻāĻ˛ā§āĻ āĻļāĻā§āĻ¤āĻŋ
- āĻĒāĻžāĻ°āĻŽāĻžāĻŖāĻŦāĻŋāĻ āĻļāĻā§āĻ¤āĻŋ
Ans. āĻ¤āĻžāĻĒāĻļāĻā§āĻ¤āĻŋ āĻāĻŦāĻ āĻāĻ˛ā§āĻ āĻļāĻā§āĻ¤āĻŋ
- 220v, 40w āĻāĻŦāĻ 110v, 40w āĻ˛ā§āĻāĻž āĻĻā§āĻā§ āĻāĻ˛ā§āĻāĻā§āĻ°āĻŋāĻ āĻŦāĻžāĻ˛ā§āĻŦā§āĻ° āĻ°ā§āĻ§ā§āĻ° āĻ
āĻ¨ā§āĻĒāĻžāĻ¤-
- 1 : 2
- 2:1
- 4:1
- 6:1
Ans. 4:1
- āĻāĻ¯āĻŧā§āĻāĻāĻŋ āĻ§āĻžāĻ°āĻ āĻļā§āĻ°ā§āĻŖāĻŋ āĻ¸āĻŽāĻŦāĻžāĻ¯āĻŧā§ āĻ¸āĻāĻ¯ā§āĻā§āĻ¤ āĻšāĻ˛ā§-
- āĻĒā§āĻ°āĻ¤ā§āĻ¯ā§āĻāĻāĻŋāĻ° āĻŦāĻŋāĻāĻŦ āĻĒāĻžāĻ°ā§āĻĨāĻā§āĻ¯ āĻ¸āĻŽāĻžāĻ¨
- āĻĒā§āĻ°āĻ¤ā§āĻ¯ā§āĻāĻāĻŋāĻ° āĻāĻžāĻ°ā§āĻ āĻ¸āĻŽāĻžāĻ¨
- āĻ˛āĻŦā§āĻ§āĻŋ āĻ§āĻžāĻ°āĻāĻ¤ā§āĻŦ āĻ¸āĻŦāĻā§āĻ˛ā§ āĻ§āĻžāĻ°āĻā§āĻ° āĻ¸āĻŽāĻˇā§āĻāĻŋ āĻĨā§āĻā§ āĻŦāĻĄāĻŧ
- āĻ˛āĻŦā§āĻ§āĻŋ āĻ§āĻžāĻ°āĻāĻ¤ā§āĻŦ āĻ¸āĻŦāĻā§āĻ˛ā§ āĻ§āĻžāĻ°āĻā§āĻ° āĻ¸āĻŽāĻˇā§āĻāĻŋāĻ° āĻ¸āĻŽāĻžāĻ¨
Ans. āĻĒā§āĻ°āĻ¤ā§āĻ¯ā§āĻāĻāĻŋāĻ° āĻāĻžāĻ°ā§āĻ āĻ¸āĻŽāĻžāĻ¨
- āĻāĻ āĻā§āĻ˛āĻŽā§āĻŦ āĻŽāĻžāĻ¨ā§āĻ° āĻĻā§āĻāĻŋ āĻ§āĻ¨āĻžāĻ¤ā§āĻŽāĻ āĻāĻ§āĻžāĻ¨ lcm āĻĻā§āĻ°ā§ āĻ
āĻŦāĻ¸ā§āĻĨāĻŋāĻ¤āĨ¤ āĻ¯āĻĻāĻŋ āĻāĻāĻāĻŋ āĻ§āĻ¨āĻžāĻ¤ā§āĻŽāĻ āĻāĻ§āĻžāĻ¨āĻā§ āĻ¸āĻ°āĻŋāĻ¯āĻŧā§ āĻ¸ā§āĻāĻžāĻ¨ā§ āĻāĻāĻāĻŋ āĻāĻ āĻā§āĻ˛āĻŽā§āĻŦ āĻŽāĻžāĻ¨ā§āĻ° āĻāĻŖāĻžāĻ¤ā§āĻŽāĻ āĻāĻ§āĻžāĻ¨ āĻŦāĻ¸āĻžāĻ¨ā§ āĻšāĻ¯āĻŧ, āĻ¤āĻŦā§ āĻāĻ§āĻžāĻ¨ āĻĻā§āĻāĻŋāĻ° āĻŽāĻ§ā§āĻ¯ā§āĻāĻžāĻ° āĻŦāĻ˛ā§āĻ° āĻŽāĻžāĻ¨-
- āĻļā§āĻ¨ā§āĻ¯
- āĻāĻā§āĻ° āĻā§āĻ¯āĻŧā§ āĻāĻŽ
- āĻāĻā§āĻ° āĻā§āĻ¯āĻŧā§ āĻŦā§āĻļāĻŋ
- āĻāĻā§āĻ° āĻ¸āĻŽāĻžāĻ¨
Ans. āĻāĻā§āĻ° āĻ¸āĻŽāĻžāĻ¨
- āĻĻā§āĻāĻŋ āĻ¤āĻ°āĻā§āĻā§āĻ° āĻĒā§āĻ°āĻ¤āĻŋāĻāĻŋāĻ° āĻ¤āĻ°āĻā§āĻāĻĻā§āĻ°ā§āĻā§āĻ¯ 12cm āĻāĻ°ā§āĨ¤ āĻ¯āĻĻāĻŋ āĻāĻāĻāĻŋ āĻĨā§āĻā§ āĻ
āĻĒāĻ°āĻāĻŋ 14cm āĻ
āĻā§āĻ°āĻāĻžāĻŽā§ āĻšāĻ¯āĻŧ, āĻ¤āĻŦā§ āĻ¤āĻžāĻĻā§āĻ° āĻŽāĻ§ā§āĻ¯ā§ āĻĻāĻļāĻž āĻĒāĻžāĻ°ā§āĻĨāĻā§āĻ¯-
- \(\pi / 3\)
- \(\pi / 4\)
- \(\pi / 5\)
- \(\pi / 6\)
Ans. \(\pi / 3\)
- 100 āĻāĻ¯āĻŧāĻžāĻ āĻāĻ° āĻāĻāĻāĻŋ āĻŦā§āĻĻā§āĻ¯ā§āĻ¤āĻŋāĻ āĻŦāĻžāĻ¤āĻŋ āĻĒā§āĻ°āĻ¤āĻŋāĻĻāĻŋāĻ¨ ā§Ē āĻāĻ¨ā§āĻāĻž āĻāĻ°ā§ āĻā§āĻŦāĻžāĻ˛āĻžāĻ¨ā§ āĻšāĻ¯āĻŧāĨ¤ āĻĒā§āĻ°āĻ¤āĻŋ āĻāĻŋāĻ˛ā§āĻāĻ¯āĻŧāĻžāĻ āĻāĻ¨ā§āĻāĻž āĻŦāĻŋāĻĻā§āĻ¯ā§ā§ āĻļāĻā§āĻ¤āĻŋāĻ° āĻŽā§āĻ˛ā§āĻ¯ 2.00 āĻāĻžāĻāĻž āĻšāĻ˛ā§ 30 āĻĻāĻŋāĻ¨ā§ āĻāĻ°āĻ āĻšāĻŦā§āĨ¤
- 24 Tk.
- 48 Tk.
- 64 Tk.
- 72 Tk.
Ans. 48 Tk.
- āĻŦāĻžāĻ¯āĻŧā§āĻļā§āĻ¨ā§āĻ¯ āĻ¸ā§āĻĨāĻžāĻ¨ā§ āĻāĻ˛ā§āĻ° āĻĻā§āĻ°ā§āĻ¤āĻŋ ‘c’āĨ¤ āĻāĻāĻāĻŋ āĻŦāĻ¸ā§āĻ¤ā§āĻ° āĻāĻ˛āĻŽāĻžāĻ¨ āĻāĻ° āĻŦāĻ¸ā§āĻ¤ā§āĻāĻŋāĻ° āĻ¨āĻŋāĻļā§āĻāĻ˛ āĻāĻ°ā§āĻ° āĻĻā§āĻŦāĻŋāĻā§āĻŖ āĻšāĻ¤ā§ āĻšāĻ˛ā§ āĻāĻ° āĻĻā§āĻ°ā§āĻ¤āĻŋ āĻšāĻ¤ā§ āĻšāĻŦā§-
- c/2
- 2c
- \(\frac{2}{\sqrt{3 c}}\)
- \(\frac{\sqrt{3}}{2} \mathrm{c}\)
Ans. \(\frac{\sqrt{3}}{2} \mathrm{c}\)
- āĻ¤āĻŋāĻ¨āĻāĻŋ āĻāĻŋāĻ¨ā§āĻ¨ āĻŽāĻžāĻ¨ā§āĻ° āĻ°ā§āĻ§ \(\mathbf{R}_{1}, \mathbf{R}_{2}, \mathbf{R}_{3}\) āĻ¸āĻŽāĻžāĻ¨ā§āĻ¤āĻ°āĻžāĻ˛ā§ āĻ¸āĻāĻ¯ā§āĻā§āĻ¤ āĻšāĻ˛ā§ –
- āĻĒā§āĻ°āĻ¤ā§āĻ¯ā§āĻāĻāĻŋāĻ° āĻĻā§âāĻĒā§āĻ°āĻžāĻ¨ā§āĻ¤ā§ āĻŦāĻŋāĻāĻŦ āĻĒāĻžāĻ°ā§āĻĨāĻā§āĻ¯ āĻ¸āĻŽāĻžāĻ¨
- āĻĒā§āĻ°āĻ¤ā§āĻ¯ā§āĻāĻāĻŋ āĻ°ā§āĻ§ā§āĻ° āĻŽāĻ§ā§āĻ¯ āĻĻāĻŋāĻ¯āĻŧā§ āĻ¤āĻĄāĻŧāĻŋā§ āĻĒā§āĻ°āĻŦāĻžāĻšāĻŽāĻžāĻ¤ā§āĻ°āĻžāĻ° āĻŽāĻžāĻ¨
- āĻŽā§āĻ āĻ°ā§āĻ§, \(\mathrm{R}=\mathrm{R}_{1}+\mathrm{R}_{2}+\mathrm{R}_{3}\)
- āĻŽā§āĻ āĻ°ā§āĻ§, \(\mathrm{R}=\left(1 / \mathrm{R}_{1}+1 / \mathrm{R}_{2}+1 / \mathrm{R}_{3}\right)^{-1}\)
Ans. āĻĒā§āĻ°āĻ¤ā§āĻ¯ā§āĻāĻāĻŋāĻ° āĻĻā§âāĻĒā§āĻ°āĻžāĻ¨ā§āĻ¤ā§ āĻŦāĻŋāĻāĻŦ āĻĒāĻžāĻ°ā§āĻĨāĻā§āĻ¯ āĻ¸āĻŽāĻžāĻ¨
- āĻāĻžāĻā§āĻ° āĻāĻāĻāĻŋ āĻāĻĒā§āĻ˛ āĻĒā§āĻĨāĻŋāĻŦā§āĻā§ f āĻŦāĻ˛ā§ āĻāĻāĻ°ā§āĻˇāĻŖ āĻāĻ°āĻā§āĨ¤ āĻĒā§āĻĨāĻŋāĻŦā§ āĻāĻĒā§āĻ˛āĻā§ F āĻŦāĻ˛ā§ āĻāĻāĻ°ā§āĻˇāĻŖ āĻāĻ°ā§āĨ¤
- \(\mathrm{F} \gg \mathrm{f}\)
- \(\mathrm{F}>\mathrm{f}\)
- \(\mathrm{F}=\mathrm{f}\)
- \(\mathrm{F}<\mathrm{f}\)
Ans. \(\mathrm{F}=\mathrm{f}\)
- āĻ¤ā§āĻāĻ¸ā§āĻā§āĻ°āĻŋāĻ¯āĻŧ āĻŦāĻ°ā§āĻā§āĻ¯ā§āĻ° āĻāĻāĻāĻŋ āĻ¨āĻŽā§āĻ¨āĻžāĻ° āĻ
āĻ°ā§āĻ§āĻžāĻ¯āĻŧā§ 60 āĻŦāĻāĻ°āĨ¤ āĻŦāĻ°ā§āĻā§āĻ¯ā§āĻ° āĻ¤ā§āĻāĻ¸ā§āĻā§āĻ°āĻŋāĻ¯āĻŧāĻ¤āĻž āĻ¤āĻžāĻ° āĻŦāĻ°ā§āĻ¤āĻŽāĻžāĻ¨ āĻŽāĻžāĻ¨ā§āĻ° 12.5% āĻšāĻ¤ā§ āĻšāĻ˛ā§ āĻāĻ¤ āĻ¸āĻŽāĻ¯āĻŧ āĻ˛āĻžāĻāĻŦā§?
- 180 Years
- 120 Years
- 200 Years
- 240 Years
Ans. 180 Years
- āĻāĻāĻāĻŋ āĻāĻžāĻĄāĻŧāĻŋ 36 km/hr āĻŦā§āĻā§ āĻāĻ¤āĻŋāĻļā§āĻ˛āĨ¤ āĻĒā§āĻ°āĻžāĻ¯āĻŧ āĻā§āĻ¨ āĻāĻ¤āĻŋāĻ¤ā§ āĻāĻ˛āĻ˛ā§ āĻāĻžāĻĄāĻŧāĻŋāĻāĻŋāĻ° āĻāĻ¤āĻŋāĻļāĻā§āĻ¤āĻŋ āĻĻā§āĻŦāĻŋāĻā§āĻŖ āĻšāĻŦā§?
- 7 m/s
- 54 m/s
- 14 m/s
- 20 m/s
Ans. 14 m/s
- āĻ¯āĻāĻ¨ āĻāĻāĻāĻŋ āĻļāĻŦā§āĻĻā§āĻ° āĻā§āĻ¸ āĻā§āĻ¨ā§ āĻ¸ā§āĻĨāĻŋāĻ° āĻļā§āĻ°ā§āĻ¤āĻžāĻ° āĻĻāĻŋāĻā§ āĻāĻāĻŋāĻ¯āĻŧā§ āĻāĻ¸ā§ āĻ¤āĻāĻ¨ āĻ¯āĻž āĻāĻā§ āĻ¤āĻž āĻšāĻ˛ā§-
- āĻ¤āĻ°āĻā§āĻāĻĻā§āĻ°ā§āĻā§āĻ¯ā§āĻ° āĻāĻĒāĻžāĻ¤āĻ āĻŦā§āĻĻā§āĻ§āĻŋ
- āĻāĻŽā§āĻĒāĻ¨ āĻ¸āĻāĻā§āĻ¯āĻžāĻ° āĻāĻĒāĻžāĻ¤āĻ āĻŦā§āĻĻā§āĻ§āĻŋ
- āĻāĻŽā§āĻĒāĻ¨ āĻ¸āĻāĻā§āĻ¯āĻžāĻ° āĻāĻĒāĻžāĻ¤āĻāĻšāĻžāĻ¸
- āĻļāĻŦā§āĻĻā§āĻ° āĻāĻ¤āĻŋāĻŦā§āĻā§āĻ° āĻĒāĻ°āĻŋāĻŦāĻ°ā§āĻ¤āĻ¨
Ans. āĻāĻŽā§āĻĒāĻ¨ āĻ¸āĻāĻā§āĻ¯āĻžāĻ° āĻāĻĒāĻžāĻ¤āĻ āĻŦā§āĻĻā§āĻ§āĻŋ
- āĻĻā§āĻāĻŋ āĻā§āĻā§āĻāĻ° \(\overrightarrow{\mathbf{A}}=2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}-4 \hat{\mathbf{k}}\) āĻāĻŦāĻ \(\overrightarrow{\mathbf{B}}=x \hat{\mathbf{i}}+6 \hat{\mathbf{j}}-8 \hat{\mathbf{k}}\) āĻĻā§āĻāĻ¯āĻŧāĻž āĻāĻā§āĨ¤ x āĻāĻ° āĻ¯ā§ āĻŽāĻžāĻ¨ā§āĻ° āĻāĻ¨ā§āĻ¯ āĻā§āĻā§āĻāĻ° \(\overrightarrow{\mathrm{B}}\) āĻ¸āĻŽāĻžāĻ¨ā§āĻ¤āĻ°āĻžāĻ˛ āĻšāĻŦā§āĨ¤ āĻ¤āĻž āĻšāĻ˛-
- 3
- 4
- 5
- 6
Ans. 4
- 0.2m āĻĻā§āĻ°ā§āĻā§āĻ¯āĻŦāĻŋāĻļāĻŋāĻˇā§āĻ āĻāĻāĻāĻŋ āĻ¸āĻ°āĻ˛āĻĻā§āĻ˛āĻā§āĻ° āĻĻā§āĻ˛āĻ¨āĻāĻžāĻ˛ 0.9see āĻĒāĻžāĻāĻ¯āĻŧāĻž āĻā§āĻ˛āĨ¤ āĻĻā§āĻ˛āĻ¨āĻāĻžāĻ˛ 1.8sec āĻāĻ°āĻ¤ā§ āĻšāĻ˛ā§, āĻĻā§āĻ˛āĻāĻāĻŋāĻ° āĻĻā§āĻ°ā§āĻā§āĻ¯ āĻšāĻŦā§-
- 0.1 m
- 0.28 m
- 0.4 m
- 0.8 m
Ans. 0.8 m
- āĻāĻāĻāĻŋ ‘āĻāĻžāĻ°ā§āĻ¨ā§’ āĻāĻā§āĻāĻŋāĻ¨ā§āĻ° āĻā§āĻ¸ā§āĻ° āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻž 400 KāĨ¤ āĻāĻ āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻžāĻ¯āĻŧ āĻā§āĻ¸ āĻĨā§āĻā§ āĻāĻ āĻāĻā§āĻāĻŋāĻ¨ 836 J āĻ¤āĻžāĻĒ āĻā§āĻ°āĻšāĻŖ āĻāĻ°ā§ āĻāĻ° āĻ¸āĻŋāĻāĻā§ 627J āĻ¤āĻžāĻĒ āĻŦāĻ°ā§āĻāĻ¨ āĻāĻ°ā§āĨ¤ āĻ¤āĻžāĻšāĻ˛ā§ āĻ āĻāĻā§āĻāĻŋāĻ¨ā§āĻ° āĻĻāĻā§āĻˇāĻ¤āĻž-
- 25%
- 26.8%
- 28.9%
- 36%
Ans. 25%
- āĻāĻāĻāĻŋ āĻāĻ˛ā§āĻ āĻ°āĻļā§āĻŽāĻŋāĻ° āĻ¤āĻ°āĻā§āĻāĻĻā§āĻ°ā§āĻā§āĻ¯ āĻŦāĻžāĻ¯āĻŧā§āĻ¤ā§ 480nm āĻšāĻ˛ā§,āĻāĻžāĻā§ \((\mu=1.5)\) āĻ¤āĻ°āĻā§āĻāĻĻā§āĻ°ā§āĻā§āĻ¯ āĻšāĻŦā§-
- 400 nm
- 380 nm
- 320 nm
- 120 nm
Ans. 320 nm
- āĻāĻāĻāĻŋ āĻ˛āĻŋāĻĢāĻ \(2 \mathrm{~m} / \mathrm{s}^{2}\) āĻ¤ā§āĻŦāĻ°āĻŖā§ āĻ¨āĻŋāĻā§ āĻ¨āĻžāĻŽāĻā§āĨ¤ āĻ˛āĻŋāĻĢāĻā§āĻ° āĻŽā§āĻā§āĻ° 1m āĻāĻĒāĻ° āĻĨā§āĻā§ āĻāĻāĻāĻŋ āĻŦāĻ˛āĻā§ āĻ¸ā§āĻĨāĻŋāĻ° āĻ
āĻŦāĻ¸ā§āĻĨāĻž āĻĨā§āĻā§ āĻāĻžāĻĄāĻŧāĻž āĻšāĻ˛āĨ¤ \(g=10 \mathrm{~m} / \mathrm{s}^{2}\) āĻ§āĻ°āĻž āĻšāĻ˛ā§, āĻ˛āĻŋāĻĢāĻā§āĻ° āĻŽā§āĻā§ āĻ¸ā§āĻĒāĻ°ā§āĻļ āĻāĻ°āĻ¤ā§ āĻŦāĻ˛āĻāĻŋ āĻ¸āĻŽāĻ¯āĻŧ āĻ˛āĻžāĻāĻŦā§āĨ¤
- 0.5 s
- 0.6 s
- 0.7 s
- 1.1 s
Ans. 0.5 s
- 20 m/s āĻŦā§āĻā§ āĻāĻ˛āĻŽāĻžāĻ¨ 1000 kg āĻāĻ°ā§āĻ° āĻāĻāĻāĻŋ āĻā§āĻ°āĻžāĻ 1500 kg āĻāĻ°ā§āĻ° āĻāĻāĻāĻŋ āĻ¸ā§āĻĨāĻŋāĻ° āĻā§āĻ°āĻžāĻāĻā§ āĻ§āĻžāĻā§āĻāĻž āĻĻāĻŋāĻ¯āĻŧā§ āĻāĻ āĻ¸āĻžāĻĨā§ āĻ¯ā§āĻā§āĻ¤ āĻšāĻ¯āĻŧā§ āĻ¯ā§ āĻŦā§āĻā§ āĻāĻ˛āĻ¤ā§ āĻĨāĻžāĻāĻŦā§āĨ¤
- 12 m/s
- 10 m/s
- 8 m/s
- 7.5 m/s
Ans. 8 m/s
- āĻĒāĻžāĻŽā§āĻĒā§āĻ° āĻ¸āĻžāĻšāĻžāĻ¯ā§āĻ¯ā§ āĻāĻāĻāĻŋ āĻāĻāĻžāĻ°āĻšā§āĻĄ āĻĒāĻžāĻ¨āĻŋāĻ° āĻā§āĻ¯āĻžāĻā§āĻā§ 100 s āĻ¸āĻŽāĻ¯āĻŧā§ 1000 kg āĻĒāĻžāĻ¨āĻŋ āĻāĻ¤ā§āĻ¤ā§āĻ˛āĻ¨ āĻāĻ°āĻž āĻ¯āĻžāĻ¯āĻŧāĨ¤ āĻā§āĻ¯āĻžāĻā§āĻā§ āĻĒāĻžāĻ¨āĻŋāĻ° āĻāĻĄāĻŧ āĻāĻā§āĻāĻ¤āĻž 20 āĻšāĻ˛ā§ āĻĒāĻžāĻŽā§āĻĒā§āĻ° āĻā§āĻˇāĻŽāĻ¤āĻž āĻāĻ¤ kW?
- 1.96
- 2.96
- 1.02
- 1.01
Ans. 1.96
Chemistry
- āĻĒā§āĻ°āĻā§āĻ° āĻ
āĻā§āĻ¸āĻŋāĻā§āĻ¨ā§āĻ° āĻāĻĒāĻ¸ā§āĻĨāĻŋāĻ¤āĻŋāĻ¤ā§ āĻāĻ¯āĻŧāĻ˛āĻž āĻĒā§āĻĄāĻŧāĻŋāĻ¯āĻŧā§ āĻ¯ā§ āĻā§āĻ¯āĻžāĻ¸ā§āĻ¯āĻŧ āĻŽāĻŋāĻļā§āĻ°āĻŖ āĻĒāĻžāĻāĻ¯āĻŧāĻž āĻā§āĻ˛ āĻ¤āĻž āĻŦāĻŋāĻāĻžāĻ°ā§ āĻ°āĻžāĻāĻž āĻā§āĻ˛āĻž āĻĒāĻžāĻ¨āĻŋāĻ° āĻŽāĻ§ā§āĻ¯ā§ āĻĻāĻŋāĻ¯āĻŧā§ āĻĒā§āĻ°āĻŦāĻžāĻšāĻŋāĻ¤ āĻāĻ°āĻžāĻ¯āĻŧ āĻĒāĻžāĻ¨āĻŋāĻ° āĻā§āĻ˛āĻž āĻāĻžāĻŦ āĻā§āĻā§ āĻā§āĻ˛āĨ¤ āĻŦāĻŋāĻāĻžāĻ°ā§āĻ° āĻĒāĻžāĻ¨āĻŋāĻ¤ā§ āĻāĻŋ āĻŦāĻ¸ā§āĻ¤ā§ āĻāĻŋāĻ˛?
- White flower
- \(\mathrm{CaCO}_{3}\)
- \(\mathrm{BaSO}_{4}\)
- mud
Ans. \(\mathrm{CaCO}_{3}\)
- \(2 \mathrm{NO}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{~g}) = 2 \mathrm{~N} 0_{2}(\mathrm{~g})\) āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻžāĻāĻŋāĻ° āĻĒāĻ°ā§āĻā§āĻˇāĻž āĻāĻ°ā§ āĻ¨āĻŋāĻ°ā§āĻŖā§āĻ¤ āĻāĻ¤āĻŋ āĻ¸āĻŽā§āĻāĻ°āĻŖ, \(\mathbf{v}=\mathbf{k}[\mathbf{N O}]^{2}\left[\mathbf{O}_{2}\right] ;[\mathbf{N O}]\) āĻāĻ° āĻĒāĻ°āĻŋāĻŽāĻžāĻŖ āĻāĻā§āĻ° āĻā§āĻ¯āĻŧā§ āĻĻā§āĻŦāĻŋāĻā§āĻŖ āĻāĻ°āĻž āĻšāĻ˛ā§ āĻāĻĻāĻŋ āĻŦā§āĻā§āĻ° āĻāĻŋ āĻĒāĻ°āĻŋāĻŦāĻ°ā§āĻ¤āĻ¨ āĻšāĻŦā§āĨ¤
- āĻ āĻĒāĻ°āĻŋāĻŦāĻ°ā§āĻ¤āĻŋāĻ¤ āĻĨāĻžāĻāĻŦā§
- āĻĻā§āĻŦāĻŋāĻā§āĻŖ āĻšāĻŦā§
- āĻ¤āĻŋāĻ¨āĻā§āĻŖ āĻšāĻŦā§
- āĻāĻžāĻ°āĻā§āĻŖ āĻšāĻŦā§
Ans. āĻāĻžāĻ°āĻā§āĻŖ āĻšāĻŦā§
- NaOH, \(\mathrm{Na}_{2} \mathrm{CO}_{3}, \mathrm{NH}_{4} \mathrm{Cl}\) āĻāĻŦāĻ \(\mathrm{CH}_{3} \mathrm{COOH}\) āĻāĻ° 0.01 M āĻāĻ˛ā§āĻ¯āĻŧ āĻĻā§āĻ°āĻŦāĻŖāĻā§āĻ˛ā§āĻā§ āĻ¸āĻā§āĻ°āĻŋāĻ¯āĻŧāĻ¤āĻž āĻŦā§āĻĻā§āĻ§āĻŋāĻ° āĻā§āĻ°āĻŽāĻžāĻ¨ā§āĻ¸āĻžāĻ°ā§ āĻ¸āĻžāĻāĻžāĻ¨ā§ āĻļā§āĻĻā§āĻ§ āĻāĻ¤ā§āĻ¤āĻ°āĻāĻŋ āĻŦā§āĻā§ āĻ¨āĻžāĻāĨ¤
- \(\mathrm{NaOH}, \mathrm{Na}_{2} \mathrm{CO}_{3}, \mathrm{NH}_{4} \mathrm{Cl}, \mathrm{CH}_{3} \mathrm{COOH}\)
- \(\mathrm{Na}_{2} \mathrm{CO}_{3}, \mathrm{NH}_{4} \mathrm{Cl}, \mathrm{CH}_{3} \mathrm{COOH}, \mathrm{NaOH}\)
- \(\mathrm{NH}_{4} \mathrm{Cl}, \mathrm{CH}_{3} \mathrm{COOH}, \mathrm{NaOH}, \mathrm{Na}_{2} \mathrm{CO}_{3}\)
- \(\mathrm{CH}_{3} \mathrm{COOH}, \mathrm{NH}_{4} \mathrm{Cl} \mathrm{Na}_{2} \mathrm{CO}_{3}, \mathrm{NaOH}\)
Ans. \(\mathrm{Na}_{2} \mathrm{CO}_{3}, \mathrm{NH}_{4} \mathrm{Cl}, \mathrm{CH}_{3} \mathrm{COOH}, \mathrm{NaOH}\)
- āĻ¨āĻŋāĻā§ āĻĻā§āĻ¯āĻŧāĻž āĻā§āĻ¨ āĻāĻ˛ā§āĻāĻā§āĻ°āĻ¨ āĻŦāĻŋāĻ¨ā§āĻ¯āĻžāĻ¸āĻāĻŋ āĻ¸āĻ āĻŋāĻ āĻ¨āĻž?
- \(\mathrm{Ar}(18) \rightarrow 1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{6} 3 \mathrm{~s}^{2} 3 \mathrm{p}^{6}\)
- \(\mathrm{K}(19) \rightarrow[\mathrm{Ar}] 4 \mathrm{~s}^{1}\)
- \(\mathrm{Fe}(26) \rightarrow[\mathrm{Ar}] 4 \mathrm{~s}^{2} 4 \mathrm{p}^{6}\)
- \(\mathrm{Cu}(29) \rightarrow[\mathrm{Ar}] 3 \mathrm{~d}^{10} 4 \mathrm{~s}^{1}\)
Ans. \(\mathrm{Fe}(26) \rightarrow[\mathrm{Ar}] 4 \mathrm{~s}^{2} 4 \mathrm{p}^{6}\)
- āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¯āĻŧāĻžāĻ¨ā§āĻāĻžāĻŽ āĻ¸āĻāĻā§āĻ¯āĻžāĻā§āĻ˛ā§āĻ° āĻā§āĻ¨ āĻ¸ā§āĻāĻāĻŋ āĻ¨āĻŋāĻˇāĻŋāĻĻā§āĻ§āĨ¤
- \(\mathrm{n}=1, l=0, \mathrm{~m}=0, \mathrm{~s}=+1 / 2\)
- \(\mathrm{n}=3, l=2, \mathrm{~m}=2, \mathrm{~s}=-1 / 2\)
- \(\mathrm{n}=2, l=2, \mathrm{~m}=+2, \mathrm{~s}=+1 / 2\)
- \(\mathrm{n}=4, l=2, \mathrm{~m}=0, \mathrm{~s}=-1 / 2\)
Ans. \(\mathrm{n}=2, l=2, \mathrm{~m}=+2, \mathrm{~s}=+1 / 2\)
- āĻāĻāĻāĻŋ āĻ¨āĻ˛āĻā§āĻĒā§āĻ° āĻĒāĻžāĻ¨āĻŋ āĻŦāĻŋāĻļā§āĻ˛ā§āĻˇāĻŖ āĻāĻ°ā§ L āĻĒāĻžāĻ¨āĻŋāĻ¤ā§ 0.030 g āĻāĻ°ā§āĻ¸ā§āĻ¨āĻŋāĻ āĻĒāĻžāĻāĻ¯āĻŧāĻž āĻā§āĻ˛āĨ¤ āĻ āĻĒāĻžāĻ¨āĻŋāĻ¤ā§ āĻāĻ°ā§āĻ¸ā§āĻ¨āĻŋāĻā§āĻ° āĻāĻ¨āĻŽāĻžāĻ¤ā§āĻ°āĻžāĨ¤
- 3 ppm
- 300 ppm
- 30 ppm
- 3000 ppm
Ans. 30 ppm
- ML āĻāĻāĻāĻŋ āĻĻāĻžāĻ¨āĻžāĻĻāĻžāĻ° āĻ¯ā§āĻāĨ¤ āĻāĻ° āĻĒāĻžāĻ¨āĻŋāĻ¤ā§ āĻĻā§āĻ°āĻŦā§āĻā§āĻ¤ āĻšāĻŦāĻžāĻ° āĻĒāĻ°ā§āĻ¯āĻžāĻ¯āĻŧ āĻ āĻ¸āĻāĻļā§āĻ˛āĻŋāĻˇā§āĻ āĻāĻ¨āĻĨāĻžāĻ˛āĻĒāĻŋ āĻ¨āĻŋāĻā§ āĻĻā§āĻ¯āĻŧāĻž āĻšāĻ˛ā§āĨ¤ āĻ¯ā§āĻāĻāĻŋāĻ° āĻĒāĻžāĻ¨āĻŋ āĻ¯ā§āĻāĻ¨ āĻāĻ¨ā§āĻĨāĻžāĻ˛āĻĒāĻŋ \(\Delta \mathbf{H}_{1}\) (āĻāĻŋāĻ˛ā§āĻā§āĻ˛ā§) āĻāĻ¤?
\(\mathrm{ML}(\mathrm{s})+\) āĻĒāĻžāĻ¨āĻŋ \(\rightarrow \mathrm{ML}(\mathrm{aq}), \Delta \mathrm{H}=-50 \mathrm{kj}\)
\(\mathrm{ML}(\mathrm{s})+\mathrm{x} . \mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{MB} \cdot \mathrm{xH}_{2} \mathrm{O}, \Delta \mathrm{H}_{1}=?\)
\(\mathrm{MB} \cdot \mathrm{xH}_{2} \mathrm{O}(\mathrm{s})+\) āĻĒāĻžāĻ¨āĻŋ \(\rightarrow \mathrm{ML}(\mathrm{aq}), \Delta \mathrm{H}_{1}=+10 \mathrm{kj}\)- +60
- -60
- -40
- +40
Ans. -60
- 10.0 mL 0.2 M \(\mathrm{KMn} 0_{4}\) -āĻāĻ° āĻāĻ˛ā§āĻ¯āĻŧ āĻĻā§āĻ°āĻŦāĻŖ āĻāĻ¤ mL 0.2M \(\mathrm{Na}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\) āĻāĻ° āĻāĻ˛ā§āĻ¯āĻŧ āĻĻā§āĻ°āĻŦāĻŖā§ āĻ¯ā§āĻ āĻāĻ°āĻ˛ā§ āĻāĻ° \(\mathrm{Na}_{2} \mathrm{C}_{2} \mathrm{O}_{4}\) āĻ¸āĻŽā§āĻĒā§āĻ°ā§āĻŖ āĻāĻžāĻ°āĻŋāĻ¤ āĻšāĻŦā§āĨ¤
- 25
- 10
- 20
- 50
Ans. 25
- āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻž āĻŦā§āĻĻā§āĻ§āĻŋāĻ° āĻ¸āĻžāĻĨā§ āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻžāĻ° āĻŦā§āĻ āĻŦā§āĻĻā§āĻ§āĻŋāĻ° āĻĒā§āĻ°āĻ§āĻžāĻ¨ āĻāĻžāĻ°āĻŖ-
- āĻŦā§āĻļāĻŋ āĻ¸āĻāĻā§āĻ¯āĻ āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻ āĻ āĻŖā§ āĻļāĻā§āĻ¤āĻŋ āĻ āĻ°ā§āĻāĻ¨ āĻāĻ°ā§ āĻ¸āĻā§āĻ°āĻŋāĻ¯āĻŧ āĻšāĻ¯āĻŧāĨ¤
- āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻžāĻ° āĻ¸āĻā§āĻ°āĻŋāĻ¯āĻŧāĻŖ āĻļāĻā§āĻ¤āĻŋ āĻŦā§āĻĻā§āĻ§āĻŋ āĻĒāĻžāĻāĻ¯āĻŧāĻž
- āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻžāĻ° āĻ¸āĻā§āĻ°āĻŋāĻ¯āĻŧāĻŖ āĻļāĻā§āĻ¤āĻŋ āĻšā§āĻ°āĻžāĻ¸ āĻĒāĻžāĻāĻ¯āĻŧāĻž
- āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻž āĻ āĻŖā§āĻ¸āĻŽā§āĻšā§āĻ° āĻāĻ¨ā§āĻ¤-āĻāĻŖāĻŦāĻŋāĻ āĻĻā§āĻ°āĻ¤ā§āĻŦ āĻšā§āĻ°āĻžāĻ¸ āĻĒāĻžāĻāĻ¯āĻŧāĻžāĨ¤
Ans. āĻŦā§āĻļāĻŋ āĻ¸āĻāĻā§āĻ¯āĻ āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻ āĻ āĻŖā§ āĻļāĻā§āĻ¤āĻŋ āĻ āĻ°ā§āĻāĻ¨ āĻāĻ°ā§ āĻ¸āĻā§āĻ°āĻŋāĻ¯āĻŧ āĻšāĻ¯āĻŧāĨ¤
- āĻ¨āĻŋāĻ°ā§āĻĻāĻŋāĻˇā§āĻ āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻžāĻ¯āĻŧ āĻāĻāĻāĻŋ āĻŦāĻ¸ā§āĻ¤ā§āĻ° 60g āĻ¸āĻŽā§āĻĒā§āĻā§āĻ¤ āĻĻā§āĻ°āĻŦāĻŖ āĻļā§āĻāĻŋāĻ¯āĻŧā§ āĻĢā§āĻ˛āĻžāĻ° āĻĒāĻ° 10 g āĻ¤āĻ˛āĻžāĻ¨āĻŋ āĻĒāĻžāĻāĻ¯āĻŧāĻž āĻ¯āĻžāĻ¯āĻŧāĨ¤ āĻāĻā§āĻ¤ āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻžāĻ¯āĻŧ āĻĻā§āĻ°āĻŦā§āĻā§āĻ¤ āĻŦāĻ¸ā§āĻ¤ā§āĻāĻŋāĻ° āĻĻā§āĻ°āĻžāĻŦā§āĻ¯āĻ¤āĻž āĻāĻ¤? (āĻĒā§āĻ°āĻ¤āĻŋ 100 g āĻĻā§āĻ°āĻžāĻŦāĻā§)
- 25
- 15
- 20
- 22
Ans. 20
- āĻāĻ āĻ
ā§āĻ¯āĻžāĻāĻŽā§āĻ¸ā§āĻĢāĻŋāĻ¯āĻŧāĻžāĻ° āĻāĻžāĻĒā§ āĻ āĻ¨āĻŋāĻ°ā§āĻĻāĻŋāĻˇā§āĻ āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻžāĻ¯āĻŧ āĻāĻāĻāĻŋ āĻ¨āĻŋāĻ°ā§āĻĻāĻŋāĻˇā§āĻ āĻāĻ¯āĻŧāĻ¤āĻ¨ā§āĻ° āĻĒāĻžāĻ¤ā§āĻ°ā§ 4 g āĻšāĻŋāĻ˛āĻŋāĻ¯āĻŧāĻžāĻŽ 14 g āĻ¨āĻžāĻāĻā§āĻ°ā§āĻā§āĻ¨ āĻāĻŦāĻ 16g āĻ
āĻā§āĻ¸āĻŋāĻā§āĻ¨ āĻāĻŦāĻĻā§āĻ§ āĻāĻā§āĨ¤ āĻā§āĻ¨āĻāĻŋāĻ° āĻāĻāĻļāĻŋāĻ āĻāĻžāĻĒ āĻ¸āĻ°ā§āĻŦā§āĻā§āĻ?
- āĻ¨āĻžāĻāĻā§āĻ°ā§āĻā§āĻ¨
- āĻ āĻā§āĻ¸āĻŋāĻā§āĻ¨
- āĻšāĻŋāĻ˛āĻŋāĻ¯āĻŧāĻžāĻŽ
- āĻ¸āĻāĻ˛ā§āĻ° āĻāĻāĻļāĻŋāĻ āĻāĻžāĻĒ āĻ¸āĻŽāĻžāĻ¨
Ans. āĻšāĻŋāĻ˛āĻŋāĻ¯āĻŧāĻžāĻŽ
- āĻāĻ°ā§āĻ¸ā§āĻ¨āĻŋāĻ (As) āĻĢāĻ¸āĻĢāĻ°āĻžāĻ¸ (P) āĻĒāĻ°āĻŋāĻŦāĻžāĻ°ā§āĻ° āĻāĻāĻāĻŋ āĻŽā§āĻ˛āĨ¤ āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¨ āĻ¸āĻāĻā§āĻ¤āĻāĻŋ āĻāĻ¸ā§āĻ¨āĻŋāĻ āĻāĻ¸āĻŋāĻĄā§āĻ°āĨ¤
- \(\mathrm{H}_{2} \mathrm{AsO}_{4}\)
- \(\mathrm{H}_{3} \mathrm{AsO}_{3}\)
- \(\mathrm{H}_{3} \mathrm{AsO}_{4}\)
- \(\mathrm{H}_{3} \mathrm{AsO}_{2}\)
Ans. \(\mathrm{H}_{3} \mathrm{AsO}_{4}\)
- \(\mathrm{CH}_{4}\) āĻ \(\mathbf{N H}_{3}\) āĻāĻ° āĻŽāĻ§ā§āĻ¯ā§ C āĻ N āĻāĻ° āĻ¸āĻāĻāĻ°āĻŖ āĻ
āĻŦāĻ¸ā§āĻĨāĻžāĻā§āĻ˛ā§ āĻšāĻ˛ā§āĨ¤
- \(\mathrm{C}\) is \(\mathrm{sp}^{3}, \mathrm{~N}\) is \(\mathrm{sp}^{2}\)
- \(\mathrm{C}\) is \(\mathrm{sp}^{2} \mathrm{~N}\) is \(\mathrm{sp}^{3}\)
- Both are sp \(^{2}\)
- Both are sp \(^{3}\)
Ans. Both are sp \(^{3}\)
-
\(\mathbf{Q} \stackrel{\alpha}{\longrightarrow} \mathbf{R} \stackrel{\beta}{\longrightarrow} \mathbf{L} \stackrel{\gamma}{\longrightarrow} \mathbf{D}\) āĻāĻĒāĻžā§ā§ Q āĻ¤ā§āĻāĻ¸ā§āĻā§āĻ°āĻŋāĻ¯āĻŧ āĻāĻāĻ¸ā§āĻā§āĻĒāĨ¤ āĻāĻāĻ¸ā§āĻā§āĻĒāĻā§āĻ˛ā§āĻ° āĻāĻ° āĻ āĻĒā§āĻ°ā§āĻāĻ¨ āĻ¸āĻāĻā§āĻ¯āĻžāĻ° āĻāĻŋāĻ¤ā§āĻ¤āĻŋāĻ¤ā§ āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¨āĻāĻŋ āĻ¸āĻ āĻŋāĻāĨ¤
- Q = L
- R = L
- Q = L
- L = D
Ans. L = D
- \(\mathbf{H}_{2}(\mathrm{~g})+\mathbf{I}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{HI}(\mathrm{g}) \Delta \mathbf{H}=-13 \mathrm{~kJ} / \mathrm{mol}\) āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻžāĻāĻŋ 100°C āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻžāĻ¯āĻŧ āĻ¸āĻžāĻŽā§āĻ¯āĻžāĻŦāĻ¸ā§āĻĨāĻžāĻ¯āĻŧ āĻāĻ¸ā§ āĨ¤ āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¨ āĻ
āĻŦāĻ¸ā§āĻĨāĻžāĻāĻŋāĻ° āĻāĻ¨ā§āĻ¯ āĻšāĻžāĻāĻĄā§āĻ°ā§āĻā§āĻ¨ āĻā§ā§āĻĄāĻžāĻāĻĄā§āĻ° āĻļāĻ¤āĻāĻ°āĻž āĻšāĻžāĻ° āĻ¸āĻžāĻŽā§āĻ¯ āĻŽāĻŋāĻļā§āĻ°āĻŖā§ āĻŦā§āĻĄāĻŧā§ āĻ¯āĻžāĻŦā§?
- āĻāĻžāĻĒ āĻāĻŽāĻ˛ā§
- āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻž āĻāĻŽāĻ˛ā§
- āĻāĻžāĻĒ āĻŦāĻžāĻĄāĻŧāĻ˛ā§
- āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻž āĻŦāĻžāĻĄāĻŧāĻ˛ā§
Ans. āĻ¤āĻžāĻĒāĻŽāĻžāĻ¤ā§āĻ°āĻž āĻāĻŽāĻ˛ā§
- āĻ¨āĻŋāĻā§āĻ° āĻ¯ā§āĻāĻā§āĻ˛āĻŋāĻ° āĻā§āĻ¨āĻāĻŋ āĻšā§āĻĒā§āĻā§āĻ¨ā§āĻ° āĻ¸āĻŽāĻžāĻŖā§ āĻ¨āĻ¯āĻŧāĨ¤
- 2-methyl hexane
- 2,2-dimethyl pentane
- 2,3 – dimethyl butane
- 2,3 – dimethyl pentane
Ans. 2,3 – dimethyl butane
- \(\mathrm{C}_{2} \mathrm{H}_{4} \mathrm{O}_{2}\) āĻāĻŖāĻŦāĻŋāĻ āĻ¸āĻāĻā§āĻ¤ āĻŦāĻŋāĻļāĻŋāĻˇā§āĻ āĻāĻāĻāĻŋ āĻ¯ā§āĻā§āĻ° āĻāĻ˛ā§āĻ¯āĻŧ āĻĻā§āĻ°āĻŦāĻŖ āĻ¸ā§āĻĄāĻŋāĻ¯āĻŧāĻžāĻŽ āĻāĻžāĻ°ā§āĻŦāĻ¨ā§āĻā§āĻ° āĻ¸āĻžāĻĨā§ āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻž āĻāĻ°ā§ \(\mathrm{CO}_{2}\) āĻā§āĻĒāĻ¨ā§āĻ¨ āĻāĻ°ā§āĨ¤ āĻ¯ā§āĻāĻāĻŋāĻ° āĻāĻžāĻ āĻ¨āĻŋāĻ āĻ¸āĻāĻā§āĻ¤ āĻāĻŋ?
- \(\mathrm{CH}_{2}=\mathrm{CH}-\mathrm{OH}\)
- \(\mathrm{H}_{2} \mathrm{CO}_{2} \mathrm{CH}_{2}\)
- \(\mathrm{CH}_{3}-\mathrm{CO}-\mathrm{OH}\)
- \(\mathrm{CH}-\mathrm{CO}-\mathrm{CH}_{3}\)
Ans. \(\mathrm{CH}_{3}-\mathrm{CO}-\mathrm{OH}\)
- Starch \(\stackrel{\text { Stage } 1}{\longrightarrow}\) Simple sugar \(\stackrel{\text { Stage } 2}{\longrightarrow}\) ethanol
āĻ¸ā§āĻāĻžāĻ°ā§āĻ āĻĨā§āĻā§ āĻāĻĨāĻžāĻ¨āĻ˛ āĻ¤ā§āĻ°āĻŋāĻ° āĻāĻāĻāĻŋ āĻĒāĻĻā§āĻ§āĻ¤āĻŋāĨ¤ āĻĒāĻ°ā§āĻ¯āĻžāĻ¯āĻŧ āĻĻā§āĻāĻŋ āĻŦā§āĻāĻžāĻ¤ā§ āĻā§āĻ¨ āĻļāĻŦā§āĻĻ āĻ¯ā§āĻāĻ˛ āĻŦā§āĻ¯āĻŦāĻšāĻžāĻ° āĻāĻ°āĻž āĻšāĻ¯āĻŧāĨ¤- Cracking
- Fermentation
- Hydrolysis
- Polymerization
Ans. Fermentation
- \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) āĻāĻžāĻ°āĻŋāĻ¤ āĻšāĻ¯āĻŧā§ z āĻā§āĻĒāĻ¨ā§āĻ¨ āĻāĻ°ā§āĨ¤ Z \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\) āĻāĻ°
āĻ¸āĻžāĻĨā§ āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻž āĻāĻ°ā§ āĻāĻˇā§āĻāĻžāĻ° āĻ¤ā§āĻ°āĻŋ āĻāĻ°ā§āĨ¤ Z āĻāĻŋ?- \(\mathrm{HCOOH}\)
- \(\mathrm{CH}_{3} \mathrm{COOH}\)
- \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{COOH}\)
- \(\mathrm{CH}_{3} \mathrm{COOC}_{2} \mathrm{H}_{5}\)
Ans. \(\mathrm{CH}_{3} \mathrm{COOH}\)
- āĻĒā§āĻ°ā§āĻāĻŋāĻ¨ āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¨ āĻ¯ā§āĻā§āĻ° āĻĒāĻ˛āĻŋāĻŽāĻžāĻ°?
- \(\alpha\) – amino acid
- \(\alpha\) -D glucose
- Deoxyribonucleotide
- fatty acid
Ans. \(\alpha\) – amino acid
- āĻ
ā§āĻ¯āĻžāĻ¸āĻŋāĻāĻŋāĻ˛āĻŋāĻ¨ā§ āĻāĻžāĻ°ā§āĻŦāĻ¨, āĻāĻžāĻ°ā§āĻŦāĻ¨ āĻ¤ā§ā§°āĻŋāĻŦāĻ¨ā§āĻ§āĻ¨ā§āĻ° āĻŽāĻ§ā§āĻ¯ā§ āĻ¸āĻŋāĻāĻŽāĻž āĻŦāĻ¨ā§āĻ§āĻ¨ā§āĻ° āĻ¸āĻāĻā§āĻ¯āĻž āĻšāĻ˛ā§āĨ¤
- Three
- One
- Two
- Zero
Ans. One
- āĻ¨āĻŋāĻā§āĻ° āĻ¯ā§āĻāĻā§āĻ˛āĻŋāĻ° āĻā§āĻ¨āĻāĻŋ āĻ¸āĻŋ-āĻā§āĻ°āĻžāĻ¨ā§āĻ¸ āĻ¸āĻŽāĻžāĻŖā§ āĻ¸āĻŽā§āĻāĻŦ?
- \(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}_{2}\)
- \(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}_{2}\)
- \(\mathrm{CH}_{3}-\mathrm{CH}_{3}\)
- \(\mathrm{CH}_{3}-\mathrm{C}_{4} \mathrm{H}_{6}-\mathrm{CH}_{3}\)
Ans. \(\mathrm{CH}_{3}-\mathrm{C}_{4} \mathrm{H}_{6}-\mathrm{CH}_{3}\)
- āĻāĻ°ā§āĻŦāĻŋ āĻĨā§āĻā§ āĻ¸āĻžāĻŦāĻžāĻ¨ āĻ¤ā§āĻ°āĻŋ āĻāĻ°āĻžāĻ° āĻāĻ¨ā§āĻ¯ āĻā§āĻ¨ āĻ§āĻ°āĻ¨ā§āĻ° āĻŦāĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻž āĻ¸āĻāĻāĻāĻŋāĻ¤ āĻšāĻ¯āĻŧāĨ¤
- Hydrolysis
- Polymerization
- Fermentation
- Substitution
Ans. Hydrolysis
- āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¨ āĻ¯ā§āĻāĻāĻŋāĻ° āĻ¨āĻžāĻŽ IUPAC āĻĒāĻĻā§āĻ§āĻ¤āĻŋāĻ¤ā§ āĻ¸āĻ āĻŋāĻ āĻāĻžāĻŦā§ āĻ˛āĻŋāĻāĻž āĻšāĻ¯āĻŧāĻ¨āĻŋāĨ¤
- \(\mathrm{CH}_{3} \mathrm{CHClCH}_{2} \mathrm{OH}:\) 2- chloropropane- \(\mathrm{l}-\mathrm{ol}\)
- \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHClCH}_{2} \mathrm{OH}\) : 3- chlorobutane – 1 -ol
- \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}-\mathrm{CH}_{3}: 2\) – methyl hexane
- \(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}-\mathrm{CH}_{2}-\mathrm{CH}_{3}: 3\) – methyl hexane
Ans. \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CHClCH}_{2} \mathrm{OH}\) : 3- chlorobutane – 1 -ol
- āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¨ āĻ¸ā§āĻāĻāĻŋāĻ° āĻāĻ¯āĻŧāĻ¨āĻ¸āĻŽā§āĻš āĻ¸āĻŽ-āĻāĻ˛ā§āĻāĻā§āĻ°āĻ¨āĻŋāĻ?
- \(\mathrm{Mg}^{2+}, \mathrm{Ca}^{2+}, \mathrm{Sr}^{2+}\)
- \(\mathrm{F}^{-}, \mathrm{Cl}^{-}, \mathrm{Br}^{-}\)
- \(\mathrm{N}^{3-}, \mathrm{O}^{2-}, \mathrm{F}^{-}\)
- \(\mathrm{Al}^{3+}, \mathrm{Fe}^{3+}, \mathrm{CR}^{3+}\)
Ans. \(\mathrm{N}^{3-}, \mathrm{O}^{2-}, \mathrm{F}^{-}\)
Mathematics
- \(\sin 65^{\circ}+\cos 65^{\circ}\) āĻŽāĻžāĻ¨ –
- \(\frac{\sqrt{3}}{2} \cos 40^{\circ}\)
- \(\frac{1}{2} 20^{\circ}\)
- \(\sqrt{2} \cos 20^{\circ}\)
- \(\frac{\sqrt{3}}{2} 40^{\circ}\)
Ans. \(\sqrt{2} \cos 20^{\circ}\)
- \(\left(a+\frac{1}{a}\right)^{18}\) )āĻāĻ° āĻŦāĻŋāĻ¸ā§āĻ¤ā§āĻ¤āĻŋāĻ¤ā§ a° āĻāĻ° āĻ¸āĻšāĻ āĻāĻ¤?
- 48920
- 48620
- 48640
- 48720
Ans. 48620
- \(3 x^{2}-7 y^{2}+4 x y-8 x=0\) āĻŦāĻā§āĻ°āĻ°ā§āĻāĻžāĻāĻŋāĻ° (-1, 1) āĻŦāĻŋāĻ¨ā§āĻĻā§āĻ¤ā§ āĻ
āĻā§āĻāĻŋāĻ¤ āĻ¸ā§āĻĒāĻ°ā§āĻļāĻā§āĻ° āĻĸāĻžāĻ˛-
- \(-\frac{5}{9}\)
- \(-\frac{5}{6}\)
- \(-\frac{9}{5}\)
- \(\frac{9}{5}\)
Ans. \(-\frac{5}{9}\)
- (1, -1) āĻŦāĻŋāĻ¨ā§āĻĻā§āĻāĻžāĻŽā§ āĻāĻŦāĻ 2x – 3y + 6 = 0 āĻ°ā§āĻāĻžāĻ° āĻāĻĒāĻ° āĻ˛āĻŽā§āĻŦ āĻ¸āĻ°āĻ˛āĻ°ā§āĻāĻžāĻ° āĻ¸āĻŽā§āĻāĻ°āĻŖāĨ¤
- 3y + 2x = -5
- 2x + 3y = -1
- 2y – 3x = 1
- 3x + 2y = 1
Ans. 3x + 2y = 1
- \(\left(\begin{array}{cc}x-y & 7 \\ 7 & x+y\end{array}\right)=\left(\begin{array}{ll}8 & 1 \\ 7 & 2\end{array}\right)\) āĻšāĻ˛ā§, (x, y) =?
- (-5,-3)
- (5,-3)
- (-5,3)
- (5,3)
Ans. (5,-3)
- āĻ¨ā§āĻā§āĻ° āĻā§āĻ¨ āĻ°āĻžāĻļāĻŋāĻŽāĻžāĻ˛āĻžāĻāĻŋ cos3A āĻā§ cosA āĻŦāĻž sinA āĻāĻ° āĻŦāĻšā§āĻĒāĻĻā§ āĻ°ā§āĻĒā§ āĻĒā§āĻ°āĻāĻžāĻļ āĻāĻ°ā§-
- \(3 \cos A-4 \cos ^{3} A\)
- \(4 \cos ^{3} A-3 \cos A\)
- \(3 \sin A-4 \sin ^{3} A\)
- \(4 \sin ^{3} A-4 \sin ^{3} A\)
Ans. \(4 \cos ^{3} A-3 \cos A\)
- \(\omega\) āĻ¯āĻĻāĻŋ āĻāĻāĻā§āĻ° āĻāĻāĻāĻŋ āĻāĻāĻŋāĻ˛ (āĻāĻžāĻ˛ā§āĻĒāĻ¨āĻŋāĻ) āĻāĻ¨āĻŽā§āĻ˛ āĻšāĻ¯āĻŧ āĻ¤āĻŦā§ \(\left(1-\omega+\omega^{2}\right)\left(1-\omega^{2}+\omega^{4}\right)=?\)
- 4
- 6
- 3
- 2
Ans. 4
- āĻāĻ āĻĒā§āĻ¯āĻžāĻā§āĻ āĻ¤āĻžāĻ¸ āĻĨā§āĻā§ āĻāĻāĻāĻŋ āĻ¤āĻžāĻ¸ āĻĻā§āĻŦāĻāĻžāĻŦā§ āĻ¨ā§āĻāĻ¯āĻŧāĻž āĻšāĻ˛ā§āĨ¤ āĻ¤āĻžāĻ¸āĻāĻŋ āĻšāĻ°āĻ¤āĻ¨ āĻŦāĻž āĻāĻŋāĻ°āĻžāĻ¤āĻ¨ āĻšāĻāĻ¯āĻŧāĻžāĻ° āĻ¸āĻŽā§āĻāĻžāĻŦāĻ¨āĻž āĻāĻ¤?
- \(\frac{1}{2}\)
- 2
- \(\frac{4}{13}\)
- \(\frac{1}{4}\)
Ans. \(\frac{1}{2}\)
- \(\int \frac{d x}{x+\sqrt{x}}=?\)
- \(\ln (\sqrt{x}+1)+c)\)
- \(\tan ^{-1}(\sqrt{x}+1)+c\)
- \(2 \ln (\sqrt{x}+1)+c\)
- \(2 \tan ^{-1}(\sqrt{x}+1)+c\)
Ans. \(2 \ln (\sqrt{x}+1)+c\)
- \(\lambda\) āĻāĻ° āĻā§āĻ¨ āĻŽāĻžāĻ¨ā§āĻ° āĻāĻ¨ā§āĻ¯ \(4 \hat{\mathbf{i}}+2 \hat{\mathbf{j}}-3 \hat{\mathbf{k}}\) āĻāĻŦāĻ \(\lambda \hat{\mathbf{i}}-3 \hat{\mathbf{j}}+2 \hat{\mathbf{k}}\) āĻā§āĻā§āĻāĻ°āĻĻā§āĻŦāĻ¯āĻŧ āĻĒāĻ°āĻ¸ā§āĻĒāĻ° āĻ˛āĻŽā§āĻŦ āĻšāĻŦā§?
- -3
- 3
- -12
- 12
Ans. 3
- āĻŦāĻžāĻ¸ā§āĻ¤āĻŦ āĻ¸āĻāĻā§āĻ¯āĻžāĻ¯āĻŧ: 0 <|x-3|< 4 āĻāĻ° āĻ¸āĻŽāĻžāĻ§āĻžāĻ¨ āĻ¸ā§āĻāĻ
- \(\{x:-1< x>7\}\)
- \(\{x:-1 \leq x \geq 7\}\)
- \(\{x:-1< x<3\} \cap\{x: 3< x<7\}\)
- \(\{x:-1< x<3\} \cup\{x: 3< x<7\}\)
Ans. \(\{x:-1< x<3\} \cup\{x: 3< x<7\}\)
-
\(y=\cos (\sqrt{x})\) āĻšāĻ˛ā§, āĻ¤āĻāĻ¨ \(\frac{d y}{d x}=?\)
- \(\sin (\sqrt{x})\)
- \(-\sin (\sqrt{x})\)
- \(-\frac{\sin (\sqrt{x})}{\sqrt{x}}\)
- \(-\frac{\sin (\sqrt{x})}{2 \sqrt{x}}\)
Ans. \(-\frac{\sin (\sqrt{x})}{2 \sqrt{x}}\)
- (- 9, 9) āĻāĻŦāĻ (5, 5) āĻŦāĻŋāĻ¨ā§āĻĻā§āĻĻā§āĻŦāĻ¯āĻŧā§āĻ° āĻ¸āĻāĻ¸āĻžāĻ¯ā§āĻāĻ āĻ°ā§āĻāĻžāĻāĻļāĻā§ āĻŦā§āĻ¯āĻžāĻ¸ āĻ§āĻ°ā§ āĻ
āĻāĻā§āĻāĻŋāĻ¤ āĻŦā§āĻ¤ā§āĻ¤ā§āĻ° āĻ¸āĻŽā§āĻāĻ°āĻŖ-
- \(x^{2}+y^{2}-4 x+14 y=0\)
- \(x^{2}+y^{2}-4 x-14 y=0\)
- \(x^{2}+y^{2}+4 x+14 y=0\)
- \(x^{2}+y^{2}+4 x-14 y=0\)
Ans. \(x^{2}+y^{2}+4 x-14 y=0\)
-
p āĻāĻ° āĻāĻŋāĻ°ā§āĻĒ āĻŽāĻžāĻ¨ā§āĻ° āĻāĻ¨ā§āĻ¯ \(\mathbf{x}^{2}+\mathbf{p x}+\mathbf{1}=\mathbf{0}\) āĻ¸āĻŽā§āĻāĻ°āĻŖāĻāĻŋāĻ° āĻŽā§āĻ˛āĻĻā§āĻŦā§ āĻāĻāĻŋāĻ˛ āĻšāĻŦā§?
- \(-2 \leq p \leq 2\)
- \(-4< p \leq 4\)
- \(-2<\mathrm{p}<2\)
- \(-4 \leq \mathrm{p}<2\)
Ans. \(-2<\mathrm{p}<2\)
- āĻ¨āĻŋāĻŽā§āĻ¨ā§āĻā§āĻ¤ āĻ°āĻžāĻļāĻŋāĻŽāĻžāĻ˛āĻžāĻāĻŋāĻ° āĻŽāĻžāĻ¨:\(1+\omega+\omega^{2}=?\)
- -1
- 0
- 1
- \(\frac{1}{2}\)
Ans. 0
- āĻĒā§āĻ°āĻā§āĻˇā§āĻĒāĻā§āĻ° āĻā§āĻ°āĻŽāĻŖāĻāĻžāĻ˛ T, āĻāĻ¨ā§āĻā§āĻŽāĻŋāĻ āĻĒāĻžāĻ˛ā§āĻ˛āĻž R āĻāĻŦāĻ āĻ
āĻ¨ā§āĻā§āĻŽāĻŋāĻā§āĻ° āĻ¸āĻā§āĻā§ āĻĒā§āĻ°āĻā§āĻˇā§āĻĒāĻŖ āĻā§āĻŖ \(\alpha \) āĻšāĻ˛ā§,\(\frac{T^{2}}{R}=?\)
- \(-\frac{2}{\mathrm{~g}} \tan \alpha\)
- \(-\frac{2}{\mathrm{~g}} \cot \alpha\)
- \(\frac{2}{g} \tan \alpha\)
- \(\frac{2}{\mathrm{~g}} \cot \alpha\)
Ans. \(\frac{2}{g} \tan \alpha\)
- 3x+4y = 10 āĻ°ā§āĻāĻžāĻāĻŋāĻ° āĻāĻĒāĻ° āĻŽā§āĻ˛āĻŦāĻŋāĻ¨ā§āĻĻā§ āĻšāĻ¤ā§ āĻ
āĻāĻāĻŋāĻ¤ āĻ˛āĻŽā§āĻŦā§āĻ° āĻĻā§āĻ°ā§āĻā§āĻ¯-
- 2
- \(\sqrt{2}\)
- 5
- \(\sqrt{5}\)
Ans. 2
- 4 āĻāĻ¨ āĻŽāĻšāĻŋāĻ˛āĻž āĻ 6 āĻāĻ¨ āĻĒā§āĻ°ā§āĻˇā§āĻ° āĻŽāĻ§ā§āĻ¯ āĻšāĻ¤ā§ 4 āĻ¸āĻĻāĻ¸ā§āĻ¯āĻŦāĻŋāĻļāĻŋāĻˇā§āĻ āĻāĻāĻāĻŋ āĻāĻĒāĻāĻŽāĻŋāĻāĻŋ āĻāĻ¤ āĻĒā§āĻ°āĻāĻžāĻ°ā§ āĻāĻ āĻ¨ āĻāĻ°āĻž āĻ¯āĻžāĻŦā§, āĻ¯āĻžāĻ¤ā§ āĻāĻāĻāĻ¨ āĻ¨āĻŋāĻ°ā§āĻĻāĻŋāĻˇā§āĻ āĻĒā§āĻ°ā§āĻˇ āĻ¸āĻ°ā§āĻŦāĻĻāĻžāĻ āĻ
āĻ¨ā§āĻ¤āĻ°ā§āĻā§āĻā§āĻ¤ āĻšāĻŦā§?
- 504
- 210
- 126
- 84
Ans. 84
- \(y^{2}=4 x\) āĻāĻŦāĻ y =x āĻĻā§āĻŦāĻžāĻ°āĻž āĻāĻŦāĻĻā§āĻ§ āĻā§āĻˇā§āĻ¤ā§āĻ°ā§āĻ° āĻā§āĻˇā§āĻ¤ā§āĻ°āĻĢāĻ˛-
- \(\frac{8}{3}\)
- 3
- 8
- \(\frac{3}{8}\)
Ans. \(\frac{8}{3}\)
-
\(\left|\begin{array}{ccc}-8 & 3 & 3 \\ 3 & -8 & 5 \\ 5 & 5 & -8\end{array}\right|\) āĻ¨āĻŋāĻ°ā§āĻŖāĻžāĻ¯āĻŧāĻāĻāĻŋāĻ° āĻŽāĻžāĻ¨-
- 1
- -1
- 0
- 2
Ans. 0
- āĻāĻāĻ āĻŦāĻŋāĻ¨ā§āĻĻā§āĻ¤ā§ āĻā§āĻ°āĻŋāĻ¯āĻŧāĻžāĻ°āĻ¤ 2 āĻāĻāĻ āĻ 3 āĻāĻāĻ āĻŽāĻžāĻ¨ā§āĻ° āĻĻā§āĻāĻāĻŋ āĻŦāĻ˛ā§āĻ° āĻ˛āĻŦā§āĻ§āĻŋ āĻŽāĻžāĻ¨ 4 āĻāĻāĻāĨ¤ āĻŦāĻ˛ āĻĻā§āĻāĻāĻŋāĻ° āĻ
āĻ¨ā§āĻ¤āĻ°ā§āĻā§āĻā§āĻ¤ āĻā§āĻŖ āĻāĻ¤?
- \(\cos ^{-1}\left(\frac{1}{4}\right)\)
- \(\cos ^{-1}\left(\frac{1}{2}\right)\)
- \(\cos ^{-1}\left(\frac{1}{3}\right)\)
- \(\cos ^{-1}\left(\frac{1}{5}\right)\)
Ans. \(\cos ^{-1}\left(\frac{1}{4}\right)\)
- \(\int_{1}^{e} \ln x d x\) āĻāĻ° āĻŽāĻžāĻ¨-
- e
- \(\mathrm{e}^{-1}\)
- \(\mathrm{e}^{+1}\)
- 1
Ans. 1
- āĻĻāĻļāĻŽāĻŋāĻ āĻ¸āĻāĻā§āĻ¯āĻž 123 āĻāĻ° āĻĻā§āĻŦāĻŋāĻŽāĻŋāĻ (āĻŦāĻžāĻāĻ¨āĻžāĻ°āĻŋ) āĻĒāĻĻā§āĻ§āĻ¤āĻŋāĻ¤ā§ āĻĒā§āĻ°āĻāĻžāĻļ-
- 1110111
- 1111011
- 1110110
- 1101111
Ans. 1111011
- āĻāĻāĻāĻŋ āĻā§āĻ˛āĻžāĻ¸ā§āĻ° 120 āĻāĻ¨ āĻāĻžāĻ¤ā§āĻ° āĻ¸āĻāĻ˛ā§āĻ āĻā§āĻ°āĻŋāĻā§āĻ āĻ
āĻĨāĻŦāĻž āĻĢā§āĻāĻŦāĻ˛ āĻ
āĻĨāĻŦāĻž āĻāĻāĻ¯āĻŧāĻ āĻā§āĻ˛ā§āĨ¤ 75 āĻāĻ¨ āĻā§āĻ°āĻŋāĻā§āĻ āĻā§āĻ˛ā§ āĻāĻŦāĻ 60 āĻāĻ¨āĨ¤ āĻĢā§āĻāĻŦāĻ˛ āĻā§āĻ˛ā§āĨ¤ āĻāĻ¤āĻāĻ¨ āĻāĻāĻ¯āĻŧāĻ āĻā§āĻ˛ā§?
- 13
- 15
- 25
- 23
Ans. 15
- āĻ¨ā§āĻā§āĻ° āĻā§āĻ¨āĻāĻŋ āĻ¸āĻ¤ā§āĻ¯ āĻāĻā§āĻ¤āĻŋ-
- \(\mathrm{A} / \mathrm{B}=\mathrm{A} \cup \mathrm{B}^{\prime}\)
- \(\mathrm{A} / \mathrm{B}=\mathrm{A} \cap \mathrm{B}^{\prime}\)
- \(\mathrm{A} / \mathrm{B}=\mathrm{A}^{\prime} \cup \mathrm{B}\)
- \(\mathrm{A} / \mathrm{B}=\mathrm{A}^{\prime} \cup \mathrm{B}\)
Ans. \(\mathrm{A} / \mathrm{B}=\mathrm{A} \cap \mathrm{B}^{\prime}\)
Biology
-
āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¨āĻāĻŋ āĻĻā§āĻŦāĻžāĻ°āĻž HIV āĻāĻ āĻŋāĻ¤?
- āĻĒā§āĻ°ā§āĻāĻŋāĻ¨ āĻ āĻ ā§āĻ¯āĻžāĻŽāĻŋāĻ¨ā§ āĻ ā§āĻ¯āĻžāĻ¸āĻŋāĻĄ
- āĻ¨āĻŋāĻāĻā§āĻ˛āĻŋāĻ āĻ ā§āĻ¯āĻžāĻ¸āĻŋāĻĄ
- āĻā§āĻ˛āĻžāĻāĻā§āĻĒā§āĻ°ā§āĻāĻŋāĻ¨ āĻ āĻ°āĻŋāĻāĻžāĻ°ā§āĻ¸ āĻā§āĻ°āĻžāĻ¨ā§āĻ¸āĻā§āĻ°āĻŋāĻĒā§āĻā§āĻ
- āĻĒā§āĻ°ā§āĻāĻŋāĻ¨ āĻ āĻāĻ°ā§āĻŦāĻŋ
Ans. āĻā§āĻ˛āĻžāĻāĻā§āĻĒā§āĻ°ā§āĻāĻŋāĻ¨ āĻ āĻ°āĻŋāĻāĻžāĻ°ā§āĻ¸ āĻā§āĻ°āĻžāĻ¨ā§āĻ¸āĻā§āĻ°āĻŋāĻĒā§āĻā§āĻ
- āĻā§āĻ¨āĻāĻŋ āĻāĻžāĻāĻ°āĻžāĻ¸āĻāĻ¨āĻŋāĻ¤ āĻ°ā§āĻ?
- āĻĒā§āĻ˛āĻŋāĻ
- āĻāĻ˛ā§āĻ°āĻž
- āĻāĻŋāĻā§āĻ¨āĻžāĻ¸
- āĻŦāĻā§āĻ˛āĻŋāĻāĻŽ
Ans. āĻĒā§āĻ˛āĻŋāĻ
- āĻā§āĻ¨ āĻā§āĻŦ āĻāĻŋāĻ¨āĻŋāĻā§ āĻŽāĻĻā§ āĻ°ā§āĻĒāĻžāĻ¨ā§āĻ¤āĻ°āĻŋāĻ¤ āĻāĻ°ā§?
- Spirogyra
- Saccharomyces
- Euglena
- Penicillium
Ans. Saccharomyces
- āĻ¸ā§āĻ¨ā§āĻĻāĻ°āĻŦāĻ¨ āĻŽā§āĻ¯āĻžāĻ¨āĻā§āĻ°ā§āĻ āĻ
āĻā§āĻāĻ˛ā§ āĻāĻ¯āĻŧāĻāĻŋ āĻāĻā§āĻ˛āĻāĻŋāĻā§āĻ¯āĻžāĻ˛ āĻā§āĻ¨ āĻāĻā§?
- āĻāĻāĻāĻŋ
- āĻĻā§āĻāĻāĻŋ
- āĻ¤āĻŋāĻ¨āĻāĻŋ
- āĻāĻžāĻ°āĻāĻŋ
Ans. āĻ¤āĻŋāĻ¨āĻāĻŋ
- āĻĢā§āĻ˛ā§ āĻŽāĻžā§ā§āĻ¸āĻŋāĻ¸ āĻšāĻ¯āĻŧ –
- āĻŦā§āĻ¤āĻŋāĻ¤ā§
- āĻĻāĻ˛ā§
- āĻĒā§āĻāĻā§āĻļāĻ°ā§
- āĻŦā§āĻāĻžā§
Ans. āĻĒā§āĻāĻā§āĻļāĻ°ā§
- āĻļā§āĻ°ā§āĻŖāĻŋāĻŦāĻŋāĻ¨ā§āĻ¯āĻžāĻ¸ā§ âSpeciesâ āĻļāĻŦā§āĻĻāĻāĻŋ āĻĒā§āĻ°āĻĨāĻŽ āĻā§ āĻŦā§āĻ¯āĻŦāĻšāĻžāĻ° āĻāĻ°ā§āĻ¨?
- Carolus Linnaeus
- John Rey
- De Candolle
- Earnst Mayr
Ans. Carolus Linnaeus
- āĻ¸āĻŽāĻĒāĻžāĻļā§āĻŦā§āĻ¯āĻŧ-āĻŽā§āĻā§āĻ¤ āĻāĻžāĻ¸ā§āĻā§āĻ˛āĻžāĻ° āĻŦāĻžāĻ¨ā§āĻĄāĻ˛ āĻĒāĻžāĻāĻ¯āĻŧāĻž āĻ¯āĻžāĻ¯āĻŧ –
- āĻĻā§āĻŦāĻŋāĻŦā§āĻāĻĒāĻ¤ā§āĻ°ā§ āĻāĻžāĻŖā§āĻĄā§
- āĻāĻāĻŦā§āĻāĻĒāĻ¤ā§āĻ°ā§ āĻāĻžāĻŖā§āĻĄā§
- āĻāĻāĻŦā§āĻāĻĒāĻ¤ā§āĻ°ā§ āĻŽā§āĻ˛ā§
- āĻĒāĻžāĻ¤āĻžāĻ¯āĻŧ
Ans. āĻĻā§āĻŦāĻŋāĻŦā§āĻāĻĒāĻ¤ā§āĻ°ā§ āĻāĻžāĻŖā§āĻĄā§
- āĻĒāĻžāĻ¨āĻŋ āĻ¸āĻāĻŦāĻšāĻ¨āĻ¤āĻ¨ā§āĻ¤ā§āĻ°ā§āĻ° āĻāĻĒāĻ¸ā§āĻĨāĻŋāĻ¤āĻŋ āĻā§āĻ¨ āĻĒāĻ°ā§āĻŦā§ āĻĻā§āĻāĻž āĻ¯āĻžāĻ¯āĻŧ?
- Porifera
- Echinodermata
- Mollusca
- Chordata
Ans. Echinodermata
- āĻĒā§āĻ˛āĻžāĻ¸ā§āĻāĻŋāĻĄ āĻŦāĻŋāĻšā§āĻ¨ āĻāĻĻā§āĻāĻŋāĻĻ āĻā§āĻ¨āĻāĻŋ?
- āĻŽāĻ¸
- āĻ¸ā§āĻĒāĻžāĻāĻ°ā§āĻāĻžāĻāĻ°āĻž
- āĻ ā§āĻ¯āĻžāĻāĻžāĻ°āĻŋāĻāĻžāĻ¸
- āĻ¸āĻžāĻāĻāĻžāĻ¸
Ans. āĻ ā§āĻ¯āĻžāĻāĻžāĻ°āĻŋāĻāĻžāĻ¸
- āĻĒā§āĻ˛āĻžāĻāĻŽāĻŋāĻĄ DNA āĻā§āĻĻāĻ¨ āĻāĻ°āĻž āĻšāĻ¯āĻŧ-
- Amylase enzym
- Restriction enzyme
- Protease enzyme
- Cellulase enzyme
Ans. Restriction enzyme
- āĻŦāĻžāĻāĻ˛āĻžāĻĻā§āĻļā§ Cycas āĻāĻĻā§āĻāĻŋāĻĻ āĻĒā§āĻ°āĻžāĻā§āĻ¤āĻŋāĻāĻāĻžāĻŦā§ āĻāĻ¨ā§āĻŽā§ –
- āĻĻāĻŋāĻ¨āĻžāĻāĻĒā§āĻ°ā§
- āĻŦāĻ°āĻŋāĻļāĻžāĻ˛ā§
- āĻŽā§āĻŽā§āĻ¨āĻļāĻžāĻšā§āĻ° āĻŽāĻ§ā§āĻĒā§āĻ° āĻŦāĻ¨ā§
- āĻāĻā§āĻāĻā§āĻ°āĻžāĻŽā§āĻ° āĻŦāĻžāĻ°āĻŋāĻ¯āĻŧāĻžāĻĄāĻžāĻ˛āĻž āĻŦāĻ¨ā§
Ans. āĻāĻā§āĻāĻā§āĻ°āĻžāĻŽā§āĻ° āĻŦāĻžāĻ°āĻŋāĻ¯āĻŧāĻžāĻĄāĻžāĻ˛āĻž āĻŦāĻ¨ā§
- CFC āĻŦāĻŋāĻ¨āĻˇā§āĻ āĻāĻ°ā§-
- āĻ¨āĻžāĻāĻā§āĻ°ā§āĻā§āĻ¨
- āĻāĻžāĻ°ā§āĻŦāĻ¨ āĻĄāĻžāĻāĻ āĻā§āĻ¸āĻžāĻāĻĄ
- āĻāĻā§āĻ¨ āĻ¸ā§āĻ¤āĻ°
- āĻšāĻžāĻāĻĄā§āĻ°ā§āĻā§āĻ˛ā§āĻ°āĻŋāĻ āĻ ā§āĻ¯āĻžāĻ¸āĻŋāĻĄ
Ans. āĻāĻā§āĻ¨ āĻ¸ā§āĻ¤āĻ°
- āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¨āĻāĻŋ āĻāĻā§āĻ¸āĻŋāĻ¸ā§āĻā§āĻŽā§āĻ° āĻ
āĻā§āĻŦ āĻāĻĒāĻžāĻĻāĻžāĻ¨?
- āĻŽāĻžāĻāĻŋ
- āĻāĻĻā§āĻāĻŋāĻĻ
- āĻŦā§āĻ¯āĻžāĻāĻā§āĻ°āĻŋāĻ¯āĻŧāĻž
- āĻŽāĻžāĻ¨ā§āĻˇ
Ans. āĻŽāĻžāĻāĻŋ
- āĻŽāĻžāĻ¨āĻŦāĻĻā§āĻšā§ āĻ¸āĻ°ā§āĻŦāĻŦā§āĻšā§ āĻā§āĻ°āĻ¨ā§āĻĨāĻŋ āĻā§āĻ¨āĻāĻŋ?
- āĻ¯āĻā§ā§
- āĻ āĻā§āĻ¨ā§āĻ¯āĻžāĻļāĻ¯āĻŧ
- āĻĨāĻžāĻāĻ°āĻ¯āĻŧā§āĻĄ āĻā§āĻ°āĻ¨ā§āĻĨāĻŋ
- āĻĒā§āĻ¯āĻžāĻ°ā§āĻāĻŋāĻĄ āĻā§āĻ°āĻ¨ā§āĻĨāĻŋ
Ans. āĻ¯āĻā§ā§
- āĻ¸ā§āĻ¨ā§āĻš āĻāĻžāĻ¤ā§āĻ¯āĻŧ āĻāĻžāĻĻā§āĻ¯ āĻĒāĻ°āĻŋāĻĒāĻžāĻā§ āĻā§āĻ¨ āĻā§āĻ¸ā§āĻāĻ āĻ
āĻāĻļ āĻā§āĻ°āĻšāĻŖ āĻāĻ°ā§?
- āĻ˛āĻžāĻāĻĒā§āĻ
- āĻ˛ā§āĻ¯āĻžāĻāĻā§āĻ
- āĻĒā§āĻ°ā§āĻāĻŋāĻ¯āĻŧā§āĻ
- āĻŽāĻ˛āĻā§āĻ
Ans. āĻ˛āĻžāĻāĻĒā§āĻ
- āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¨ āĻāĻ°ā§āĻāĻŋāĻ āĻ¸ā§āĻ¨āĻžāĻ¯āĻŧā§āĻāĻŋ āĻ¸āĻāĻŦā§āĻĻā§?
- āĻ āĻ˛āĻĢā§āĻ¯āĻžāĻā§āĻāĻ°āĻŋ
- āĻ āĻā§āĻ˛ā§āĻŽā§āĻāĻ°
- āĻā§āĻāĻžāĻ¸
- āĻĢā§āĻ¸āĻŋāĻ¯āĻŧāĻžāĻ˛
Ans. āĻ āĻ˛āĻĢā§āĻ¯āĻžāĻā§āĻāĻ°āĻŋ
- āĻā§āĻ¨ āĻ°āĻā§āĻ¤āĻā§āĻ°ā§āĻĒ āĻŦāĻšāĻ¨āĻāĻžāĻ°ā§ āĻŦā§āĻ¯āĻā§āĻ¤āĻŋāĻā§ âāĻ¸āĻžāĻ°ā§āĻŦāĻāĻ¨ā§āĻ¨ āĻĻāĻžāĻ¤āĻžâ āĻŦāĻ˛āĻž āĻšāĻ¯āĻŧ?
- B
- O
- A
- AB
Ans. O
- āĻŽāĻžāĻ¨ā§āĻˇā§āĻ° āĻāĻ°ā§āĻāĻŋāĻ¤ā§ āĻŽā§āĻ āĻ
āĻ¸ā§āĻĨāĻŋāĻ° āĻ¸āĻāĻā§āĻ¯āĻž-
- 25
- 29
- 27
- 32
Ans. 29
- āĻ˛āĻžāĻāĻ¸ā§āĻ¸ā§āĻŽ āĻĒā§āĻ°āĻĨāĻŽ āĻā§ āĻāĻŦāĻŋāĻˇā§āĻāĻžāĻ° āĻāĻ°ā§āĻ¨?
- Robert Brown
- De Duve
- Robert Hook
- Camilo Golgi
Ans. De Duve
- āĻŽāĻžāĻāĻā§āĻāĻ¨ā§āĻĄā§āĻ°āĻŋāĻ¯āĻŧāĻžāĻ° āĻāĻŋāĻ¤āĻ°ā§āĻ° āĻ
āĻ¨āĻŋāĻ¯āĻŧāĻŽāĻŋāĻ¤ āĻāĻžāĻāĻāĻā§ āĻāĻŋ āĻŦāĻ˛ā§ ?
- āĻ˛ā§āĻ¯āĻžāĻŽā§āĻ˛ā§
- āĻ¸āĻŋāĻ¸ā§āĻāĻžāĻ°āĻ¨āĻŋ
- āĻā§āĻ°āĻŋāĻ¸ā§āĻāĻŋ
- āĻā§āĻ°ā§āĻŽāĻžāĻāĻŋāĻ¨ āĻ¤āĻ¨ā§āĻ¤ā§
Ans. āĻā§āĻ°āĻŋāĻ¸ā§āĻāĻŋ
- āĻ¨āĻŋāĻā§āĻ° āĻā§āĻ¨āĻāĻŋ DNA āĻ
āĻŖā§āĻ¤ā§ āĻ
āĻ¨ā§āĻĒāĻ¸ā§āĻĨāĻŋāĻ¤?
- āĻ¸āĻžāĻāĻā§āĻ¸āĻŋāĻ¨
- āĻāĻĄāĻŋāĻ¨āĻŋāĻ¨
- āĻāĻāĻ°āĻžāĻ¸āĻŋāĻ˛
- āĻā§āĻ¯āĻŧāĻžāĻ¨āĻŋāĻ¨
Ans. āĻāĻāĻ°āĻžāĻ¸āĻŋāĻ˛
- āĻĒā§āĻ¨āĻ°āĻžāĻŦā§āĻ¤ā§āĻ¤āĻŋ āĻŽāĻ¤āĻŦāĻžāĻĻā§āĻ° āĻĒā§āĻ°āĻŦāĻā§āĻ¤āĻž āĻā§?
- Ernst Haeckel
- August Weismann
- Hugo de Vries
- James Watson
Ans. Ernst Haeckel
- āĻ¨āĻŋāĻā§ āĻāĻ˛ā§āĻ˛āĻŋāĻāĻŋāĻ¤ āĻā§āĻ¨ āĻĒā§āĻ°āĻžāĻŖā§āĻ¤ā§ āĻšāĻŋāĻŽā§āĻ¸āĻŋāĻ˛ āĻĨāĻžāĻā§?
- āĻā§āĻāĻā§
- āĻ¤ā§āĻ˛āĻžāĻĒā§āĻāĻž
- āĻŽā§āĻ¯āĻžāĻ˛ā§āĻ°āĻŋāĻ¯āĻŧāĻž āĻĒāĻ°āĻā§āĻŦā§
- āĻšāĻžāĻāĻĄā§āĻ°āĻž
Ans. āĻ¤ā§āĻ˛āĻžāĻĒā§āĻāĻž
- āĻā§āĻ¨ āĻā§āĻ¤ā§āĻ°ā§āĻ° āĻĢā§āĻ˛ā§ āĻā§āĻ¯āĻžāĻā§āĻ¸āĻŋāĻ˛āĻž āĻĨāĻžāĻā§?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- Liliaceae
- Liguminosae
- Solanaceae
- Malvaceae
Ans. Liguminosae
- āĻāĻžāĻļāĻŋ āĻ¨āĻŋāĻ°āĻžāĻŽāĻ¯āĻŧā§ āĻŦā§āĻ¯āĻŦāĻšā§āĻ¤ āĻāĻĻā§āĻāĻŋāĻĻ āĻā§āĻ¨āĻāĻŋ?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- Eclipta prostrata
- Adhatoda vasica
- Ruellia tuberosa
- Cynodon dactylon
Ans. Adhatoda vasica
āĻŦāĻžāĻāĻ˛āĻž
- ‘āĻ ā§āĻāĻ āĻ āĻ¨āĻžāĻā§āĻ°’ āĻāĻŋāĻĻā§āĻ°ā§āĻ° āĻ¸āĻžāĻšāĻžāĻ¯ā§āĻ¯ā§ āĻāĻā§āĻāĻžāĻ°āĻŋāĻ¤ āĻšāĻ¯āĻŧ-
- āĻ
- āĻ
- āĻ¨
- āĻŽ
Ans. āĻŽ
- āĻ¸āĻāĻ¯ā§āĻā§āĻ¤ āĻŦā§āĻ¯āĻā§āĻāĻ¨āĻ§ā§āĻŦāĻ¨āĻŋāĻ° āĻŽāĻ§ā§āĻ¯ā§ āĻ¸ā§āĻŦāĻ°ā§āĻ° āĻāĻāĻŽāĻā§ āĻā§ āĻŦāĻ˛ā§?
- āĻŦāĻŋāĻĒā§āĻ°āĻāĻ°ā§āĻˇ
- āĻ¸ā§āĻŦāĻ°āĻ¸āĻā§āĻāĻ¤āĻŋ
- āĻ āĻāĻŋāĻļā§āĻ°ā§āĻ¤āĻŋ
- āĻ¸āĻŽā§āĻāĻŦāĻ¨
Ans. āĻŦāĻŋāĻĒā§āĻ°āĻāĻ°ā§āĻˇ
- ‘āĻā§āĻļāĻĒā§āĻ¤ā§āĻ¤āĻ˛āĻŋ’ āĻļāĻŦā§āĻĻā§āĻ° āĻāĻāĻŋāĻ§āĻžāĻ¨āĻŋāĻ āĻ
āĻ°ā§āĻĨ-
- āĻā§āĻ¨ āĻŦā§āĻ¯āĻā§āĻ¤āĻŋāĻ° āĻĒā§āĻ°āĻ¤ā§āĻā§ āĻŽā§āĻ°ā§āĻ¤āĻŋ
- āĻā§āĻļāĻ¨āĻŋāĻ°ā§āĻŽāĻŋāĻ¤ āĻĒā§āĻ¤ā§āĻ˛
- āĻā§āĻ˛āĻ¨āĻžāĻ° āĻĒā§āĻ¤ā§āĻ˛
- āĻā§āĻļāĻāĻžāĻ¯āĻŧ āĻĒāĻĻāĻžāĻ°ā§āĻĨ
Ans. āĻā§āĻļāĻ¨āĻŋāĻ°ā§āĻŽāĻŋāĻ¤ āĻĒā§āĻ¤ā§āĻ˛
- ‘āĻĒā§āĻ°āĻāĻ¨ā§āĻŽ’ āĻļāĻŦā§āĻĻā§āĻ° āĻ¯āĻĨāĻžāĻ¯āĻĨ āĻāĻā§āĻāĻžāĻ°āĻŖ-
- āĻĒā§āĻ°āĻāĻ¨ā§āĻŽ
- āĻĒā§āĻ°āĻāĻ¨ā§āĻŽā§
- āĻĒā§āĻ°ā§āĻāĻ¨ā§āĻŽā§
- āĻĒā§āĻ°ā§āĻā§āĻ¨ā§āĻŽā§
Ans. āĻĒā§āĻ°ā§āĻāĻ¨ā§āĻŽā§
- ‘āĻāĻ¸ā§āĻĒāĻžāĻ¤’ āĻļāĻŦā§āĻĻāĻāĻŋ āĻā§āĻ¨ āĻāĻžāĻˇāĻžāĻ°?
- āĻāĻāĻ°ā§āĻāĻŋ
- āĻĢāĻ°āĻžāĻ¸āĻŋ
- āĻāĻ˛āĻ¨ā§āĻĻāĻžāĻ
- āĻĒāĻ°ā§āĻ¤ā§āĻāĻŋāĻ
Ans. āĻĒāĻ°ā§āĻ¤ā§āĻāĻŋāĻ
- ‘āĻāĻŽāĻŋ āĻ¤āĻžāĻ° āĻāĻĻā§āĻ§āĻ¤āĻĒā§āĻ°ā§āĻŖ āĻāĻāĻ°āĻ¨ā§ āĻŦā§āĻ¯āĻžāĻĨāĻŋāĻ¤ āĻšāĻāĻ¯āĻŧāĻžāĻāĻŋāĨ¤’ āĻ¸āĻžāĻ§ā§ āĻāĻžāĻˇāĻžāĻ° āĻ āĻŦāĻžāĻā§āĻ¯ā§ āĻŽā§āĻ āĻāĻ¯āĻŧāĻāĻŋ āĻā§āĻ˛ āĻāĻā§?
- ā§¨āĻāĻŋ
- ā§ŠāĻāĻŋ
- ā§ĒāĻāĻŋ
- ā§ĢāĻāĻŋ
Ans. ā§ĒāĻāĻŋ
- āĻāĻĒāĻ¸āĻ°ā§āĻāĻ¯ā§āĻā§āĻ¤ āĻļāĻŦā§āĻĻ āĻā§āĻ¨āĻāĻŋ?
- āĻŽāĻ¨ā§āĻ¤ā§āĻˇ
- āĻ¸āĻ¨ā§āĻ¤ā§āĻˇ
- āĻāĻļā§āĻ¤ā§āĻˇ
- āĻĒā§āĻ°āĻŋāĻ¯āĻŧāĻ¤ā§āĻˇ
Ans. āĻāĻļā§āĻ¤ā§āĻˇ
- āĻŦāĻŋāĻāĻā§āĻ¤āĻŋāĻšā§āĻ¨ āĻ¨āĻžāĻŽāĻļāĻŦā§āĻĻāĻā§ āĻŦāĻ˛ā§-
- āĻāĻĒāĻ¸āĻ°ā§āĻ
- āĻ āĻ¨ā§āĻ¸āĻ°ā§āĻ
- āĻ āĻĒāĻŋāĻ¨āĻŋāĻšāĻŋāĻ¤āĻŋ
- āĻĒā§āĻ°āĻžāĻ¤āĻŋāĻĒāĻĻāĻŋāĻ
Ans. āĻĒā§āĻ°āĻžāĻ¤āĻŋāĻĒāĻĻāĻŋāĻ
- ‘āĻŦāĻŋāĻĻā§āĻ¯ā§āĻ¤ā§ āĻāĻ˛ā§ āĻšāĻ¯āĻŧāĨ¤’ āĻ āĻŦāĻžāĻā§āĻ¯ā§ ‘āĻŦāĻŋāĻĻā§āĻ¯ā§āĻ¤ā§’ āĻļāĻŦā§āĻĻāĻāĻŋ āĻā§āĻ¨ āĻāĻžāĻ°āĻā§āĻ° āĻĻā§āĻˇā§āĻāĻžāĻ¨ā§āĻ¤?
- āĻāĻ°āĻŖ
- āĻ āĻ§āĻŋāĻāĻ°āĻŖ
- āĻ āĻĒāĻžāĻĻāĻžāĻ¨
- āĻāĻ°ā§āĻŽ
Ans. āĻāĻ°āĻŖ
- ‘āĻāĻŽāĻĄāĻŧāĻž āĻāĻžāĻ ā§āĻ° āĻĸā§āĻāĻāĻŋ’ āĻŦāĻžāĻāĻ§āĻžāĻ°āĻžāĻ° āĻĒā§āĻ°āĻā§āĻ¤ āĻ
āĻ°ā§āĻĨ-
- āĻāĻŽāĻĄāĻŧāĻž āĻāĻžāĻ āĻĻāĻŋāĻ¯āĻŧā§ āĻ¤ā§āĻ°āĻŋ āĻĸā§āĻāĻāĻŋ
- āĻāĻŽāĻĄāĻŧāĻž āĻāĻžāĻ ā§āĻ° āĻŽāĻ¤ā§ āĻĻā§āĻ°ā§āĻŦāĻ˛ āĻĸā§āĻāĻāĻŋ
- āĻ āĻ˛ā§āĻ āĻŦāĻ¸ā§āĻ¤ā§
- āĻ āĻĒāĻĻāĻžāĻ°ā§āĻĨ
Ans. āĻ āĻĒāĻĻāĻžāĻ°ā§āĻĨ
- âāĻĒāĻā§āĻāĻŋāĻ˛â āĻāĻ° āĻŦāĻŋāĻĒāĻ°ā§āĻ¤ āĻļāĻŦā§āĻĻ āĻā§āĻ¨āĻāĻŋ?
- āĻĒāĻ°āĻŋāĻā§āĻāĻ¨ā§āĻ¨
- āĻāĻā§āĻā§āĻŦāĻ˛
- āĻ¨āĻŋāĻ°ā§āĻŽāĻ˛
- āĻ āĻŽā§āĻ˛āĻžāĻ¨
Ans. āĻ¨āĻŋāĻ°ā§āĻŽāĻ˛
- āĻā§āĻ¨āĻāĻŋ āĻ¤āĻĻā§āĻāĻŦ āĻļāĻŦā§āĻĻ?
- āĻāĻ°ā§
- āĻŽāĻšāĻŋāĻˇ
- āĻšāĻžāĻ¤āĻŋ
- āĻšāĻ°āĻŋāĻŖ
Ans. āĻšāĻžāĻ¤āĻŋ
- āĻā§āĻ¨āĻāĻŋ āĻļā§āĻĻā§āĻ§ āĻŦāĻžāĻ¨āĻžāĻ¨?
- āĻ¨āĻŋāĻļā§āĻŦāĻžāĻ¸
- āĻ¨ā§āĻļā§āĻŦāĻžāĻ¸
- āĻ¨āĻŋāĻāĻļā§āĻŦāĻžāĻ¸
- āĻ¨āĻŋāĻāĻļā§āĻŦāĻžāĻļ
Ans. āĻ¨āĻŋāĻāĻļā§āĻŦāĻžāĻ¸
- âāĻāĻĒāĻ˛āĻāĻŖā§āĻĄâ āĻŦāĻ˛āĻ¤ā§ āĻŦā§āĻāĻžāĻ¯āĻŧ-
- āĻāĻžāĻ ā§āĻ° āĻā§āĻāĻ°ā§
- āĻĒāĻžāĻĨāĻ°ā§āĻ° āĻā§āĻāĻ°ā§
- āĻŦāĻžāĻāĻļā§āĻ° āĻā§āĻāĻ°ā§
- āĻāĻ āĻā§āĻāĻ°ā§ āĻŽāĻžāĻāĻŋ
Ans. āĻĒāĻžāĻĨāĻ°ā§āĻ° āĻā§āĻāĻ°ā§
- ‘Petrologyâ āĻļāĻŦā§āĻĻā§āĻ° āĻŦāĻžāĻāĻ˛āĻž āĻĒāĻ°āĻŋāĻāĻžāĻˇāĻž-
- āĻļāĻŋāĻ˛āĻžāĻ¤āĻ¤ā§āĻ¤ā§āĻŦ
- āĻ¤ā§āĻ˛āĻŦāĻŋāĻĻā§āĻ¯āĻž
- āĻĒā§āĻā§āĻ°ā§āĻ˛ āĻŦāĻŋāĻā§āĻāĻžāĻ¨
- āĻā§āĻŦāĻžāĻ˛āĻžāĻ¨āĻŋ āĻļāĻžāĻ¸ā§āĻ¤ā§āĻ°
Ans. āĻļāĻŋāĻ˛āĻžāĻ¤āĻ¤ā§āĻ¤ā§āĻŦ
- ‘āĻāĻĨā§āĻĒāĻāĻĨāĻ¨’ āĻļāĻŦā§āĻĻāĻāĻŋ āĻā§ āĻ°ā§āĻ¤āĻŋāĻ¤ā§ āĻāĻ āĻŋāĻ¤?
- āĻāĻĒāĻ¸āĻ°ā§āĻāĻ¯ā§āĻā§
- āĻ¸āĻ¨ā§āĻ§āĻŋāĻ¯ā§āĻā§
- āĻĒā§āĻ°āĻ¤ā§āĻ¯āĻ¯āĻŧāĻ¯ā§āĻā§
- āĻ¸āĻŽāĻžāĻ¸āĻ¯ā§āĻā§
Ans. āĻ¸āĻŽāĻžāĻ¸āĻ¯ā§āĻā§
- âāĻāĻ āĻĻā§āĻ° āĻŦāĻ¨ā§ āĻ¸āĻ¨ā§āĻ§ā§āĻ¯āĻž āĻ¨āĻžāĻŽāĻŋāĻā§ āĻāĻ¨ āĻāĻŦāĻŋāĻ°ā§āĻ° āĻ°āĻžāĻā§â āĻĒāĻāĻā§āĻ¤āĻŋāĻāĻŋ āĻā§āĻ¨ āĻāĻŦāĻŋāĻ¤āĻžāĻ° āĻ
āĻ¨ā§āĻ¤āĻ°ā§āĻāĻ¤?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻāĻŦāĻ°
- āĻ¤āĻžāĻšāĻžāĻ°ā§āĻ āĻĒāĻĄāĻŧā§ āĻŽāĻ¨ā§
- āĻŦāĻžāĻāĻ˛āĻžāĻĻā§āĻļ
- āĻ§āĻ¨ā§āĻ¯āĻŦāĻžāĻĻ
Ans. āĻāĻŦāĻ°
- ‘āĻā§āĻŦā§āĻ° āĻŦāĻžāĻ āĻāĻžāĻĄāĻŧāĻžāĻ¨ āĻĻāĻžāĻāĨ¤’ ‘āĻĒāĻĻā§āĻŽāĻžāĻ¨āĻĻā§āĻ° āĻŽāĻžāĻāĻŋ’ āĻāĻĒāĻ¨ā§āĻ¯āĻžāĻ¸ā§ āĻāĻā§āĻ¤āĻŋāĻāĻŋ āĻāĻžāĻ°?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻšā§āĻ¸ā§āĻ¨ āĻŽāĻŋāĻāĻž
- āĻāĻŽāĻŋāĻ¨ā§āĻĻā§āĻĻāĻŋ
- āĻāĻšāĻ° āĻŽāĻžāĻāĻŋ
- āĻ§āĻ¨āĻā§āĻāĻ¯āĻŧ
Ans. āĻāĻšāĻ° āĻŽāĻžāĻāĻŋ
- âāĻ¸ā§āĻŦāĻĒā§āĻ¨ā§ āĻ¤āĻŦ āĻā§āĻ˛āĻ˛āĻā§āĻˇā§āĻŽā§ āĻāĻ¯āĻŧā§ āĻĻāĻŋāĻ˛āĻž āĻĒāĻ°ā§â āĻŦāĻā§āĻāĻāĻžāĻˇāĻž’ āĻāĻŦāĻŋāĻ¤āĻžāĻ¯āĻŧ āĻ āĻĒāĻāĻā§āĻ¤āĻŋāĻ° āĻ āĻŋāĻ āĻĒāĻ°ā§āĻ° āĻĒāĻāĻā§āĻ¤āĻŋ āĻā§āĻ¨āĻāĻŋ?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻ āĻāĻŋāĻāĻžāĻ°ā§-āĻĻāĻļāĻž āĻ¤āĻŦā§ āĻā§āĻ¨ āĻ¤ā§āĻ° āĻāĻāĻŋ
- āĻāĻ°ā§ āĻŦāĻžāĻāĻž, āĻŽāĻžāĻ¤ā§āĻā§āĻˇā§ āĻ°āĻ¤āĻ¨ā§āĻ° āĻ°āĻžāĻāĻŋ
- āĻŽāĻžāĻ¤ā§āĻāĻžāĻˇāĻž-āĻ°ā§āĻĒ āĻāĻ¨āĻŋ āĻĒā§āĻ°ā§āĻŖ āĻŽāĻ¨āĻŋāĻāĻžāĻ˛ā§
- āĻ¯āĻž āĻĢāĻŋāĻ°āĻŋ āĻ āĻā§āĻāĻžāĻ¨ āĻ¤ā§āĻ, āĻ¯āĻžāĻ°ā§ āĻĢāĻŋāĻ°āĻŋ āĻāĻ°ā§āĻ°
Ans. āĻāĻ°ā§ āĻŦāĻžāĻāĻž, āĻŽāĻžāĻ¤ā§āĻā§āĻˇā§ āĻ°āĻ¤āĻ¨ā§āĻ° āĻ°āĻžāĻāĻŋ
- ‘āĻāĻ āĻļāĻŋāĻŦāĻŋāĻ°ā§ āĻ¤ā§āĻŽāĻžāĻ° āĻāĻŽāĻžāĻ° āĻŽāĻžāĻāĻāĻžāĻ¨ā§ āĻāĻŽāĻžāĻ° āĻĒāĻŋāĻ¤āĻžāĻ° āĻ˛āĻžāĻļ āĻļā§āĻ¯āĻŧā§ āĻāĻā§āĨ¤’ ‘āĻ°āĻā§āĻ¤āĻžāĻā§āĻ¤ āĻĒā§āĻ°āĻžāĻ¨ā§āĻ¤āĻ°’ āĻ¨āĻžāĻāĻā§ āĻ āĻāĻā§āĻ¤āĻŋāĻāĻŋ āĻāĻžāĻ°?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻšāĻŋāĻ°āĻŖāĻŦāĻžāĻ˛āĻž
- āĻĻāĻŋāĻ˛ā§āĻĒ
- āĻā§āĻšāĻ°āĻž
- āĻāĻžāĻ°ā§āĻĻāĻŋ
Ans. āĻā§āĻšāĻ°āĻž
- ‘āĻāĻ āĻĒā§āĻ°āĻāĻžāĻŦā§ āĻ¸āĻžāĻ°āĻž āĻĒā§āĻĨāĻŋāĻŦā§āĻ° āĻāĻŦāĻšāĻžāĻāĻ¯āĻŧāĻžāĻ¯āĻŧ āĻŦāĻĄāĻŧ āĻ°āĻāĻŽ āĻāĻ˛āĻ-āĻĒāĻžāĻ˛āĻ āĻāĻā§āĨ¤’ ‘āĻĻā§āĻ°ā§āĻ¯ā§āĻāĻĒā§āĻ°āĻŦāĻŖ āĻĒā§āĻĨāĻŋāĻŦā§ : āĻŦāĻžāĻāĻ˛āĻžāĻĻā§āĻļ āĻ āĻŦāĻŋāĻļā§āĻŦ’ āĻĒā§āĻ°āĻŦāĻ¨ā§āĻ§ā§ āĻāĻŋāĻ¸ā§āĻ° āĻĒā§āĻ°āĻāĻžāĻŦā§āĻ° āĻāĻĨāĻž āĻŦāĻ˛āĻž āĻšāĻ¯āĻŧā§āĻā§?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻā§āĻ°ā§āĻ¨ āĻšāĻžāĻāĻ¸ āĻĒā§āĻ°āĻ¤āĻŋāĻā§āĻ°āĻŋāĻ¯āĻŧāĻž
- āĻāĻ˛-āĻ¨āĻŋāĻ¨āĻŋāĻ
- āĻĒāĻ°āĻŋāĻŦā§āĻļ āĻĻā§āĻˇāĻŖ
- āĻĒāĻžāĻ°āĻŽāĻžāĻŖāĻŦāĻŋāĻ āĻ¤ā§āĻāĻ¸ā§āĻā§āĻ°āĻŋāĻ¯āĻŧāĻž
Ans. āĻāĻ˛-āĻ¨āĻŋāĻ¨āĻŋāĻ
- ‘āĻŽāĻ¨ āĻāĻāĻā§āĻ¤ā§āĻ āĻāĻ āĻ¤ā§ āĻāĻžāĻ¯āĻŧ, āĻ¨ā§āĻā§āĻ¤ā§āĻ āĻ¨āĻžāĻŽāĻ¤ā§ āĻāĻžāĻ¯āĻŧāĨ¤’ āĻ āĻŦāĻžāĻā§āĻ¯āĻāĻŋ āĻā§āĻ¨ āĻ°āĻāĻ¨āĻžāĻ¯āĻŧ āĻāĻā§?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻšā§āĻŽāĻ¨ā§āĻ¤ā§
- āĻ¸āĻžāĻšāĻŋāĻ¤ā§āĻ¯ā§ āĻā§āĻ˛āĻž
- āĻ āĻ°ā§āĻ§āĻžāĻā§āĻā§
- āĻāĻāĻāĻŋ āĻ¤ā§āĻ˛āĻ¸ā§ āĻāĻžāĻā§āĻ° āĻāĻžāĻšāĻŋāĻ¨ā§
Ans. āĻ¸āĻžāĻšāĻŋāĻ¤ā§āĻ¯ā§ āĻā§āĻ˛āĻž
- ‘āĻāĻ¨āĻ¨ā§āĻĻā§āĻ° āĻ§āĻ°ā§āĻŽ āĻāĻ āĻ¯ā§ āĻ¤āĻž āĻ¸āĻāĻā§āĻ°āĻžāĻŽāĻāĨ¤’ āĻā§āĻ¨ āĻ°āĻāĻ¨āĻžāĻ°?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻ¯ā§āĻŦāĻ¨ā§āĻ° āĻāĻžāĻ¨
- āĻ¸āĻžāĻšāĻŋāĻ¤ā§āĻ¯ā§ āĻā§āĻ˛āĻž
- āĻāĻžāĻˇāĻžāĻ° āĻāĻĨāĻž
- āĻ āĻ°ā§āĻ§āĻžāĻā§āĻā§
Ans. āĻ¸āĻžāĻšāĻŋāĻ¤ā§āĻ¯ā§ āĻā§āĻ˛āĻž
- ‘āĻĒā§āĻ°āĻā§āĻ° āĻŽāĻ¨ āĻā§āĻāĻŋāĻ¯āĻŧā§ āĻāĻ˛āĻžāĻ° āĻļāĻŋāĻ˛ā§āĻĒ āĻ¸ā§ āĻŦā§āĻļ āĻ°āĻĒā§āĻ¤ āĻāĻ°ā§āĻāĻŋāĻ˛āĨ¤’ āĻāĻā§āĻ¤āĻŋāĻāĻŋ āĻāĻžāĻ° āĻ¸āĻŽā§āĻĒāĻ°ā§āĻā§ āĻāĻ°āĻž āĻšāĻ¯āĻŧā§āĻā§?(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻ¨āĻžāĻ¸āĻŋāĻ°
- āĻŽāĻ¨ā§āĻ°āĻā§āĻāĻ¨
- āĻāĻāĻĻā§āĻļ āĻŽāĻžāĻ˛ā§
- āĻšāĻ°āĻŋāĻĻāĻžāĻ¸
Ans. āĻŽāĻ¨ā§āĻ°āĻā§āĻāĻ¨
- âāĻ
āĻ°ā§āĻ§āĻžāĻā§āĻā§â āĻĒā§āĻ°āĻŦāĻ¨ā§āĻ§ā§ āĻ°āĻŦā§āĻ¨ā§āĻĻā§āĻ°āĻ¨āĻžāĻĨ āĻ āĻžāĻā§āĻ°ā§āĻ° āĻāĻāĻāĻŋ āĻāĻŦāĻŋāĻ¤āĻžāĻ° āĻ¨āĻžāĻŽ āĻāĻā§āĨ¤ āĻāĻŦāĻŋāĻ¤āĻžāĻāĻŋāĻ° āĻ¨āĻžāĻŽ-(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- āĻŽāĻžāĻ¨āĻ¸āĻ¸ā§āĻ¨ā§āĻĻāĻ°ā§
- āĻ¨āĻŦāĻĻāĻŽā§āĻĒāĻ¤ā§āĻ¤āĻŋāĻ° āĻĒā§āĻ°ā§āĻŽāĻžāĻ˛āĻžāĻĒ
- āĻŦāĻŋāĻā§āĻŋāĻ¨ā§
- āĻĒā§āĻ°ā§āĻŽā§āĻ° āĻ āĻāĻŋāĻˇā§āĻ
Ans. āĻ¨āĻŦāĻĻāĻŽā§āĻĒāĻ¤ā§āĻ¤āĻŋāĻ° āĻĒā§āĻ°ā§āĻŽāĻžāĻ˛āĻžāĻĒ
English
Read the passage and answer the Q. (01-05)
Between the fuel cells that will power the cars of the future and today’s petrol and diesel engines lie hybrid internal-combustion/electric vehicles. No one now believes that battery-driven electric cars will take over : the batteries are too heavy and run down too quickly. But cars that get their electricity from and internal-combustion engine acting as a generator are a reality. Two such hybrid vehicles are already selling in America and Japan. However, they cost more than normal models, and weigh more than
conventionally powered cars.
- Which of the following is not correct? A hybrid vehicle _____
- is costly
- does not need petrol or diesel
- is heavy
- uses petrol and diesel
Ans. uses petrol and diesel
- This is a passage about _____
- petrol engines
- diesel engines
- internal combustion engines
- electric engines
Ans. internal combustion engines
- An antonym for ‘hybrid’ in line 2 is _____
- mixture
- complex
- pure
- blend
Ans. pure
- ‘Power’ in line 1 is ______
- noun
- verb
- participle
- gerund
Ans. verb
- Batteries that ‘run down too quickly’ are-
- uneconomical
- universal
- fast
- fashinable
Ans. uneconomical
- The earth _____ round the sun.
- moves
- spans
- shoots
- skids
Ans. moves
- One of the characteristics of the moon is the way it continuously changes its _____
- appearance
- mass
- volume
- topography
Ans. appearance
- Even one has seen birds soaring in wide circles _____ land.
- behind
- across
- over
- into
Ans. over
- I cannot make _____ what you are aiming at.
- in
- out
- on
- for
Ans. out
- The man must apologize ____ what he has done.
- to
- for
- at
- by
Ans. for
- Your argument does not stand _____ reason.
- at
- into
- form
- to
Ans. to
- You may _____ down for a nap as soon as you do your homework.
- lay
- lie
- lain
- laid
Ans. lie
- We talked for a long time after we _____ home.
- return
- had returned
- has been returned
- returned
Ans. had returned
- Our friends _____ our house the day before.
.- having left
- had left
- have been left
- had been left
Ans. had left
- Forty yards _____ a good distance.
- is
- are
- were
- had
Ans. is
- It _____ raining since morning.
- was
- has been
- is
- had been
Ans. has been
- The bus _____ left before all the passengers arrived.
- were
- had
- have
- would been
Ans. had
-
āĻ¸ā§āĻ āĻāĻ¨āĻāĻ¨ā§ āĻļā§āĻ¤ā§ āĻāĻŽāĻŋ āĻāĻžāĻāĻĒāĻŋāĻ¤ā§ āĻ˛āĻžāĻāĻŋāĻ˛āĻžāĻŽ-
- I began trembling in that biting cold
- The trembling of me began in that biting
- I began to tremble in that biting cold
- I was trembling in that terrible coldness
Ans. I began to tremble in that biting cold
-
āĻ¤āĻŋāĻ¨āĻŋ āĻ°āĻžāĻā§ āĻāĻ°āĻāĻ° āĻāĻ°āĻā§āĻ¨-
- He is burning with anger
- He is shouthing in rage
- He is bursting into anger
- He is boiling with rage
Ans. He is bursting into anger
- Identify the misspelt word:
- Illiterate
- Embarras
- Parallel
- Occurrence
Ans. Embarras
- The word ‘Solitary’ in ‘The solitary Reaper’ means-(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- pretty
- lonely
- cheerful
- musical
Ans. lonely
- The tone of the speaker in âThe Patriot’ by Robert Browing is-(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- happy
- angry
- congused
- bitter
Ans. bitter
- The poet Robert Herrick requests the daffodils to wait till-(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- the morning prayer
- the evening prayer
- the sunrise prayer
- the noon
Ans. the evening prayer
- The writer in ‘The Luncheon’ could not turn down the lady’s proposal because-(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- the day was pretty
- the lady was kind
- the lady admired his book
- the writer was young
Ans. the writer was young
- Miss Clark in ‘A Mother in Manville’ is a spinster; in other words she is _____(āĻĒā§āĻ°āĻžāĻ¤āĻ¨ āĻ¸āĻŋāĻ˛ā§āĻŦāĻžāĻ¸)
- a spinner of stories
- a woman involeved in spinning
- a married woman
- an unmarried woman
Ans. an unmarried woman
Choose the right word to fill in the gap: Q. 06-11
Choose the appropriate verb form : Q 12-17
Choose the best translations, Q. (18-20)