DU A Unit Admission Question Solution 2013-2014
āύāĻŋāĻā§āϰ āĻāĻŋāĻĄāĻŋāĻāϤ⧠āĻĻā§āĻā§ āύāĻžāĻ āĻŦāĻŋāϏā§āϤāĻžāϰāĻŋāϤ:
āĻā§āϰā§āϏāĻāĻŋ āĻāĻŋāύāϤ⧠āĻĒāĻžāĻļā§āϰ āĻŦāĻžāĻāύāĻāĻŋ āĻā§āϞāĻŋāĻ āĻāϰ:  
āĻā§āϰā§āϏā§āϰ āĻĄā§āĻŽā§ āĻāĻŋāĻĄāĻŋāĻ(āĻāĻāĻžāĻŦā§ āĻĒāĻĻāĻžāϰā§āĻĨāĻŦāĻŋāĻā§āĻāĻžāύ+āϰāϏāĻžā§āύ+āĻāĻā§āĻāϤāϰāĻāĻŖāĻŋāϤ āĻāϰ āĻŦāĻŋāĻāϤ āĻŦāĻŋāĻļ āĻŦāĻāϰā§āϰ āϏāĻāϞ āĻĒā§āϰāĻļā§āύā§āϰ āϏāĻŽāĻžāϧāĻžāύ āĻĨāĻžāĻāĻŦā§ āĻāĻŋāĻĄāĻŋāĻāϤā§)
āĻĒāĻĻāĻžāϰā§āĻĨāĻŦāĻŋāĻā§āĻāĻžāύ
- \(\frac{d^{2} x}{d t^{2}}+25 x=0\) āϏāĻŽā§āĻāϰāĻŖāĻāĻŋ āĻāĻāĻāĻŋ āϏāϰāϞ āĻāύā§āĻĻāĻŋāϤ āϏā§āĻĒāύā§āĻĻāύ āĻŦāϰā§āĻŖāύāĻž āĻāϰā§āĨ¤ āĻāĻ āϏā§āĻĒāύā§āĻĻāύā§āϰ āĻā§āĻŖāĻŋāĻ āĻāĻŽā§āĻĒāĻžāĻā§āĻ āĻāϤ?
- \(100 \mathrm{~s}^{-1}\)
- \(25 \mathrm{~s}^{-1}\)
- \(10 \mathrm{~s}^{-1}\)
- \(5 \mathrm{~s}^{-1}\)
Ans. \(5 \mathrm{~s}^{-1}\)
- āϏā§āĻĒāĻžāϰāĻāύā§āĻĄāĻžāĻā§āĻāϰ āϏāĻžāϧāĻžāϰāĻŖ āĻāύā§āĻĄāĻžāĻā§āĻāϰā§āϰ āĻā§āϝāĻŧā§ āĻŦā§āĻļāĻŋ āϏā§āĻļā§āĻā§āĻāϞāĨ¤ āϝāĻĻāĻŋ āϏā§āĻĒāĻžāϰāĻāύā§āĻĄāĻžāĻā§āĻāϰ āĻāĻŦāĻ āϏāĻžāϧāĻžāϰāĻŖ āĻāύā§āĻĄāĻžāĻā§āĻāϰ āĻ
āĻŦāϏā§āĻĨāĻžāϝāĻŧ āĻāύāĻā§āϰāĻĒāĻŋ āϝāĻĨāĻžāĻā§āϰāĻŽā§ \(\mathbf{S}_{\mathrm{s}}\) āĻāĻŦāĻ \(\mathbf{S}_{\mathbf{n}}\) āĻšāϝāĻŧ āϤāĻŦā§ āύāĻŋāĻŽā§āύā§āϰ āĻā§āύāĻāĻŋ āϏāĻ āĻŋāĻ?
- \(\mathrm{S}_{\mathrm{s}}=\mathrm{S}_{\mathrm{n}}\)
- \(\mathrm{S}_{\mathrm{s}}>\mathrm{S}_{\mathrm{n}}\)
- \(\mathrm{S}_{\mathrm{s}}<\mathrm{S}_{\mathrm{n}}\)
- \(\mathrm{S}_{\mathrm{s}} \geq \mathrm{S}_{\mathrm{n}}\)
Ans. \(\mathrm{S}_{\mathrm{s}}<\mathrm{S}_{\mathrm{n}}\)
- 100w āĻāĻŦāĻ 220v āϞāĻŋāĻāĻŋāϤ āĻāĻāĻāĻŋ āĻŦā§āĻĻā§āϝā§āϤāĻŋāĻ āĻŦāĻžāϞā§āĻŦ āĻĒā§āϰāϤāĻŋāĻĻāĻŋāύ 10 āĻāύā§āĻāĻž āĻā§āĻŦāϞā§āĨ¤ 1k-Wh-āĻāϰ āĻŽā§āϞā§āϝ 3.00 āĻāĻžāĻāĻž āĻšāϞā§,āĻāϰ āĻāύā§āϝ āĻā§āϞāĻžāĻ āĻŽāĻžāϏ⧠āĻŦā§āĻĻā§āϝā§āϤāĻŋāĻ āĻŦāĻŋāϞ āĻāϤ āĻāϏāĻŦā§?
- 200 Tk
- 155 Tk
- 150 Tk
- 93 Tk
Ans. 93 Tk
- āĻāĻāĻāĻŋ āĻāϤāĻŋāĻļā§āϞ āĻāϞā§āĻāĻā§āϰāύā§āϰ āĻāϰ \(\mathrm{m}_{\mathrm{e}}\) āĻšāϞā§, āύāĻŋāĻā§āϰ āĻā§āύāĻāĻŋ āϏāĻ āĻŋāĻ?
- \(\mathrm{m}_{\mathrm{e}}>9.11 \times 10^{-31} \mathrm{~kg}\)
- \(\mathrm{m}_{\mathrm{e}}<9.11 \times 10^{-31} \mathrm{~kg}\)
- \(\mathrm{m}_{\mathrm{e}}=9.11 \times 10^{-31} \mathrm{~kg}\)
- \(\mathrm{m}_{\mathrm{e}}<<9.11 \times 10^{-31} \mathrm{~kg}\)
Ans. \(\mathrm{m}_{\mathrm{e}}>9.11 \times 10^{-31} \mathrm{~kg}\)
- āϝāĻĻāĻŋ \(\overrightarrow{\mathrm{A}}=2 \hat{\mathrm{i}}+3 \hat{\mathrm{j}}-5 \hat{\mathrm{k}}\) āĻāĻŦāĻ \(\overrightarrow{\mathrm{B}}=\mathbf{m} \hat{\mathrm{i}}+2 \hat{\mathrm{j}}+\mathbf{1 0} \hat{\mathrm{k}}\) āϤāĻŦā§ m- āĻāϰ āĻŽāĻžāύ āĻāϤ āĻšāϞ⧠āĻā§āĻā§āĻāϰāĻĻā§āĻŦāϝāĻŧ āĻĒāϰāϏā§āĻĒāϰā§āϰ āĻāĻĒāϰ āϞāĻŽā§āĻŦ āĻšāĻŦā§?
- 12
- 20
- 22
- 120
Ans. 22
- āĻāĻāĻāĻŋ āϏāϰāϞ āĻĻā§āϞāĻā§āϰ āĻĻā§āϰā§āĻā§āϝ āĻ
āĻĒāϰāĻāĻŋāϰ āĻĻā§āĻŦāĻŋāĻā§āĻŖāĨ¤ āĻĻā§āĻŦāĻŋāϤā§āϝāĻŧ āϏāϰāϞ āĻĻā§āϞāĻā§āϰ āĻĻā§āϞāύāĻāĻžāϞ 3s āĻšāϞ⧠āĻĒā§āϰāĻĨāĻŽāĻāĻŋāϰ āĻĻā§āϞāύāĻāĻžāϞ āĻāϤ?
- \(5.25 \mathrm{~s}\)
- \(4.24 \mathrm{~s}\)
- \(3.455 \mathrm{~s}\)
- \(6.20 \mathrm{~s}\)
Ans. \(4.24 \mathrm{~s}\)
-
āϞā§āĻāĻāĻŋāϤā§āϰā§, X āĻĻā§āĻŦāĻžāϰāĻž āĻāĻāĻāĻŋ āĻā§āϝāĻžāϏā§āϰ āĻĒā§āϰāĻžāĻĨāĻŽāĻŋāĻ āĻ
āĻŦāϏā§āĻĨāĻž āĻĻā§āĻāĻžāύ⧠āĻšāĻā§āĻā§āĨ¤ āϞā§āĻāĻāĻŋāϤā§āϰ⧠āĻā§āύ āϰā§āĻāĻžāĻāĻŋ āĻāĻāĻāĻŋ āĻĒā§āϰāĻā§āϰāĻŋāϝāĻŧāĻžāϝāĻŧ āĻā§āϝāĻžāϏāĻāĻŋ āĻĻā§āĻŦāĻžāϰāĻžāĨ¤ āĻŦāĻž āĻā§āϝāĻžāϏā§āϰ āĻāĻĒāϰ āĻā§āύ⧠āĻāĻžāĻ āĻāϰāĻž āĻšāĻā§āĻā§ āύāĻž āύāĻŋāϰā§āĻĻā§āĻļ āĻāϰā§āĨ¤
- XA
- XB
- XC
- XD
Ans. XB
- āϏāĻŽā§āĻĻā§āϰ⧠āύā§āĻāϰ āĻāϰāĻž āĻāĻāĻāĻŋ āĻāĻžāĻšāĻžāĻā§āϰ āĻā§āϝāĻžāĻĒā§āĻā§āύ āϞāĻā§āώā§āϝ āĻāϰā§āύ āϝ⧠āĻĸā§āĻāϝāĻŧā§āϰ āĻļā§āϰā§āώāĻā§āϞ⧠āĻĒāϰāϏā§āĻĒāϰ āĻĨā§āĻā§ 16m āĻĻā§āϰ⧠āĻāĻŦāĻ āĻĒā§āϰāϤāĻŋ 2s āĻĒāϰāĻĒāϰ āĻāĻāĻāĻŋ āĻĸā§āĻ āĻāϏāĻā§āĨ¤ āĻĸā§āĻāĻā§āϞā§āϰ āĻŦā§āĻ āĻāϤ?
- \(8 \mathrm{~ms}^{-1}\)
- \(16 \mathrm{~ms}^{-1}\)
- \(32 \mathrm{~ms}^{-1}\)
- \(64 \mathrm{~ms}^{-1}\)
Ans. \(8 \mathrm{~ms}^{-1}\)
- āĻāĻāĻāĻŋ āĻŦā§āϞā§āĻ āĻāĻāĻāĻŋ āĻāĻžāĻ ā§āϰ āϤāĻā§āϤāĻž āĻā§āĻĻ āĻāϰāϤ⧠āĻĒāĻžāϰā§āĨ¤ āĻŦā§āϞā§āĻāĻāĻŋāϰ āĻāϤāĻŋ 4 āĻā§āĻŖ āĻŦā§āĻĻā§āϧāĻŋ āĻāϰāϞ⧠āĻāĻšāĻž āĻāϝāĻŧāĻāĻŋ āĻ āĻāĻāĻ āĻŽāĻžāĻĒā§āϰ āϤāĻā§āϤāĻž āĻā§āĻĻ āĻāϰāϤ⧠āĻĒāĻžāϰāĻŦā§?
- 12
- 9
- 8
- 16
Ans. 16
- 4 kg āĻ 6kg āĻāϰā§āϰ āĻĻā§āĻāĻāĻŋ āĻŦāϏā§āϤ⧠āϝāĻĨāĻžāĻā§āϰāĻŽā§ \(10 \mathrm{~ms}^{-1}\) āĻāĻŦāĻ \(5 \mathrm{~ms}^{-1}\) āĻŦā§āĻā§ āĻāĻāĻ āĻĻāĻŋāĻā§ āĻāϤāĻŋāĻļā§āϞāĨ¤ āĻĒāϰāϏā§āĻĒāϰ āϧāĻžāĻā§āĻāĻž āĻāĻžāĻāϝāĻŧāĻžāϰ āĻĒāϰ āĻŦāϏā§āϤ⧠āĻĻā§āĻāĻāĻŋ āϝā§āĻā§āϤ āĻ
āĻŦāϏā§āĻĨāĻžāϝāĻŧ āĻāϞāϤ⧠āĻĨāĻžāĻāϞā§, āϝā§āĻā§āϤ āĻŦāϏā§āϤā§āϰ āĻŦā§āĻ āĻāϤ?
- \(10 \mathrm{~ms}^{-1}\)
- \(7 \mathrm{~ms}^{-1}\)
- \(6 \mathrm{~ms}^{-1}\)
- \(4 \mathrm{~ms}^{-1}\)
Ans. \(7 \mathrm{~ms}^{-1}\)
- āϏā§āϰāĻļāĻā§āϤāĻŋ āĻā§āύ āĻĒāĻĻā§āϧāϤāĻŋāϤ⧠āϏā§āώā§āĻāĻŋ āĻšāϝāĻŧ?
- Fission
- Induced Fission
- Fusion
- Chemical Reaction
Ans. Fusion
- āĻāĻāĻāĻŋ āϏāĻŽāĻŦāĻžāĻšā§ āĻĒā§āϰāĻŋāĻāĻŽā§āϰ āĻĒā§āϰāϤāĻŋāϏāϰāĻžāĻā§āĻ \(\sqrt{2}\) āĻšāϞā§,āĻāϰ āύā§āϝā§āύāϤāĻŽ āĻŦāĻŋāĻā§āϝā§āϤāĻŋ āĻā§āĻŖ āĻāϤ?
- 60°
- 15°
- 30°
- 45°
Ans. 30°
- 16 cm āĻĢā§āĻāĻžāϏ āĻĻā§āϰāϤā§āĻŦ āĻŦāĻŋāĻļāĻŋāώā§āĻ āĻāϤā§āϤāϞ āϞā§āύā§āϏ āĻĨā§āĻā§ āĻāϤ āĻĻā§āϰ⧠āĻŦāϏā§āϤ⧠āϏā§āĻĨāĻžāĻĒāύ āĻāϰāϞ⧠āĻŦāĻžāϏā§āϤāĻŦ āĻŦāĻŋāĻŽā§āĻŦā§āϰ āĻāĻāĻžāϰ āĻŦāϏā§āϤā§āϰ āĻāĻāĻžāϰā§āϰ āĻĻā§āĻŦāĻŋāĻā§āĻŖ āĻšāĻŦā§?
- 24 cm
- 16 cm
- 8 cm
- 32 cm
Ans. 24 cm
- āĻāĻāĻāĻŋ āĻšāĻžāĻāĻĄā§āϰā§āĻā§āύ āĻĒāϰāĻŽāĻžāĻŖā§ āĻāϤā§āϤā§āĻāĻŋāϤ āĻ
āĻŦāϏā§āĻĨāĻž āĻĨā§āĻā§ āύāĻŋāĻŽā§āύāϤāĻŽ āĻļāĻā§āϤāĻŋāϏā§āϤāϰ⧠āĻāϏāϞ⧠āϝ⧠āĻĢā§āĻāύ āύāĻŋāĻāϏāϰāĻŖ āĻāϰāĻŦā§ āϤāĻžāϰ āϤāϰāĻā§āĻāĻĻā§āϰā§āĻā§āϝ āĻāϤ āĻšāĻŦā§? āĻāϤā§āϤā§āĻāĻŋāϤ āĻļāĻā§āϤāĻŋāϏā§āϤāϰ āĻāĻŦāĻ āύāĻŋāĻŽā§āύāϤāĻŽ āĻļāĻā§āϤāĻŋāϏā§āϤāϰā§āϰ āĻļāĻā§āϤāĻŋ āϝāĻĨāĻžāĻā§āϰāĻŽā§ -3.4 eV āĻāĻŦāĻ -13.6 evāĨ¤ [āĻĻā§āĻāϝāĻŧāĻž āĻāĻā§, āĻĒā§āϞā§āϝāĻžāĻā§āĻ āϧā§āϰā§āĻŦāĻ, \(\mathrm{h}=6.63 \times 10^{-34} \mathrm{~J}-\mathrm{s}\) āĻāĻŦāĻ āĻāϞā§āϰ āĻŦā§āĻ, \(c=3.0 \times 10^{8} \mathrm{~ms}^{-1}\)]
- \(1.95 \times 10^{-26} \mathrm{~m}\)
- \(1.21 \times 10^{-7} \mathrm{~m}\)
- \(1.0 \times 10^{-7} \mathrm{~m}\)
- \(0.15 \mathrm{~m}\)
Ans. \(1.21 \times 10^{-7} \mathrm{~m}\)
- āĻŦā§āĻļāĻŋ āĻĨā§āĻā§ āĻāĻŽ āĻā§āĻĻāύ āĻā§āώāĻŽāϤāĻž āĻā§āϰāĻŽā§ āϤāĻŋāύāĻāĻŋ āϤā§āĻāϏā§āĻā§āϰāĻŋāϝāĻŧ āϰāĻļā§āĻŽāĻŋ āĻšāϞā§-
- \(\alpha, \beta \& \gamma\)
- \(\beta, \gamma \& \alpha\)
- \(\gamma, \alpha \& \beta\)
- \(\gamma, \beta \& \alpha\)
Ans. \(\gamma, \beta \& \alpha\)
- āĻāĻāĻāĻŋ m āĻāϰā§āϰ āĻāĻŦāĻ e āĻāϧāĻžāύā§āϰ āĻĒā§āϰā§āĻāύāĻā§ āĻļā§āύā§āϝ āĻĨā§āĻā§ V āĻŦāĻŋāĻāĻŦ āĻĒāĻžāϰā§āĻĨāĻā§āϝ⧠āϤā§āĻŦāϰāĻŋāϤ āĻāϰāĻž āĻšāϞ⧠āĻāϰ āĻļā§āώ āĻŦā§āĻ āĻāϤ?
- \(\sqrt{\frac{2 \mathrm{eV}}{\mathrm{m}}}\)
- \(\frac{2 \mathrm{eV}}{\mathrm{m}}\)
- \(\sqrt{\frac{\mathrm{eV}}{\mathrm{m}}}\)
- \(\frac{\mathrm{eV}}{\mathrm{m}}\)
Ans. \(\sqrt{\frac{2 \mathrm{eV}}{\mathrm{m}}}\)
- āĻĻā§āĻāĻāĻŋ āϤāĻĄāĻŧāĻŋā§ āĻĒā§āϰāĻŦāĻžāĻš āϝāĻĨāĻžāĻā§āϰāĻŽā§ \(\mathbf{I}=\mathbf{I}_{0} \sin \omega \mathbf{t}\) āĻ \(\mathbf{I}=\mathbf{I}_{0} \sin [\omega(\mathbf{t}+\mathbf{T} / 3)]\) āĻĻā§āĻŦāĻžāϰāĻž āĻĒā§āϰāĻāĻžāĻļ āĻāϰāĻž āϝāĻžāϝāĻŧ; āĻāĻĻā§āϰ āĻŽāϧā§āϝ⧠āĻĻāĻļāĻž āĻĒāĻžāϰā§āĻĨāĻā§āϝ āĻāϤ?
- \(\pi / 2\)
- \(\pi / 3\)
- \(2\pi / 3\)
- \(\pi \)
Ans. \(2\pi / 3\)
- āĻāĻāĻāĻŋ āĻāĻĻāϰā§āĻļ āĻā§āϝāĻžāϏā§āϰ āύāĻŽā§āύāĻžāϰ āϤāĻžāĻĒāĻŽāĻžāϤā§āϰāĻž 20°C, āϝāĻĻāĻŋ āύāĻŽā§āύāĻžāĻāĻŋāϰ āĻāĻžāĻĒ āĻāĻŦāĻ āĻāϝāĻŧāϤāύ āĻĻā§āĻŦāĻŋāĻā§āĻŖ āĻāϰāĻž āĻšāϝāĻŧ, āϤāĻŦā§ āĻĒāϰāĻŋāĻŦāϰā§āϤāĻŋāϤ āϤāĻžāĻĒāĻŽāĻžāϤā§āϰāĻž āĻāϤ?
- 20°C
- 80°C
- 900°C
- 1200°C
Ans. 900°C
- āĻāĻāĻāĻŋ āĻĒāĻĻāĻžāϰā§āĻĨā§ āϤāĻžāĻĒ āĻĒā§āϰā§ā§āĻ āĻāϰāĻžāϰ āĻĒāϰāĻ āϤāĻžāĻĒāĻŽāĻžāϤā§āϰāĻžāϰ āĻĒāϰāĻŋāĻŦāϰā§āϤāύ āĻšāϝāĻŧāύāĻŋāĨ¤ āύāĻŋāĻā§āϰ āĻā§āύ āĻāĻā§āϤāĻŋāĻāĻŋ āĻāĻ āĻāĻāύāĻžāϰ āĻāĻĒāϝā§āĻā§āϤ āĻŦā§āϝāĻžāĻā§āϝāĻž āĻĒā§āϰāĻĻāĻžāύ āĻāϰā§?
- āĻĒāĻĻāĻžāϰā§āĻĨāĻāĻŋ āĻ āĻŦāĻļā§āϝāĻ āĻā§āϝāĻžāϏ
- āĻĒāĻĻāĻžāϰā§āĻĨāĻāĻŋāϰ āĻĻāĻļāĻž āĻĒāϰāĻŋāĻŦāϰā§āϤāύ āĻšāĻā§āĻā§
- āĻĒāĻĻāĻžāϰā§āĻĨāĻāĻŋāϰ āϤāĻžāĻĒā§āϝāĻŧ āĻŦā§āĻļāĻŋāώā§āĻā§āϝ āĻŦā§āϝāϤāĻŋāĻā§āϰāĻŽ āϧāϰā§āĻŽā§
- āĻāĻžāϰāĻĒāĻžāĻļā§āϰ āĻĒāϰāĻŋāĻŦā§āĻļā§āϰ āϤā§āϞāύāĻžāϝāĻŧ āĻĒāĻĻāĻžāϰā§āĻĨā§āϰ āϤāĻžāĻĒāĻŽāĻžāϤā§āϰāĻž āĻāĻŽ
Ans. āĻĒāĻĻāĻžāϰā§āĻĨāĻāĻŋāϰ āĻĻāĻļāĻž āĻĒāϰāĻŋāĻŦāϰā§āϤāύ āĻšāĻā§āĻā§
- r āĻĻā§āϰāϤā§āĻŦā§ āϰāĻžāĻāĻž āĻĻā§āĻāĻŋ āĻā§āώā§āĻĻā§āϰ āĻāĻŖāĻžāϰ āĻŽāϧā§āϝ⧠āĻĒāϰāϏā§āĻĒāϰ āĻŽāϧā§āϝāĻžāĻāϰā§āώā§āϝāĻŧ āĻāĻāϰā§āώāĻŖ āĻŦāϞ F, āĻāĻŖāĻž āĻĻā§āĻāĻāĻŋāϰ āĻŽāĻžāĻāĻāĻžāύ⧠āĻāĻāĻāĻŋ āĻāĻžāϰ⧠āϞā§āĻšāĻžāϰ āĻĒāĻžāϤ āϰāĻžāĻāĻž āĻšāϞ⧠āĻāĻāύ āϤāĻžāĻĻā§āϰ āĻŽāϧā§āϝ⧠āĻĒāϰāϏā§āĻĒāϰ āĻāĻāϰā§āώāĻŖ āĻŦāϞ āĻāϤ?
- 0
- F
- F/2
- F/4
Ans. F
- āĻāĻŋāϤā§āϰ⧠āĻĻā§āĻāĻžāύ⧠āĻĒāĻĨ āĻĻāĻŋāϝāĻŧā§ āĻāĻāĻāĻŋ 4.0 N āĻāĻāύā§āϰ āĻĒāĻžāĻĨāϰāĻā§ āĻĒā§āĻĨāĻŋāĻŦā§āϰ āĻ
āĻāĻŋāĻāϰā§āώā§āϝāĻŧ āĻā§āώā§āϤā§āϰ⧠P āĻŦāĻŋāύā§āĻĻā§ āĻĨā§āĻā§ R āĻŦāĻŋāύā§āĻĻā§āϤ⧠āϏā§āĻĨāĻžāύāĻžāύā§āϤāϰāĻŋāϤ āĻāϰāĻž āĻšāϞā§āĨ¤ āĻĒāĻžāĻĨāϰāĻāĻŋāϰ āϏā§āĻĨāĻŋāϤāĻŋāĻļāĻā§āϤāĻŋ āĻāϤ āĻŦā§āĻĻā§āϧāĻŋ āĻĒā§āϞ?
- 120 J
- 200 J
- 280 J
- 1200 J
Ans. 120 J
- āĻĒāϰāϏā§āĻĒāϰ āĻĨā§āĻā§ s āĻĻā§āϰāϤā§āĻŦā§ āĻ
āĻŦāϏā§āĻĨāĻŋāϤ āĻĻā§āĻāĻāĻŋ āϏāĻŽāĻžāύā§āϤāϰāĻžāϞ āĻāĻŋāĻĄāĻŧāĻā§ āĻāĻāĻŦāϰā§āĻŖā§ āĻāϞ⧠āĻĻā§āĻŦāĻžāϰāĻž āĻāϞā§āĻāĻŋāϤ āĻāϰ⧠āĻāĻŋāĻĄāĻŧ āĻĨā§āĻā§ D āĻĻā§āϰāϤā§āĻŦā§ āĻ
āĻŦāϏā§āĻĨāĻŋāϤ āĻĒāϰā§āĻĻāĻžāϝāĻŧ āĻŦā§āϝāĻžāϤāĻŋāĻāĻžāϰ āĻĒāĻā§āĻāĻŋ āĻĒāĻžāĻāϝāĻŧāĻž āĻā§āϞāĨ¤ āϧāϰāĻž āϝāĻžāĻ āĻĄā§āϰāĻžāϰ āĻĒā§āϰāϏā§āĻĨ X, āϝāĻĻāĻŋ s āĻāĻŦāĻ D āĻāĻāϝāĻŧāĻā§ āĻĻā§āĻŦāĻŋāĻā§āĻŖ āĻāϰāĻž āĻšāϝāĻŧ āϤāĻŦā§ āĻĄā§āϰāĻžāϰ āĻĒā§āϰāϏā§āĻĨā§āϰ āĻŽāĻžāύ āĻāĻŋ āĻšāĻŦā§?
- X/2
- X
- 2X
- 4X
Ans. X
- āĻŦāϰā§āϤāύā§āϤ⧠B āĻāĻŦāĻ C āĻŦāĻŋāύā§āĻĻā§āϰ āĻŽāϧā§āϝ⧠āĻŦāĻŋāĻāĻŦ āĻĒāĻžāϰā§āĻĨāĻā§āϝ āĻāϤ?
- 1 V
- 2 V
- 3 V
- 9 V
Ans. 2 V
- āϞā§āĻāĻāĻŋāϤā§āϰ⧠āĻāĻāĻāĻŋ āϤāĻžāϰā§āϰ āĻĻā§āĻ āĻĒā§āϰāĻžāύā§āϤā§āϰ āĻŦāĻŋāĻāĻŦ āĻĒāĻžāϰā§āĻĨāĻā§āϝā§āϰ āϏāĻžāĻĨā§ āϤāĻĄāĻŧāĻŋā§ āĻĒā§āϰāĻŦāĻžāĻšā§āϰ āĻĒāϰāĻŋāĻŦāϰā§āϤāύ āĻĻā§āĻāĻžāύ⧠āĻšāϝāĻŧā§āĻā§āĨ¤ āϤāĻžāϰāĻāĻŋāϰ āϰā§āϧ āĻāϤ?
- \(6 \Omega\)
- \(0.67 \Omega\)
- \(5 \Omega\)
- \(1.5 \Omega\)
Ans. \(1.5 \Omega\)
- āĻāĻāĻāĻŋ āϏāĻŽāĻžāύā§āϤāϰāĻžāϞ āĻĒāĻžāϤ āϧāĻžāϰāĻāĻā§ āĻāĻžāϰā§āĻāĻŋāϤ āĻāϰāĻžāϰ āĻĢāϞ⧠āĻāĻāĻŋāϰ āĻĒāĻžāϤ āĻĻā§āĻāĻāĻŋāϰ āĻŽāϧā§āϝ⧠āĻŦāĻŋāĻāĻŦ āĻĒāĻžāϰā§āĻĨāĻā§āϝ āĻšāϝāĻŧ VāĨ¤ āϧāĻžāϰāĻāĻāĻŋāϰ āϏāĻā§āĻāĻŋāϤ āĻļāĻā§āϤāĻŋ āĻĻā§āĻŦāĻŋāĻā§āĻŖ āĻāϰāĻžāϰ āĻāύā§āϝ āĻŦāĻŋāĻāĻŦ āĻĒāĻžāϰā§āĻĨāĻā§āϝ āĻāϤ āĻšāĻŦā§?
- \(\frac{1}{4} \mathrm{~V}\)
- \(\frac{1}{2} \mathrm{~V}\)
- \(\sqrt{2} \mathrm{~V}\)
- 2 V
Ans. \(\sqrt{2} \mathrm{~V}\)
- āύāĻŋāĻā§āϰ āĻŽāĻŋāĻļā§āϰāĻŋāϤ āĻāĻāĻ āĻā§āϞā§āϰ āĻŽāϧā§āϝ⧠āĻā§āύāĻāĻŋ āĻāϝāĻŧāĻžāĻ āĻāϰ āϏāĻŽāϤā§āϞā§āϝ āύāϝāĻŧ?
- Joul/sec
- (Amp) (Volt)
- \(\left(\mathrm{Amp}^{2}\right)(\Omega)\)
- \(\Omega^{2} /\) Volt
Ans. \(\Omega^{2} /\) Volt
- āĻāĻāĻāĻŋ āĻŦāĻŋāĻĻā§āϝā§ā§ āĻĒāϰāĻŋāĻŦāĻžāĻšā§ āϞāĻŽā§āĻŦāĻž āϏāϰāϞ āϤāĻžāϰ āĻĨā§āĻā§ 2 cm āĻĻā§āϰāϤā§āĻŦā§ āĻā§āĻŽā§āĻŦāĻ āĻā§āώā§āϤā§āϰā§āϰ āĻŽāĻžāύ \(\mathbf{1 0}^{-6} \mathrm{~T}\) āĻšāϞ⧠āϤāĻžāϰāĻāĻŋāϰ āĻŽāϧā§āϝ āĻĻāĻŋāϝāĻŧā§ āĻĒā§āϰāĻŦāĻžāĻšāĻŋāϤ āĻŦāĻŋāĻĻā§āϝā§ā§ āĻāϰ āĻĒāϰāĻŋāĻŽāĻžāĻŖ āĻāϤ?
- 0.01 A
- 0.1 A
- 1 A
- 10 A
Ans. 0.1 A
- \({ }_{83}^{214} \mathrm{Bi}\) āĻāĻāϏā§āĻā§āĻĒ āĻšāϤ⧠āĻāĻāĻāĻŋ āĻāϞāĻĢāĻž āĻāĻŖāĻž āύāĻŋāĻāϏāϰāĻŖ āĻāϰ āĻĢāϞ⧠āĻĒā§āϰā§āĻĄāĻžāĻā§āĻ āĻāĻāϏā§āĻā§āĻĒ āĻšāĻŦā§-
- \({ }_{79}^{210} \mathrm{Au}\)
- \({ }_{81}^{210} \mathrm{Ti}\)
- \({ }_{83}^{210} \mathrm{Bi}\)
- \({ }_{85}^{218} \mathrm{At}\)
Ans. \({ }_{81}^{210} \mathrm{Ti}\)
- āĻāĻāĻāĻŋ āĻāĻžāĻ ā§āϰ āĻāĻŖā§āĻĄāĻā§ āĻāύā§āĻā§āĻŽāĻŋāĻā§āϰ āϏāĻžāĻĨā§ 60° āĻā§āĻŖā§ 200N āĻŦāϞ āĻĻā§āĻŦāĻžāϰāĻž āĻāĻžāύāĻž āĻšāĻā§āĻā§āĨ¤ āĻŦāϏā§āϤā§āĻāĻŋāϰ āĻāĻĒāϰ āĻāύā§āĻā§āĻŽāĻŋāĻā§āϰ āĻĻāĻŋāĻā§ āĻāĻžāϰā§āϝāĻāĻžāϰ⧠āĻŦāϞ āĻāϤ?
- 200 N
- 100 N
- 175 N
- zero
Ans. 100 N
- āĻāĻāĻāĻŋ āĻĒāĻžāĻĨāϰāĻā§ āĻā§āĻŽāĻŋ āĻĨā§āĻā§ 45 m āĻāĻāĻā§ āĻĻāĻžāϞāĻžāύā§āϰ āĻāĻĒāϰ āĻĨā§āĻā§ āĻā§āĻŽāĻŋāϰ āϏāĻŽāĻžāύā§āϤāϰāĻžāϞ⧠\(16 \mathrm{~ms}^{-1}\) āĻŦā§āĻā§ āύāĻŋāĻā§āώā§āĻĒ āĻāϰāĻž āĻšāϞā§āĨ¤ āĻĒāĻžāĻĨāϰāĻāĻŋāϰ āĻā§āĻŽāĻŋāϤ⧠āĻĒā§āĻāĻžāϤ⧠āĻāϤ āϏāĻŽāϝāĻŧ āϞāĻžāĻāĻŦā§?
- 2.8 s
- 0.4 s
- 3 s
- 1 s
Ans. 3 s
āϰāϏāĻžā§āύ
-
āĻŦāĻŋāĻā§āϰāĻŋāϝāĻŧāĻžāϝāĻŧ āĻĒā§āϰāĻāĻžāĻŦāĻā§āϰ āĻāĻžāĻ āĻšāϞ-
- āϏāĻžāĻŽā§āϝāĻžāĻŦāϏā§āĻĨāĻž āĻĄāĻžāύ āĻĻāĻŋāĻā§ āύā§āϝāĻŧāĻž
- āĻŦāĻŋāĻā§āϰāĻŋāϝāĻŧāĻžāϰ āϏāĻā§āϰāĻŋāϝāĻŧāύ āĻļāĻā§āϤāĻŋ \(\mathrm{E}_{\mathrm{a}}\) āĻāĻŽāĻžāύā§
- āĻŦāĻŋāĻā§āϰāĻŋāϝāĻŧāĻžāϰ āĻāύāĻĨāĻžāϞāĻĒāĻŋ āĻŦā§āĻĻā§āϧāĻŋ āĻāϰāĻž
- āϏāĻžāĻŽā§āϝ āĻŽāĻŋāĻļā§āϰāĻŖā§ āĻā§āĻĒāĻžāĻĻā§āϰ % āĻĒāϰāĻŋāĻŽāĻžāύ āĻŦā§āĻĻā§āϧāĻŋ āĻāϰāĻž
Ans. āĻŦāĻŋāĻā§āϰāĻŋāϝāĻŧāĻžāϰ āϏāĻā§āϰāĻŋāϝāĻŧāύ āĻļāĻā§āϤāĻŋ \(\mathrm{E}_{\mathrm{a}}\) āĻāĻŽāĻžāύā§
- āĻāĻāĻāĻŋ āĻšā§āϝāĻžāϞāĻžāĻāĻĄ āϞāĻŦāĻŖāĻā§ āĻāύ \(\mathbf{H}_{2} \mathrm{SO}_{4}\) āĻ āĻāϤā§āϤāĻĒā§āϤ āĻāϰāĻž āĻšāϞ āĻŦā§āĻā§āύāĻŋ āϧā§āϝāĻŧāĻžāϰ āĻā§āĻĒāϤā§āϤāĻŋ āĻā§āύ āĻāϝāĻŧāύā§āϰ āĻāĻĒāϏā§āĻĨāĻŋāϤāĻŋ āύāĻŋāϰā§āĻĻā§āĻļāĻ?
- \(\mathrm{I}^{-}\)
- \(\mathrm{Br}^{-}\)
- \(\mathrm{Cl}^{-}\)
- \(\mathrm{F}^{-}\)
Ans. \(\mathrm{I}^{-}\)
- āύāĻŋāĻŽā§āύā§āϰ āĻŦāĻŋāĻā§āϰāĻŋāϝāĻŧāĻžāϰ āĻĒā§āϰāĻŽāĻžāĻŖ āĻŦāĻŋāĻā§āϰāĻŋāϝāĻŧāĻž āĻāύāĻĨāĻžāϞāĻĒāĻŋ, \(\Delta \mathrm{H}_{\mathrm{R}}^{\circ}\) āĻāϤ?
\(2 \mathrm{C}+3 \mathrm{H}_{2} \rightarrow \mathrm{C}_{2} \mathrm{H}_{6}\)
āĻāĻžāϰā§āĻŦāύ (C), āĻšāĻžāĻāĻĄā§āϰā§āĻā§āύ (H) āĻāĻŦāĻ āĻāĻĨā§āύ (CH) āĻāϰ āĻĒā§āϰāĻŽāĻžāĻŖ āĻĻāĻšāύ āϤāĻžāĻĒ,\(\mathbf{\Delta} \mathbf{H}_{\mathbf{C}}^{\circ}\) āϝāĻĨāĻžāĻā§āϰāĻŽā§ -394, -286, āĻāĻŦāĻ \(-1561 \mathrm{~kJ} \mathrm{~mol}^{-1}\)- \(\Delta \mathrm{H}_{\mathrm{R}}^{\circ}=-394-286+156 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
- \(\Delta \mathrm{H}_{\mathrm{R}}^{\circ}=-1561-(2 \times-394)-(3 \times-286) \mathrm{kJ} \mathrm{mol}^{-1}\)
- \(\Delta \mathrm{H}_{\mathrm{R}}^{\circ}=-1561+394+286 \mathrm{~kJ} \mathrm{~mol}^{-1}\)
- \(\Delta \mathrm{H}_{\mathrm{R}}^{\circ}=2 \times(-394)+3 \times(-286)-(-1561) \mathrm{kJ} \mathrm{mol}^{-1}\)
Ans. \(\Delta \mathrm{H}_{\mathrm{R}}^{\circ}=2 \times(-394)+3 \times(-286)-(-1561) \mathrm{kJ} \mathrm{mol}^{-1}\)
- āύāĻŋāĻŽā§āύā§āϰ āĻā§āύāĻāĻŋ āĻā§āĻĢāϞāύā§āϰ āĻŽāύā§āĻŽāĻžāϰ?
- \(\mathrm{CH}_{2}=\mathrm{CH}_{2}\)
- \(\mathrm{CHCl}-\mathrm{CHCl}\)
- \(\mathrm{C}_{6} \mathrm{H}_{6}-\mathrm{CH}=\mathrm{CH}_{2}\)
- \(\mathrm{CF}_{2}=\mathrm{CF}_{2}\)
Ans. \(\mathrm{CF}_{2}=\mathrm{CF}_{2}\)
- āĻŦā§āϰā§āĻŽāĻŋāύ āĻāĻĨāĻŋāύā§āϰ āϏāĻžāĻĨā§ āĻŦāĻŋāĻā§āϰāĻŋāϝāĻŧāĻž āĻāϰā§āĨ¤ āĻŦāĻŋāĻā§āϰāĻŋāϝāĻŧāĻžāĻāĻŋāϰ āĻā§āĻļāϞ āĻāĻŋ?
- āĻā§āύā§āĻĻā§āϰāĻžāĻāϰā§āώ⧠āϝā§āϤ
- āĻā§āύā§āĻĻā§āϰāĻžāĻāϰā§āώ⧠āĻĒā§āϰāϤāĻŋāϏā§āĻĨāĻžāĻĒāύ
- āĻāϞā§āĻāĻā§āϰāĻā§āϰāĻžāĻšā§ āϝā§āϤ
- āĻāϞā§āĻā§āϰāĻā§āϰāĻžāĻšā§ āĻĒā§āϰāϤāĻŋāϏā§āĻĨāĻžāĻĒāύ
Ans. āĻāϞā§āĻāĻā§āϰāĻā§āϰāĻžāĻšā§ āϝā§āϤ
- \(\mathbf{H}_{2} \mathbf{O}_{2}\) āĻā§ \(\mathrm{MnO}_{4}^{-}\) āĻĻā§āĻŦāĻžāϰāĻž āĻāĻžāϰāĻŖ āĻāϰāĻž āĻšāϞ⧠āĻā§āώ āĻŦāĻŋāĻāĻŦ, \(\mathbf{E}^{\circ}\) Cell
āĻšāĻŋāϏāĻžāĻŦ āĻāϰāĨ¤ āĻ āϰā§āϧ-āĻŦāĻŋāĻā§āϰāĻŋāϝāĻŧāĻžāĻā§āϞ⧠āĻšāϞ-
\(2 \mathrm{H}^{+}+\mathrm{O}_{2}+2 \mathrm{e}^{-} \rightleftharpoons \mathrm{H}_{2} \mathrm{O}_{2} ; \mathrm{E}^{0}=+0.68 \mathrm{~V}\)
\(\mathrm{MnO}_{4}^{-}+8 \mathrm{H}^{+}+5 \mathrm{e}^{-}=\mathrm{Mn}^{2+}+4 \mathrm{H}_{2} \mathrm{O} ; \mathrm{E}^{0}=+1.51 \mathrm{~V}\)- \(\mathrm{E}_{\mathrm{Cell}}^{0}=-0.83 \mathrm{~V}\)
- \(\mathrm{E}_{\text {Cell }}^{0}=+0.83 \mathrm{~V}\)
- \(\mathrm{E}_{\text {Cell }}^{0}=+0.38 \mathrm{~V}\)
- \(\mathrm{E}_{\mathrm{Cell}}^{0}=+2.19 \mathrm{~V}\)
Ans. \(\mathrm{E}_{\text {Cell }}^{0}=+0.83 \mathrm{~V}\)
- 100°C āϤāĻžāĻĒāĻŽāĻžāϤā§āϰāĻžāϝāĻŧ āĻ 1 āĻŦāĻžāϝāĻŧā§āĻŽāύā§āĻĄāϞā§āϝāĻŧ āĻāĻžāĻĒā§ 1 āĻāĻŋāϞā§āĻā§āϰāĻžāĻŽ āĻāϞā§āϝāĻŧ āĻŦāĻžāώā§āĻĒā§āϰ āĻāϝāĻŧāϤāύ āĻāϤ?
- 12 L
- 100 L
- 1200 L
- 1701 L
Ans. 1701 L
- āύāĻŋāĻŽā§āύā§āϰ āĻā§āύāĻāĻŋ āĻā§āϝāĻžāύāĻŋāĻāĻžāϰ⧠āĻŦāĻŋāĻā§āϰāĻŋāϝāĻŧāĻž?
- \(2 \mathrm{HCHO}(1) \stackrel{50 \% \mathrm{NaOH}, 20-30^{\circ} \mathrm{C}}{\rightarrow} \mathrm{CH}_{3} \mathrm{OH}(\mathrm{aq})+\)\(\mathrm{HCOO}^{-} \mathrm{Na}^{+}(\mathrm{aq})\)
-
\(2 \mathrm{CH}_{3} \mathrm{CHO}(1) \stackrel{\text { dil. } \mathrm{NaOH}, 20-30^{\circ} \mathrm{C}}{\rightarrow} \mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH})\)
\(\mathrm{CH}_{2} \mathrm{CHO}(\mathrm{aq})\) - \(\mathrm{CH}_{3} \mathrm{CHO}(1) \stackrel{\mathrm{LiAlH}_{4}, \text { conc. HCI }}{\longrightarrow} \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\)
-
\(\mathrm{CH}_{3} \mathrm{CONH}_{2}(\mathrm{aq})+\mathrm{Br}_{2}(\mathrm{aq})+4 \mathrm{NaOH}(\mathrm{aq}) \stackrel{\text { Heat }}{\rightarrow}\)
\(\mathrm{CH}_{3} \mathrm{NH}_{2}(\mathrm{aq})+2 \mathrm{NaBr}(\mathrm{aq})+\mathrm{Na}_{2} \mathrm{CO}_{3}(\mathrm{aq})+\)
\(2 \mathrm{H}_{2} \mathrm{O}(1)\)
Ans. \(2 \mathrm{HCHO}(1) \stackrel{50 \% \mathrm{NaOH}, 20-30^{\circ} \mathrm{C}}{\rightarrow} \mathrm{CH}_{3} \mathrm{OH}(\mathrm{aq})+\)\(\mathrm{HCOO}^{-} \mathrm{Na}^{+}(\mathrm{aq})\)
- āĻāĻāĻāĻŋ āĻĒā§āϰāĻĨāĻŽ āĻŦāĻŋāĻā§āϰāĻŋāϝāĻŧāĻžāϝāĻŧ āĻ
āϰā§āϧāĻžāϝāĻŧā§ 15 min āĻšāϞ⧠āĻšāĻžāϰ āϧā§āϰā§āĻŦāĻ āĻāϤ?
- \(4.62 \times 10^{-2} \mathrm{~min}^{-1}\)
- \(3.20 \times 10^{-2} \mathrm{~min}^{-1}\)
- \(5.01 \times 10^{-2} \mathrm{~min}^{-1}\)
- \(4.50 \times 10^{-2} \mathrm{~min}^{-1}\)
Ans. \(4.62 \times 10^{-2} \mathrm{~min}^{-1}\)
- āĻāĻāĻāĻŋ āϰā§āĻā§āϰ āϰāĻā§āϤā§āϰ āĻā§āϞā§āĻā§āĻā§āϰ āĻĒāϰāĻŋāĻŽāĻžāĻŖ \(\mathbf{1 0} \mathrm{mmol} \mathbf{L}^{-1}\)āĨ¤āĻŽāĻŋāϞāĻŋāĻā§āϰāĻžāĻŽ/ āĻĄā§āϏāĻŋāϞāĻŋāĻāĻžāϰ āĻāĻāĻā§ āĻāϰ āĻŽāĻžāύ āĻāϤ?
- 180
- 18.0
- 1.80
- None
Ans. 180
- āĻĸāĻžāϞāĻžāĻ āϞā§āĻšā§ āĻāĻžāϰā§āĻŦāύā§āϰ āĻĒāϰāĻŋāĻŽāĻžāύ āĻāϤ?
- \(2.0-4.5 \%\)
- \(0.12-0.25 \%\)
- \(0.20 \%\)
- \(0.25-1.70 \%\)
Ans. \(2.0-4.5 \%\)
- āύāĻŋāĻŽā§āύā§āϰ āĻŦāĻŋāĻā§āϰāĻŋāϝāĻŧāĻžāϝāĻŧ āĻā§āύāĻāĻŋ āϏāϤā§āϝ?
\(\mathrm{SnCl}_{2}+2 \mathrm{FeCl}_{3}=\mathrm{SnCl}_{4}+2 \mathrm{FeCl}_{2}\)- Sn āĻāĻžāϰāĻŋāϤ āĻšāϝāĻŧā§āĻā§
- Cl āĻāĻžāϰāĻŋāϤ āĻšāϝāĻŧā§āĻā§
- Fe āĻāĻžāϰāĻŋāϤ āĻšāϝāĻŧā§āĻā§
- Cl āĻŦāĻŋāĻāĻžāϰāĻŋāϤ āĻšāϝāĻŧā§āĻā§
Ans. Sn āĻāĻžāϰāĻŋāϤ āĻšāϝāĻŧā§āĻā§
- āĻāĻāϏā§āĻāύā§āϰ āĻāĻĻāĻžāĻšāϰāĻŖ-
- \({ }_{7}^{13} \mathrm{~N},{ }_{6}^{13} \mathrm{C}\)
- \({ }_{18}^{40} \mathrm{Ar},{ }_{20}^{40} \mathrm{Ca}\)
- \({ }_{20}^{40} \mathrm{Ca},{ }_{19}^{40} \mathrm{~K}\)
- \({ }_{15}^{31} \mathrm{P},{ }_{16}^{32} \mathrm{~S}\)
Ans. \({ }_{15}^{31} \mathrm{P},{ }_{16}^{32} \mathrm{~S}\)
- āĻĒā§āϰāĻĒāĻžāĻāύ⧠\(\sigma \)-āĻŦāύā§āϧāύ āĻāĻŦāĻ \(\pi \) āĻŦāύā§āϧāύ āĻāϰ āϏāĻāĻā§āϝāĻž āĻāϤ?
- 3āĻāĻŋ \(\sigma \)-āĻŦāύā§āϧāύ āĻāĻŦāĻ 2āĻāĻŋ \(\pi \)-āĻŦāύā§āϧāύ
- 6āĻāĻŋ \(\sigma \)-āĻŦāύā§āϧāύ āĻāĻŦāĻ 2āĻāĻŋ \(\pi \)-āĻŦāύā§āϧāύ
- 2āĻāĻŋ \(\sigma \)-āĻŦāύā§āϧāύ āĻāĻŦāĻ 2āĻāĻŋ \(\pi \)-āĻŦāύā§āϧāύ
- 2āĻāĻŋ \(\sigma \)-āĻŦāύā§āϧāύ āĻāĻŦāĻ 4āĻāĻŋ \(\pi \)-āĻŦāύā§āϧāύ
Ans. 6āĻāĻŋ \(\sigma \)-āĻŦāύā§āϧāύ āĻāĻŦāĻ 2āĻāĻŋ \(\pi \)-āĻŦāύā§āϧāύ
- āύāĻŋāĻŽā§āύā§āϰ āĻā§āύ āĻā§āĻŦ āϝā§āĻāĻāĻŋ āĻā§ā§āĻĄā§āĻĢāϰāĻŽ āĻĒāϰā§āĻā§āώāĻž āĻĻā§āϝāĻŧ āύāĻž?
- \(\mathrm{CH}_{3} \mathrm{COCl}\)
- \(\mathrm{CH}_{3} \mathrm{CHOHCH}_{3}\)
- \(\mathrm{CH}_{3} \mathrm{COCH}_{3}\)
- \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\)
Ans. \(\mathrm{CH}_{3} \mathrm{COCl}\)
- \(\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}\) āĻāϰ āĻāύā§āϝ āϏāϰā§āĻŦā§āĻā§āĻ āĻāϤāĻāĻŋ āĻāĻĨāĻžāϰ āϝā§āĻā§āϰ āϏāĻŽāĻžāĻŖā§ āĻĒāĻžāĻāϝāĻŧāĻž āϝāĻžāϝāĻŧ?
- 3
- 4
- 5
- 6
Ans. 3
- āĻāĻāĻāĻŋ āĻāĻĒāĻžāϰ (II) āĻĻā§āϰāĻŦāĻŖā§āϰ āĻŽāϧā§āϝ āĻĻāĻŋāϝāĻŧā§ āĻ
āϰā§āϧ āĻāĻŖā§āĻāĻž āϝāĻžāĻŦāϤ 10.0 Ampere āĻŦāĻŋāĻĻā§āϝā§ā§ āĻĒā§āϰāĻŦāĻžāĻšāĻŋāϤ āĻāϰāϞ⧠āĻāĻŋ āĻĒāϰāĻŋāĻŽāĻžāĻŖ āĻāĻĒāĻžāϰ āϏāĻā§āĻāĻŋāϤ āĻŦāĻž āĻĻā§āϰāĻŦā§āĻā§āϤ āĻšāĻŦā§?
- 6.3 g
- 1.5 g
- 0.60 g
- None
Ans. None
-
āĻāĻāĻāĻŋ 1.0M āϏā§āĻĄāĻŋāϝāĻŧāĻžāĻŽ āĻšāĻžāĻāĻĄā§āϰā§āĻā§āϏāĻžāĻāĻĄā§āϰ āĻāϞā§āϝāĻŧ āĻĻā§āϰāĻŦāĻŖā§āϰ 100mL āĻā§ āϏāĻŽā§āĻĒā§āϰā§āĻŖāϰā§āĻĒā§ āύāĻŋāϰāĻĒā§āĻā§āώ āĻāϰāϤ⧠āĻāϤ āĻāϝāĻŧāϤāύ 0.5M āĻ
āĻā§āϏāĻžāϞāĻŋāĻ āĻāϏāĻŋāĻĄ āĻĒā§āϰā§ā§āĻāύ āĻĒāĻĄāĻŧāĻŦā§?
- 50 mL
- 100 mL
- 200 mL
- 400 mL
Ans. 100 mL
- IUPAC āĻĒāĻĻā§āϧāϤāĻŋāϤ⧠āύāĻŋāĻŽā§āύā§āϰ āϝā§āĻāĻāĻŋāϰ āύāĻžāĻŽ āĻāĻŋ?
\(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{C}-\mathrm{CH}_{2}-\mathrm{CH}\left(\mathrm{CH}_{3}\right)_{2}\)- 2,2,4-Trimethylpentane
- 2,4,4-Trimethylpentane
- Isopentane
- Neooctane
Ans. 2,2,4-Trimethylpentane
- āύāĻŋāĻā§āϰ āĻŦāĻŋāĻā§āϰāĻŋāϝāĻŧāĻžāϰ āĻĒā§āϰāϧāĻžāύ āĻā§āĻĒāĻžāĻĻ āĻāĻŋ?
\(\mathrm{CH} \equiv \mathrm{CH}+\mathrm{H}_{2} \mathrm{O} \stackrel{20 \% \mathrm{H}_{2} \mathrm{SO}_{4} \cdot 60^{\circ} \mathrm{C}}{\rightarrow} ?\)- \(\mathrm{CH}_{3} \mathrm{CHO}\)
- \(\mathrm{CH}_{3} \mathrm{COOH}\)
- \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\)
- \(\mathrm{CH}_{3} \mathrm{COCH}_{3}\)
Ans. \(\mathrm{CH}_{3} \mathrm{CHO}\)
- āύāĻŋāĻā§āϰ āĻā§āύ āĻ
āϰāĻŦāĻŋāĻāĻžāϞ āĻāϞā§āĻāĻā§āϰāύ āĻāĻā§ āĻĒā§āϰāĻŦā§āĻļ āĻāϰā§?
- 4f
- 5d
- 6p
- 7s
Ans. 4f
- āύāĻŋāĻŽā§āύā§āϰ āĻŽāĻŋāĻļā§āϰāĻŖāĻā§āϞā§āϰ āĻŽāϧā§āϝ⧠āĻā§āύāĻāĻŋ āĻŦāĻžāĻĢāĻžāϰ āĻĻā§āϰāĻŦāĻŖ?
- 0.2 M 10 mL CH2COOH + 0.2 M 10 mL NaOH
- 0.2 M 10 mL CH3COOH + 0.1 M 10 mL NaOH
- 0.1 M 10 mL CH3COOH + 0.2 M 10 mL NaOH
- 0.1 M 10 mL HCl + 0.2 M 10 mL NaOH
Ans. 0.2 M 10 mL CH3COOH + 0.1 M 10 mL NaOH
- 0.1 M \(\mathrm{CH}_{3} \mathrm{COOH}\) āĻĻā§āϰāĻŦāĻŖā§āϰ pH āĻāϤ? āĻāĻāĻžāύā§, \(\mathbf{K}_{\mathrm{a}}=1.8 \times 10^{-5}\)
- 2.672
- 2.772
- 2.872
- 2.972
Ans. 2.872
- āύāĻŋāĻŽā§āύā§āϰ āĻā§āύāĻāĻŋ āϏāϰā§āĻŦāĻžāϧāĻŋāĻ āϏāĻāĻā§āϝāĻ āϝā§āĻ āĻāĻ āύ āĻāϰā§?
- Argon
- Krypton
- Xenon
- Radon
Ans. Xenon
- \(\mathrm{S}_{2} \mathrm{O}_{3}{ }^{2-}\) āĻāĻŦāĻ \(\mathrm{S}_{4} \mathrm{O}_{6}^{2-}\) āĻ āϏāĻžāϞāĻĢāĻžāϰā§āϰ āĻāĻžāϰāĻŖ āϏāĻāĻā§āϝāĻž āĻšāϞ-
- -2 and -2.5
- +2 and +2.5
- +4 and +6
- +2 and -2
Ans. +2 and +2.5
- āĻŦā§āύāĻāĻŋāύ āĻĄāĻžāϝāĻŧāĻžāĻā§āύāĻŋāϝāĻŧāĻžāĻŽ āĻā§āϞā§āϰāĻžāĻāĻĄā§āϰ āĻāϞā§āϝāĻŧ āĻĻā§āϰāĻŦāĻŖāĻā§ āϤāĻžāĻĒ āĻĻā§āϝāĻŧāĻž āĻšāϞ⧠āĻāĻŋ āĻāĻā§?
- Formation of phenol
- Formation of nitrobenzene
- Formation of diphenyl
- Formation of phenylhydrazine
Ans. Formation of phenol
- HCHO āĻ
āĻŖā§āϤ⧠āĻāĻžāϰā§āĻŦāύā§āϰ āĻšāĻžāĻāĻŦā§āϰāĻŋāĻĄāĻžāĻāĻā§āĻļāύ āĻšāϞ-
- sp
- \(\mathrm{sp}^{2}\)
- \(\mathrm{sp}^{3}\)
- None
Ans. \(\mathrm{sp}^{2}\)
- āĻŽāĻžāϰāĻāĻžāϰ⧠(II) āĻ
āĻā§āϏāĻžāĻāĻĄ āϤāĻžāĻĒā§ āύāĻŋāĻŽā§āύā§āϰ āĻŦāĻŋāĻā§āϰāĻŋāϝāĻŧāĻž āĻ
āύā§āϏāĻžāϰ⧠āĻāĻžāĻā§āĻāϞ⧠āĻ āĻĒā§āϰāĻā§āϰāĻŋāϝāĻŧāĻžāĻāĻŋāϰ āϏāĻžāĻŽā§āϝāĻžāĻāĻāĻā§ āĻāĻŋāĻāĻžāĻŦā§ āĻĒā§āϰāĻāĻžāĻļ āĻāϰāĻž āϝāĻžāϝāĻŧ?
\(2 \mathrm{HgO}(\mathrm{s}) \rightleftharpoons 2 \mathrm{Hg}(l)+\mathrm{O}_{2}(\mathrm{~g})\)- \(\mathrm{K}=\frac{[\mathrm{Hg}]^{2}\left[\mathrm{O}_{2}\right]}{[\mathrm{HgO}]^{2}}\)
- \(\mathrm{K}=\frac{[\mathrm{Hg}]\left[\mathrm{O}_{2}\right]}{[\mathrm{HgO}]}\)
- \(\mathrm{K}=[\mathrm{Hg}]\left[\mathrm{O}_{2}\right]\)
- \(\mathrm{K}=\left[\mathrm{O}_{2}\right]\)
Ans. \(\mathrm{K}=\left[\mathrm{O}_{2}\right]\)
- āύāĻŋāĻā§āϰ āύāĻŋāĻāĻā§āϞāĻŋāϝāĻŧāĻžāϰ āĻŦāĻŋāĻā§āϰāĻŋāϝāĻŧāĻžāϝāĻŧ X-āĻā§ āĻāĻŋ āĻŦāϞāĻž āϝāĻžāϝāĻŧ?
\({ }_{7}^{14} \mathrm{~N}+\alpha \rightarrow { }_{8}^{17} \mathrm{~O}+\mathrm{X}\)- Proton
- \(\beta\)-particle
- \(\gamma\)-ray
- Neutron
Ans. Proton
- āĻĢā§āύāϞ āĻ āĻāϞāĻā§āĻšāϞ āĻāĻāϝāĻŧā§āϰ āĻāύā§āϝ āύāĻŋāĻŽā§āύā§āϰ āĻā§āύāĻāĻŋ āϏāϤā§āϝ?
- \(\mathrm{PCl}_{5}\) āĻāϰ āϏāĻžāĻĨā§ āĻŦāĻŋāĻā§āϰāĻŋāϝāĻŧāĻž āĻāϰā§
- āϰāĻžāĻāĻŽāĻžāϰ āĻāĻžāĻāĻŽā§āϝāĻžāύ āĻŦāĻŋāĻā§āϰāĻŋāϝāĻŧāĻž āĻĒā§āϰāĻĻāϰā§āĻļāύ āĻāϰā§
- āĻĒāĻžāύāĻŋāϰ āϏāĻžāĻĨā§ āĻŦāĻŋāĻā§āϰāĻŋāϝāĻŧāĻž āĻāϰā§
- āϞā§āĻāĻžāϏ āĻŦāĻŋāĻāĻžāϰāĻā§āϰ āϏāĻžāĻĨā§ āĻŦāĻŋāĻā§āϰāĻŋāϝāĻŧāĻž āĻāϰā§
Ans. \(\mathrm{PCl}_{5}\) āĻāϰ āϏāĻžāĻĨā§ āĻŦāĻŋāĻā§āϰāĻŋāϝāĻŧāĻž āĻāϰā§
āĻāĻŖāĻŋāϤ
-
(3, -1) āĻāĻŦāĻ (5, 2) āĻŦāĻŋāύā§āĻĻā§āĻĻā§āĻŦāϝāĻŧā§āϰ āϏāĻāϝā§āĻžāĻāĻāĻžāϰ⧠āϏāϰāϞāϰā§āĻāĻžāĻā§ 3:4 āĻ
āύā§āĻĒāĻžāϤ⧠āĻŦāĻšāĻŋāĻāϏā§āĻĨāĻāĻžāĻŦā§ āĻŦāĻŋāĻāĻā§āϤāĻāĻžāϰ⧠āĻŦāĻŋāύā§āĻĻā§āϰ āϏā§āĻĨāĻžāύāĻžāĻā§āĻ-
- \(\left(\frac{14}{3}, 3\right)\)
- \(\left(\frac{27}{7}, \frac{2}{7}\right)\)
- \(\left(\frac{27}{4}, \frac{4}{3}\right)\)
- āĻā§āύā§āĻāĻŋāĻ āύā§
Ans. āĻā§āύā§āĻāĻŋāĻ āύā§
- \(f(x)=\sqrt{x^{2}-5 x+6}\) āĻĢāĻžāĻāĻļāύā§āϰ āĻĄā§āĻŽā§āĻāύ āĻāĻŦāĻ āϰā§āĻā§āĻ āϝāĻĨāĻžāĻā§āϰāĻŽā§-
- \(x \leq 2,3 \leq x\) and \(y \geq 0\)
- \(2 \leq x \leq 3\) and \(y \geq 0\)
- \(x \geq 3\) and \(y>0\)
- \(x \leq 2, x \geq 3\) and \(y>0\)
Ans. \(x \leq 2,3 \leq x\) and \(y \geq 0\)
-
32 ft/sec āĻāĻĻāĻŋāĻŦā§āĻ āĻāĻŦāĻ āĻā§āĻŽāĻŋāϰ āϏāĻžāĻĨā§ \(30^{\circ}\) āĻā§āĻŖā§ āĻŦāϏā§āϤ⧠āύāĻŋāĻā§āώā§āĻĒ āĻāϰāĻž āĻšāϞā§āĨ¤ āĻāĻšāĻžāϰ āĻāύā§āĻā§āĻŽāĻŋāĻ āĻĒāĻžāϞā§āϞāĻž-
- \(16 \mathrm{ft}\)
- \(21 \sqrt{3}\) ft
- \(32 \mathrm{ft}\)
- \(16 \sqrt{3} \mathrm{ft}\)
Ans. \(16 \sqrt{3} \mathrm{ft}\)
-
If \(x^{n}+y^{n}=a^{n}\) then \(\frac{d y}{d x}=?\)
- \(\left(\frac{x}{y}\right)^{n}\)
- \(\left(-\frac{x}{y}\right)^{n}\)\(\left(-\frac{x}{y}\right)^{n}\)
- \(-\left(\frac{x}{y}\right)^{n-1}\)
- \(+\left(\frac{x}{y}\right)^{n-1}\)
Ans. \(-\left(\frac{x}{y}\right)^{n-1}\)
- \(\cot \theta+\sqrt{3}=2 \operatorname{cosec} \theta\) āϏāĻŽā§āĻāϰāĻŖā§āϰ āϏāĻŽāĻžāϧāĻžāύ-
- \(\theta=2 \mathrm{n} \pi-\frac{\pi}{3}\)
- \(\theta=2 n \pi+\frac{\pi}{3}\)
- \(\theta=2 \mathrm{n} \pi+\frac{\pi}{6}\)
- \(\theta=2 n \pi-\frac{\pi}{6}\)
Ans. \(\theta=2 n \pi+\frac{\pi}{3}\)
-
\(\left(\begin{array}{ll}\cos \theta & \sin \theta \\ -\sin \theta & \cos \theta\end{array}\right)\) āĻāϰ āĻŦāĻŋāĻĒāϰā§āϤ āĻŽā§āϝāĻžāĻā§āϰāĻŋāĻā§āϏ-
- \(\left(\begin{array}{ll}\cos \theta & -\sin \theta \\ -\sin \theta & \cos \theta\end{array}\right)\)
- \(\left(\begin{array}{ll}\cos \theta & -\sin \theta \\ \sin \theta & -\cos \theta\end{array}\right)\)
- \(\left(\begin{array}{ll}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta\end{array}\right)\)
- \(\left(\begin{array}{ll}\cos \theta & \sin \theta \\ \sin \theta & \cos \theta\end{array}\right)\)
Ans. \(\left(\begin{array}{ll}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta\end{array}\right)\)
- 4 āĻāύ āĻŽāĻšāĻŋāϞāĻžāϏāĻš 10 āĻŦā§āϝāĻā§āϤāĻŋāϰ āĻŽāϧā§āϝ āĻĨā§āĻā§ 5 āĻāύā§āϰ āĻāĻāĻāĻŋ āĻāĻŽāĻŋāĻāĻŋ āĻāĻ āύ āĻāϰāϤ⧠āĻšāĻŦā§ āϝāĻžāϤ⧠āĻ
āύā§āϤāϤ āĻāĻāĻāύ āĻŽāĻšāĻŋāϞāĻž āĻ
āύā§āϤāϰā§āĻā§āĻā§āϤ āĻĨāĻžāĻāĻŦā§āĨ¤ āĻāϤ āĻŦāĻŋāĻāĻŋāύā§āύ āĻĒā§āϰāĻāĻžāϰ⧠āĻ āĻāĻŽāĻŋāĻāĻŋ āĻāĻ āύ āĻāϰāĻž āϝā§āϤ⧠āĻĒāĻžāϰā§?
- 1440
- 246
- 120
- 60
Ans. 246
- \(\left|\begin{array}{lll}0 & 3 & 2 x+7 \\ 2 & 7 x & 9+5 x \\ 0 & 0 & 2 x+5\end{array}\right|=0\) āĻšāϞā§, x āĻāϰ āĻŽāĻžāύ
- \(-\frac{9}{2}\)
- \(-\frac{7}{2}\)
- \(-\frac{5}{2}\)
- 0
Ans. \(-\frac{5}{2}\)
- \(\arctan \left\{\sin \left(\arccos \frac{\sqrt{2}}{\sqrt{3}}\right)\right\}\) āϏāĻŽāĻžāύ
- \(\frac {\pi}{2}\)
- \(\frac {\pi}{3}\)
- \(\frac {\pi}{4}\)
- \(\frac {\pi}{6}\)
Ans. \(\frac {\pi}{6}\)
- āĻā§āύ⧠āĻŦāĻŋāύā§āĻĻā§āϤ⧠P āĻāĻŦāĻ 2P āĻŽāĻžāύā§āϰ āĻĻā§āĻāĻāĻŋ āĻŦāϞ āĻā§āϰāĻŋāϝāĻŧāĻžāĻļā§āϞāĨ¤ āĻĒā§āϰāĻĨāĻŽ āĻŦāϞāĻāĻŋāĻā§ āĻĻā§āĻŦāĻŋāĻā§āĻŖ āĻāϰ⧠āĻĻā§āĻŦāĻŋāϤā§āϝāĻŧāĻāĻŋāϰ āĻŽāĻžāύ ā§Ē āĻāĻāĻ āĻŦā§āĻĻā§āϧāĻŋ āĻāϰāĻž āĻšāϞā§, āϤāĻžāĻĻā§āϰ āϞāĻŦā§āϧāĻŋāϰ āĻĻāĻŋāĻ āĻ
āĻĒāϰāĻŋāĻŦāϰā§āϤāĻŋāϤ āĻĨāĻžāĻā§āĨ¤ P āĻāϰ āĻŽāĻžāύ-
- 1
- 2
- 4
- 8
Ans. 4
- \(\mathbf{y}=-\sqrt{\mathbf{a}^{2}-\mathbf{x}^{2}}\) āĻ \(\mathbf{y}=\mathbf{0}\) āĻĻā§āĻŦāĻžāϰāĻž āĻāĻŦāĻĻā§āϧ āĻā§āώā§āϤā§āϰā§āϰ āĻā§āώā§āϤā§āϰāĻĢāϞ-
- \(\frac{1}{4} \pi \mathrm{a}^{2}\)
- \(\frac{1}{2} \pi \mathrm{a}^{2}\)
- \(\pi \mathrm{a}^{2}\)
- \(\frac{1}{2} \mathrm{a}^{2}\)
Ans. \(\frac{1}{2} \pi \mathrm{a}^{2}\)
- 101101 āĻāϰ āϏāĻžāĻĨā§ āĻā§āύ āύā§āϝā§āύāϤāĻŽ āĻĻā§āĻŦāĻŋāĻŽāĻŋāĻ āϏāĻāĻā§āϝāĻž āϝā§āĻžāĻ āĻāϰāϞ⧠āϝā§āĻžāĻāĻĢāϞ 16 āĻĻā§āĻŦāĻžāϰāĻž āĻŦāĻŋāĻāĻžāĻā§āϝ āĻšāĻŦā§?
- 10011
- 111
- 110
- 11
Ans. 11
- \(-\frac{1}{2}-\frac{1}{2.2^{2}}-\frac{1}{3.2^{3}}-\frac{1}{4.2^{4}}-\ldots \ldots\) āϧāĻžāϰāĻžāĻāĻŋāϰ āϏāĻŽāώā§āĻāĻŋ-
- -2 ln 2
- – ln 2
- -2 e
- – e
Ans. – ln 2
- āĻŦāĻžāϏā§āϤāĻŦ āϏāĻāĻā§āϝāĻžāϝāĻŧ \(\frac{1}{|3 x+1|} \geq 5\) āĻ
āϏāĻŽāϤāĻžāĻāĻŋāϰ āϏāĻŽāĻžāϧāĻžāύ-
- \(\left(-\frac{2}{3},-\frac{1}{3}\right) \cup\left(-\frac{1}{3},-\frac{4}{5}\right)\)
- \(\left[-\frac{2}{5},-\frac{1}{3}\right) \cup\left(-\frac{1}{3},-\frac{4}{15}\right]\)
- \(\left(-\frac{2}{3},-\frac{4}{15}\right)\)
- None
Ans. \(\left[-\frac{2}{5},-\frac{1}{3}\right) \cup\left(-\frac{1}{3},-\frac{4}{15}\right]\)
-
\(\underset {x \rightarrow 0} {\overset { } {\mathrm lim} } \frac{cos x-1}{ x^{2}}=?\)
- \(-1\)
- \(-\frac{1}{2}\)
- \(\frac{1}{2}\)
- 1
Ans. \(-\frac{1}{2}\)
- (3, -1) āĻŦāĻŋāύā§āĻĻā§āĻāĻžāĻŽā§ āĻāĻŦāĻ \(x^{2}+y^{2}-6 x+8 y=0\) āĻŦā§āϤā§āϤā§āϰ āϏāĻžāĻĨā§ āĻāĻāĻā§āύā§āĻĻā§āϰāĻŋāĻ āĻŦā§āϤā§āϤā§āϰ āϏāĻŽā§āĻāϰāĻŖ-
- \(x^{2}+y^{2}+6 x-8 y+16=0\)
- \(x^{2}+y^{2}-6 x-8 y-16=0\)
- \(x^{2}+y^{2}-6 x+8 y+16=0\)
- \(x^{2}+y^{2}-6 x-8 y+16=0\)
Ans. \(x^{2}+y^{2}-6 x+8 y+16=0\)
-
sinA + cosA = sinB + cosB āĻšāϞā§, A + B = ?
- \(\pi\)
- \(\pi / 2\)
- \(2\pi\)
- \(\pi/4\)
Ans. \(\pi / 2\)
- \(\left(2 x^{2}-\frac{1}{4 x}\right)^{11}\) āĻāϰ āĻŦāĻŋāϏā§āϤā§āϤāĻŋāϤ⧠\(\mathbf{x}^{7}\) āĻāϰ āϏāĻšāĻ-
- \(-\frac{231}{8}\)
- 231
- \(\frac{231}{4}\)
- \(\frac{231}{8}\)
Ans. \(-\frac{231}{8}\)
- \(z_{1}=2+i\) āĻāĻŦāĻ \(z_{2}=3+i\) āĻšāϞā§, \(\mathbf{z}_{1} \overline{\mathbf{z}}_{2}\) āĻāϰ āĻŽāĻĄā§āϞāĻžāϏ-
- 6
- \(5 \sqrt{2}\)
- 7
- \(5 \sqrt{3}\)
Ans. \(5 \sqrt{2}\)
- āĻĒā§āϰā§āĻŖāϏāĻāĻā§āϝāĻž āϏāĻšāĻāϏāĻš āĻĻā§āĻŦāĻŋāĻŽāĻžāϤā§āϰāĻŋāĻ āϏāĻŽā§āĻāϰāĻŖ, āϝāĻžāϰ āĻāĻāĻāĻŋ āĻŽā§āϞ \(\sqrt{-5}-1\)
- \(x^{2}+2 x+6=0\)
- \(x^{2}+x+3=0\)
- \(x^{2}+2 x-6=0\)
- \(x^{2}+x-3=0\)
Ans. \(x^{2}+2 x+6=0\)
- āĻāĻāĻāĻŋ āĻāϝāĻŧāϤāĻā§āώā§āϤā§āϰā§āϰ āĻĻā§āϰā§āĻā§āϝ 20% āĻŦā§āĻĻā§āϧāĻŋ āĻāĻŦāĻ āĻĒā§āϰāϏā§āĻĨ 20% āĻšā§āϰāĻžāϏ āĻāϰāϞ⧠āĻāϰ āĻā§āώā§āϤā§āϰāĻĢāϞā§āϰ āĻļāϤāĻāϰāĻž āĻĒāϰāĻŋāĻŦāϰā§āϤāύ-
- decreases by 4%
- increases by 4%
- increases by 5%
- remains unchanged
Ans. decreases by 4%
- x + y = 3 āĻāĻŦāĻ y – x = 1 āϏāϰāϞāϰā§āĻāĻžāĻĻā§āĻŦāϝāĻŧā§āϰ āĻā§āĻĻāĻŦāĻŋāύā§āĻĻā§āĻāĻžāĻŽā§, x āĻ
āĻā§āώā§āϰ āϏāĻŽāĻžāύā§āϤāϰāĻžāϞ āϏāĻŽā§āĻāϰāĻŖ-
- \( y=2 \)
- \( 2y=2 \)
- \( x=1 \)
- \( x+3=0 \)
Ans. \( y=2 \)
- āĻāĻāĻ āĻŦā§āϝāĻžāϏāĻžāϰā§āϧā§āϰ āĻŦā§āϤā§āϤ⧠āĻ
āϞāĻŋāĻāĻŋāϤ āĻāĻāĻāĻŋ āϏāĻŽāĻŦāĻžāĻšā§ āϤā§āϰāĻŋāĻā§āĻā§āϰ āĻŦāĻžāĻšā§āϰ āĻĻā§āϰā§āĻā§āϝ-
- \(\frac{3}{2}\) units
- \(\frac{\sqrt{3}}{2}\) units
- \(\sqrt{3}\) units
- 1 units
Ans. \(\sqrt{3}\) units
- āϧāύāĻžāϤā§āĻŽāĻ x āĻāϰ āĻāύā§āϝ \(\mathbf{F}(\mathbf{x})=\int_{1}^{x} \ln t \mathbf{d} \mathbf{t}\) āĻšāϞā§, \(\mathbf{F}^{\prime}(\mathbf{x})=?\)
- \(\frac{1}{x}\)
- ln x
- x ln x
- x ln x – x
Ans. ln x
- 1, 2, 3, 4, 5, 6 āĻ 7 āĻĨā§āĻā§ āĻĒā§āύāϰāĻžāĻŦā§āϤā§āϤāĻŋ āĻāĻžāĻĄāĻŧāĻž āϤāĻŋāύ āĻ
āĻā§āĻā§āϰ āϏāĻāĻā§āϝāĻž āĻāĻ āύ āĻāϰāĻž āĻšāϞā§, āĻāϝāĻŧāĻāĻŋ āϏāĻāĻā§āϝāĻžāϰ āĻŽāĻžāύ 100 āĻĨā§āĻā§ 500 āĻāϰ āĻŽāϧā§āϝā§?
- 240
- 60
- 120
- 480
Ans. 120
- ABC āϤā§āϰāĻŋāĻā§āĻā§āϰ BC, CA āĻ AB āĻŦāĻžāĻšā§āϰ āĻŽāϧā§āϝāĻŦāĻŋāύā§āĻĻā§āĻā§āϞ⧠āϝāĻĨāĻžāĻā§āϰāĻŽā§ D,E āĻ F āĻšāϞā§-
- \(\overrightarrow{\mathrm{AD}}=\overrightarrow{\mathrm{AB}}+\overrightarrow{\mathrm{BC}}\)
- \(\overrightarrow{\mathrm{AD}}=\overrightarrow{\mathrm{AF}}+\overrightarrow{\mathrm{AE}}\)
- \(\overrightarrow{\mathrm{AD}}=\overrightarrow{\mathrm{AB}}+\overrightarrow{\mathrm{AC}}\)
- \(\overrightarrow{\mathrm{AD}}=\overrightarrow{\mathrm{BE}}+\overrightarrow{\mathrm{CF}}\)
Ans. \(\overrightarrow{\mathrm{AD}}=\overrightarrow{\mathrm{AF}}+\overrightarrow{\mathrm{AE}}\)
- āϝāĻĻāĻŋ f(x) = (x – 2) (1-x) āĻšāϝāĻŧ, āϤāĻŦā§ f(f(3)) āĻāϰ āĻŽāĻžāύ-
- 9
- -12
- 12
- 8
Ans. -12
- 1, 0, 2 āĻĻā§āĻŦāĻžāϰāĻž āĻāĻ āĻŋāϤ āϤāĻŋāύ āĻ
āĻā§āĻāĻŦāĻŋāĻļāĻŋāώā§āĻ āϏāĻāĻā§āϝāĻžāĻā§āϞ⧠āĻšāϤ⧠āĻĻā§āĻŦāĻāϝāĻŧāύ āĻĒāĻĻā§āϧāϤāĻŋāϤ⧠āĻāĻāĻāĻŋ āϏāĻāĻā§āϝāĻž āύā§āϝāĻŧāĻž āĻšāϞ⧠āϏāĻāĻā§āϝāĻžāĻāĻŋ 10 āĻĻā§āĻŦāĻžāϰāĻž āĻŦāĻŋāĻāĻžāĻā§āϝ āĻšāĻāϝāĻŧāĻžāϰ āϏāĻŽā§āĻāĻžāĻŦāύāĻž-
- \(\frac{1}{2}\)
- \(\frac{1}{3}\)
- \(\frac{2}{9}\)
- \(\frac{1}{6}\)
Ans. \(\frac{1}{2}\)
- \(x^{2}-4 x+12 y-40=0\) āĻĒāϰāĻžāĻŦā§āϤā§āϤā§āϰ āĻāĻĒāĻā§āύā§āĻĻā§āϰāĻŋāĻ āϞāĻŽā§āĻŦā§āϰ āĻĻā§āϰā§āĻā§āϝ-
- 12
- 8
- 6
- 4
Ans. 12
- x āĻāϰ āĻā§āύ āĻŽāĻžāύā§āϰ āĻāύā§āϝ \(y=x+\frac{1}{x}\) āĻŦāĻā§āϰāϰā§āĻāĻžāĻāĻŋāϰ āĻĸāĻžāϞ āĻļā§āύā§āϝ āĻšāĻŦā§?
- \(\pm \frac{3}{2}\)
- \(\pm 2\)
- 1
- \(\pm 1\)
Ans. \(\pm 1\)
āĻā§āĻŦāĻŦāĻŋāĻā§āĻāĻžāύ
-
āύāĻŋāĻā§āϰ āĻā§āύāĻāĻŋāϰ āϏāĻā§āĻāĻŋāϤ āĻāĻžāĻĻā§āϝ āĻĢā§āϞā§āϰāĻŋāĻĄāĻŋāϝāĻŧāĻžāύ āϏā§āĻāĻžāϰā§āĻ?
- Spirogyra
- Navicula
- Polysiphonia
- Sargassum
Ans. Polysiphonia
- Jellyfish āĻā§āύ āĻĒāϰā§āĻŦā§āϰ āĻĒā§āϰāĻžāĻŖā§?
- Annelida
- Cnidaria
- Porifera
- Arthropoda
Ans. Cnidaria
- āĻāĻŋāϏā§āϝ⧠āĻāĻžāϞāĻāĻžāϰ āĻĒā§āϰāϝā§āĻā§āϤāĻŋāϰ āĻāύāĻ āĻā§?
- āĻŽā§āύā§āĻĄā§āϞ
- āĻšāĻžāĻāĻŋāύāϏāύ
- āϞā§āϝāĻžāĻŽāĻžāϰā§āĻ
- āĻšā§āϝāĻžāĻŦāĻžāϰāϞā§āϝāĻžāύā§āĻĄ
Ans. āĻšā§āϝāĻžāĻŦāĻžāϰāϞā§āϝāĻžāύā§āĻĄ
- āϏāĻāĻā§āϰāĻŽāĻŖāĻā§āώāĻŽ āĻāĻžāĻāϰāĻžāϏ āĻāĻŖāĻžāĻā§ āĻŦāϞāĻž āĻšāϝāĻŧ-
- Nucleocapside
- Virions
- Capsid
- Capsomere
Ans. Virions
- āύāĻŋāĻā§āϰ āĻā§āύāĻāĻŋ āĻāĻĻāĻŋāĻā§āώ -āĻāϰ āĻāĻĻāĻžāĻšāϰāĻŖ?
- Saccharomyces
- Penicillium
- Agaricus
- Bacillus
Ans. Bacillus
- Species Plantarumâ-āĻāϰ āϰāĻāϝāĻŧāĻŋāϤāĻž āĻšāϞā§āύ-
- āĻāϰā§āĻ āĻŦā§āύāĻĨāĻžāĻŽ
- āĻā§āϝāĻžāϰā§āϞāĻžāϏ āϞāĻŋāύāĻŋāϝāĻŧāĻžāϏ
- āĻ ā§āϝāĻžāĻĄāϞāĻĢ āĻāĻā§āĻāϞāĻžāϰ
- āĻŽāĻžāĻāĻā§āϞ āĻ ā§āϝāĻžāĻĄāĻžāύāϏāύ
Ans. āĻā§āϝāĻžāϰā§āϞāĻžāϏ āϞāĻŋāύāĻŋāϝāĻŧāĻžāϏ
- Pteris-āĻāϰ āĻā§āϝāĻžāĻŽā§āĻā§āĻĢāĻžāĻāĻāĻā§ āĻŦāϞāĻž āĻšāϝāĻŧ-
- āĻā§āϝāĻžāĻŽā§āĻā§āĻĢā§āϰ
- āϏā§āĻā§āĻŽāĻŋāϝāĻŧāĻžāĻŽ
- āĻĒā§āϰā§āĻĨā§āϝāĻžāϞāĻžāϏ
- āĻĒā§āϰā§āĻā§āύā§āĻŽāĻž
Ans. āĻĒā§āϰā§āĻĨā§āϝāĻžāϞāĻžāϏ
- Malvaceae āĻā§āϤā§āϰā§āϰ āĻĒā§āĻāϏā§āϤāĻŦāĻā§āϰ āĻāĻ āύ āĻāĻŋ?
- āĻā§āĻā§āϰāĻžāĻĄāĻŋāύā§āĻŽāĻžāϏ
- āĻĻā§āĻŦāĻŋāĻā§āĻā§āĻāĻ
- āĻāĻāĻā§āĻā§āĻāĻ
- āĻĻāϞāϞāĻā§āύ
Ans. āĻāĻāĻā§āĻā§āĻāĻ
- āĻ
āϏāĻŽā§āĻĒā§āϰā§āĻŖ āĻĒā§āϰāĻāĻāϤāĻž āĻšāϞ⧠āĻŽāύā§āĻšāĻžāĻāĻŦā§āϰāĻŋāĻĄ āĻā§āϰāϏā§āϰ \(\mathbf{F}_{2}\) āĻāύā§āϤ⧠āĻĢāĻŋāύā§āĻāĻžāĻāĻĒā§āϰ āĻ
āύā§āĻĒāĻžāϤ āĻšāϝāĻŧ-
- 3:1
- 9:3:3:1
- 12:3:1
- 1:2:1
Ans. 1:2:1
- āύāĻŋāĻā§āϰ āĻā§āύāĻāĻŋāĻā§ āĻā§āĻŦāύā§āϤ āĻā§āĻŦāĻžāĻļā§āĻŽ āĻŦāϞāĻž āĻšāϝāĻŧ?
- Ficus
- Navicula
- Cycas
- Hibiscus
Ans. Cycas
- āύāĻŋāĻā§āϰ āĻā§āύ āĻā§āώā§āĻĻā§āϰāĻžāĻā§āĻāĻāĻŋ āĻā§āϰāĻžāύāĻžāĻŽ āϧāĻžāϰāĻŖ āĻāϰā§?
- āĻā§āϞā§āϰā§āĻĒā§āϞāĻžāϏā§āĻ
- āϰāĻžāĻāĻŦā§āϏā§āĻŽ
- āϞāĻžāĻāϏā§āϏā§āĻŽ
- āĻŽāĻžāĻāĻā§āĻāύā§āĻĄā§āϰāĻŋāϝāĻŧāĻž
Ans. āĻā§āϞā§āϰā§āĻĒā§āϞāĻžāϏā§āĻ
- āĻā§āώ āĻŦāĻŋāĻāĻžāĻāύā§āϰ āĻā§āύ āĻĒāϰā§āϝāĻžāϝāĻŧā§ āϏāĻŋāύā§āϝāĻžāĻĒāϏāĻŋāϏ āĻāĻā§?
- āϞā§āĻĒā§āĻā§āĻāĻŋāύ
- āĻāĻžāĻāĻā§āĻāĻŋāύ
- āĻĒā§āϝāĻžāĻāĻžāĻāĻāĻŋāύ
- āĻĄāĻŋāĻĒā§āϞā§āĻāĻŋāύ
Ans. āĻāĻžāĻāĻā§āĻāĻŋāύ
- āĻĒāϰāĻŋāĻĒāĻ āĻĒāϰā§āϝāĻžāϝāĻŧā§ āύāĻŋāĻā§āϰ āĻā§āύ āĻā§āώ⧠āύāĻŋāĻāĻā§āϞāĻŋāϝāĻŧāĻžāϏ āĻĨāĻžāĻā§ āύāĻž?
- āϏāĻŋāĻāύāϞ
- āϏā§āĻā§āĻŽāĻžāĻāĻžāϞ āϏā§āϞ
- āĻāĻžāĻāϞā§āĻŽ āĻĢāĻžāĻāĻŦāĻžāϰ
- āĻĢā§āϞā§āϝāĻŧā§āĻŽ āĻĢāĻžāĻāĻŦāĻžāϰ
Ans. āϏāĻŋāĻāύāϞ
- āĻāĻā§ā§°ā§āϝāĻŧ āĻĢāĻā§āĻĢāϏāĻĢāϰāĻžāĻāϞā§āĻļāύā§āϰ āĻāĻ āĻāĻā§āϰ⧠āĻāϤāĻāĻŋ ATP āϤā§āϰāĻŋ āĻšāϝāĻŧ?
- 1
- 2
- 3
- 4
Ans. 1
- āĻŽāĻžāύā§āώā§āϰ āĻĻāĻļāĻŽ āĻāϰā§āĻāĻŋāĻ āϏā§āύāĻžāϝāĻŧā§āϰ āύāĻžāĻŽ āĻāĻŋ?
- āĻ āĻĒāĻāĻŋāĻ
- āĻā§āĻāĻžāϏ
- āĻ āĻĄāĻŋāĻāϰāĻŋ
- āĻšāĻžāĻāĻĒā§āĻā§āϞā§āϏāĻžāϞ
Ans. āĻā§āĻāĻžāϏ
- āĻā§āύāĻāĻŋ āύā§āĻĢā§āϰāύā§āϰ āĻ
āĻāĻļ āύāϝāĻŧ?
- Renal pelvis
- Glomerulus
- Loop of Henle
- Collecting duct
Ans. Renal pelvis
- āĻā§āύ āĻšāϰāĻŽā§āύāĻāĻŋāϰ āĻā§āϏ āĻĒāĻŋāĻā§āĻāĻāĻžāϰāĻŋ āĻā§āϰāύā§āĻĨāĻŋ āύāϝāĻŧ?
- Progesteron
- FSH
- LH
- Oxytocin
Ans. Progesteron
- āĻā§āύ āĻĒā§āϰāĻžāĻŖā§āĻāĻŋ āĻāĻžāĻĻā§āϝ āĻļāĻŋāĻāϞā§āϰ āϤā§āϤā§āϝāĻŧ āϏā§āϤāϰā§?
- Cow
- Tiger
- Caterpillar
- Elephant
Ans. Tiger
- āĻŦā§āĻā§āĻā§āϰ āĻā§āύ āĻ
āĻāĻļā§ Filtration āĻšāϝāĻŧ?
- āĻšā§āύāϞāĻŋāϰ āϞā§āĻĒ
- āĻā§āϞā§āĻŽā§āϰā§āϞāĻžāϏ
- āĻā§āĻĄāĻŧāĻžāĻĻā§āĻļā§āϝāĻŧ āĻĒā§āϝāĻžāĻāĻžāύ⧠āύāĻžāϞāĻŋāĻāĻž
- āĻŽā§āϤā§āϰāĻĨāϞāĻŋ
Ans. āĻā§āϞā§āĻŽā§āϰā§āϞāĻžāϏ
- āĻŽāĻžā§ā§āϏāĻŋāϏ āĻā§āώ āĻŦāĻŋāĻāĻžāĻāύ āĻā§āĻĨāĻžāϝāĻŧ āĻšāϝāĻŧ?
- āĻĢā§āϏāĻĢā§āϏ
- āϝā§āύ āĻā§āώ
- āϝāĻā§ā§
- āĻ āϏā§āĻĨāĻŋ
Ans. āϝā§āύ āĻā§āώ
- āύāĻŋāĻā§āϰ āĻā§āύāĻāĻŋāĻā§ āĻŽāĻžāϏā§āĻāĻžāϰ āĻā§āϞā§āϝāĻžāύā§āĻĄ āĻŦāϞāĻž āĻšāϝāĻŧ?
- Pituitary Gland
- Thyroid Gland
- Parotid Gland
- Lymph Gland
Ans. Pituitary Gland
- āĻā§āύ āϰāĻā§āϤā§āϰ āĻā§āϰā§āĻĒāĻā§ âUniversal Donorâ āĻŦāϞāĻž āĻšāϝāĻŧ?
- AB
- B
- O
- A
Ans. O
- āĻŽāĻžāύā§āώā§āϰ āĻ
āĻā§āϏā§āĻŽ āĻāϤ⧠āĻā§āĻĄāĻŧāĻž?
- 44
- 23
- 24
- 22
Ans. 22
- Platypus āĻā§āĻĨāĻžāϝāĻŧ āĻĒāĻžāĻāϝāĻŧāĻž āϝāĻžāϝāĻŧ?
- Australia
- Oriental Region
- Africa
- Bangladesh
Ans. Australia
- āĻā§āϞāĻžāĻā§āύ āĻāĻ āϧāϰāύā§āϰ-
- āĻļāϰā§āĻāϰāĻž
- āĻāĻŽāĻŋāώ
- āĻāύāĻŋāĻ āĻĒāĻĻāĻžāϰā§āĻĨ
- āĻāϰā§āĻŦāĻŋ
Ans. āĻāĻŽāĻŋāώ
- āύāĻŋāĻā§āϰ āĻā§āύāĻāĻŋ āĻāĻžāϞāĻŽā§āĻā§āϰ āĻŦā§āĻā§āĻāĻžāύāĻŋāĻ āύāĻžāĻŽ?(āĻĒā§āϰāĻžāϤāύ āϏāĻŋāϞā§āĻŦāĻžāϏ)
- Andrographis paniculata
- Bacopa monnieri
- Centella asiatica
- Ocimum sanctum
Ans. Andrographis paniculata
- Amoeba āĻāϰ āĻāϞāύ āĻ
āĻā§āĻā§āϰ āύāĻžāĻŽ āĻāĻŋ?(āĻĒā§āϰāĻžāϤāύ āϏāĻŋāϞā§āĻŦāĻžāϏ)
- āĻŽāĻžāĻāĻā§āϰā§āĻāĻŋāϞāĻžāĻ
- āϏāĻŋāĻāĻĄā§āĻĒāĻĒāĻžāĻĄāĻŋāϝāĻŧāĻž
- āϏāĻŋāϞāĻŋāϝāĻŧāĻž
- āĻĢā§āϞāĻžāĻā§āϞāĻž
Ans. āϏāĻŋāĻāĻĄā§āĻĒāĻĒāĻžāĻĄāĻŋāϝāĻŧāĻž
- āĻā§āύ āĻĒā§āϰāĻžāĻŖā§ āĻāĻŽāĻžāĻļāϝāĻŧ āϏā§āώā§āĻāĻŋ āĻāϰā§?(āĻĒā§āϰāĻžāϤāύ āϏāĻŋāϞā§āĻŦāĻžāϏ)
- Wuchereria bancrofti
- Aedes
- Entamoeba
- Ascaris
Ans. Entamoeba
- āĻā§ āĻāύā§āĻāĻŋāύā§āύā§āĻāĻžāϞ āĻĄā§āϰāĻŋāĻĢāĻ āϏāĻŽā§āĻĒāϰā§āĻā§ āĻāϧā§āύāĻŋāĻ āϧāĻžāϰāĻŖāĻž āĻĻā§āύ?(āĻĒā§āϰāĻžāϤāύ āϏāĻŋāϞā§āĻŦāĻžāϏ)
- āĻāϝāĻŧā§āĻāύāĻžāϰ
- āĻĄāĻžāϰāĻāĻāύ
- āĻĢā§āϞā§āĻāĻžāϰ
- āĻŦā§āĻāύ
Ans. āĻāϝāĻŧā§āĻāύāĻžāϰ
- āĻā§āύāĻāĻŋ āĻā§āϰāĻŋāύ āĻšāĻžāĻāϏ āĻā§āϝāĻžāϏ āύāϝāĻŧ?(āĻĒā§āϰāĻžāϤāύ āϏāĻŋāϞā§āĻŦāĻžāϏ)
- \(\mathrm{SO}_{2}\)
- \(\mathrm{CH}_{4}\)
- \(\mathrm{CO}_{2}\)
- \(\mathrm{H}_{2} \mathrm{O}\)
Ans. \(\mathrm{SO}_{2}\)
āĻŦāĻžāĻāϞāĻž
- āĻĒā§āϰāϤāĻŋāώā§āĻ āĻž āϞāĻžāĻ āĻāϰā§āĻā§ āϝā§-
- āĻĒā§āϰāϤāĻŋāώā§āĻ āĻŋāϤ
- āϏāĻĢāϞ
- āϞāĻŦā§āϧāĻĒā§āϰāϤāĻŋāώā§āĻ
- āĻĒā§āϰāϤāĻŋāώā§āĻ āĻžāϞāĻŦā§āϧ
Ans. āϞāĻŦā§āϧāĻĒā§āϰāϤāĻŋāώā§āĻ
- ‘āĻŦā§āĻĻā§āϧāĻŋ’ āĻļāĻŦā§āĻĻāĻāĻŋāϰ āĻ āĻŋāĻ āĻĒā§āϰāĻā§āϤāĻŋ āĻ āĻĒā§āϰāϤā§āϝāϝāĻŧ-
- āĻŦā§āĻĻ + āϧāĻŋ
- āĻŦā§āϧ + āĻĻāĻŋ
- âāĻŦā§āϧ⧠+ āϤāĻŋ
- āĻŦā§āĻĻā§āϧ + āĻ
Ans. âāĻŦā§āϧ⧠+ āϤāĻŋ
- ‘āĻāĻ āϏāĻŽāϝāĻŧ āϏā§āϰā§āϝāĻā§ āĻĸā§āĻā§ āĻ
āύā§āĻ āĻŽā§āĻā§āϰ …’ āĻļā§āύā§āϝāϏā§āĻĨāĻžāύā§āϰ āĻļāĻŦā§āĻĻāĻāĻŋ āĻšāĻā§āĻā§-
- āϰāĻžāĻļāĻŋ
- āĻĻāϞ
- āĻĒāĻžāĻāĻŋ
- āĻĒāĻžāϞāĻ
Ans. āĻĒāĻžāϞāĻ
- ‘āĻāϏāϞ āĻāĻĨāĻž āĻāĻ āϝ⧠āĻŽāĻžāύā§āώā§āϰ āĻĻā§āĻšāĻŽāύā§āϰ āϏāĻāϞ āĻĒā§āϰāĻāĻžāϰ āĻā§āϰāĻŋāϝāĻŧāĻžāϰ āĻŽāϧā§āϝ⧠āĻā§āϰā§āĻĄāĻŧāĻž āĻļā§āϰā§āώā§āĻ āĻā§āύāύāĻž āϤāĻž āĻāĻĻā§āĻĻā§āĻļā§āϝāĻšā§āύ’ āĻāĻĻā§āϧā§āϤāĻžāĻāĻļā§ āĻĒā§āϰā§ā§āĻāύā§āϝāĻŧ āϝāϤāĻŋāĻāĻŋāĻšā§āύā§āϰ āϏāĻāĻā§āϝāĻž-
- āĻĻā§āĻ
- āϤāĻŋāύ
- āĻĒāĻžāĻāĻ
- āĻāϝāĻŧ
Ans. āϤāĻŋāύ
- The wind suddenly dropped. āĻŦāĻžāĻā§āϝāĻāĻŋāϰ āϝāĻĨāĻžāϝāĻĨ āĻŦāĻā§āĻāĻžāύā§āĻŦāĻžāĻĻ?
- āĻŦāĻžāϤāĻžāϏ āĻĒāĻĄāĻŧā§ āĻā§āϞ
- āĻŦāĻžāϤāĻžāϏāĻāĻž āĻāĻŽā§ āĻā§āϞ
- āĻšāĻ āĻžā§ āĻŦāĻžāϤāĻžāϏ āĻāĻŽā§ āĻā§āϞ
- āĻšāĻ āĻžā§ āϏā§āϤāĻŦā§āϧāϤāĻž āύā§āĻŽā§ āĻāϞ
Ans. āĻšāĻ āĻžā§ āĻŦāĻžāϤāĻžāϏ āĻāĻŽā§ āĻā§āϞ
- âāĻĒā§āϰāĻžāĻā§āύâ āĻāϰ āĻŦāĻŋāĻĒāϰā§āϤ āĻļāĻŦā§āĻĻ-
- āϤāϰā§āĻŖ
- āύāĻŦā§āύ
- āĻ āϰā§āĻŦāĻžāĻā§āύ
- āύā§āϤāύ
Ans. āĻ āϰā§āĻŦāĻžāĻā§āύ
- âāĻŽā§āύāĻŋāĻŽā§āĻā§â āĻŦāϞāϤ⧠āĻŦā§āĻāĻžāϝāĻŧ-
- āĻā§āϤā§
- āϞāĻžāĻā§āĻ
- āĻŽā§āĻāϰāĻž
- āĻŦāĻŋāĻĄāĻŧāĻžāϞāĻŽā§āĻā§
Ans. āϞāĻžāĻā§āĻ
- âāĻļāĻŋāĻļāĻŋāϰ āϝāĻāύ āĻā§āϞ⧠āϤāĻāύ āϤāĻžāĻšāĻžāϰ āĻŽāĻžāϰ āĻŽā§āϤā§āϝ⧠āĻšāϝāĻŧāĨ¤â āĻŦāĻžāĻā§āϝāĻāĻŋ-
- āϏāϰāϞ
- āϝā§āĻāĻŋāĻ
- āĻāĻāĻŋāϞ
- āĻāĻŖā§āĻĄ
Ans. āĻāĻāĻŋāϞ
- āĻā§āύāĻāĻŋ āĻŦāĻŋāĻļā§āώāĻŖ?
- āĻĻāĻŋāύ
- āĻĻāĻŋāύāĻžāύā§āϤ
- āĻĻāĻŋāύ-āϰāĻžāϤ
- āĻĻā§āύ
Ans. āĻĻā§āύ
- âāĻšāĻžāϏāĻŋ āĻĻāĻŋāϝāĻŧā§ āĻāϰāĻāĻžāĻā§ āĻāϰāĻŋāϝāĻŧā§ āϰāĻžāĻāϤ⧠āϏā§āĨ¤ āĻŦāĻžāĻā§āϝāĻāĻŋāϤ⧠âāĻĻāĻŋāϝāĻŧā§â āĻšāϞā§-
- āĻ āĻŦā§āϝāϝāĻŧ
- āĻĒā§āϰāϤā§āϝāϝāĻŧ
- āĻ āύā§āϏāϰā§āĻ
- āĻāĻĒāϏāϰā§āĻ
Ans. āĻ āύā§āϏāϰā§āĻ
- āύāĻŋāĻā§āϰ āĻā§āύāĻāĻŋ āĻŦāĻŋāϰāĻžāĻŽāĻāĻŋāĻšā§āύ āύāϝāĻŧ?
- āĻāĻŽāĻž (,)
- āϏā§āĻŽāĻŋ-āĻā§āϞāύ [;]
- āĻĄā§āϝāĻžāϏ [-]
- āĻšāĻžāĻāĻĢā§āύ [-]
Ans.
- āĻā§āύāĻāĻŋ āϧā§āĻŦāύāĻŋāĻŦāĻŋāĻĒāϰā§āϝāϝāĻŧā§āϰ āĻāĻĻāĻžāĻšāϰāĻŖ?
- āĻŦāĻĄāĻŧāĻĻāĻžāĻĻāĻž > āĻŦāĻĄāĻŧāĻĻāĻž
- āĻāĻŋāĻā§ > āĻāĻŋāĻā§
- āĻĒāĻŋāĻļāĻžāĻ > āĻĒāĻŋāĻāĻžāĻļ
- āĻŽā§āĻā§āϤāĻž > āĻŽā§āĻā§āϤāĻž
Ans. āĻĒāĻŋāĻļāĻžāĻ > āĻĒāĻŋāĻāĻžāĻļ
- āĻā§āύāĻāĻŋ āĻ
āĻĒāĻĒā§āϰā§ā§āĻā§āϰ āĻĻā§āώā§āĻāĻžāύā§āϤ?
- āĻāĻ
- āĻāĻāϤā§āϰ
- āĻāĻāϤā§āϰāĻŋāϤ
- āĻāĻāĻžāĻā§
Ans. āĻāĻāϤā§āϰāĻŋāϤ
- āĻā§āύāĻāĻŋ āĻāĻāĻžāĻā§āώāϰ āĻļāĻŦā§āĻĻ?
- āĻŽāĻžāĻŽāĻž
- āĻāĻžāĻ
- āĻĻāĻŋāĻĻāĻŋ
- āĻāĻžāĻāĻž
Ans. āĻāĻžāĻ
- ‘āĻā§āĻāϞāĻžāϏ’ āĻāϰ āĻĒā§āϰāϤāĻŋāĻļāĻŦā§āĻĻ-
- āĻā§āĻļāĻāĻžāϝāĻŧ
- āĻāĻžāĻāĻāĻĄāĻŧāĻž
- āĻā§āώā§āĻŖāĻāĻžāϝāĻŧ
- āĻāĻŋāϰāĻāĻŋāĻāĻŋ
Ans. āĻāĻŋāϰāĻāĻŋāĻāĻŋ
- ‘āĻā§āĻā§āĻ’ āĻāϰ āĻļāĻŦā§āĻĻāĻžāϰā§āĻĨ-
- āĻāĻā§āĻā§āϰ
- āĻā§āϰāĻŽāϰ
- āĻā§āĻāĻā§āĻ
- āĻāĻžāĻĄāĻŧ
Ans. āĻā§āϰāĻŽāϰ
- āĻĒā§āĻā§āϝāĻŧāĻž āĻļāĻŦā§āĻĻā§āϰ āĻ
āϰā§āĻĨ-
- āĻ āύā§āĻāϤ
- āϞāĻžāĻ āĻŋāϝāĻŧāĻžāϞ
- āϏāύā§āϤā§āϰāĻžāϏā§
- āĻĻāĻžāϞāĻžāϞ
Ans. āĻ āύā§āĻāϤ
- āĻā§āύāĻāĻŋ āϝā§āĻā§āĻŽ āϏā§āĻŦāϰāϧā§āĻŦāύāĻŋ?
- āĻ
- āĻ
- āĻ
- āĻ
Ans. āĻ
- āĻā§āύ āĻļāĻŦā§āĻĻāĻāĻŋāϰ āĻĒā§āϰā§āώāĻŦāĻžāĻāĻ āϰā§āĻĒ āύā§āĻ?
- āϏāϤā§
- āĻ āĻžāĻā§āϰāύ
- āĻāĻŋ
- āώā§āĻĄāĻŧāĻļā§
Ans. āώā§āĻĄāĻŧāĻļā§
- āĻŦā§āϝāĻā§āĻāύāĻŦāϰā§āĻŖā§āϰ āϏāĻāĻā§āώāĻŋāĻĒā§āϤ āϰā§āĻĒāĻā§ āĻā§ āĻŦāϞā§?
- āĻĢāϞāĻž
- āĻāĻžāϰ
- āĻ āĻā§āώāϰ
- āϧā§āĻŦāύāĻŋāĻŽā§āϞ
Ans. āĻĢāϞāĻž
- ‘āĻāĻāĻž’ āĻĒā§āϰāϤā§āϝāϝāĻŧ āĻā§āύ āĻļāĻŦā§āĻĻā§ āĻā§āώā§āĻĻā§āϰāĻžāϰā§āĻĨā§ āĻŦā§āϝāĻŦāĻšā§āϤ āĻšāϝāĻŧā§āĻā§?
- āϏā§āĻŦāĻŋāĻāĻž
- āĻŽāĻžāϞāĻŋāĻāĻž
- āĻŦāĻžāϞāĻŋāĻāĻž
- āĻāĻžāϞāĻŋāĻāĻž
Ans. āĻŽāĻžāϞāĻŋāĻāĻž
- ‘āϏāĻāϞ āĻāĻžāϤā§āϰāϰāĻžāĻ āϝāĻĨāĻžāϏāĻŽāϝāĻŧā§ āĻāĻĒāϏā§āĻĨāĻŋāϤ āĻšāϝāĻŧā§āĻā§āĨ¤’ āĻŦāĻžāĻā§āϝāĻāĻŋāϤ⧠āĻā§ āϧāϰāύā§āϰ āĻā§āϞ āĻāĻā§?
- āĻŦāĻžāύāĻžāύ
- āĻĒāĻĻ
- āĻŦāĻāύ
- āĻŦāĻŋāĻāĻā§āϤāĻŋ
Ans. āĻŦāĻāύ
- âāĻā§āϞā§āϰ āϞāĻžāĻ āĻ
āĻŽā§āĻŦāϞā§āϰ āĻāĻĻā§â āĻŦāĻžāĻāϧāĻžāϰāĻžāϰ āĻ
āϰā§āĻĨ āĻā§?
- āĻā§āϰā§āĻŖāĻļā§āϰā§āĻŖ āϞā§āĻ
- āĻŽāĻŋāĻļāĻŋāϝāĻŧā§ āĻĢā§āϞāĻž
- āϏāĻŦ āĻĒāĻā§āώā§āϰ āĻŽāύ āϝā§āĻāĻŋāϝāĻŧā§ āĻāϞāĻž
- āĻĒā§āĻāĻĨāĻŋāĻāϤ āĻŦāĻŋāĻĻā§āϝāĻž
Ans. āϏāĻŦ āĻĒāĻā§āώā§āϰ āĻŽāύ āϝā§āĻāĻŋāϝāĻŧā§ āĻāϞāĻž
- âāĻšā§āĻŽāύā§āϤā§â āĻāϞā§āĻĒā§ āĻāϞā§āϞā§āĻāĻā§āϤ āĻāĻĄāĻŽāύā§āĻĄ āĻŦāĻžāϰā§āĻā§āϰ āϞā§āĻāĻž âāĻĢā§āϰā§āĻā§āĻ āϰā§āĻā§āϞā§āϝā§āĻļāύ’ āĻā§āϰāύā§āĻĨāĻāĻŋ āĻāϤ āĻā§āϰāĻŋāϏā§āĻāĻžāĻŦā§āĻĻā§ āĻĒā§āϰāĻāĻžāĻļāĻŋāϤ āĻšāϝāĻŧ?(āĻĒā§āϰāĻžāϤāύ āϏāĻŋāϞā§āĻŦāĻžāϏ)
- ā§§ā§ā§¯ā§Ļ
- ā§§ā§ā§¯ā§¨
- ā§§ā§ā§¯ā§Ē
- ā§§ā§Žā§Ļā§§
Ans. ā§§ā§ā§¯ā§Ļ
- âāϏā§āύāĻžāϰ āϤāϰ⧒ āĻāĻŦāĻŋāϤāĻžāϝāĻŧ ‘āĻŦāĻžāĻāĻāĻž āĻāϞ” āĻŦāϞāϤ⧠āĻĒā§āϰāϤā§āĻā§ āĻ
āϰā§āĻĨā§ āĻā§āĨ¤ āĻŦā§āĻāĻžāύ⧠āĻšāϝāĻŧā§āĻā§?(āĻĒā§āϰāĻžāϤāύ āϏāĻŋāϞā§āĻŦāĻžāϏ)
- āĻāĻŦāĻŋāϰ āĻŦā§āϝāĻā§āϤāĻŋāϏāϤā§āϤāĻž
- āĻŽāĻšāĻžāĻāĻžāϞ
- āĻāĻžāϞāϏā§āϰā§āϤ
- āĻāĻŦāĻŋāϰ āϏā§āώā§āĻāĻŋāĻāϰā§āĻŽ
Ans. āĻāĻžāϞāϏā§āϰā§āϤ
- āĻā§āύ āĻĻā§āĻāĻŋ āϰāĻāύāĻžāϝāĻŧ ‘āϏā§āϤāĻž” āύāĻžāĻŽā§āϰ āĻāϞā§āϞā§āĻ āĻĒāĻžāĻāϝāĻŧāĻž āϝāĻžāϝāĻŧ?(āĻĒā§āϰāĻžāϤāύ āϏāĻŋāϞā§āĻŦāĻžāϏ)
- āĻšā§āĻŽāύā§āϤ⧠āĻ āĻ āϰā§āϧāĻžāĻā§āĻā§
- āĻšā§āĻŽāύā§āϤ⧠āĻ āϏāĻžāĻšāĻŋāϤā§āϝ⧠āĻā§āϞāĻž
- āĻ āϰā§āϧāĻžāĻā§āĻā§ āĻ āĻŦāĻŋāϞāĻžāϏā§
- āĻ āϰā§āϧāĻžāĻā§āĻā§ āĻ āϏāĻžāĻšāĻŋāϤā§āϝ⧠āĻā§āϞāĻž
Ans. āĻšā§āĻŽāύā§āϤ⧠āĻ āĻ āϰā§āϧāĻžāĻā§āĻā§
- âāĻāĻĨāĻžāϞâ āĻā§?(āĻĒā§āϰāĻžāϤāύ āϏāĻŋāϞā§āĻŦāĻžāϏ)
- āĻāĻā§āĻāĻžāĻĻāύ
- āĻĒāĻžāϤā§āϰ
- āĻā§āϝāĻŧāĻžāϞ
- āĻāϏā§āϤāĻžāĻŦāϞ
Ans. āĻā§āϝāĻŧāĻžāϞ
- āĻāϞā§āĻĒā§āϰ āϰāĻžāĻāĻž āĻāĻŋāϞ āĻā§?(āĻĒā§āϰāĻžāϤāύ āϏāĻŋāϞā§āĻŦāĻžāϏ)
- āϰāĻžāĻšāĻžāϤ
- āϰā§āĻŖā§
- āύāĻžāĻāĻŋāĻŽ
- āϤāĻĒā§
Ans. āϤāĻĒā§
- āĻāĻŽāύ āϧāĻžāύā§āϰ āĻāϞā§āϞā§āĻ āĻāĻā§ āĻā§āύ āĻāĻŦāĻŋāϤāĻžāϝāĻŧ?(āĻĒā§āϰāĻžāϤāύ āϏāĻŋāϞā§āĻŦāĻžāϏ)
- āĻāĻŦāϰ
- āϏā§āύāĻžāϰ āϤāϰā§
- āĻāĻŽāĻžāϰ āĻĒā§āϰā§āĻŦ āĻŦāĻžāĻāϞāĻž
- āĻŦāĻžāĻāϞāĻžāĻĻā§āĻļ
Ans. āĻŦāĻžāĻāϞāĻžāĻĻā§āĻļ
- ‘āĻā§āύ āϏāĻāĻŋ āĻā§āĻŖā§ āĻāĻžāĻāĻĻāĻŋāĻ āĻŦāϏāĻŋāϝāĻŧāĻž?’ āĻĒāĻāĻā§āϤāĻŋāĻāĻŋ āĻā§āύ āϰāĻāύāĻžāϝāĻŧ āĻĒāĻžāĻāϝāĻŧāĻž āϝāĻžāϝāĻŧ?(āĻĒā§āϰāĻžāϤāύ āϏāĻŋāϞā§āĻŦāĻžāϏ)
- āĻŦāĻŋāϞāĻžāϏā§
- āϤāĻžāĻšāĻžāϰā§āĻ āĻĒāĻĄāĻŧā§ āĻŽāύā§
- āĻšā§āĻŽāύā§āϤā§
- āĻ āϰā§āϧāĻžāĻā§āĻā§
Ans. āĻ āϰā§āϧāĻžāĻā§āĻā§
āĻāĻāϰā§āĻāĻŋ
Read the following passage and answer the questions below (1-5)
Increased numbers of women in science can only be a good thing. Not simply because it is grossly unjust for women to be unable to experience the challenging but also hugely intellectually rewarding experience of participating in scientific research, but also because the cost to society of excluding women is intolerably high. We need the very best minds going into science, and it stands to reason that if women are excluded, we cut this resource in half. What’s more, women bring new ways of thinking and a broader range of ideas to the table, which is crucial for science to flourish. All scientists have a responsibility to be feminists and encourage women to participate in science and fight the barriers that exist. However, this is often more easily said than done. There are several proposed reasons for why women are discouraged from participating in science at a ranger of levels -form primary school children to professors. Among other things, these include a lack of role models and support networks -as well as harassment and bullying-but also less obvious barriers, for example, unconscious biases in job interviews and letters of reference. In the end, the way to tackle prejudice against women is to increase awareness of the particular challenges faced by female scientists and to put systems in place that promote equal opportunities. Meanwhile, we need outstanding female role models to show unequivocally that women can compete on the same intellectual level as men and encourage other women to follow their lead. Together we can create the level playing field which is so desperately required.
-
Which of the following opinions is not shared by the writer of the passage?
- A Participation of women science is beneficial for humanity.
- Women bring in new ideas and resources.
- Women tend to be more intelligent than men.
- Excluding women from science is counter-productive.
Ans. Women tend to be more intelligent than men.
- If an idea âstands to reasonâ, it is-
- illogical
- apparently sensible
- irrational
- sensible
Ans. apparently sensible
- In the passage, âflourishâ means the opposite of-
- boom
- decline
- unfold
- grow
Ans. decline
- Which of the following is not the reason for women staying away from science, according to the passage?
- lack of role models
- inadequate facilities
- orthodox mindset
- character trait
Ans. orthodox mindset
- âUnequivocally” means-
- indirectly
- clearly
- hesitantly
- politely
Ans. clearly
- Never _____ till tomorrow what you can do today.
- put off
- put down
- put up with
- put up
Ans. put off
- The name “Schengenâ originates _____ a small town Luxemberg, situated near the French and German borders.
- from, in
- in, in
- in, away from
- at, near
Ans. from, in
- The planting and care of woody plants, especially trees, is known as-
- arboriculture
- husbandry
- pisciculture
- aquaculture
Ans. arboriculture
- âThe experiment has been a resounding success.” Here “resoundingâ means.
- moderate
- somewhat
- huge
- quick
Ans. huge
- You are advised to make your visa application _____ of your proposed travel date.
- well in advance
- on time
- at the time
- early
Ans. well in advance
- _____ the exams are over, we can plan for a sight seeing tour.
- Even now
- Now that
- Now and then
- Now or never
Ans. Now that
- In 1962, the story of Helen Keller’s life _____ into a fillm, The Miracle Worker.
- made
- had made
- was made
- has been made
Ans. was made
- Water is essential to life and we depend on it, _____ many people take water for granted.
- yet
- but also
- nonetheless
- furthermore
Ans. furthermore
- If I fail my exams, my parents ___ let me go to Cox’s Bazar this summer.
- wouldn’t
- would not have
- were not
- won’t
Ans. won’t
- âOncology’ relates to ______
- law
- medicine
- ecology
- environment
Ans. medicine
- “Malignancyâ is _____
- the feeling of hatred
- the state of a disease likely to cause death
- the science of maleness
- the belief in life after death
Ans. the state of a disease likely to cause death
- The antonym of âmigrantâ is _____
- expatriate
- gypsy
- native
- nomad
Ans. native
- The correct spelling is ______
- sobrity
- sobriaty
- sobriety
- sobrighty
Ans. sobriety
-
A philanthropist is someone who _____
- is extremely intellilgent
- is rich and helps the poor and the needy
- studies philology
- understand the secret of the needy
Ans. is rich and helps the poor and the needy
- We were just having a friendly _____ about cricket.
- gossip
- chat
- whisper
- report
Ans. chat
- We hid our boat in the bushes and set _____ a camp ______the river.
- by, in
- on, at
- up, by
- down, over
Ans. on, at
- If I were you, I _____ to the picnic with my friends.
- will by going
- would go
- will go
- going
Ans. would go
- Water is our life source; it makes up 70% of _____ bodies.
- us
- their
- our
- ours
Ans. our
- It is now _____ expensive to repair the damage which has been done.
- very much
- too much
- many
- too
Ans. too much
- If we have _____ anything from our mistakes, we will keep the new areas of water clean.
- learn
- learned
- learning
- learnt
Ans. learned, learnt
- The registered parcel _____ arrived for you is on the table.
- who
- whom
- which
- when
Ans. which
- You must ______ of Helen Keller.
- hear
- heard
- have heard
- hearing
Ans. have heard
- No _____ figures are available about the bus accident casualties.
- precised
- precis
- precisely
- precise
Ans. precise
- I am sick of rain and bad weather! Hopefully, when we wake up tomorrow morning, the sun ______
- is shining
- will be shining
- will be shine
- will shining
Ans. will be shining
- By the time I get to Khulna this evening, I _____ more than three hundred miles.
- will driving
- will be driving
- will have been driving
- will have been driven
Ans. will have been driving